I need to return distinct ID's of records which meet following conditions :
must have records with field reason_of_creation = 1
and must NOT have records with field reason_of_creation = 0 or null
in the same time.
While i was able to do it, i keep wondering is there more elegant (even recommended) way of doing it.
Here is anonymized version of what i have :
select distinct st.some_id from (
select st.some_id, wanted.wanted_count as wanted, unwanted.unwanted_count as unwanted
from some_table st
left join (
select st.some_id, count(st.reason_of_creation) as wanted_count
from some_table st
where st.reason_of_creation=1
group by st.some_id
) wanted on wanted.some_id = st.some_id
left join (
select st.some_id, count(st.reason_of_creation) as unwanted_count
from some_table st
where st.reason_of_creation=0
group by st.some_id
) unwanted on unwanted.some_id = st.some_id
where wanted.wanted_count >0 and (unwanted.unwanted_count = 0 or unwanted.unwanted_count is null)
) st;
Sample data :
some_id reason_of_creation
1 1
1 0
2 1
3 null
4 0
4 1
5 1
desired result would be list of records with some_id = 2, 5
It seems to me your query is overkill,all you need is some post aggregation filtering
SELECT some_id FROM t
GROUP BY some_id
HAVING SUM(CASE WHEN reason_of_creation = 1 THEN 1 ELSE 0 END)>0
AND SUM(CASE WHEN reason_of_creation = 0 OR reason_of_creation IS NULL THEN 1 ELSE 0 END)=0
I think that more elegant query exists and it is based on assumption what reasoson_of_crdeation field is integer, so minimal possible it's value, which greater than 0 is 1
This is for possible negative values for reasoson_of_crdeation:
select someid from st
where reasoson_of_crdeation != -1
group by someid
having(min(nvl(abs(reasoson_of_crdeation), 0)) = 1)
or
select someid from st
group by someid
having(min(nvl(abs(case when reasoson_of_crdeation = -1 then -2 else reasoson_of_crdeation end), 0)) = 1)
And this one in a case if reasoson_of_crdeation is non-negative integer:
select someid from st
group by someid
having(min(nvl(reasoson_of_crdeation, 0)) = 1)
Related
I have a simple select query with some joins like:
SELECT
[c].[column1]
, [c].[column2]
FROM [Customer] AS [c]
INNER JOIN ...
So I do a left join with my principal table as:
LEFT JOIN [Communication] AS [com] ON [c].[CustomerGuid] = [com].[ComGuid]
this relatioship its 1 to *, one customer can have multiple communications
So in my select I want to get value 1 or 2 depending of condition:
Condition:
if ComTypeKey (from communication) table have a row with value 3 and have another row with vale 4 return 1 then 0
So I try something like:
SELECT
[c].[column1]
, [c].[column2]
, IIF([com].[ComTypeKey] = 3 AND [com].[ComTypeKey] = 4,1,0)
FROM [Customer] AS [c]
INNER JOIN ...
LEFT JOIN [Communication] AS [com] ON [c].[CustomerGuid] = [com].[ComGuid]
But it throws me two rows, beacause there are 2 rows on communication. My desire value is to get only one row with value 1 if my condition is true
If you have multiple rows you need GROUP BY, then count the relevant keys and subtract 1 to get (1, 0)
SELECT
[c].[column1]
, [c].[column2]
, COUNT(CASE WHEN [ComTypeKey] IN (3,4) THEN 1 END) - 1 as FLAG_CONDITION
FROM [Customer] AS [c]
INNER JOIN ...
LEFT JOIN [Communication] AS [com]
ON [c].[CustomerGuid] = [com].[ComGuid]
GROUP BY
[c].[column1]
, [c].[column2]
I'm not really sure I understand.
This will literally find if both values 3 and 4 exist for that CustomerGuid, and only select one of them in that case - not filtering out any record otherwise.
If this is not what you want, providing sample data with the expected result would remove the ambiguity.
SELECT Field1,
Field2,
...
