sql purchase items - sql

I need a stored procedure for solve this problem. I have table with name Items With Values
id qty
1 5
2 10
3 15
If a parameter value = 10, and the table will be
id qty
1 0
2 5
3 15

If your dbms supports window functions (ms sql server 2012+ is used below):
declare #prm int = 10;
select id, qty
, case
when qty + tot <= #prm then 0
when tot > #prm then qty
else (qty + tot) - #prm
end currQty
from (
select id, qty, coalesce (sum(qty) over(order by id rows between unbounded preceding and 1 preceding), 0) tot
from
-- your table here
(values
(1,5 )
,(2,10)
,(3,15)
) tbl (id,qty)
) t;

Basically, you want to use a cumulative sum for this purpose. The rest is just arithmetic. I like to phrase this as:
select t.*,
(case when running_qty <= #parameter
then 0
when running_qty - qty <= #parameter
then running_qty - #parameter
else qty
end) as new_qty
from (select t.*,
sum(qty) over (order by id) as running_qty
from t
) t;
Here is a db<>fiddle.

Related

CASE WHEN condition with MAX() function

There are a lot questions on CASE WHEN topic, but the closest my question is related to this How to use CASE WHEN condition with MAX() function query which has not been resolved.
Here is some of my sample data:
date
debet
2022-07-15
57190.33
2022-07-14
815616516.00
2022-07-15
40866.67
2022-07-14
1221510.00
So, I want to all records for the last two dates and three additional columns: sum(sales) for the previous day, sum for the current day and the difference between them:
SELECT
[debet],
[date] ,
SUM( CASE WHEN [date] = MAX(date) THEN [debet] ELSE 0 END ) AS sum_act,
SUM( CASE WHEN [date] = MAX(date) - 1 THEN [debet] ELSE 0 END ) AS sum_prev ,
(
SUM( CASE WHEN [date] = MAX(date) THEN [debet] ELSE 0 END )
-
SUM( CASE WHEN [date] = MAX(date) - 1 THEN [debet] ELSE 0 END )
) AS diff
FROM
Table
WHERE
[date] = ( SELECT MAX(date) FROM Table WHERE date < ( SELECT MAX(date) FROM Table) )
OR
[date] = ( SELECT MAX(date) FROM Table WHERE date = ( SELECT MAX(date) FROM Table ) )
GROUP BY
[date],
[debet]
Further, of course, it informs that I can't use the aggregate function inside CASE WHEN. Now I use this combination: sum(CASE WHEN [date] = dateadd(dd,-3,cast(getdate() as date)) THEN [debet] ELSE 0 END). But here every time I need to make an adjustment for weekends and holidays. The question is, is there any other way than using 'getdate' in 'case when' Statement to get max date?
Expected result:
date
sum_act
sum_prev
diff
2022-07-15
97190.33
0.00
97190.33
2022-07-14
0.00
508769.96
-508769.96
You can use dense_rank() to filter the last 2 dates in your table. After that you can use either conditional case expression with sum() to calculate the required value
select [date],
sum_act = sum(case when rn = 1 then [debet] else 0 end),
sum_prev = sum(case when rn = 2 then [debet] else 0 end),
diff = sum(case when rn = 1 then [debet] else 0 end)
- sum(case when rn = 2 then [debet] else 0 end)
from
(
select *, rn = dense_rank() over (order by [date] desc)
from tbl
) t
where rn <= 2
group by [date]
db<>fiddle demo
Two steps:
Get the sums for the last three dates
Show the results for the last two dates.
Well, we could also get all daily sums in step 1, but we just need the last three in order to calculate the sums for the last two days, so why aggregate more data than necessary?
Here is the query. You may have to put the date column name in brackets in SQL Server, as date is a keyword in SQL.
select top(2)
date,
sum_debit_current,
sum_debit_previous,
sum_debit_current - sum_debit_previous as diff
(
select
date,
sum(debet) as sum_debit_current,
lag(sum(debet)) over (order by date) as sum_debit_previous
from table
where date in (select distinct top(3) date from table order by date desc)
group by date
)
order by date desc;
(SQL Server uses TOP(n) instead of standard SQL FETCH FIRST 3 ROWS and while SELECT DISTINCT TOP(3) date looks like "get the top 3 rows, then apply distinct on their date", it is really "apply distinct on the dates, then get the top 3" like in standard SQL.)

