i have sql query like this,
SELECT CAST(SUM(`op_total`) AS int) as total
FROM `dashboard_sales`
WHERE `op_status` IN ('settlement', 'capture') AND
`order_date` between '2018-01-01' and '2019-06-30' AND
`order_status` IN ('Ordered', 'Validated','Awaiting Packing','Packing Process','Ready to Ship','Shipped','Completed')
and this is the result,
first image:
but because there is duplication of data in some order_id so the results are bigger than the original
and i have make another query using group by like this,
SELECT CAST(SUM(`op_total`) AS int) as total
FROM `dashboard_sales`
WHERE
`op_status` IN ('settlement', 'capture')
AND `order_date` between '2018-01-01' and '2019-06-30'
AND `order_status` IN ('Ordered', 'Validated','Awaiting Packing','Packing Process','Ready to Ship','Shipped','Completed')
GROUP BY `order_id`
but the result is like this,
second image:
how to make like first image when i use group by?
use a subquery on top of your query
select sum(total) as total
from
(
SELECT CAST(SUM(op_total) AS int) as total
FROM dashboard_sales
WHERE op_status IN ('settlement', 'capture')
AND order_date between '2018-01-01' and '2019-06-30'
AND order_status IN ('Ordered', 'Validated','Awaiting Packing','Packing Process','Ready to Ship','Shipped','Completed')
GROUP BY order_id
)A
Related
I have the following problem.
Part of a task is to determine the visitor(s) with the most money spent between 2000 and 2020.
It just looks like this.
SELECT UserEMail FROM Visitor
JOIN Ticket ON Visitor.UserEMail = Ticket.VisitorUserEMail
where Ticket.Date> date('2000-01-01') AND Ticket.Date < date ('2020-12-31')
Group by Ticket.VisitorUserEMail
order by SUM(Price) DESC;
Is it possible to output more than one person if both have spent the same amount?
Use rank():
SELECT VisitorUserEMail
FROM (SELECT VisitorUserEMail, SUM(PRICE) as sum_price,
RANK() OVER (ORDER BY SUM(Price) DESC) as seqnum
FROM Ticket t
WHERE t.Date >= date('2000-01-01') AND Ticket.Date <= date('2021-01-01')
GROUP BY t.VisitorUserEMail
) t
WHERE seqnum = 1;
Note: You don't need the JOIN, assuming that ticket buyers are actually visitors. If that assumption is not true, then use the JOIN.
Use a CTE that returns all the total prices for each email and with NOT EXISTS select the rows with the top total price:
WITH cte AS (
SELECT VisitorUserEMail, SUM(Price) SumPrice
FROM Ticket
WHERE Date >= '2000-01-01' AND Date <= '2020-12-31'
GROUP BY VisitorUserEMail
)
SELECT c.VisitorUserEMail
FROM cte c
WHERE NOT EXISTS (
SELECT 1 FROM cte
WHERE SumPrice > c.SumPrice
)
or:
WITH cte AS (
SELECT VisitorUserEMail, SUM(Price) SumPrice
FROM Ticket
WHERE Date >= '2000-01-01' AND Date <= '2020-12-31'
GROUP BY VisitorUserEMail
)
SELECT VisitorUserEMail
FROM cte
WHERE SumPrice = (SELECT MAX(SumPrice) FROM cte)
Note that you don't need the function date() because the result of date('2000-01-01') is '2000-01-01'.
Also I think that the conditions in the WHERE clause should include the =, right?
I posted a question similar to this, and got an answer, but the answer isn't configurable - my fault I should have been more clear, so I'll try again.
I have a table where TABLENAME has the following information - OrderDate, OrderNumber, CustomerID, ProductSKU, ProductName exist. This table has lines for invoices. So an order will have a data line for every item in the order.
