calculating month salary for an employee - sql

Question

I am working on my Database in MS Access 2010
and i Need to build a query to Calculate the month salary for each Employee
it goes like this :
Input from user , which Year
Input from user again , which Month
Show Every Employee's Salary for the Input date
There are 2 Tables in the Query : Shifts , Employees
Shifts has a field for EmployeeID and a field for Day
Day field format is : Short Date
The problem is i don't know how to access the Month and the Year only !
I know that this is completely wrong , but i wanna do something like this:
SELECT
FROM EmployeesTBL INNER JOIN ShiftsTBL ON EmployeesTBL.EmployeeID = ShiftsTBL.EmployeeID
WHERE
Year(ShiftsTBL.Day)=[Enter Year]
AND
Month(ShiftsTBL.Day)=[Enter Month]
;
What do i need to write after SELECT to get the Sum of all Shifts and divide it by number of days the emp worked
Note : in the Shifts Table , i have EntryDate and ExitDate for every shift

Answer 1

Access has a bunch of built in date functions. I believe Month(date) and Year(date) will give you what you need.
Something like
SELECT EmpName
FROM Employees, Shifts
WHERE Employees.EmployeeID = Shifts.EmployeeID
AND
Month(Shifts.Day) = INPUT2.VALUE
AND
Year(Shifts.Day) = INPUT1.VALUE
should get you what you want!
EDIT: Aggregation: how this works will depend on how your database is set up. I think I understand you want to sum the hours worked and divide by the number of days?
If so, you will use Sum() and Count(). And you will Group By EmployeeID
SELECT Sum(Shifts)/Count(DaysWorked) AS SumDividedByCount
FROM EmployeesTBL INNER JOIN ShiftsTBL
ON EmployeesTBL.EmployeeID = ShiftsTBL.EmployeeID
WHERE
Year(ShiftsTBL.[Day])=[Enter Year]
AND
Month(ShiftsTBL.[Day])=[Enter Month]
GROUP BY EmployeeID
I used the WHERE clause because I think the results need to be filtered before they're grouped. If the results needed to be filtered after they were grouped, the HAVING clause would be used (and would go AFTER the GROUP BY)