Org.openqa.selenium.ElementNotInteractableException: element not interactable
When I try to upload file but when I use action 'click', window to upload file is visible
#FindBy(id = "uniform-fileUpload")
WebElement uploadFile;
So when I try this method:
public void uploadFile(){
uploadFile.click();
}
Everything is ok and window to select file is open so element is visible.
But when I try this:
uploadFile.sendKeys("C:\\test.png");
}
I have exeption:
org.openqa.selenium.ElementNotInteractableException: element not interactable
Page:
http://automationpractice.com/index.php?controller=contact
You are trying to send keystrokes to a div. You need to select on the input under the div, and then send the keystrokes to that instead.
<div class="uploader" id="uniform-fileUpload">
<input type="file" name="fileUpload" id="fileUpload" class="form-control">
...
</div>
Try id fileUpload instead.
Change this
#FindBy(id = "uniform-fileUpload")
WebElement uploadFile;
to
#FindBy(id = "fileUpload")
WebElement uploadFile;
Since this is the input element that needs to be the target for your file input.
I had this error when doing something like this in a generic methiod:
element.Clear(); // <-- OpenQA.Selenium.ElementNotInteractableException
element.SendKeys(value);
Turns out, that you cannot use the Clear() function on an <input type="file"/> dialog.
Related
I am trying with the following Selenium Code using Cucumber for W3Schools site. When I click on "Try it yourself" button then it navigates to another page opening different window and the window control also goes to the new window opened. So,In the new window opened, if i click the run button, it throws an exception:
invalid Selector
code:
//This clicks on the Try it yourself button
#FindBy(how=How.XPATH,using="//*[#id=\"main\"]/div[4]/p/a")
private WebElement TryItYourself;
public void TryItYourSelfClick()
{
TryItYourself.click();
}
//Now,a new window opens up where I want to click on Run Button
#FindBy(how=How.LINK_TEXT,using="Run >>")
private WebElement RunButton;
public void RunClick()
{
RunButton.click();
}
Calling Run Method
#Then("^a new window should appear$")
public void a_new_window_should_appear() {
System.out.println("Run button before Clicking");
driver.manage().timeouts().implicitlyWait(10, TimeUnit.SECONDS);
obj1.RunClick();
System.out.println("Run after clicking");
driver.manage().timeouts().implicitlyWait(10, TimeUnit.SECONDS);
Set <String> handle=driver.getWindowHandles();
String firstWinHandle=driver.getWindowHandle();
String WinHandle=handle.iterator().next();
if(WinHandle!=firstWinHandle)
{
driver.switchTo().window(WinHandle);
System.out.println("Working for new window opened");
}
}
why this invalid selector exception is coming?
HTML code:
<div class="w3-bar w3-light-grey" style="border-top:1px solid #f1f1f1;overflow:auto">
<a id="tryhome" href="https://www.w3schools.com" target="_blank" title="w3schools.com Home" class="w3-button w3-bar-item topnav-icons fa fa-home" style="font-size:28px;color:#999999;margin-top:-2px"></a>
<button class="w3-button w3-bar-item w3-green w3-hover-white w3-hover-text-green" onclick="submitTryit(1)">Run »</button>
<span class="w3-right w3-hide-medium w3-hide-small" style="padding:8px 8px 8px 8px;display:block"></span>
<span class="w3-right w3-hide-small" style="padding:8px 0;display:block;float:right;"><span id="framesize">Result Size: <span>433 x 439</span></span></span>
</div>
I'm not familiar with cucumber, but does it have an option to use cssSelector?
I looked at the button and found
body .trytopnav button
as a valid selector.
This error message...
invalid Selector Exception
...implies that the how=How.LINK_TEXT,using="Run >>" was not a valid selector.
The main issue is the element is not a LINK_TEXT but a <button> tag with text as Run ».