I want to know, which customers have ordered the same item, more than once, where the order is within 90 of any other order of that same product by that customer, after a specific date. Same product in the same order number do not count. The catch is that I want "more than once" to be configurable, so if I need to see 3 or more, or 4 or more I can adjust AND I want to see the counts. Here's the query I have so far, which I think gives me the items and the counts - but not the 90 day thing:
EDITED: I don't think the former version gave me the right counts
SELECT customerid, productsku, productname, count(distinct ordernumber) FROM tablename
WHERE orderdate >'2017-11-01'
GROUP BY customerid, productsku, productname
HAVING COUNT(distinct ordernumber) > 2
Try doing this. it'll go back 90 days
declare #date date = '2017-11-01'
SELECT customerid, productsku, productname, count(distinct ordernumber) FROM tablename
WHERE orderdate >= dateadd(DD,-90,#date) and orderdate <= #date
GROUP BY customerid, productsku, productname
HAVING COUNT(distinct ordernumber) > 1
yes that is what I was doing in the first query. so this might be a really crappy way of doing it but without seeing any data it was kind of tough. this query shows gives you the order dates as well. hope it helps
WITH DupsWithin90Days (customerid,productsku,productname,orderdate,num)
as
(
select customerid,productsku,productname,orderdate ,count(*) num from (
SELECT X.customerid, X.productsku, X.productname,X.ORDERDATE,ROW_NUMBER() OVER (partition by x.customerid,x.orderdate order by x.orderdate) rownum
FROM
(
SELECT T1.customerid, T1.productsku, T1.productname,T1.ORDERDATE
FROM TABLENAME1 T1
) X
JOIN
(
SELECT T2.customerid, T2.productsku, T2.productname,T2.ORDERDATE
FROM
TABLENAME1 T2
) Y
ON X.customerid = Y.customerid AND X.orderdate >= dateadd(DD,-90,Y.orderdate)
) dup
where rownum > 1
group by customerid,productsku,productname,orderdate
)
select customerid,productsku,productname,orderdate
from DupsWithin90Days
order by customerid ,orderdate desc
I'm trying to sum a certain column over a certain date range. The kicker is that I want this to be a CTE, because I'll have to use it multiple times as part of a larger query. Since it's a CTE, it has to have the date column as well as the sum and ID columns, meaning I have to group by date AND ID. That will cause my results to be grouped by ID and date, giving me not a single sum over the date range, but a bunch of sums, one for each day.
To make it simple, say we have:
create table orders (
id int primary key,
itemID int foreign key references items.id,
datePlaced datetime,
salesRep int foreign key references salesReps.id,
price int,
amountShipped int);
Now, we want to get the total money a given sales rep made during a fiscal year, broken down by item. That is, ignoring the fiscal year bit:
select itemName, sum(price) as totalSales, sum(totalShipped) as totalShipped
from orders
join items on items.id = orders.itemID
where orders.salesRep = '1234'
group by itemName
Simple enough. But when you add anything else, even the price, the query spits out way more rows than you wanted.
select itemName, price, sum(price) as totalSales, sum(totalShipped) as totalShipped
from orders
join items on items.id = orders.itemID
where orders.salesRep = '1234'
group by itemName, price
Now, each group is (name, price) instead of just (name). This is kind of sudocode, but in my database, just this change causes my result set to jump from 13 to 32 rows. Add to that the date range, and you really have a problem:
select itemName, price, sum(price) as totalSales, sum(totalShipped) as totalShipped
from orders
join items on items.id = orders.itemID
where orders.salesRep = '1234'
and orderDate between 150101 and 151231
group by itemName, price
This is identical to the last example. The trouble is making it a CTE:
with totals as (
select itemName, price, sum(price) as totalSales, sum(totalShipped) as totalShipped, orderDate as startDate, orderDate as endDate
from orders
join items on items.id = orders.itemID
where orders.salesRep = '1234'
and orderDate between startDate and endDate
group by itemName, price, startDate, endDate
)
select totals_2015.itemName as itemName_2015, totals_2015.price as price_2015, ...
totals_2016.itemName as itemName_2016, ...
from (
select * from totals
where startDate = 150101 and endDate = 151231
) totals_2015
join (
select *
from totals
where startDate = 160101 and endDate = 160412
) totals_2016
on totals_2015.itemName = totals_2016.itemName
Now the grouping in the CTE is way off, more than adding the price made it. I've thought about breaking the price query into its own subquery inside the CTE, but I can't escape needing to group by the dates in order to get the date range. Can anyone see a way around this? I hope I've made things clear enough. This is running against an IBM iSeries machine. Thank you!
