how to transpose rows to columns for the grouped data? - sql

Question

While doing the employees and supervisors analysis, I got in trouble with the BigQuery statements.
SELECT SupervisorName, Emp_Status, COUNT(DISTINCT EmpNO)AS NUMBER
FROM
(SELECT
EmpNO,
EmpName,
(CASE WHEN TerminationDate IS NULL THEN 'Active'
ELSE 'Terminated'
END
)AS Emp_Status,
DateOfBirth,
DATE_DIFF(CURRENT_DATE(),DateOfBirth,YEAR) AS Age,
SupervisorName
FROM `Table1`
)
GROUP BY SupervisorName, Emp_Status
ORDER BY SupervisorName, NUMBER DESC
The result is shown below:
Row SupervisorName Emp_Status NUMBER
1 null Terminated 321
2 null Active 2
3 Ahearn Active 3
4 Ahearn Terminated 2
5 Allen Active 6
6 Allen Terminated 3
......
How can I change it to like this:
Row SupervisorName Active Termination Total
1 Null 2 321 323
2 Ahearn 3 2 5
3 Allen 6 3 9
......

Answer 1

The standard pattern here is to use SUM and CASE to get the result -- as below:
SELECT
SupervisorName,
SUM(CASE WHEN Emp_Status = 'Active' THEN 1 ELSE 0 END) AS Active,
SUM(CASE WHEN Emp_Status = 'Terminated' THEN 1 ELSE 0 END) AS Termination,
COUNT(*) AS Total
FROM (
SELECT
EmpNO,
EmpName,
CASE WHEN TerminationDate IS NULL THEN 'Active' ELSE 'Terminated' END AS Emp_Status,
DateOfBirth,
DATE_DIFF(CURRENT_DATE(),DateOfBirth,YEAR) AS Age,
SupervisorName
FROM `Table1`
)
GROUP BY SupervisorName
Note, I left the same sub-query you had, but as given you don't actually need a sub-query, you can just change the CASE statement to look at termination date instead of the string you created in the sub-query.
I assume your actual code is more complicated so I left it like this.

Answer 2

maybe that's what you want
select
SupervisorName,
count(distinct if(TerminationDate is null, EmpNO, null)) as active,
count(distinct if(TerminationDate is null, null, EmpNO)) as terminated,
count(distinct EmpNO) as dist_total,
count(*) as total
from
`Table1`
where
-- you should use keyword "date" and iso8601 format
LastHireDate between date'2018-01-01'
and current_date()
group by
1
order by
1, 4 desc