I am trying to write a query that will give me transaction amount sum happened in one date. The problem is , when I added column date in my query, I get individual values not their sum. The requirement for this query is to have one entry for each merchant but i am getting multiple rows for one merchant.
SELECT SUBSTR(m.MERCHANTLASTNAME, 1, 36) Name1,
m.MERCHANTBANKBSB MerchantAccbsb,
m.MERCHANTBANKACCNR Merchant_act,
m.MERCHANTID merchantid,
t.transactiondate date1,
sum(t.TRANSACTIONAMOUNT) as total
FROM fss_merchant m
JOIN fss_terminal term
ON m.MERCHANTID = term.MERCHANTID
JOIN FSS_DAILY_TRANSACTION t
ON term.TERMINALID = t.TERMINALID
group by t.transactiondate, SUBSTR(m.MERCHANTLASTNAME, 1, 36), m.MERCHANTID, m.MERCHANTBANKBSB, m.MERCHANTBANKACCNR,
m.MERCHANTLASTNAME
Output of my query:
I want to get one entry per each merchant with the sum of transaction amount in one day, not multiple rows of transaction in that day.
You can calculate the total amount in different inner query with the truncated date and join it with FSS_MERCHANT table so that issues described by #SatishSK and #mangusta is taken care.
You can use the following query:
SELECT
SUBSTR(M.MERCHANTLASTNAME, 1, 36) NAME1,
M.MERCHANTBANKBSB MERCHANTACCBSB,
M.MERCHANTBANKACCNR MERCHANT_ACT,
M.MERCHANTID MERCHANTID,
M_DATA.TRANSACTIONDATE DATE1,
M_DATA.TOTAL AS TOTAL
FROM
FSS_MERCHANT M
INNER JOIN (
SELECT
TERM.MERCHANTID MERCHANTID,
TRUNC(T.TRANSACTIONDATE) TRANSACTIONDATE,
SUM(T.TRANSACTIONAMOUNT) AS TOTAL
FROM
FSS_TERMINAL TERM
JOIN FSS_DAILY_TRANSACTION T ON TERM.TERMINALID = T.TERMINALID
GROUP BY
TERM.MERCHANTID,
TRUNC(T.TRANSACTIONDATE)
) M_DATA ON ( M.MERCHANTID = M_DATA.MERCHANTID );
Good luck!!
t.transactiondate column might contain date+time values. Use TRUNC(t.transactiondate) where you are using just t.transactiondate. You will get sum(transaction amount) "Date-wise" for each merchant.
OR
Filter out rows based on "Date" value in WHERE clause to retrieve data pertaining to a specific date.
Probably the reason is that you have included both m.MERCHANTLASTNAME and SUBSTR(m.MERCHANTLASTNAME,1,36) into the group by clause.
In case if there are entries with same SUBSTR(m.MERCHANTLASTNAME,1,36) but different m.MERCHANTLASTNAME, this is going to yield duplicates. You need to remove m.MERCHANTLASTNAME from group by clause
Related
I have run into an issue I don't know how to solve. I'm working with a MS Access DB.
I have this data:
I want to write a SELECT statement, that gives the following result:
For each combination of Project and Invoice, I want to return the record containing the maximum date, conditional on all records for that combination of Project and Invoice being Signed (i.e. Signed or Date column not empty).
In my head, first I would sort the irrelevant records out, and then return the max date for the remaining records. I'm stuck on the first part.
Could anyone point me in the right direction?
Thanks,
Hulu
Start with an initial query which fetches the combinations of Project, Invoice, Date from the rows you want returned by your final query.
SELECT
y0.Project,
y0.Invoice,
Max(y0.Date) AS MaxOfDate
FROM YourTable AS y0
GROUP BY y0.Project, y0.Invoice
HAVING Sum(IIf(y0.Signed Is Null,1,0))=0;
The HAVING clause discards any Project/Invoice groups which include a row with a Null in the Signed column.
If you save that query as qryTargetRows, you can then join it back to your original table to select the matching rows.
SELECT
y1.Project,
y1.Invoice,
y1.Desc,
y1.Value,
y1.Signed,
y1.Date
FROM
YourTable AS y1
INNER JOIN qryTargetRows AS sub
ON (y1.Project = sub.Project)
AND (y1.Invoice = sub.Invoice)
AND (y1.Date = sub.MaxOfDate);
Or you can do it without the saved query by directly including its SQL as a subquery.
