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I have a string such as this:
`a|b^c|d|e^f|g`
and I want to maintain the pipe delimiting, but remove the carrot sub-delimiting, only retaining the first value of that sub-delimiter.
The output result would be:
`a|b|d|e|g`
Is there a way I can do this with a simple SQL function?
Another option, using CHARINDEX, REPLACE and SUBSTRING:
DECLARE #OriginalString varchar(50) = 'a|b^c^d^e|f|g'
DECLARE #MyString varchar(50) = #OriginalString
WHILE CHARINDEX('^', #MyString) > 0
BEGIN
SELECT #MyString = REPLACE(#MyString,
SUBSTRING(#MyString,
CHARINDEX('^', #MyString),
CASE WHEN CHARINDEX('|', #MyString, CHARINDEX('^', #MyString)) > 0 THEN
CHARINDEX('|', #MyString, CHARINDEX('^', #MyString)) - CHARINDEX('^', #MyString)
ELSE
LEN(#MyString)
END
)
, '')
END
SELECT #OriginalString As Original, #MyString As Final
Output:
Original Final
a|b^c^d^e|f|g a|b|f|g
This expression will replace the first instance of caret up to the subsequent pipe (or end of string.) You can just run a loop until no more rows are updated or no more carets are found inside the function, etc.
case
when charindex('^', s) > 0
then stuff(
s,
charindex('^', s),
charindex('|', s + '|', charindex('^', s) + 1) - charindex('^', s),
''
)
else s
end
Here's a loop you can adapt for a function definition:
declare #s varchar(30) = 'a|b^c^d|e|f^g|h^i';
declare #n int = charindex('^', #s);
while #n > 0
begin
set #s = stuff(#s, #n, charindex('|', #s + '|', #n + 1) - #n, '');
set #n = charindex('^', #s, #n + 1);
end
select #s;
A little bit of care needs to be taken for the trailing of the string where there won't be a final pipe separator. You can see I've handled that.
First split the values delimited by | then extract the first value and concatenate the result back to get the result
Try this
SELECT Cast(left(intr,len(intr)-1) AS VARCHAR(1000)) AS res
FROM (SELECT LEFT(split_val, Isnull(NULLIF(Charindex('^', split_val), 0)-1, Len(split_val))) + '|'
FROM Udf_splitstring('a|bdd^c|d|e^f|g', '|')
FOR xml path (''))a (intr)
Result : a|bdd|d|e|g
Here is a article about split string functions Split strings the right way – or the next best way
I've below query:
DECLARE #url varchar (max)='http://v.mercola.com/blogs/public_blog/New-Diet-Pill-Expands-1-000-Times-in-Your-Stomach-24728.aspx'
SELECT replace(replace(RIGHT(#URL , CHARINDEX ('/' ,REVERSE(#URL))-1),'.aspx',''),'-',' ') as abc
Which returns below output:
Actual output -
Expected output
i.e i want to eliminate the string after last occurrence of -.
What changes do i have to make to get the expected output..
In all i want a substring after last occurence of / and before last occurence of - as shown above.
Please help and thanks in advance...!
Try this
DECLARE #url VARCHAR (max)='http://v.mercola.com/blogs/public_blog/New-Diet-Pill-Expands-1-000-Times-in-Your-Stomach-24728.aspx'
SELECT Reverse(LEFT(mid, Charindex('/', mid) - 1))
FROM (SELECT Substring(Reverse(#url), Charindex('-', Reverse(#url)) + 1, Len(#url)) AS mid) a
Something like this:
DECLARE #url varchar (max)='http://v.mercola.com/blogs/public_blog/New-Diet-Pill-Expands-1-000-Times-in-Your-Stomach-24728.aspx'
declare #suffix varchar(max)
select #suffix = RIGHT(#URL , CHARINDEX ('/' ,REVERSE(#URL))-1)
select left(#suffix, len(#suffix) - charindex('-', reverse(#suffix)))
Output:
New-Diet-Pill-Expands-1-000-Times-in-Your-Stomach
Another option:
DECLARE #url varchar (max)='http://v.mercola.com/blogs/public_blog/New-Diet-Pill-Expands-1-000-Times-in-Your-Stomach-24728.aspx'
DECLARE #LastSlash int = LEN(#URL) - CHARINDEX('/', REVERSE(#URL)) + 2,
#LastMinus int = LEN(#URL) - CHARINDEX ('-', REVERSE(#URL)) + 1
SELECT SUBSTRING(#URL, #LastSlash, #LastMinus-#LastSlash)
I got the following entry in my database:
images/test.jpg
I want to trim the entry so I get: test
So basically, I want everything after / and before .