FieldN
FROM (SELECT TMP.*,
CASE WHEN hasBothValues = 1 THEN
ROW_NUMBER() OVER ( PARTITION BY CustomerGuid ORDER BY 1 )
ELSE 1
END AS iterim_rn
FROM (SELECT TD.*,
MAX(CASE WHEN Value1 = '3' THEN 1 ELSE 0 END) OVER
( PARTITION BY CustomerGuid ) *
MAX(CASE WHEN Value1 = '4' THEN 1 ELSE 0 END) OVER
( PARTITION BY CustomerGuid ) AS hasBothValues
FROM TEST_DATA TD
) TMP
) TMP2
WHERE interim_rn = 1
I am attempting to set values to zero if a user does not exist in one of my tables. Currently, I am using decode to count the number of users that meet a certain criteria and then display the result.
SELECT T.D_CODE,
T.C_NO,
SUM(DECODE(t.Value, 'A', 1, 0)) AS FirstValue,
SUM(DECODE(t.Value, 'B', 1, 0)) AS SecondValue,
SUM(DECODE(t.Value, 'C', 1, 0)) AS ThirdValue,
SUM(DECODE(t.Value, 'F', 1, 0)) AS LastValue
FROM Table T,
Table OtherTable S
WHERE T.T_SSN = S.SSN(+)
AND T.D_CODE = 'INF'
GROUP BY t.D_CODE,
T.C_NO;
The issue is that I have a third table (TT) that has additional values in it. If TT has a value that is not present in Table T, then I need to display that record with 0's for all of the Decode values.
Required output would look something like:
D_CODE, C_NO, FirstValue, SecondValue, ThirdValue, LastValue
INF 600 2 0 0 0
INF 501 0 0 1 0
INF 400 0 0 0 0
Where INF 400 does not exist in Table t, only in Table TT
Any suggestions?
Your problem is that you are filtering the users by T.D_CODE = 'INF' which means that any user that does not met that criteria will not come at all in the results. So, for what I understood of your question you need this:
SELECT T.D_CODE,
T.C_NO,
SUM(CASE WHEN T.D_CODE = 'INF' AND t.Value = 'A' THEN 1 ELSE 0 END) AS FirstValue,
SUM(CASE WHEN T.D_CODE = 'INF' AND t.Value = 'B' THEN 1 ELSE 0 END) AS AS SecondValue,
SUM(CASE WHEN T.D_CODE = 'INF' AND t.Value = 'C' THEN 1 ELSE 0 END) AS AS ThirdValue,
SUM(CASE WHEN T.D_CODE = 'INF' AND t.Value = 'D' THEN 1 ELSE 0 END) AS AS LastValue
FROM Table T
LEFT JOIN Table OtherTable S
ON T.T_SSN = S.SSN
LEFT JOIN AnotherTable TT
ON T.T_SSN = TT.SSN
GROUP BY t.D_CODE,
T.C_NO;
Since you didn't provide any more details about your TT table I just guessed the relation between it and the T table.
Side note: Always use the SQL ANSI [LEFT ]JOINs style.
ALSO Note that for your current query and current fetched fields tables S and TT are totally irrelevant, unless you didn't explain it right.
Hey guys I have the below sample data which i want to query for.
MemberID AGEQ1 AGEQ2 AGEQ2
-----------------------------------------------------------------
1217 2 null null
58458 3 2 null
58459 null null null
58457 null 5 null
299576 6 5 7
What i need to do is to lookup the table and if any AGEx COLUMN contains any data then it counts the number of times there is data for that row in each column
Results example:
for memberID 1217 the count would be 1
for memberID 58458 the count would be 2
for memberID 58459 the count would be 0 or null
for memberID 58457 the count would be 1
for memberID 299576 the count would be 3
This is how it should look like in SQL if i query the entire table
1 Children - 2
2 Children - 1
3 Children - 1
0 Children - 1
So far i have been doing it using the following query which isnt very efficient and does give incorrect tallies as there are multiple combinations that people can answer the AGE question. Also i have to write multiple queries and change the is null to is not null depending on how many children i am looking to count a person has
select COUNT (*) as '1 Children' from Member
where AGEQ1 is not null
and AGEQ2 is null
and AGEQ3 is null
The above query only gives me an answer of 1 but i want to be able to count the other columns for data as well
Hope this is nice and clear and thank you in advance
If all of the columns are integers, you can take advantage of integer math - dividing the column by itself will yield 1, unless the value is NULL, in which case COALESCE can convert the resulting NULL to 0.