How to make Ranking using case by Partition in SQL Server?

I need to do Ranking, if the value is negative, then sort it by Asc, if it is positive then sort it by Desc
select
Itemcode,
isnull(sum(ss.DiscQty * ss.Cost),0) DescCost,
RANK()OVER(Partition by Itemcode order by
case when isnull(sum(ss.DiscQty * ss.Cost),0) < 0 THEN isnull(sum(ss.DiscrepancyQty * ss.Cost),0) END ASC,
case when isnull(sum(ss.DiscQty * ss.Cost),0) > 0 THEN isnull(sum(ss.DiscQty * ss.Cost),0) END DESC
) RANKS
from
ss
Group by
ItemNo
Is this the pattern you are after?
Have simplified the code to highlight what is happening
;WITH Example (n) AS
(
SELECT 1 UNION ALL
SELECT 2 UNION ALL
SELECT 3 UNION ALL
SELECT -1 UNION ALL
SELECT -2 UNION ALL
SELECT -3
)
SELECT n
,ROW_NUMBER() OVER (ORDER BY ABS(n)-0 DESC)
FROM Example
ORDER BY n,ROW_NUMBER() OVER (ORDER BY ABS(n)-0 DESC)
You cannot change the criteria dynamically. Do the following
SELECT
Brand,
ItemNo,
RANK() OVER (PARTITION BY ItemNo ORDER BY
CASE WHEN ISNULL(Disc, 0) > 0 THEN SUM(Quantity * Item.Cost) ELSE 0 END DESC,
CASE WHEN ISNULL(ST_ItemEntry.Discrepancy, 0) < 0 THEN SUM(Quantity * Item.Cost) ELSE 0 END ASC
) AS [Rank]
FROM
item
GROUP BY
Brand,ItemNo

How to return Value based on Subquery in SQL Server?

I Have a table with ITEM , OPCODE ,WorkCenter, LOT , COIL ,Strt_Time(DateTime) .I want to return Previous WorkCenter and NextWorkCenter along with ITEM , OPCODE ,WorkCenter, LOT , COIL ,Strt_Time .
A coil of particlular LOT will be routed from Workcenter to Workcenter with time stamp(Strt_time)
Please kindly advise how to achieve this in SQL Server 2008 .
Thanks in advance.
In SQL Server 2012 you should use LEAD and LAG Functions.
Since you are using SQL Server 2008, here is a workaround:
WITH WorkCenter_details AS
(
SELECT
ROW_NUMBER() OVER ( ORDER BY Strt_Time) rn,
(ROW_NUMBER() OVER ( ORDER BY Strt_Time)) / 2 rndiv2,
(ROW_NUMBER() OVER ( ORDER BY Strt_Time) + 1) / 2 rnplus1div2,
ITEM, OPCODE, WorkCenter, LOT, COIL, Strt_Time
FROM
MyTable
)
SELECT
rn, rndiv2, rnplus1div2,
ITEM, OPCODE, WorkCenter, LOT, COIL, Strt_Time,
CASE
WHEN rn % 2 = 1
THEN MAX(CASE WHEN rn % 2 = 0 THEN WorkCenter END) OVER (PARTITION BY rndiv2)
ELSE MAX(CASE WHEN rn % 2 = 1 THEN WorkCenter END) OVER (PARTITION BY rnplus1div2)
END AS WorkCenter_Previous,
CASE
WHEN rn % 2 = 1
THEN MAX(CASE WHEN rn % 2 = 0 THEN WorkCenter END) OVER (PARTITION BY rnplus1div2)
ELSE MAX(CASE WHEN rn % 2 = 1 THEN WorkCenter END) OVER (PARTITION BY rndiv2)
END AS WorkCenter_Next
FROM
WorkCenter_details
ORDER BY
ITEM, Strt_Time
This works only if workcenter is numeric

