I have a query built below on the total amount of requests created in a year grouped by the task name (c.status_text) and the year they were worked(a.finish_date). In the SR_WORKFLOW table in my query below, there is a field called 'assigned_to' which is the employee number of the user that finished a ticket. I need to find the average number of requests our employees complete in a year/month, etc grouped by the task name (c.status_text). If I can figure out how to write this query for a year, I should be able to do the rest of them. So essentially what I am doing is trying to count the number of employees that have worked a specific task and then get the average number of tasks a person worked. Sorry if that sounds confusing. If so I will try to explain better.
I am able to get the totals of each employee id but that is over 5000 lines of results and does not give me an average.
select count(*) as [Total SRs],
c.status_text,
DATEPART(YEAR, a.finish_date) as [Year]
from SR_WORKFLOW a
inner join SR_SERVICE_REQUEST b on a.sr_id = b.sr_id
inner join WORKFLOW c on a.WORKFLOW_GUID = c.WORKFLOW_GUID
where b.type = 'Fed Wire'
and a.finish_date >= '2018-01-01'
and a.assigned_to is not null
group by rollup(c.STATUS_TEXT, DATEPART(YEAR, a.finish_date))
order by c.status_text
Related
Goal: SUM/AVG Client Data over multiple dates/transactions.
Detailed Question: How do I properly Group clients ('PlayerID') then SUM the int(MinsPlayed), then AVG (AvgBet)?
Current Issue: my Results are giving individual transactions day by day over the 90 day time period instead of the SUM/AVG over the 90 days.
Current Script/Results: FirstName-Riley is showing each individual daily transaction instead of 1 total SUM/AVG over set time period
Firstly, you don't need to use DISTINCT as you are going to be aggregating the results using GROUP BY, so you can take that out.
The reason you are returning a row for each transaction is that your GROUP BY clause includes the column you are trying to aggregate (e.g. TimePlayed). Typically, you only want to GROUP BY the columns that are not being aggregated, so remove all the columns from the GROUP BY clause that you are aggregating using SUM or AVG (TimePlayed, PlayerSkill etc.).
Here's your current SQL:
SELECT DISTINCT CDS_StatDetail.PlayerID,
StatType,
FirstName,
LastName,
Email,
SUM(TimePlayed)/60 AS MinsPlayed,
SUM(CashIn) AS AvgBet,
SUM(PlayerSkill) AS AvgSkillRating,
SUM(PlayerSpeed) AS Speed,
CustomFlag1
FROM CDS_Player INNER JOIN CDS_StatDetail
ON CDS_Player.Player_ID = CDS_StatDetail.PlayerID
WHERE StatType='PIT' AND CDS_StatDetail.GamingDate >= '1/02/17' and CDS_StatDetail.GamingDate <= '4/02/2017' AND CustomFlag1='N'
GROUP BY CDS_StatDetail.PlayerID, StatType, FirstName, LastName, Email, TimePlayed, CashIn, PlayerSkill, PlayerSpeed, CustomFlag1
ORDER BY CDS_StatDetail.PlayerID
You want something like:
SELECT CDS_StatDetail.PlayerID,
SUM(TimePlayed)/60 AS MinsPlayed,
AVG(CashIn) AS AvgBet,
AVG(PlayerSkill) AS AvgSkillRating,
SUM(PlayerSpeed) AS Speed,
FROM CDS_Player INNER JOIN CDS_StatDetail
ON CDS_Player.Player_ID = CDS_StatDetail.PlayerID
WHERE StatType='PIT' AND CDS_StatDetail.GamingDate BETWEEN '2017-01-02' AND '2017-04-02' AND CustomFlag1='N'
GROUP BY CDS_StatDetail.PlayerID
Next time, please copy and paste your text, not just linking to a screenshot.
I have a table that contains data about a series of visits to shops.
The raw data for these visits can be found here.
My main table will have 1 row per Country, and will use something along the lines of:
Select Distinct o.Country from OtherTable as o
I need to add a new column to my main table, that uses the following calculation:
"Avg Visits by User" = (Sum of (No. Call IDs / No. unique User IDs)
for each day) / No. unique of days (based on Actual Start) for the
row.