SELECT
MemberID,
COALESCE(AGEQ1 / AGEQ1, 0)
+ COALESCE(AGEQ2 / AGEQ2, 0)
+ COALESCE(AGEQ3 / AGEQ3, 0)
+ COALESCE(AGEQ4 / AGEQ4, 0)
+ COALESCE(AGEQ5 / AGEQ5, 0)
+ COALESCE(AGEQ6 / AGEQ6, 0)
FROM dbo.table_name;
To get the number of people with each count of children, then:
;WITH y(y) AS
(
SELECT TOP (7) rn = ROW_NUMBER() OVER
(ORDER BY [object_id]) - 1 FROM sys.objects
),
x AS
(
SELECT
MemberID,
x = COALESCE(AGEQ1 / AGEQ1, 0)
+ COALESCE(AGEQ2 / AGEQ2, 0)
+ COALESCE(AGEQ3 / AGEQ3, 0)
+ COALESCE(AGEQ4 / AGEQ4, 0)
+ COALESCE(AGEQ5 / AGEQ5, 0)
+ COALESCE(AGEQ6 / AGEQ6, 0)
FROM dbo.table_name
)
SELECT
NumberOfChildren = y.y,
NumberOfPeopleWithThatMany = COUNT(x.x)
FROM y LEFT OUTER JOIN x ON y.y = x.x
GROUP BY y.y ORDER BY y.y;
I'd look at using UNPIVOT. That will make your wide column into rows. Since you don't care about what value was in a column, just the presence/absence of value, this will generate a row per not-null column.
The trick then becomes mashing that into the desired output format. It could probably have been done cleaner but I'm a fan of "showing my work" so that others can conform it to their needs.
SQLFiddle
-- Using the above logic
WITH HadAges AS
(
-- Find everyone and determine number of rows
SELECT
UP.MemberID
, count(1) AS rc
FROM
dbo.Member AS M
UNPIVOT
(
ColumnValue for ColumnName in (AGEQ1, AGEQ2, AGEQ3)
) AS UP
GROUP BY
UP.MemberID
)
, NoAge AS
(
-- Account for those that didn't show up
SELECT M.MemberID
FROM
dbo.Member AS M
EXCEPT
SELECT
H.MemberID
FROM
HadAges AS H
)
, NUMBERS AS
(
-- Allowable range is 1-6
SELECT TOP 6
ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) AS TheCount
FROM
sys.all_columns AS SC
)
, COMBINATION AS
(
-- Link those with rows to their count
SELECT
N.TheCount AS ChildCount
, H.MemberID
FROM
NUMBERS AS N
LEFT OUTER JOIN
HadAges AS H
ON H.rc = N.TheCount
UNION ALL
-- Deal with the unlinked
SELECT
0
, NA.MemberID
FROM
NoAge AS NA
)
SELECT
C.ChildCount
, COUNT(C.MemberID) AS Instances
FROM
COMBINATION AS C
GROUP BY
C.ChildCount;
Try this:
select id, a+b+c+d+e+f
from ( select id,
case when age1 is null then 0 else 1 end a,
case when age2 is null then 0 else 1 end b,
case when age3 is null then 0 else 1 end c,
case when age4 is null then 0 else 1 end d,
case when age5 is null then 0 else 1 end e,
case when age6 is null then 0 else 1 end f
from ages
) as t
See here in fiddle http://sqlfiddle.com/#!3/88020/1
To get the quantity of persons with childs
select childs, count(*) as ct
from (
select id, a+b+c+d+e+f childs
from
(
select
id,
case when age1 is null then 0 else 1 end a,
case when age2 is null then 0 else 1 end b,
case when age3 is null then 0 else 1 end c,
case when age4 is null then 0 else 1 end d,
case when age5 is null then 0 else 1 end e,
case when age6 is null then 0 else 1 end f
from ages ) as t
) ct
group by childs
order by 1
See it here at fiddle http://sqlfiddle.com/#!3/88020/24
Sorry for the confusing title. I was having trouble searching for the solution I am looking for because I do not know how to summarize it in a few words.