SELECT
y1.Project,
y1.Invoice,
y1.Desc,
y1.Value,
y1.Signed,
y1.Date
FROM
YourTable AS y1
INNER JOIN
(
SELECT y0.Project, y0.Invoice, Max(y0.Date) AS MaxOfDate
FROM YourTable AS y0
GROUP BY y0.Project, y0.Invoice
HAVING Sum(IIf(y0.Signed Is Null,1,0))=0
) AS sub
ON (y1.Project = sub.Project)
AND (y1.Invoice = sub.Invoice)
AND (y1.Date = sub.MaxOfDate);
Write A SQL query, which should be possible in MS-Access too, like this:
SELECT
Project,
Invoice,
MIN([Desc]) Descriptions,
SUM(Value) Value,
MIN(Signed) Signed,
MAX([Date]) "Date"
FROM data
WHERE Signed<>'' AND [Date]<>''
GROUP BY
Project,
Invoice
output:
Project
Invoice
Descriptions
Value
Signed
Date
A
1
Ball
100
J.D.
2022-09-20
B
1
Sofa
300
J.D.
2022-09-22
B
2
Desk
100
J.D.
2022-09-23
Note: for invoice 1 on project A, you will see a value of 300, which is the total for that invoice (when grouping on Project='A' and Invoice=1).
Maybe I should have used DCONCAT (see: Concatenation in between records in Access Query ) for the Description, to include 'TV' in it. But I am unable to test that so I am only referring to this answer.
Try joining a second query:
Select *
From YourTable As T
Inner Join
(Select Project, Invoice, Max([Date]) As MaxDate
From YourTable
Group By Project, Invoice) As S
On T.Project = S.Project And T.Invoice = S.Invoice And T.Date = S.MaxDate
I am trying to subquery and aggregate in SQL after doing an initial query with multiple joins. My ultimate goal is to get a count (or a sum) of specimens tested based on a grouping of multiple columns. This is slightly different from SQL Server query - Selecting COUNT(*) with DISTINCT and SQL Server: aggregate error on grouping.
The three tables that I use (PERSON, SPECIMEN, TEST), have 1-many relationships. So PERSON has many SPECIMENS and those SPECIMENS have many TESTS. I did three inner joins to combine these tables plus an additional table (ANALYSIS).
WITH TALLY as (
SELECT PERSON.NAME, PERSON.PHASE, TEST.DATE_STARTED, TEST.ANALYSIS, SPECIMEN.GROUP, TEST.STATUS,
ANALYSIS.ANALYSIS_TYPE, SPECIMEN.SPECIMEN_NUMBER
FROM DB.TEST
INNER JOIN
DB.SAMPLE ON
TEST.SPECIMEN_NUMBER = SPECIMEN.SPECIMEN_NUMBER
INNER JOIN
DB.PRODUCT ON
SPECIMEN.PERSON = PERSON.NAME
INNER JOIN
DB.ANALYSIS ON
TEST.ANALYSIS = ANALYSIS.NAME
WHERE PERSON.NAME = 'Joe'
AND TEST.DATE_STARTED >= '20-DEC-16' AND TEST.DATE_STARTED <='01-APR-18'
AND PERSON.PHASE = 'PHASE1'
ORDER BY TEST.DATE_STARTED)
SELECT COUNT(DISTINCT ANALYSIS) as SPECIMEN_COUNT, DATE_STARTED, ANALYSIS, STATUS, GROUP, ANALYSIS_TYPE
FROM TALLY
GROUP BY DATE_STARTED, ANALYSIS, STATUS, GROUP, ANALYSIS_TYPE
ORDER BY DATE_STARTED;
This gives me the repeated columns: first grouping repeated 4 times
What I am trying to see is: aggregated first grouping with total count
Any thoughts as to what is missing? SUM instead of COUNT or in addition to COUNT creates an error. Thanks in advance!
9/17/2020 Update: I have tried adding a subquery because I also need to use a new column of metadata (ANALYSIS_TYPE_ALIAS) which is created in the first query through a CASE STATEMENT(...). I have also tried using another subquery with inner join to count based on those conditions to a temp table, but still cannot seem to aggregate to flatten the table. Here is my current attempt:
WITH TALLY as (
SELECT PERSON.NAME, PERSON.PHASE, TEST.DATE_STARTED, TEST.ANALYSIS, SPECIMEN.GROUP, TEST.STATUS,
ANALYSIS.ANALYSIS_TYPE...
