Get single row depending of conditional - sql

I have a simple select query with some joins like:
SELECT
[c].[column1]
, [c].[column2]
FROM [Customer] AS [c]
INNER JOIN ...
So I do a left join with my principal table as:
LEFT JOIN [Communication] AS [com] ON [c].[CustomerGuid] = [com].[ComGuid]
this relatioship its 1 to *, one customer can have multiple communications
So in my select I want to get value 1 or 2 depending of condition:
Condition:
if ComTypeKey (from communication) table have a row with value 3 and have another row with vale 4 return 1 then 0
So I try something like:
SELECT
[c].[column1]
, [c].[column2]
, IIF([com].[ComTypeKey] = 3 AND [com].[ComTypeKey] = 4,1,0)
FROM [Customer] AS [c]
INNER JOIN ...
LEFT JOIN [Communication] AS [com] ON [c].[CustomerGuid] = [com].[ComGuid]
But it throws me two rows, beacause there are 2 rows on communication. My desire value is to get only one row with value 1 if my condition is true

If you have multiple rows you need GROUP BY, then count the relevant keys and subtract 1 to get (1, 0)
SELECT
[c].[column1]
, [c].[column2]
, COUNT(CASE WHEN [ComTypeKey] IN (3,4) THEN 1 END) - 1 as FLAG_CONDITION
FROM [Customer] AS [c]
INNER JOIN ...
LEFT JOIN [Communication] AS [com]
ON [c].[CustomerGuid] = [com].[ComGuid]
GROUP BY
[c].[column1]
, [c].[column2]

I'm not really sure I understand.
This will literally find if both values 3 and 4 exist for that CustomerGuid, and only select one of them in that case - not filtering out any record otherwise.
If this is not what you want, providing sample data with the expected result would remove the ambiguity.
SELECT Field1,
Field2,
...
FieldN
FROM (SELECT TMP.*,
CASE WHEN hasBothValues = 1 THEN
ROW_NUMBER() OVER ( PARTITION BY CustomerGuid ORDER BY 1 )
ELSE 1
END AS iterim_rn
FROM (SELECT TD.*,
MAX(CASE WHEN Value1 = '3' THEN 1 ELSE 0 END) OVER
( PARTITION BY CustomerGuid ) *
MAX(CASE WHEN Value1 = '4' THEN 1 ELSE 0 END) OVER
( PARTITION BY CustomerGuid ) AS hasBothValues
FROM TEST_DATA TD
) TMP
) TMP2
WHERE interim_rn = 1

Related

DB2 SQL Result Set without Duplicates

I am trying to adjust this SQL syntax to only show one row if it has a dash number in the field or field is empty.
Select Distinct TRIM(TRANSLATE(itnbr,' ','F')),
Case When t3.dashonly Is NULL Then '' Else t3.dashonly End As dashonly
From amflib1.itmrva t1
Join webprddt1.drawmext17 t2 On t2.afctdwg = t1.uu25
Left Join webprddt1.wqmssoadn t3 On t3.itemno = t1.itnbr
Where t2.recseq = '0060' Order By 1
As is the resultset is:
00001 DASHONLY
--------------- ---------------
41031052-1
41031052-1 -1
41031052-10
41031052-11 -11
41031052-11
41031052-12
41031052-12 -12
41031052-13
41031052-14
41031052-15
41031052-17
Desired resultset:
00001 DASHONLY
--------------- ---------------
41031052-1 -1
41031052-10
41031052-11 -11
41031052-12 -12
41031052-13
41031052-14
41031052-15
41031052-17
Thought I don't have test data to test your query, the query below should work.
You can use ROW_NUMBER() to sort the rows in each subgroup according to a sorting criteria, and then just pick the first one per group.
select *
from (
select
TRIM(TRANSLATE(itnbr,' ','F')),
case when t3.dashonly is null then '' else t3.dashonly end As dashonly,
row_number() over(partition by TRIM(TRANSLATE(itnbr,' ','F'))
order by case when t3.dashonly is null then 0 else 1 end) as rn
from amflib1.itmrva t1
join webprddt1.drawmext17 t2 on t2.afctdwg = t1.uu25
left join webprddt1.wqmssoadn t3 on t3.itemno = t1.itnbr
where t2.recseq = '0060'
) x
where rn = 1
order by 1