How can I solve it?
use the following function
left(#test, charindex('/', #test) - 1)
If you want to get this out of your table using SQL, take a look at the following functions that will help you: SUBSTRING and CHARINDEX. You can use those to trim your entries.
A possible query will look like this (where col is the name of the column that contains your image directories:
SELECT SUBSTRING(col, LEN(SUBSTRING(col, 0, LEN(col) - CHARINDEX ('/', col))) + 1,
LEN(col) - LEN(SUBSTRING(col, 0, LEN(col) - CHARINDEX ('/', col))) - LEN(SUBSTRING(
col, CHARINDEX ('.', col), LEN(col))));
Bit of an ugly beast. It also depends on the standard format of 'dir/name.ext'.
Edit:
This one (inspired by praveen) is more generic and deals with extensions of different length:
SELECT SUBSTRING(col, LEN(LEFT(col, CHARINDEX ('/', col))) + 1, LEN(col) - LEN(LEFT(col,
CHARINDEX ('/', col))) - LEN(RIGHT(col, LEN(col) - CHARINDEX ('.', col))) - 1);
Before
SELECT SUBSTRING(ParentBGBU,0,CHARINDEX('/',ParentBGBU,0)) FROM dbo.tblHCMMaster;
After
SELECT SUBSTRING(ParentBGBU,CHARINDEX('-',ParentBGBU)+1,LEN(ParentBGBU)) FROM dbo.tblHCMMaster
----select characters before / including /
select SUBSTRING ('abcde/wxyz',0,CHARINDEX('/','abcde/wxyz')+1)
--select characters after / including /
select SUBSTRING('abcde/wxyz',CHARINDEX('/','abcde/wxyz'),LEN('abcde/wxyz'))
declare #T table
(
Col varchar(20)
)
insert into #T
Select 'images/test1.jpg'
union all
Select 'images/test2.png'
union all
Select 'images/test3.jpg'
union all
Select 'images/test4.jpeg'
union all
Select 'images/test5.jpeg'
Select substring( LEFT(Col,charindex('.',Col)-1),charindex('/',Col)+1,len(LEFT(Col,charindex('.',Col)-1))-1 )
from #T
I have made a method which is much more general :
so :
DECLARE #a NVARCHAR(MAX)='images/test.jpg';
--Touch here
DECLARE #keysValueToSearch NVARCHAR(4000) = '/'
DECLARE #untilThisCharAppears NVARCHAR(4000) = '.'
DECLARE #keysValueToSearchPattern NVARCHAR(4000) = '%' + #keysValueToSearch + '%'
--Nothing to touch here
SELECT SUBSTRING(
#a,
PATINDEX(#keysValueToSearchPattern, #a) + LEN(#keysValueToSearch),
CHARINDEX(
#untilThisCharAppears,
#a,
PATINDEX(#keysValueToSearchPattern, #a) + LEN(#keysValueToSearch)
) -(PATINDEX(#keysValueToSearchPattern, #a) + LEN(#keysValueToSearch))
)
SELECT Substring('ravi1234#gmail.com', 1, ( Charindex('#', 'ravi1234#gmail.com')
- 1 ))
Before,
RIGHT('ravi123#gmail.com', ( Charindex('#', 'ravi123#gmail.com') + 1 ))
After
I just did this in one of my reports and it was very simple.
Try this:
=MID(Fields!.Value,8,4)
Note: This worked for me because the value I was trying to get was a constant not sure it what you are trying to get is a constant as well.
I know this has been a while.. but here is an idea
declare #test varchar(25) = 'images/test.jpg'
select
#test as column_name
, parsename(replace(#test,'/','.'),1) as jpg
,parsename(replace(#test,'/','.'),2) as test
,parsename(replace(#test,'/','.'),3) as images
I found Royi Namir's answer useful but expanded upon it to create it as a function. I renamed the variables to what made sense to me but you can translate them back easily enough, if desired.
Also, the code in Royi's answer already handled the case where the character being searched from does not exist (it starts from the beginning of the string), but I wanted to also handle cases where the character that is being searched to does not exist.