I have a single table, table_name, with columns Indicator, ID, and Num. The Indicator is either 0 or 1 and the ID can exist up to 2 times. If the ID number exists twice, one of the indicator is 0 and the other is 1 and if the ID exists once, its indicator is 0. My query needs to be able to return 0 if the indicator for a row is 0 and Num from the matching ID with indicator 0 if the indicator is 1.
Indicator----ID-----Num
1-------------01----3000
0-------------01----4000
0-------------02----5000
0-------------03----100
1-------------04----400
0-------------04----200
RESULTS of Query
4000
0
0
0
200
0
This is tricky, because you want to be sure not to lose any rows. For that reason, I'm doing this with a nested select statement:
select (case when indicator = 0 then 0
else (select t2.num from table_name t2 where t2.id = t.id and t2.indicator = 0)
end) as Val
from table_name t
Here is an example of it working (assuming your database supports with):
with table_name as (
select 1 as indicator, 1 as id, 3000 as num union all
select 0, 1, 4000 union all
select 0, 2, 5000 union all
select 0, 3, 100 union all
select 1, 4, 400 union all
select 0, 4, 200
)
select (case when indicator = 0 then 0
else (select t2.num from table_name t2 where t2.id = t.id and t2.indicator = 0)
end) as Val
from table_name t
select case when oneId.id is null the 0 else zero.num end case
from table1 zero
left join table1 oneId
on zero.id = oneId.id
and 1 = oneId.indicator
where zero.indicator = 0
Try this:
SELECT IF(t1.indicator = 0 OR t2.Num IS NULL, 0, t2.Num)
FROM table_name as t1
LEFT JOIN table_name as t2 ON(
t1.ID = t2.ID
AND t1.indicator != t2.indicator
)
http://sqlfiddle.com/#!2/61623a/3
My table structure is this
id last_mod_dt nr is_u is_rog is_ror is_unv
1 x uuid1 1 1 1 0
2 y uuid1 1 0 1 1
3 z uuid2 1 1 1 1
I want the count of rows with:
is_ror=1 or is_rog =1
is_u=1
is_unv=1
All in a single query. Is it possible?
The problem I am facing is that there can be same values for nr as is the case in the table above.
Case statments provide mondo flexibility...
SELECT
sum(case
when is_ror = 1 or is_rog = 1 then 1
else 0
end) FirstCount
,sum(case
when is_u = 1 then 1
else 0
end) SecondCount
,sum(case
when is_unv = 1 then 1
else 0
end) ThirdCount
from MyTable
you can use union to get multiple results e.g.
select count(*) from table with is_ror=1 or is_rog =1
union
select count(*) from table with is_u=1
union
select count(*) from table with is_unv=1
Then the result set will contain three rows each with one of the counts.
Sounds pretty simple if "all in a single query" does not disqualify subselects;
SELECT
(SELECT COUNT(DISTINCT nr) FROM table1 WHERE is_ror=1 OR is_rog=1) cnt_ror_reg,
(SELECT COUNT(DISTINCT nr) FROM table1 WHERE is_u=1) cnt_u,
(SELECT COUNT(DISTINCT nr) FROM table1 WHERE is_unv=1) cnt_unv;
how about something like
SELECT
SUM(IF(is_u > 0 AND is_rog > 0, 1, 0)) AS count_something,
...
from table
group by nr
I think it will do the trick
I am of course not sure what you want exactly, but I believe you can use the logic to produce your desired result.