SQL find consecutive days of specific threshold reached

I have two columns; the_day and amount_raised. I want to find the count of consecutive days that at least 1 million dollars was raised. Am I able to do this in SQL? Ideally, I'd like to create a column that counts the consecutive days and then starts over if the 1 million dollar threshold is not reached.
What I've done thus far is create a third column that puts a 1 in the row if 1 million was reached. Could I create a subquery and count the consecutive 1's listed, then reset when it hits 0?
and here is the desired output
select dt,amt,
case when amt>=1000000 then -1+row_number() over(partition by col order by dt)
else 0 end col1
from (select *, sum(case when amt >= 1000000 then 0 else 1 end) over(order by dt) col
from t) x
Sample Demo
SELECT the_day,
amount_raised,
million_threshold,
CASE WHEN million_threshold <> lag_million_threshold AND million_threshold = lead_million_threshold
THEN 1
WHEN million_threshold = lag_million_threshold
THEN SUM(million_threshold) OVER ( ORDER BY the_day ROWS UNBOUNDED PRECEDING )
ELSE 0
END AS consecutive_day_cnt
FROM
(
SELECT the_day,
amount_raised,
million_threshold,
LAG(million_threshold,1) OVER ( ORDER BY the_day ) AS lag_million_threshold,
LEAD(million_threshold,1) OVER ( ORDER BY the_day ) AS lead_million_threshold
FROM
(
SELECT the_day,
amount_raised,
CASE WHEN amount_raised >= 1000000
THEN 1
ELSE 0
END AS million_threshold
FROM Yourtable
)
);