I have formed this additional select statement to get the number of calls and users by day - but I am struggling to join this to my main table:
Select DATEPART(DAY, c.ActualStart) As 'Day',
CAST(CAST(COUNT(c.CallID) AS DECIMAL (5,1))/CAST(COUNT(Distinct c.UserID) AS DECIMAL (5,1)) AS DECIMAL (5,1)) as 'Value' from CallInfo as c
where (c.Status = 3))
Group by DATEPART(DAY, c.ActualStart)
For the country GB, I would expect to come to the see the following output:
Day Calls Users Calls / Users
13-Jun 29 8 3.625
14-Jun 31 7 4.428571429
So, in my main table, the calculation for my new column would be:
8.053571 / 2
Therefore, if I somehow add this to my table I would expect the following output:
Country Unique Days Sum of Calls/Users for each day) Final Calc
GB 2 8.053571429 4.026785714
I have tried adding this as a join, but I don't know how to join this to my main table. I could for example join on Call Id - but this would require the addition of a callID column in my inner query, and this would mean that the values are incorrect.
You can use a subquery to make calculations by day and after that make calculations by country. The result SQL query can be like this:
-- Make calculation by country, from the subquery
SELECT Country, UniqueDays = count(TheDay), CallsUserPerDay = sum(CallsPerUser),
FinalCalc = sum(CallsPerUser) / cast(count(TheDay) as DECIMAL)
FROM (
-- SUBQUERY: Make calculations by day
SELECT c.Country, c.ActualStart as TheDay,
Calls = COUNT(c.CallID),
Users = COUNT(Distinct c.UserID),
COUNT(c.CallID)
/CAST(COUNT(Distinct c.UserID) AS DECIMAL) as CallsPerUser
FROM CallInfo as c
WHERE (c.Status = 3)
GROUP BY c.Country, c.ActualStart
) data
GROUP BY Country
Note: I avoid use precission on DECIMAL casting to avoid rounding on final result.
I have a database project at my school and I am almost finished. The only thing that I need is average movies per day. I have a watchhistory where you can find the users who have watch a movie. The instrucition is that you filter the people out of the watchhistory who have an average of 2 movies per day.
I wrote the following SQL statement. But every time I get errors. Can someone help me?
SQL:
SELECT
customer_mail_address,
COUNT(movie_id) AS AantalBekeken,
COUNT(movie_id) / SUM(GETDATE() -
(SELECT subscription_start FROM Customer)) AS AveragePerDay
FROM
Watchhistory
GROUP BY
customer_mail_address
The error:
Msg 130, Level 15, State 1, Line 1
Cannot perform an aggregate function on an expression containing an aggregate or a subquery.
I tried something different and this query sums the total movie's per day. Now I need the average of everything and that SQL only shows the cusotmers who are have more than 2 movies per day average.
SELECT
Count(movie_id) as AantalPerDag,
Customer_mail_address,
Cast(watchhistory.watch_date as Date) as Date
FROM
Watchhistory
GROUP BY
customer_mail_address, Cast(watch_date as Date)
The big problem that I see is that you're trying to use a subquery as if it's a single value. A subquery could potentially return many values, and unless you have only one customer in your system it will do exactly that. You should be JOINing to the Customer table instead. Hopefully the JOIN only returns one customer per row in WatchHistory. If that's not the case then you'll have more work to do there.
SELECT
customer_mail_address,
COUNT(movie_id) AS AantalBekeken,
CAST(COUNT(movie_id) AS DECIMAL(10, 4)) / DATEDIFF(dy, C.subscription_start, GETDATE()) AS AveragePerDay
FROM
WatchHistory WH
INNER JOIN Customer C ON C.customer_id = WH.customer_id -- I'm guessing at the join criteria here since no table structures were provided
GROUP BY
C.customer_mail_address,
C.subscription_start
HAVING
COUNT(movie_id) / DATEDIFF(dy, C.subscription_start, GETDATE()) <> 2
I'm guessing that the criteria isn't exactly 2 movies per day, but either less than 2 or more than 2. You'll need to adjust based on that. Also, you'll need to adjust the precision for the average based on what you want.