Returning only id's of records that meet criteria

I need to return distinct ID's of records which meet following conditions :
must have records with field reason_of_creation = 1
and must NOT have records with field reason_of_creation = 0 or null
in the same time.
While i was able to do it, i keep wondering is there more elegant (even recommended) way of doing it.
Here is anonymized version of what i have :
select distinct st.some_id from (
select st.some_id, wanted.wanted_count as wanted, unwanted.unwanted_count as unwanted
from some_table st
left join (
select st.some_id, count(st.reason_of_creation) as wanted_count
from some_table st
where st.reason_of_creation=1
group by st.some_id
) wanted on wanted.some_id = st.some_id
left join (
select st.some_id, count(st.reason_of_creation) as unwanted_count
from some_table st
where st.reason_of_creation=0
group by st.some_id
) unwanted on unwanted.some_id = st.some_id
where wanted.wanted_count >0 and (unwanted.unwanted_count = 0 or unwanted.unwanted_count is null)
) st;
Sample data :
some_id reason_of_creation
1 1
1 0
2 1
3 null
4 0
4 1
5 1
desired result would be list of records with some_id = 2, 5
It seems to me your query is overkill,all you need is some post aggregation filtering
SELECT some_id FROM t
GROUP BY some_id
HAVING SUM(CASE WHEN reason_of_creation = 1 THEN 1 ELSE 0 END)>0
AND SUM(CASE WHEN reason_of_creation = 0 OR reason_of_creation IS NULL THEN 1 ELSE 0 END)=0
I think that more elegant query exists and it is based on assumption what reasoson_of_crdeation field is integer, so minimal possible it's value, which greater than 0 is 1
This is for possible negative values for reasoson_of_crdeation:
select someid from st
where reasoson_of_crdeation != -1
group by someid
having(min(nvl(abs(reasoson_of_crdeation), 0)) = 1)
or
select someid from st
group by someid
having(min(nvl(abs(case when reasoson_of_crdeation = -1 then -2 else reasoson_of_crdeation end), 0)) = 1)
And this one in a case if reasoson_of_crdeation is non-negative integer:
select someid from st
group by someid
having(min(nvl(reasoson_of_crdeation, 0)) = 1)

sql Select id that matches combination of column

I have a token table
id | status
------------
1 | taken
1 | used
1 | deleted
2 | taken
2 | deleted
3 | taken
I need to count how many tokens are used ( in use or used).
If a token is taken and deleted without being used then it should not be counted.
So sql would be sth like
SELECT count(*) if the id's status is not (taken & deleted)
The desired number of used token in above example is 2 as
id 1 has been taken used and deleted -> count it
id 3 has been taken -> count it
id 2 has been taken and deleted without being used -> do not count it
A little bit verbose but efficient and still readable and maintainable:
SELECT COUNT(DISTINCT id)
FROM dbo.Token t
WHERE EXISTS
(
SELECT 1 FROM dbo.Token t1
WHERE t.id = t1.id
AND t1.status = 'used'
)
OR
(
EXISTS(
SELECT 1 FROM dbo.Token t1
WHERE t.id = t1.id
AND t1.status = 'taken'
)
AND NOT EXISTS(
SELECT 1 FROM dbo.Token t1
WHERE t.id = t1.id
AND t1.status = 'deleted'
)
)
Demo
Use aggregation and a having clause to get the list of eligible ids:
SELECT id
FROM token t
GROUP BY id
HAVING SUM(case when status = 'taken' then 1 else 0 end) > 0 or
SUM(case when status = 'used' then 1 else 0 end) > 0;
To get the count, use a subquery or CTE:
SELECT COUNT(*)
FROM (SELECT id
FROM token t
GROUP BY id
HAVING SUM(case when status = 'taken' then 1 else 0 end) > 0 or
SUM(case when status = 'used' then 1 else 0 end) > 0
) t
Try this:
SELECT SUM(CASE WHEN (CHARINDEX('used', data.status) > 0) OR (data.status = 'taken') THEN 1 ELSE 0 END) as [count]
FROM
(
SELECT DISTINCT id, (SELECT STUFF((SELECT Distinct ',' + status
FROM token a
WHERE a.id = b.id
FOR XML PATH (''))
, 1, 1, '')) as status
FROM token b
) data
Demo
You need to be able to take into account all three conditions, so a naive approach would be to just compare each three with a case statement:
WITH grouped as
(
select id from #uses group by id
)
select grouped.id,
used =
CASE WHEN used.id is not null THEN 'YES'
WHEN taken.id is not null and deleted.id is null THEN 'YES'
ELSE 'NO'
END
from grouped
left join #uses taken on grouped.id = taken.id
and taken.use_status = 'taken'
left join #uses used on grouped.id = used.id
and used.use_status = 'used'
left join #uses deleted on grouped.id = deleted.id
and deleted.use_status = 'deleted'
The case statement will stop whenever the condition is met, so you only need to WHEN's and an ELSE to meet the conditions.
This is a naive approach, though, and assumes that you only ever have one row per id and use status type. You'd have to do some additional work if that wasn't the case.
if token has been taken and used -> do not count it
SELECT
SUM(DECODE(status, 'taken', 1, 0)) +
SUM(DECODE(status, 'used', 1, 0)) -
SUM(DECODE(status, 'deleted', 1, 0))
FROM
token t
WHERE
status <> 'used' OR
EXISTS(SELECT 1 FROM token t2 WHERE t2.id = t.id and t2.status = 'deleted')
if token has been taken and used -> count it
SELECT
COUNT(1)
FROM
token t
WHERE
status = 'taken' AND
(
EXISTS(SELECT 1 FROM token t2 WHERE t2.id = t.id and t2.status = 'used') OR
NOT EXISTS(SELECT 1 FROM token t2 WHERE t2.id = t.id and t2.status = 'deleted')
)
Coming back to this question, one solution could be with using Pivot
SELECT COUNT(id)
FROM (
SELECT id, status FROM Token
) src
PIVOT
(
COUNT(status) FOR status IN ([taken], [used], [deleted])
) pvt
WHERE (taken = 1 AND deleted = 0)OR (used = 1)
DEMO

SQL (TSQL) - Select values in a column where another column is not null?