In that case it acts in a similar manner by starting from the searched from character and returning the rest of the characters to the end of the string.
CREATE FUNCTION [dbo].[getValueBetweenTwoStrings](#inputString
NVARCHAR(4000), #stringToSearchFrom NVARCHAR(4000), #stringToSearchTo
NVARCHAR(4000))
RETURNS NVARCHAR(4000)
AS
BEGIN
DECLARE #retVal NVARCHAR(4000)
DECLARE #stringToSearchFromSearchPattern NVARCHAR(4000) = '%' +
#stringToSearchFrom + '%'
SELECT #retVal = SUBSTRING (
#inputString,
PATINDEX(#stringToSearchFromSearchPattern, #inputString) + LEN(#stringToSearchFrom),
(CASE
CHARINDEX(
#stringToSearchTo,
#inputString,
PATINDEX(#stringToSearchFromSearchPattern, #inputString) + LEN(#stringToSearchFrom))
WHEN
0
THEN
LEN(#inputString) + 1
ELSE
CHARINDEX(
#stringToSearchTo,
#inputString,
PATINDEX(#stringToSearchFromSearchPattern, #inputString) + LEN(#stringToSearchFrom))
END) - (PATINDEX(#stringToSearchFromSearchPattern, #inputString) + LEN(#stringToSearchFrom))
)
RETURN #retVal
END
Usage:
SELECT dbo.getValueBetweenTwoStrings('images/test.jpg','/','.') AS MyResult
I got some invalid length errors. So i made this function, this should not give any length problems. Also when you do not find the searched text it will return a NULL.
CREATE FUNCTION [FN].[SearchTextGetBetweenStartAndStop](#string varchar(max),#SearchStringToStart varchar(max),#SearchStringToStop varchar(max))
RETURNS varchar(max)
BEGIN
SET #string = CASE
WHEN CHARINDEX(#SearchStringToStart,#string) = 0
OR CHARINDEX(#SearchStringToStop,RIGHT(#string,LEN(#string) - CHARINDEX(#SearchStringToStart,#string) + 1 - LEN(#SearchStringToStart))) = 0
THEN NULL
ELSE SUBSTRING(#string
,CHARINDEX(#SearchStringToStart,#string) + LEN(#SearchStringToStart) + 1
,(CHARINDEX(#SearchStringToStop,RIGHT(#string,LEN(#string) - CHARINDEX(#SearchStringToStart,#string) + 1 - LEN(#SearchStringToStart)))-2)
)
END
RETURN #string
END
if Input= pg102a-wlc01s.png.intel.com and Output should be pg102a-wlc01s
we can use below query :
select Substring(pc.name,0,charindex('.',pc.name,0)),pc.name from tbl_name pc
You can try this:
Declare #test varchar(100)='images/test.jpg'
Select REPLACE(RIGHT(#test,charindex('/',reverse(#test))-1),'.jpg','')
Below query gives you data before '-'
Ex- W12345A-4S
SELECT SUBSTRING(Column_Name,0, CHARINDEX('-',Column_Name)) as 'new_name'
from [abc].
Output - W12345A
Inspired by the work of Josien, I wondered about a simplification.
Would this also work? Much shorter:
SELECT SUBSTRING(col, CHARINDEX ('/', col) + 1, CHARINDEX ('.', col) - CHARINDEX ('/', col) - 1);
(I can't test right now because of right issues at my company SQL server, which is a problem in its own right)
Simply Try With LEFT ,RIGHT ,CHARINDEX
select
LEFT((RIGHT(a.name,((CHARINDEX('/', name))+1))),((CHARINDEX('.', (RIGHT(a.name,
((CHARINDEX('/', name))+1)))))-1)) splitstring,
a.name
from
(select 'images/test.jpg' as name)a
declare #searchStart nvarchar(100) = 'search ';
declare #searchEnd nvarchar(100) = ' ';
declare #string nvarchar(4000) = 'This is a string to search (hello) in this text ';
declare #startIndex int = CHARINDEX(#searchStart, #string,0) + LEN(#searchStart);
declare #endIndex int = CHARINDEX(#searchEnd, #string, #startIndex + 1);
declare #length int = #endIndex - #startIndex;
declare #sub nvarchar(4000) = SUBSTRING(#string, #startIndex, #length)
select #startIndex, #endIndex, #length, #sub
This is a little more legible than the one-liners in this answer which specifically answer the question, but not in a generic way that would benefit all readers. This could easily be made into a function as well with a slight modification.
