SQL query on table [closed] - sql

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I have a table like the following
sl.no Machine Id date status
I need to get the last status for each machine ID for each day.(Everyday each machine ID will have many entries .I need to get the last entry for that day for each machine ID)
Please help

Hope this will solve your issue
Select MachineID, Date,
(Select Top 1 t1.Status
FROM table As t1
WHERE t1.MachineID = table.MachineID
AND t1.Date = table.Date
order by slno desc)
FROM table
Group BY MachineID, Date

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Tracking Employee Changes - SQL query [closed]

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I have this table of employees that gets updated at the end of each month. I know how to detect changes (2 rows; one of old and one of new) but I need to summarize the changes as showing in the second table using sql query.
With JobHistory AS(
Select
*,
LEAD([DepartmentName]) over (Partition by [EmployeeNumber] order by [ASofDate]) as NewDepartmentName,
LAG([DepartmentName]) over (Partition by [EmployeeNumber] order by [ASofDate]) as OldDepartmentName
FROM [EmployeeDirectory]
)
Select *
FROM JobHistory
WHERE (
(NewDepartmentName <> [DepartmentName])
OR
( OldDepartmentName <> [DepartmentName])
)
ORDER by AsOfDate, EmployeeNumber
[Table]
Required Results

How can we display the last 7 Records from table in Oracle 11G SQL only? [closed]

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How can I write this query without TOP and Limit only use the SQL
You just sort the data one way, grab the records you want, then sort it the other way:
SELECT SOME_FIELD
FROM (SELECT st.*
FROM SOME_TABLE st
ORDER BY SOME_FIELD DESC)
WHERE ROWNUM <= 7
ORDER BY SOME_FIELD ASC
dbfiddle here

To select max date and time [closed]

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I have data with column createdate like '24/04/2019 14:52:38',24/04/2019 14:52:37,24/04/2019 14:52:35,24/03/2019 14:52:38 etc.
how to get data based on max date and time in SQL query.
select
top(1) *
from
xx
order by
createdate desc
something like this? (works if createdate column is of date/datetime/timestamp type)
select
*
from
<table_name>
where
createdate = (select
max(createdate)
from
<table_name>)

sql in ms-access [closed]

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I have a table name customers with two columns, case id and owner. I need to write a query to select random 5 caseids for every name in owner column.please help
For a start, you need something like:
SELECT TOP 5
ID,
[Case ID],
[Owner],
Rnd(-Timer()*[ID]) AS RandomRecord
FROM
[Cases]
ORDER BY
Rnd(-Timer()*[ID]);
to be used as a subquery filtered on OwnerID of your Owners' table.
I once posted an article on this with a lot more details:
Random Rows in Microsoft Access
You can use in:
select t.*
from t
where t.id in (select top 5 id
from t as t2
where t2.name = t.name
order by Rnd(-Timer()*[ID])
);

How to find group which is having Status Active? [closed]

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I have a id which is having more than one Accountid in a table with status Active . I need to find group of active for the particular ID .
Please find my below query .is it correct or something need to modify to get better optimized result .
select id,count(Accountid) from CustomerAccount
where status='Active'
group by id
having count(*)>( select min(maxxount) from(
select id,count(accountid) as maxxount
from CustomerAccount
group by id)A)
Use this query:
select id,count(Accountid) from CustomerAccount
where status='Active'
group by id
having count(*) >1