I have a table in which cells can be as follows:
user_group can be admin, allow, disallow
user_subscription can be all, penalty, autogoal
I need to get the records that correspond to the following expression:
All admin and allow where user_subscription == all`` orautogoal```
I tried to do it like this:
('SELECT * FROM USERS WHERE (user_group="allow" OR user_group="admin" AND user_subscription="autogoal" OR user_subscription="all")')
But it does not work. I have 2 entries in the database:
user_group=admin, user_subscription=```all``
user_group=allow, user_subscription=```autogoal``
I always get only the second entry.
You must use parentheses correctly, because the AND operator has higher precedence than the OR operator.
So your WHERE condition is equivalent to:
user_group="allow"
OR
(user_group="admin" AND user_subscription="autogoal")
OR
user_subscription="all"
Write the statement like this:
SELECT * FROM USERS
WHERE
(user_group="allow" OR user_group="admin")
AND
(user_subscription="autogoal" OR user_subscription="all")
You can find more here.
Or with the IN operator:
SELECT * FROM USERS
WHERE
user_group IN ("allow", "admin")
AND
user_subscription IN ("autogoal", "all")
You are missing some parenthesis in your WHERE clause
Try this :
SELECT *
FROM USERS
WHERE (user_group="allow" OR user_group="admin")
AND (user_subscription="autogoal" OR user_subscription="all")
Related
I've the following subquery in an sql query:
(
SELECT ID_PLAN, ID_CURSO, NEDICION, NOMBRE AS NOMBREUNIDAD FROM ASISTEN, ALUMNOS, UNIDADES
WHERE ASISTEN.COD = ALUMNOS.COD AND UNIDADES.IDESTRUCTURA = ALUMNOS.IDESTRUCTURA
AND UNIDADES.CDUNDORG = ALUMNOS.CDUNDORG
AND UPPER(TRANSLATE(UNIDADES.NOMBRE, 'áéíóúÁÉÍÓÚ', 'aeiouAEIOU')) LIKE '%CONSEJERIA%'
GROUP BY ID_PLAN, ID_CURSO, NEDICION) ASIS
Problem I have I believe lies in that both table ALUMNOS and UNIDADES have a column named 'NOMBRE' so if I attempt to execute the query I obtain:
00000 - "column ambiguously defined"
To avoid that I thought about changing NOMBRE AS NOMBREUNIDAD to:
UNIDADES.NOMBRE AS NOMBREUNIDAD
But if I do that I get a:
00000 - "not a GROUP BY expression"
So, I don't know what to do so that subquery executes properly.
What should I change to properly execute query without changing the column name?
Aliases are pretty useful, if you use them. The simplify queries and make them easier to read and maintain. I'd suggest you to do so, as it'll also help query to work because Oracle doesn't know which table you actually meant when you selected those 4 columns - which tables do they belong to?
This is just a guess as I don't know your tables so you'll have to fix it yourself. Also, I literally JOINed tables; try to avoid comma-separating them in FROM clause and doing join in WHERE clause as it is supposed to filter data.
GROUP BY, as already commented, is probably useless. If you wanted to fetch distinct set of values, then use appropriate keyword: distinct.
SELECT DISTINCT n.id_plan,
s.id_curso,
u.nedicion,
u.nombre
FROM asisten n
JOIN alumnos s ON n.cod = s.cod
JOIN unidades u
ON u.idestructura = s.idestructura
AND u.cdundorg = s.cdundorg
WHERE UPPER (TRANSLATE (u.nombre, 'áéíóúÁÉÍÓÚ', 'aeiouAEIOU')) LIKE '%CONSEJERIA%'
I managed to solve my problem:
(
SELECT ID_PLAN, ID_CURSO, NEDICION, UNIDADES.NOMBRE AS NOMBREUNIDAD
FROM ASISTEN, ALUMNOS, UNIDADES
WHERE ASISTEN.COD = ALUMNOS.COD AND UNIDADES.IDESTRUCTURA = ALUMNOS.IDESTRUCTURA
AND UNIDADES.CDUNDORG = ALUMNOS.CDUNDORG
AND UPPER(TRANSLATE(UNIDADES.NOMBRE, 'áéíóúÁÉÍÓÚ', 'aeiouAEIOU')) LIKE '%CONSEJERIA%'
GROUP BY UNIDADES.NOMBRE,ID_PLAN, ID_CURSO, NEDICION
)
I have an SQL query like this (written for PostgreSQL):
SELECT *
FROM users
WHERE users.company_id = ANY(ARRAY[945387, 969109, 1460013, 1460044]) AND
users.profession_id = ANY(ARRAY[2738, 6388])
GROUP BY users.company_id
but I can't run it like this for AthenaQuery (getting SYNTAX_ERROR: Function any not registered).