Update Value without cursor

I have a table in the database.
Bill
ID Total Paid Status
1 1000 1000 Paid
2 500 400 Part Paid
3 700 0 Unpaid
4 200 0 Unpaid
Now the User pays PAID_AMT -> $900, which i want to distribute such that my table looks:
ID Total Paid Status
1 1000 1000 Paid
2 500 500 Paid
3 700 700 Paid
4 200 100 Part Paid
It can be easily done using cursor, but i want to avoid cursors.
Is it possible to achieve this using simple update queries with Output parameters.
Something like this
Update Bill
Set Paid = Total,
Status = 'Paid',
Output PAID_AMT = PAID_AMT - (Total-Paid )
where Total-Paid > PAID_AMT
The following query shows the amount owed, assuming SQL Server 2012:
select b.*,
sum(total - paid) over (order by id) as cumNotPaid
from bill b
You can now distribute the amount:
select b.*,
(case when cumNotPaid >= #AMOUNT then 0
when cumNotPaid - toBePaid <= #AMOUNT then toBePaid
else #AMOUNT - cumnotPaid
end) as PaidAmount
from (select b.*,
sum(total - paid) over (order by id) as cumNotPaid,
total - paid as ToBePaid
from bill b
) b
Now, this is an updatable CTE, so we can use this in an update statement:
with toupdate as (
(select b.*,
(case when cumNotPaid >= #AMOUNT then 0
when cumNotPaid - toBePaid <= #AMOUNT then toBePaid
else #AMOUNT - cumnotPaid
end) as PaidAmount
from (select b.*,
sum(total - paid) over (order by id) as cumNotPaid,
total - paid as ToBePaid
from bill b
) b
)
update toupdate
set paid = PaidAmount,
status = (case when total = paid then 'Paid' when total = 0 then 'UnPaid'
else 'PartPaid'
end);
I don't know what version of SQL server do you, if it 2008 then you could not use rolling sum with window function. You can try this recursive query:
declare #paid_amount int = 900
;with cte1 as (
select
b.id,
b.total - b.paid as diff,
row_number() over(order by id) as row_num
from Bill as b
where b.total <> b.paid
), cte2 as (
select
c1.id, c1.row_num, #paid_amount - c1.diff as paid_amount
from cte1 as c1
where c1.row_num = 1
union all
select
c1.id, c1.row_num, c2.paid_amount - c1.diff as paid_amount
from cte1 as c1
inner join cte2 as c2 on c2.row_num + 1 = c1.row_num
where c2.paid_amount > 0
)
update Bill set
Paid =
case
when c.paid_amount >= 0 then b.Total
else b.Total - b.Paid + c.paid_amount
end,
Status = case when c.paid_amount >= 0 then 'Paid' else 'Part Paid' end
from Bill as b
inner join cte2 as c on c.id = b.id
sql fiddle demo
for SQL server 2012 it's a bit easier:
declare #paid_amount int = 900
;with cte1 as (
select
b.id,
b.total - b.paid as amount_to_pay,
sum(b.total - b.paid) over(order by b.id) as amount
from Bill as b
where b.total <> b.paid
), cte2 as (
select
c.id,
#paid_amount - c.amount as remain_amount
from cte1 as c
where #paid_amount - c.amount + c.amount_to_pay >= 0
)
update Bill set
Paid =
case
when c.remain_amount >= 0 then b.Total
else b.Total - b.Paid + c.remain_amount
end,
Status = case when c.remain_amount >= 0 then 'Paid' else 'Part Paid' end
from Bill as b
inner join cte2 as c on c.id = b.id;
sql fiddle demo
If you are using SQL 2012 you can use the following:
DECLARE #PayAmount INT = 900;
WITH Dues AS
(
SELECT *, Total-Paid AS Due
FROM Bill
)
, Cumulative AS
(
SELECT *, SUM(Due) OVER (ORDER BY Id) AS CumulativeTotalDue
FROM Dues
)
, Payable AS
(
SELECT *, #PayAmount - CumulativeTotalDue AS AmountLeftAfterPaying
FROM Cumulative
)
, BillWithAmountToApplyRaw AS
(
SELECT *
, CASE
WHEN AmountLeftAfterPaying >= 0 THEN Due
ELSE Due + AmountLeftAfterPaying
END AS RawAmountToApply
FROM Payable
)
, BillWithAmountToApply AS
(
SELECT *, CASE WHEN RawAmountToApply < 0 THEN 0 ELSE RawAmountToApply END AS AmountToApply
FROM BillWithAmountToApplyRaw
)
That will give you the amount to apply in the AmountToApply column.
So you can use the above as
UPDATE BillWithAmountToApply
SET Paid = Paid + AmountToApply
FROM BillWithAmountToApply
(Use
SELECT *
FROM BillWithAmountToApply
to check it out first if you want)
SQL 2008 Version (less efficient because of the repeated joins, which aren't necessary in 2012):
WITH Dues AS
(
SELECT *, Total-Paid AS Due
FROM Bill
)
, CumulativeDue AS
(
SELECT base.Id, SUM(cumulative.Due) AS CumulativeTotalDue
FROM Dues base
JOIN Dues cumulative ON cumulative.Id <= base.Id
GROUP BY base.Id
)
, Cumulative AS
(
SELECT Dues.*, CumulativeDue.CumulativeTotalDue
FROM Dues
JOIN CumulativeDue ON CumulativeDue.Id = Dues.Id
)
... as above
Schema objects:
--BEGIN TRAN;
--CREATE TABLE Bill
--(
-- ID Int PRIMARY KEY IDENTITY,
-- Total INT NOT NULL,
-- Paid INT NOT NULL DEFAULT(0),
-- Status AS
-- CASE
-- WHEN Paid = Total THEN 'Paid'
-- WHEN Paid = 0 THEN 'Unpaid'
-- ELSE 'Part Paid'
-- END
--);
--WITH KnownValues(Total, Paid) AS
--(
-- SELECT 1000, 1000
-- UNION ALL SELECT 500, 400
-- UNION ALL SELECT 700, 0
-- UNION ALL SELECT 200, 0
--)
--INSERT INTO Bill(Total, Paid)
--SELECT *
--FROM KnownValues;
--COMMIT