If there are more than one or none occurences of given character use this:
DECLARE #rightidx int = CASE
WHEN 'images/images/test.jpg' IS NULL OR (CHARINDEX('.', 'images/images/test.jpg')) <= 0 THEN LEN('images/images/test.jpg')
ELSE (CHARINDEX('.', REVERSE('images/images/test.jpg')) - 1)
END
SELECT RIGHT('images/images/test.jpg', #rightidx)
This was the approach I took.
CREATE FUNCTION dbo.get_text_before_char(#my_string nvarchar(255),#my_char char(1))
RETURNS nvarchar(255)
AS
BEGIN;
return IIF(#my_string LIKE '%' + #my_char + '%',left (#my_string, IIF(charindex(#my_char, #my_string) - 1<1,1,charindex(#my_char, #my_string) - 1)),'');
END;
CREATE FUNCTION dbo.get_text_after_char(#my_string nvarchar(255),#my_char char(1))
RETURNS nvarchar(255)
AS
BEGIN;
return IIF ( #my_string LIKE '%' + #my_char + '%' ,RIGHT ( #my_string , IIF ( charindex ( #my_char ,reverse(#my_string) )-1 < 1 ,1 ,charindex ( #my_char ,reverse(#my_string) )-1 ) ) , '' )
END;
SELECT
dbo.get_text_before_char('foo-bar','-')
, dbo.get_text_after_char('foo-bar','-')
declare #test varchar(100)='images/test.jpg'
select right(left(#test, charindex('.', #test) - 1),4)
I have the following string.
Input
--------------
2030031469-NAI
To get the numeric part, I am using the following script
declare #str varchar(50)= '2030031469-NAI'
Select
#str
,SUBSTRING(#str, 1, NULLIF(CHARINDEX('-', #str) - 1, -1))
,Left(#str,PATINDEX('%-%',#str)-1)
to get the following output
Output:
----------
2030031469
Is there any other easy/elegant way of doing the same?
select left(#str, patindex('%[^0-9]%', #str+'.') - 1)
In case your string start with alphabet and end with number like ERT-123
you can use this query:
(select substring(#str,patindex('%[0-9]%', #str),len(#str)))
Please check with this, i used in my project for extracting phone numbers
CREATE Function [dbo].[RemoveNonNumericCharacters](#Temp VarChar(1000))
Returns VarChar(1000)
AS
Begin
While PatIndex('%[^0-9]%', #Temp) > 0
Set #Temp = Stuff(#Temp, PatIndex('%[^0-9]%', #Temp), 1, '')
Return #TEmp
End
To extract number from an unformatted string
DECLARE #Text NVARCHAR(100)= 'extract only 23124R integer ##%%'
SELECT SUBSTRING(#Text, PATINDEX('%[0-9]%',#Text), PATINDEX('%[^0-9]%',SUBSTRING(#Text, PATINDEX('%[0-9]%',#Text), LEN(#Text)))-1) [ONLY_INT]
How do I get the nth word in a sentence or a set of strings with space delimiter?
Sorry for the change in the requirement.Thank you.
By using instr.
select substr(help, 1, instr(help,' ') - 1)
from ( select 'hello my name is...' as help
from dual )
instr(help,' ') returns the positional index of the first occurrence of the second argument in the first, inclusive of the string you're searching for. i.e. the first occurrence of ' ' in the string 'hello my name is...' plus the space.
substr(help, 1, instr(help,' ') - 1) then takes the input string from the first character to the index indicated in instr(.... I then remove one so that the space isn't included..