Solution
Change the Locator Strategy as follows:
#FindBy(how=How.XPATH,using="//button[contains(.,'Run »')]")
//or
#FindBy(how=How.XPATH,using="//button[contains(.,'Run')]")
private WebElement RunButton;
look here https://www.seleniumhq.org/exceptions/invalid_selector_exception.jsp we need to avoid using >> as possible, so try to use another locator by avoiding these
I am trying to upload file using sendkeys()
but selenium webdriver test fails with error:
"The element is not yet visible: By.xpath: //input[#id='upload-file-pc']"
Here is the html:
<input id="upload-file-pc" class="file-field-input" type="file" onchange="return validateFileSelected(this);" name="upload-file-pc"/>
<a class="dropbox-dropin-btn dropbox-dropin-default file-field-link" href="Javascript:void(0);">
<span class="dropin-btn-status"/>
Choose from Computer
</a>
Code:
String fileLocation = CommonConstants.TEST_FILE_LOCATION + this.config.getString("simpletext");
logger.info("text file location: {}", fileLocation);
WebExecutionHelper.waitForElementVisible(driver, By.xpath("//input[#type='file']")).sendKeys(fileLocation);
Upload Button Image:
Please help
Selenium probably doesn't operate on hidden elements. What you can do is force it to appear with executeScript:
// get <input> element
input = driver.findElementById("upload-file-pc")
// make it visible
driver.executeScript(`
var input = arguments[0];
input.className = '';
input.style.display = 'block';
input.style.position = 'fixed';
input.style.bottom = 0;
input.style.left = 0;
`, input)
// set the file
input.sendKeys(fileLocation)
Selenium can't operate (e.g sendKeys, click) on invisible element.
You can send the uploaded file's absolute path in backgroud by executeScript.
Java example:
WebElement fileUpload = driver.findElement(By.css("#upload-file-pc"));
JavascriptExecutor js = (JavascriptExecutor) driver;
js.executeScript("return arguments[0].value=arguments[1];", fileUpload);
This is my sample html code.
<div class="content">
<M class="mclass">
<section id="sideA">
<div id="mainContent">
<div class="requestClass">
<span>Check</span>
<input type="text" id="box">
</div>
</div>
<section>
<section id="sideB">
...
<section>
</M>
</div>
I want to set some value to my text field ("box"). So I tired to set like below code
driver.findElement(By.xpath("...")).sendKeys("SetValue");
My Xpath id is correct, it's exist in the page but am getting this error
no such element: Unable to locate element: {"method":"xpath","selector":"id("..."}
Why I am getting this error because of my custom tag,if yes how to get element inside custom tag?
As per the HTML you have provided to fill in some value to the text field represented by <input type="text" id="box"> you can use either of the following line of code:
cssSelector :
driver.findElement(By.cssSelector("section#sideA input#box")).sendKeys("SetValue");
xpath :
driver.findElement(By.xpath("//section[#id='sideA']//input[#id='box']")).sendKeys("SetValue");
If you still want to use XPath. This worked for me-
driver.FindElement(By.XPath(#"//*[#id='box']")).SendKeys("AB");
I don't think the custom tag causes any problem as the CssSelector also works-
driver.FindElement(By.CssSelector(#"m[class='mclass'] input")).SendKeys("AB");
You can use ID or xpath to locate it, My suggestion you have to use ID. Also use Explicit wait till element to be visible.
Using ID, your code is like this:
WebElement elem= driver.findElement(By.id("box"));
WebDriverWait wait=new WebDriverWait(driver, 10);
wait.until(ExpectedConditions.visibilityOf(elem));
elem.sendKeys("test");
You can also use JavascriptExecutor
WebElement elem= driver.findElement(By.id("box"));
WebDriverWait wait=new WebDriverWait(driver, 10);
wait.until(ExpectedConditions.visibilityOf(elem));
JavascriptExecutor myExecutor = ((JavascriptExecutor) driver);
myExecutor.executeScript("arguments[0].value='test';", elem);
ID and Xpath is changing for "OK" button every time while saving(Account).
HTML Code:
<div class="modal-footer" style="display: block;">
<div class="bootstrap-dialog-footer">
<div class="bootstrap-dialog-footer-buttons">
<button id="fe02d6bd-6058-4871-b0e1-c1e914f64a6a" class="btn btn- default">Ok</button>
</div>
</div>
</div>
</div>
Xpath:.//*[#id='fe02d6bd-6058-4871-b0e1-c1e914f64a6a']
"ID"/XPath is not constant and it is varying while saving.
use the below code:
driver.findElement(By.cssSelector("div.bootstrap-dialog-footer-buttons>button.btn.btn-default"));
You can devise your own XPath locator to find the OK button by it's text content like so:
//button[.='Ok']
The first part of the XPath expression - //button - will select all <button> WebElements within the currently focused content.
The second part - [.='Ok'] - is a predicate that will filter out any WebElements whose exact text content is not equal to 'Ok'.
If it is the only OK button available on the page then you can probably use below code.
driver.findElement(By.xpath("//button[contains(.,'Ok')]"));
Else you can take a reference of parent window and locate a button on it as below
WebElement modalWin = driver.findElement(By.id("modal-window-id"));
modalWin.findElement(By.xpath("//button[contains(.,'Ok')]"));
This below code helps to click OK button in any page.
just call this method with parameter saying OK
public void buttonClick(String buttonname){
WebElemennt button = driver.findelement(by.xpath("//button[text(),'Ok']"))
or
WebElemennt button = driver.findelement(by.cssselector(".btn btn- default"))
for(int i=0; i<button.size;i++)
{
if(button.get(i).gettext().equalIgnorecase(buttonname))
{
button.get(i).click
}
}
}
Let me know result..