I will keep this simple- I would like to know if there is a good way to select all the values in a column when it never has a null in another column. For example.
A B
----- -----
1 7
2 7
NULL 7
4 9
1 9
2 9
From the above set I would just want 9 from B and not 7 because 7 has a NULL in A. Obviously I could wrap this as a subquery and USE the IN clause etc. but this is already part of a pretty unique set and am looking to keep this efficient.
I should note that for my purposes this would only be a one-way comparison... I would only be returning values in B and examining A.
I imagine there is an easy way to do this that I am missing, but being in the thick of things I don't see it right now.
You can do something like this:
select *
from t
where t.b not in (select b from t where a is null);
If you want only distinct b values, then you can do:
select b
from t
group by b
having sum(case when a is null then 1 else 0 end) = 0;
And, finally, you could use window functions:
select a, b
from (select t.*,
sum(case when a is null then 1 else 0 end) over (partition by b) as NullCnt
from t
) t
where NullCnt = 0;
The query below will only output one column in the final result. The records are grouped by column B and test if the record is null or not. When the record is null, the value for the group will increment each time by 1. The HAVING clause filters only the group which has a value of 0.
SELECT B
FROM TableName
GROUP BY B
HAVING SUM(CASE WHEN A IS NULL THEN 1 ELSE 0 END) = 0
If you want to get all the rows from the records, you can use join.
SELECT a.*
FROM TableName a
INNER JOIN
(
SELECT B
FROM TableName
GROUP BY B
HAVING SUM(CASE WHEN A IS NULL THEN 1 ELSE 0 END) = 0
) b ON a.b = b.b

Joining two select queries from the same table

The table contains an ID column, valueHeading column and a value column. I want to separate the value column into two new columns called valueHeading1 and valueHeading2 depending on which type of valueHeading the value has.
So I want to join this select:
Edit: Full join
SELECT ID
,valueHeading
,value as 'valueHeading1'
FROM table1
WHERE valueHeading = 'valueHeading1'
With This select:
SELECT ID
,value as 'valueHeading2'
FROM table1
WHERE valueHeading = 'valueHeading2'
on their respective ID's. How do I do this?
Edit to illustrate what I want to do:
Original table:
ID valueHeading value
0 valueHeading1 a
0 valueHeading2 a
1 valueHeading1 ab
1 valueHeading2 NULL
2 valueHeading1 abcd
2 valueHeading2 abc
New Table:
ID valueHeading1 valueHeading2
0 a a
1 ab NULL
2 abcd abc
If you need only join use this. Using case when is elegant way if you don't need join.
SELECT * FROM
(SELECT ID
,valueHeading
,value as 'valueHeading1'
FROM table1
WHERE valueHeading = 'valueHeading1') AS TAB_1,
(SELECT ID
,value as 'valueHeading2'
FROM table1
WHERE valueHeading = 'valueHeading2') AS TAB_2
WHERE TAB_1.ID = TAB_2.ID
Try something like :
SELECT ID
, CASE WHEN valueHeading = 'valueHeading1' THEN value ELSE NULL END AS valueHeading1
, CASE WHEN valueHeading = 'valueHeading2' THEN value ELSE NULL END AS valueHeading2
FROM table1
WHERE valueHeading IN ('valueHeading1', 'valueHeading2')
If you want to regroup all values on one row for each ID, you can try :
SELECT ID
, MAX(CASE WHEN valueHeading = 'valueHeading1' THEN value ELSE NULL END) AS valueHeading1
, MAX(CASE WHEN valueHeading = 'valueHeading2' THEN value ELSE NULL END) AS valueHeading2
FROM table1
WHERE valueHeading IN ('valueHeading1', 'valueHeading2')
GROUP BY ID
HAVING MAX(CASE WHEN valueHeading = 'valueHeading1' THEN value ELSE NULL END) IS NOT NULL
OR MAX(CASE WHEN valueHeading = 'valueHeading2' THEN value ELSE NULL END) IS NOT NULL
See SQLFiddle. I also tried on Oracle 11g and MSSQL 2012, and it works each time.
In SQLServer2005+ possible use PIVOT
SELECT ID, valueHeading1, valueHeading2
FROM
(
SELECT *
FROM dbo.test28
WHERE valueHeading IN ('valueHeading1', 'valueHeading2')
) x
PIVOT
(
MAX(value)
FOR valueHeading IN ([valueHeading1], [valueHeading2])
) p
Demo on SQLFiddle
self join could be a simple solution
SELECT DISTINCT t1.ID, t1.value as valueHeading1, t2.value as valueHeading2,
FROM table1 t1
INNER JOIN table1 t2 ON t1.ID = t2.ID
WHERE t1.valueHeading <> t2.valueHeading