For the nth occurrence just change this slightly:
instr(help,' ',1,n) is the nth occurrence of ' ' from the first character. You then need to find the positional index of the next index instr(help,' ',1,n + 1), lastly work out the difference between them so you know how far to go in your substr(.... As you're looking for the nth, when n is 1 this breaks down and you have to deal with it, like so:
select substr( help
, decode( n
, 1, 1
, instr(help, ' ', 1, n - 1) + 1
)
, decode( &1
, 1, instr(help, ' ', 1, n ) - 1
, instr(help, ' ', 1, n) - instr(help, ' ', 1, n - 1) - 1
)
)
from ( select 'hello my name is...' as help
from dual )
This will also break down at n. As you can see this is getting ridiculous so you might want to consider using regular expressions
select regexp_substr(help, '[^[:space:]]+', 1, n )
from ( select 'hello my name is...' as help
from dual )
Try this. An example of getting the 4th word:
select names from (
select
regexp_substr('I want my two dollars','[^ ]+', 1, level) as names,
rownum as nth
from dual
connect by regexp_substr('I want my two dollars', '[^ ]+', 1, level) is not null
)
where nth = 4;
The inner query is converting the space-delimited string into a set of rows. The outer query is grabbing the nth item from the set.
Try something like
WITH q AS (SELECT 'ABCD EFGH IJKL' AS A_STRING FROM DUAL)
SELECT SUBSTR(A_STRING, 1, INSTR(A_STRING, ' ')-1)
FROM q
Share and enjoy.
And here's the solution for the revised question:
WITH q AS (SELECT 'ABCD EFGH IJKL' AS A_STRING, 3 AS OCCURRENCE FROM DUAL)
SELECT SUBSTR(A_STRING,
CASE
WHEN OCCURRENCE=1 THEN 1
ELSE INSTR(A_STRING, ' ', 1, OCCURRENCE-1)+1
END,
CASE
WHEN INSTR(A_STRING, ' ', 1, OCCURRENCE) = 0 THEN LENGTH(A_STRING)
ELSE INSTR(A_STRING, ' ', 1, OCCURRENCE) - CASE
WHEN OCCURRENCE=1 THEN 0
ELSE INSTR(A_STRING, ' ', 1, OCCURRENCE-1)
END - 1
END)
FROM q;
Share and enjoy.
CREATE PROC spGetCharactersInAStrings
(
#S VARCHAR(100) = '^1402 WSN NI^AMLAB^tev^e^^rtS htimS 0055518',
#Char VARCHAR(100) = '8'
)
AS
-- exec spGetCharactersInAStrings '^1402 WSN NI^AMLAB^tev^e^^rtS htimS 0055518', '5'
BEGIN
DECLARE #i INT = 1,
#c INT,
#pos INT = 0,
#NewStr VARCHAR(100),
#sql NVARCHAR(100),
#ParmDefinition nvarchar(500) = N'#retvalOUT int OUTPUT'
DECLARE #D TABLE
(
ID INT IDENTITY(1, 1),
String VARCHAR(100),
Position INT
)
SELECT #c = LEN(#S), #NewStr = #S
WHILE #i <= #c
BEGIN
SET #sql = ''
SET #sql = ' SELECT #retvalOUT = CHARINDEX(''' + + #Char + ''',''' + #NewStr + ''')'
EXEC sp_executesql #sql, #ParmDefinition, #retvalOUT=#i OUTPUT;
IF #i > 0
BEGIN
set #pos = #pos + #i
SELECT #NewStr = SUBSTRING(#NewStr, #i + 1, LEN(#S))
--SELECT #NewStr '#NewStr', #Char '#Char', #pos '#pos', #sql '#sql'
--SELECT #NewStr '#NewStr', #pos '#pos'
INSERT INTO #D
SELECT #NewStr, #pos
SET #i = #i + 1
END
ELSE
BREAK
END
SELECT * FROM #D
END
If you're using MySQL and cannot use the instr function that accepts four parameters or regexp_substr, you can do this way:
select substring_index(substring_index(help, ' ', 2), ' ', -1)
from (select 'hello my name is...' as help) h
Result: "my".
Replace "2" in the code above with the number of the word you want.
If you are using SQL Server 2016+ then you can take advantage of the STRING_SPLIT function. It returns rows of string values and if you aim to get nth value, then you can use Row_Number() window function.
Here there is a little trick as you don't want to really order by something so that you have to "cheat" the row_number function and allow its value in the natural order which is the STRING_SPLIT() function will spit out.
Below is a code snippet if you want to find the third word of the string
Declare #_intPart INT = 3; -- change nth work here, start # from 1 not 0
SELECT value FROM(
SELECT value,
ROW_NUMBER()OVER(ORDER BY (SELECT 1)) AS rowno
FROM STRING_SPLIT('hello world this is amazing', ' ')
) AS o1 WHERE o1.rowno = #_intPart;
You can also make a scalar function to retrieve values.