I am constantly getting "No Such Element Exception" for "First Name" test box
Below is my code:
public class southwestSignUpSave {
WebDriver oBrw;
#Before
public void loadwebsite (){
oBrw = new FirefoxDriver();
oBrw.manage().window().maximize();
oBrw.get("https://southwest.com");
oBrw.manage().timeouts().implicitlyWait(30, TimeUnit.SECONDS);
}
#Test
public void signUpAndSave(){
oBrw.findElement(By.partialLinkText("OFFERS")).click();
oBrw.findElement(By.partialLinkText("Sign")).click();
//oBrw.manage().timeouts().implicitlyWait(30, TimeUnit.SECONDS);
WebDriverWait oWait = new WebDriverWait(oBrw, 30);
oWait.until(ExpectedConditions.presenceOfElementLocated(By.id("FIRST_NAME")));
oBrw.findElement(By.id("FIRST_NAME")).clear();
oBrw.findElement(By.id("FIRST_NAME")).sendKeys("abc");
oBrw.findElement(By.id("LAST_NAME")).clear();
oBrw.findElement(By.id("LAST_NAME")).sendKeys("asd");
oBrw.findElement(By.id("EMAIL")).clear();
oBrw.findElement(By.id("EMAIL")).sendKeys("abc#asd.com");
new Select(oBrw.findElement(By.id("HOME_AIRPORT"))).selectByVisibleText("Akron/Canton, OH - CAK");
oBrw.findElement(By.id("IAN")).click();
}
}
I tried to use id and name.
where am I going wrong. I am new to Selenium WD
U can try finding the element using xpath. For that u need to install the firepath plugin in firefox and then inspect the element using firepath.
oBrw.findElement(By.xpath("copy paste the xpath here")).clear();
I would also recommend loading the driver using System property inside loadwebsite() method.
System.setProperty("webdriver.firefox.driver", "//your driver path");
oBrw=new FirefoxDriver();
if the Sign page opens in a new tab/window then u need to navigate to that tab/window because Selenium by default stays in the opening tab. To navigate u need to add the following lines of code after clicking on "Sign"-
Set<String> s=wd.getWindowHandles();
Iterator<String> it=s.iterator();
it.next();//control goes to 1st default tab
String str=it.next().toString();//control goes to the next tab
oBrw.switchTo().window(str);//driver switches to the new window/tab.
if the element is present inside a frame then also u need to switch to that frame first before finding element inside it. Below is the code-
WebElement web=oBrw.findElement(By.xpath("copy paste your frame xpath"));
oBrw.switchTo.frame(web);
now try to find the element present in the new tab/window.
FIRST NAME input text field is inside iframe. Check the below piece of HTML.
<iframe frameborder="0" src="https://luv.southwest.com/servlet/formlink/f?kOHpjQACAY" onload="scroll(0,0);" verticalscrolling="no" horizontalscrolling="no" scrolling="no" title="Click 'n Save signup form"></iframe>
<html dir="ltr">
<head>
<body>
<p>
<span class="required">*Required</span>
</p>
<div class="clear"></div>
<form id="cnsForm" onsubmit="return validateForm();" action="https://luv.southwest.com/servlet/campaignrespondent" method="POST">
<div class="form_field first_name">
<label for="first_name">
<input id="FIRST_NAME" type="text"=""="" maxlength="25" size="22" name="FIRST_NAME">
</div>
...
Hence selenium is unable to find out the element. Here we need to explicitly switch to iframe as below. Insert below code snippet before you find FIRST_NAME. (You can insert well formatted xpath of iframe. I just grabbed it from firebug.)
WebElement iframeSwitch = oBrw.findElement(By.xpath("/html/body/div[1]/div[3]/div[2]/div[1]/div/div/div[4]/div/div/div/div[3]/iframe"));
oBrw.switchTo().frame(iframeSwitch);
That Text box is inside an iFrame, so you need to switch to that iFrame first then try findElement method to locate textbox.
oBrw.findElement(By.partialLinkText("OFFERS")).click();
oBrw.findElement(By.partialLinkText("Sign")).click();
oBrw.switchTo().defaultContent();
oBrw.switchTo().frame(0);
WebElement id = oBrw.findElement(By.name("FIRST_NAME"));
id.sendKeys("USERNAME");
Hope this helps.