Depending on what you are looking for, this might be a better approach:
select 'by sales rep' breakdown
, salesRep
, '' year
, sum(price * amountShipped) amount
from etc
group by salesRep
union
select 'by sales rep and year' breakdown
, salesRep
, convert(char(4),orderDate, 120) year
, sum(price * amountShipped) amount
from etc
group by salesRep, convert(char(4),orderDate, 120)
etc
When possible group by the id columns or foreign keys because the columns are indexed already you'll get faster results. This applies to any database.
with cte as (
select id,rep, sum(sales) sls, count(distinct itemid) did, count(*) cnt from sommewhere
where date between x and y
group by id,rep
) select * from cte order by rep
or more fancy
with cte as (
select id,rep, sum(sales) sls, count(distinct itemid) did, count(*) cnt from sommewhere
where date between x and y
group by id,rep
) select * from cte join reps on cte.rep = reps.rep order by sls desc
I eventually found a solution, and it doesn't need a CTE at all. I wanted the CTE to avoid code duplication, but this works almost as well. Here's a thread explaining summing conditionally that does exactly what I was looking for.
Query :
How to sort by months ?
select format(datee,'mmm-yyyy') as [Months],sum(amount) as Amount
from ledger_broker
where ref_from like 'Purchase'
group by format(datee,'mmm-yyyy')
order by format(datee,'mmm-yyyy') desc
Output :
Try grouping by the same exact column which you select:
SELECT t.[Months], t.Amount
FROM
(
SELECT MONTH(datee) AS theMonth, YEAR(datee) AS theYear,
FORMAT(datee,'mmm-yyyy') AS [Months], SUM(amount) AS Amount
FROM ledger_transporter
WHERE ref_from LIKE 'Purchase'
GROUP BY MONTH(datee), YEAR(datee), FORMAT(datee, 'mmm-yyyy')
) t
ORDER BY t.theYear DESC, t.theMonth DESC
One way to order by date is to select the numeric month and year in your query.
change group by datee to group by format(datee,'mmm-yyyy').
select distinct format(datee,'mmm-yyyy') as [Months], sum(amount) as Amount
from ledger_transporter
where ref_from like 'Purchase'
group by format(datee,'mmm-yyyy')
order by Month(datee)
The reason is that your date, which I assume is say 01-FEB-2016 and 02-FEB-2016, is different and if you group by it, you will get 2 different records for it.
However, for format(datee,'mmm-yyyy'), ie FEB-2016, both of these dates are same. Hence the mismatch
I have the following code:
SELECT
day
,product_id
,product_name
,quantity_on_hand
,inventory_condition
FROM
(
SELECT
table1.product_id as product_id
,table1.product_name as product_name
FROM table1
WHERE
product_id = XXXX
)product_table
,
(
SELECT
table2.day as day
,table2.product_id as inv_product_id
,inventory_condition
,sum( table2.quantity) AS quantity_on_hand
FROM table2
WHERE
table2.day = TO_DATE('{RUN_DATE_YYYY/MM/DD}', 'YYYY/MM/DD')
AND table2.inventory_condition = XXX
GROUP BY
table2.day
,table2.product_id
,inventory_conditio
) inv
WHERE
product_id = inv.product_id
this code works great if I want to extract the data for a single day. But I want to extract the data for 3 different days in the same query. I've tried to use a OR() on my condition on table2.day but it will give me the sum of the data for the 3 days all together. I've also tried to do
Sum() over (Partition by table2.day)
But i'm not sure how to use the syntax.
tahks a lot for your help