How can I convert it?
You can rewrite the array operator to a standard IN condition.
Your query is equivalent to:
SELECT *
FROM users
WHERE users.company_id IN (945387, 969109, 1460013, 1460044)
AND users.profession_id IN (2738, 6388)
GROUP BY users.company_id
I am having a tons of URL's in my database and want to filter them by user-defined string in format something/*/something, where * stands for "anything". So when user defines checkout/*/complete, it means it filters out url's like:
http://my_url.com/checkout/15/complete
http://my_url.com/checkout/85/complete
http://my_url.com/checkout/something/complete
http://my_url.com/super/checkout/something/complete
etc.
How do I do that in SQL? Or should I filter out all the results and use PHP to do the job?
My SQL request now is
SELECT * FROM custom_logs WHERE pn='$webPage' AND id IN ( SELECT MAX(id) FROM custom_logs WHERE action_clicked_text LIKE '%{$text_value_active}%' GROUP BY token ) order by action_timestamp desc
This filters out all the log messages with user-defined text in column action_clicked_text, but uses LIKE statement, which will not work with * inside.
You want like. Either:
where url like '%checkout/%/complete%'
to get the urls that match he pattern. Or:
where url not like '%checkout/%/complete%'
to get the other urls.
The question is about selection from JSON in PostgreSQL.
For example, application contains translation data in jsonb:
{
"en":{
"locale":"en",
"title":"Title",
"textShort":"Short text",
"textFull":"Full text"
}
"ru":{
"locale":"ru",
"title":"Заголовок",
"textShort":"Короткий текст",
"textFull":"Подробный текст"
}
}
This query works successfully:
select *
from content_records
where translations::json->'en'->>'title' like '%Title.';
But this query requires information about the locale, but the case is that we don't know anything about locales and search must be done for every locale, for example:
select *
from content_records
where translations::json->'any locale'->>'title' like '%Title.';
In MySQL it works as:
select *
from content_records
where LOWER(JSON_EXTRACT(translations, '$.*.title')) LIKE LOWER(:title);
There is the similar function in PostgreSQL:
json_extract_path, but it requires keywords and you can't miss the key as the symbol * does in MySQL.
The question is - how to do the selection of a nested JSON in this situation?
Unfortunately, in Postgres you have to "unnest" the keys first.
Something like this:
select t.*, cr.translations
from content_records cr
cross join lateral jsonb_object_keys(translations) as t(locale)
where lower(cr.translations -> t.locale ->> 'title') like '%title';
Note that if a title matches in more than one locale, you will get one row for each matching locale. If you don't want that, you can do the following:
select cr.*
from content_records cr
where exists (select *
from jsonb_object_keys(cr.translations) as t(locale)
where lower(cr.translations -> t.locale ->> 'title') like '%title')
When I search for the Dünyas word with a LIKE operator I can see the results but when I search Dünyası word with LIKE operator, it returns no results. Problem is not ı or ü letters I tried with i and u letters as well.
This query:
select * from DbDivx where NameTurkish like '%Dünyas%' =>
returns:
Boksörün Dünyası
Geleceğin Dünyası
Su Dünyası
However:
select * from DbDivx where NameTurkish like '%Dünyası%' =>
returns nothing.
Can you help me please?
http://sqlfiddle.com/#!6/8c359/1
create table test (someName nvarchar(300))
insert into test (someName)
select N'Boksörün Dünyası'
union all select N'Geleceğin Dünyası'
union all select N'Su Dünyası'
select * from test where someName like N'%Dünyası%'
Not having any issues with the above fiddle. Note that when i inserted data without the N in front of it, the like query did not return results.
hopefully this helps!