To select max date and time [closed] - sql

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I have data with column createdate like '24/04/2019 14:52:38',24/04/2019 14:52:37,24/04/2019 14:52:35,24/03/2019 14:52:38 etc.
how to get data based on max date and time in SQL query.

select
top(1) *
from
xx
order by
createdate desc

something like this? (works if createdate column is of date/datetime/timestamp type)
select
*
from
<table_name>
where
createdate = (select
max(createdate)
from
<table_name>)

Related

SQL command to find the repetitive day? [closed]

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on which day most people login?
Use DAYNAME() like that.
SELECT DAYNAME([column_with_date])
FROM [table]
GROUP BY DAYNAME([column_with_date])
order by count(DAYNAME([column_with_date])) desc limit 1;
You can use below code to find max frequency
select date,max(freq)
from (SELECT date,count(date) as freq from TableName
group by date);
this will give the Date and max frequency of that date in column.
or you can use below code
SELECT date,count(date) as freq from TableName
group by date
limit 1;
here i'm assuming date as column name.

Write Oracle SQL queries [closed]

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how to rank each country based on number of people in SQL.
Try
SELECT * FROM (
SELECT country, count(people) as count FROM your_table GROUP BY country
) ORDER BY count DESC

How can we display the last 7 Records from table in Oracle 11G SQL only? [closed]

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How can I write this query without TOP and Limit only use the SQL
You just sort the data one way, grab the records you want, then sort it the other way:
SELECT SOME_FIELD
FROM (SELECT st.*
FROM SOME_TABLE st
ORDER BY SOME_FIELD DESC)
WHERE ROWNUM <= 7
ORDER BY SOME_FIELD ASC
dbfiddle here

sql in ms-access [closed]

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I have a table name customers with two columns, case id and owner. I need to write a query to select random 5 caseids for every name in owner column.please help
For a start, you need something like:
SELECT TOP 5
ID,
[Case ID],
[Owner],
Rnd(-Timer()*[ID]) AS RandomRecord
FROM
[Cases]
ORDER BY
Rnd(-Timer()*[ID]);
to be used as a subquery filtered on OwnerID of your Owners' table.
I once posted an article on this with a lot more details:
Random Rows in Microsoft Access
You can use in:
select t.*
from t
where t.id in (select top 5 id
from t as t2
where t2.name = t.name
order by Rnd(-Timer()*[ID])
);

SQL query on table [closed]

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I have a table like the following
sl.no Machine Id date status
I need to get the last status for each machine ID for each day.(Everyday each machine ID will have many entries .I need to get the last entry for that day for each machine ID)
Please help
Hope this will solve your issue
Select MachineID, Date,
(Select Top 1 t1.Status
FROM table As t1
WHERE t1.MachineID = table.MachineID
AND t1.Date = table.Date
order by slno desc)
FROM table
Group BY MachineID, Date