Sorting comma delimited datasets in row - sql

Question

This is what is given
Numbers Powers
4,5,1 WATER,FIRE
6,3,9 ICE,WATER,FIRE
My requirement is (sorted order)
Numbers Powers
1,4,5 FIRE,WATER
3,6,9 FIRE,ICE,WATER .
I want it in sorted order! How to do it in database?

Answer 1

Split column to rows, then aggregate them back, sorted.
SQL> with test (id, num, pow) as
2 (select 1, '4,5,1', 'water,fire' from dual union all
3 select 2, '6,3,9', 'ice,water,fire' from dual
4 ),
5 temp as
6 -- split columns to rows
7 (select id,
8 regexp_substr(num, '[^,]+', 1, column_value) num1,
9 regexp_substr(pow, '[^,]+', 1, column_value) pow1
10 from test join table(cast(multiset(select level from dual
11 connect by level <= regexp_count(num, ',') + 1
12 ) as sys.odcinumberlist)) on 1 = 1
13 )
14 -- aggregate them back, sorted
15 select id,
16 listagg(num1, ',') within group (order by to_number(num1)) num_result,
17 listagg(pow1, ',') within group (order by pow1) pow_result
18 from temp
19 group by id;
ID NUM_RESULT POW_RESULT
---------- ------------------------------ ------------------------------
1 1,4,5 fire,water
2 3,6,9 fire,ice,water
SQL>

Answer 2

Oracle Setup:
CREATE TABLE test_data ( Numbers, Powers ) AS
SELECT '4,5,1', 'WATER,FIRE' FROM DUAL UNION ALL
SELECT '6,3,9', 'ICE,WATER,FIRE' FROM DUAL UNION ALL
SELECT '7', 'D,B,E,C,A' FROM DUAL
Query:
SELECT (
SELECT LISTAGG( TO_NUMBER( REGEXP_SUBSTR( t.numbers, '\d+', 1, LEVEL ) ), ',' )
WITHIN GROUP ( ORDER BY TO_NUMBER( REGEXP_SUBSTR( t.numbers, '\d+', 1, LEVEL ) ) )
FROM DUAL
CONNECT BY LEVEL <= REGEXP_COUNT( t.numbers, ',' ) + 1
) AS numbers,
(
SELECT LISTAGG( REGEXP_SUBSTR( t.powers, '[^,]+', 1, LEVEL ), ',' )
WITHIN GROUP ( ORDER BY REGEXP_SUBSTR( t.powers, '[^,]+', 1, LEVEL ) )
FROM DUAL
CONNECT BY LEVEL <= REGEXP_COUNT( t.powers, ',' ) + 1
) AS numbers
FROM test_data t
Output:
NUMBERS | NUMBERS
:------ | :-------------
1,4,5 | FIRE,WATER
3,6,9 | FIRE,ICE,WATER
7 | A,B,C,D,E
db<>fiddle here

Answer 3

You can try the following:
I have used the table as I will need some value to get a distinct value. here I have used ROWID.
SELECT
ID,
LISTAGG(NUM, ',') WITHIN GROUP(
ORDER BY
NUM
) AS NUM,
LISTAGG(POW, ',') WITHIN GROUP(
ORDER BY
POW
) AS POW
FROM
(
SELECT
DISTINCT ROWID,
ID,
REGEXP_SUBSTR(NUM, '[^,]+', 1, LEVEL) NUM,
REGEXP_SUBSTR(POW, '[^,]+', 1, LEVEL) POW
FROM
TEST
CONNECT BY REGEXP_SUBSTR(NUM, '[^,]+', 1, LEVEL) IS NOT NULL
OR REGEXP_SUBSTR(POW, '[^,]+', 1, LEVEL) IS NOT NULL
)
GROUP BY ID
ORDER BY ID;
db<>fiddle demo
Cheers!!
----
UPDATE
----
As mentioned in a comment that it is generating duplicates, I have re-framed the whole query as following:
SELECT
ID,
LISTAGG(C_S.NUM, ',') WITHIN GROUP(
ORDER BY
C_S.NUM
) AS NUM,
LISTAGG(C_S.POW, ',') WITHIN GROUP(
ORDER BY
C_S.POW
) AS POW
FROM
(SELECT
T.ID,
REGEXP_SUBSTR(T.NUM, '[^,]+', 1, NUMS_COMMA.COLUMN_VALUE) NUM,
REGEXP_SUBSTR(T.POW, '[^,]+', 1, NUMS_COMMA.COLUMN_VALUE) POW
FROM
TEST T,
TABLE ( CAST(MULTISET(
SELECT
LEVEL
FROM
DUAL
CONNECT BY
LEVEL <= GREATEST(LENGTH(REGEXP_REPLACE(T.NUM, '[^,]+')),
LENGTH(REGEXP_REPLACE(T.POW, '[^,]+'))) + 1
) AS SYS.ODCINUMBERLIST) ) NUMS_COMMA) C_S
GROUP BY ID;
db<>fiddle demo updated
Cheers!!