FROM DB.TEST
INNER JOIN
DB.SAMPLE ON
TEST.SPECIMEN_NUMBER = SPECIMEN.SPECIMEN_NUMBER
INNER JOIN
DB.PRODUCT ON
SPECIMEN.PERSON = PERSON.NAME
INNER JOIN
DB.ANALYSIS ON
TEST.ANALYSIS = ANALYSIS.NAME
WHERE PERSON.NAME = 'Joe'
AND TEST.DATE_STARTED >= '20-DEC-16' AND TEST.DATE_STARTED <='01-APR-18'
AND PERSON.PHASE = 'PHASE1'
ORDER BY TEST.DATE_STARTED),
SUMMARY_COMBO AS (SELECT DISTINCT(CONCAT(CONCAT(CONCAT(CONCAT(ANALYSIS, DATE_STARTED),STATUS), GROUP), ANALYSIS_TYPE_ALIAS))AS UUID,
TALLY.NAME, TALLY.PHASE, TALLY.DATE_STARTED, TALLY.ANALYSIS, TALLY.GROUP, TALLY.STATUS, TALLY.ANALYSIS_TYPE_ALIAS
FROM TALLY)
SELECT SUMMARY_COMBO.NAME, SUMMARY_COMBO.PHASE, SUMMARY_COMBO.DATE_STARTED, SUMMARY_COMBO.ANALYSIS,SUMMARY_COMBO.GROUP, SUMMARY_COMBO.STATUS, SUMMARY_COMBO.ANALYSIS_TYPE_ALIAS,
COUNT(SUMMARY_COMBO.ANALYSIS) OVER (PARTITION BY SUMMARY_COMBO.UUID) AS SPECIMEN_COUNT
FROM SUMMARY_COMBO
ORDER BY SUMMARY_COMBO.DATE_STARTED;
This gave me the following table Shows aggregated counts, but doesn't aggregate based on unique UUID. Is there a way to take the sum of the count? I've tried to do this by storing count to a subquery and then referencing that count variable, but I am missing something in how to group the 8 columns of data that I want to show + the count of that combination of columns.
Thanks!
Just remove analysis from the group by clause, since that's the column whose distinct values you want to count. Otherwise, the query generates more groups than what you need (and the count of distinct analysis values in each group is always 1).
WITH TALLY as ( ...)
SELECT COUNT(DISTINCT ANALYSIS) as SPECIMEN_COUNT, DATE_STARTED, ANALYSIS, STATUS, GROUP, ANALYSIS_TYPE
FROM TALLY
GROUP BY DATE_STARTED, STATUS, GROUP, ANALYSIS_TYPE
ORDER BY DATE_STARTED;
I have at least 8 tables from where I need to match the customer name and fetch the quantities and get the sum of all the quantities fetched from these 8 tables. I am trying to write a code which will ignore the customer whose sum of quantities is zero.
For an example lets take two tables purchase_sugar and sales_sugar I have tried a lot of queries but only this one is returning some result which is wrong.
SELECT sum(purchase_sugar.qty + sales_sugar.qty) AS Total_Amount from purchase_sugar inner join sales_sugar on purchase_sugar.supplier = sales_sugar.customer WHERE purchase_sugar.supplier = "+str(x.id)+"
The Table structures are like:
purchase_sugar have two columns supplier and qty.
And sales_sugar have structure like customer and qty.
How can I get the SUM of QUANTITIES of these tables if I provide one name and search it through these tables and get the quantities. The other thing is that I dont want the customer to be found in all the tables. If it is found in one table we should just get the quantity from that one table and for that reason I don't think that JOIN is useful or may be i am wrong.
To take care of the situation where a supplier/customer is not in all the tables, you can use union all and group by:
select name, sum(p_qty) as sum_p, sum(s_qty) as sum_s,
sum(p_qty) + sum(s_qty)
from ((select ps.supplier as name, ps.qty as p_qty, 0 as s_qty
from purchase_sugar ps
) union all
(select ss.customer as name, 0, ss.qty
from sales_sugar ss
)
) s
group by name;
Notes:
This query gets results for all names. You can use a where clause to restrict the results to one name.
You don't have to split the quantities into two (or eight) different columns, if you just want the overall sum.