What the error message is telling you is that you can't use SUM together with COUNT.
try putting SUM(GETDATE()-(SELECT subscription_start FROM Customer)) as your second aggregate variable, and
try using HAVING & FILTER at the end of your query to select only the users that have count/sum = 2
maybe this is what you need?
lets join the two tables Watchhistory and Customers
select customer_mail_address,
COUNT(movie_id) AS AantalBekeken,
COUNT(movie_id) / datediff(Day, GETDATE(),Customer.subscription_start) AS AveragePerDay
from Watchhistory inner join Customer
on Watchhistory.customer_mail_address = Customer.customer_mail_address
GROUP BY
customer_mail_address
having AveragePerDay = 2
change the last line of code according to what you need (I did not understand if you want it in or out)
I got it guys. Finally :)
SELECT customer_mail_address, SUM(AveragePerDay) / COUNT(customer_mail_address) AS gemiddelde
FROM (SELECT DISTINCT customer_mail_address, COUNT(CAST(watch_date AS date)) AS AveragePerDay
FROM dbo.Watchhistory
GROUP BY customer_mail_address, CAST(watch_date AS date)) AS d
GROUP BY customer_mail_address
HAVING (SUM(AveragePerDay) / COUNT(customer_mail_address) >= 2
I am working on my Database in MS Access 2010
and i Need to build a query to Calculate the month salary for each Employee
it goes like this :
Input from user , which Year
Input from user again , which Month
Show Every Employee's Salary for the Input date
There are 2 Tables in the Query : Shifts , Employees
Shifts has a field for EmployeeID and a field for Day
Day field format is : Short Date
The problem is i don't know how to access the Month and the Year only !
I know that this is completely wrong , but i wanna do something like this:
SELECT
FROM EmployeesTBL INNER JOIN ShiftsTBL ON EmployeesTBL.EmployeeID = ShiftsTBL.EmployeeID
WHERE
Year(ShiftsTBL.Day)=[Enter Year]
AND
Month(ShiftsTBL.Day)=[Enter Month]
;
What do i need to write after SELECT to get the Sum of all Shifts and divide it by number of days the emp worked
Note : in the Shifts Table , i have EntryDate and ExitDate for every shift
Access has a bunch of built in date functions. I believe Month(date) and Year(date) will give you what you need.
Something like
SELECT EmpName
FROM Employees, Shifts
WHERE Employees.EmployeeID = Shifts.EmployeeID
AND
Month(Shifts.Day) = INPUT2.VALUE
AND
Year(Shifts.Day) = INPUT1.VALUE
should get you what you want!
EDIT: Aggregation: how this works will depend on how your database is set up. I think I understand you want to sum the hours worked and divide by the number of days?
If so, you will use Sum() and Count(). And you will Group By EmployeeID
SELECT Sum(Shifts)/Count(DaysWorked) AS SumDividedByCount
FROM EmployeesTBL INNER JOIN ShiftsTBL
ON EmployeesTBL.EmployeeID = ShiftsTBL.EmployeeID
WHERE
Year(ShiftsTBL.[Day])=[Enter Year]
AND
Month(ShiftsTBL.[Day])=[Enter Month]
GROUP BY EmployeeID
I used the WHERE clause because I think the results need to be filtered before they're grouped. If the results needed to be filtered after they were grouped, the HAVING clause would be used (and would go AFTER the GROUP BY)
with the below query i can able to get the approved transaction for per client on per day basis.
select
q1.client_id,
q1.receive_day,
count(q1.client_id) as cnt
from
(select * from sale where response=00) q1
group by
q1.client_id, q1.receive_day
I want to get the approval %, i.e. the approval_per, is 100*(count(client_id)/response), while count(client_id) is the number of clients for the approved transaction.
Response is a count of whole response including all the values (approved and not approved) . I can get the response by select count(response) from sale , but how to make it here for calculating % in the same query is the problem am facing now. I tried out some options as it didn't work , reached user group.
so my expected output format is client_id,receive_day,count(client_id),approval_per.
Any of your help are really appreciated
Thanks & Regards,
dti
You could simply add another subquery which calculates that count. Also for the query you have now it seems unnecessary to have that subquery (q1).
I also make the assumption that you want your percentage should be the percentage of transactions each client is responsible for. I.e. number of transactions for given client divided by number of total transactions.
SELECT
s.client_id,
s.receive_day,
count(s.client_id) as cnt,
100 * (count(s.client_id) / q1.total)
FROM
sale s,
(select count(*) total from sale) q1
WHERE
response = 00
GROUP BY
s.client_id, s.receive_day