You can aggregate before the union all, but that is not necessary.
you should JOIN the sum and not sum the join
select t1.purchase_sum + sales_sum as Total_Amount
from (
select purchase_sugar.supplier, sum(purchase_sugar.qty) as purchase_sum
from purchase_sugar
group by purchase_sugar.supplier
) t1
inner join (
select sales_sugar.customer, sum(sales_sugar.qty) as sales_sum
from sales_sugar
group by sales_sugar.customer
) t2 on t1.supplier = t2.customer and t1.supplier = "+str(x.id)+"
Struggling to go the extra step with a SQL query I'd like to run.
I have a customer database with a Customer table with the date/time detail of when the customer joined and a transaction table with details of their transactions of the years
What I'd like to do is to Group by the Join Date (as Year) and count the number that joined in each year then in the next column I'd like to then count the number who have transacted in a specific year E.g. 2016 the current year. This way I can show customer retention over the years.
Both tables are linked by a customer URN, but I am struggling to get my head around the the most efficient way to show this. I can easily count and group the members by joined year and I can display the max dated transaction but I am struggling to bring the two together. I think I need to use sub queries and a left join but it's alluding me.
Example output column headers with data
Year_Joined = 2009
Joiner_Count = 10
Transact_in_2016 = 5
Where I am syntax-wise. I know this is no where near complete. As I need to group by DateJoined and then sub query the count of customers of have transacted in 2016?
SELECT Customer.URNCustomer,
MAX(YEAR(Customer.DateJoined)),
MAX(YEAR(Tran.TranDate)) As Latest_Tran,
FROM Mydatabase.dbo.Customer
LEFT JOIN Mydatabase.dbo.Tran
ON Tran.URNCustomer = Customer.URNCustomer
GROUP BY Customer.URNCustomer
ORDER BY Customer.URNCustomer
The best approach is to do the aggregation before doing the joins. You want to count two different things, so count them individually and them combine them.
The following uses full outer join. This handles the case where there are years with no new customers and years with no transactions:
select coalesce(c.yyyy, t.yyyy) as yyyy,
coalesce(c.numcustomers, 0) as numcustomers,
coalesce(t.numtransactions, 0) as numtransactions
from (select year(c.datejoined) as yyyy, count(*) as numcustomers
from Mydatabase.dbo.Customer c
group by year(c.datejoined)
) c full outer join
(select year(t.trandate) as yyyy, count(*) as numtransactions
from database.dbo.Tran t
group by year(t.trandate)
) t
on c.yyyy = t.yyyy;
You may want to try something like this:
SELECT YEAR(Customer.DateJoined),
COUNT( Customer.URNCustomer ),
COUNT( DISTINCT Tran.URNCustomer ) AS NO_ACTIVE_IN_2016
FROM Mydatabase.dbo.Customer
LEFT Mydatabase.dbo.Tran
ON Tran.URNCustomer = Customer.URNCustomer
AND YEAR(Tran.TranDate) = 2016
GROUP BY YEAR(Customer.DateJoined)
Hi guys, I am stuck with a stubborn problem which I am unable to solve. Am trying to compile a report wherein all the dates coming from different tables would need to come into a single date field in the report. Ofcourse, the max or the most recent date from all these date columns needs to be added to the single date column for the report. I have multiple users of multiple branches/courses for whom the report would be generated.
There are multiple blogs and the latest date w.r.t to the blogtitle needs to be grouped, i.e. max(date_value) from the six date columns should give the greatest or latest date for that blogtitle.
Expected Result:
select u.batch_uid as ext_person_key, u.user_id, cm.batch_uid as ext_crs_key, cm.crs_id, ir.role_id as
insti_role, (CASE when b.JOURNAL_IND = 'N' then
'BLOG' else 'JOURNAL' end) as item_type, gm.title as item_name, gm.disp_title as ITEM_DISP_NAME, be.blog_pk1 as be_blogPk1, bc.blog_entry_pk1 as bc_blog_entry_pk1,bc.pk1,
b.ENTRY_mod_DATE as b_ENTRY_mod_DATE ,b.CMT_mod_DATE as BlogCmtModDate, be.CMT_mod_DATE as be_cmnt_mod_Date,
b.UPDATE_DATE as BlogUpDate, be.UPDATE_DATE as be_UPDATE_DATE,
bc.creation_date as bc_creation_date,
be.CREATOR_USER_ID as be_CREATOR_USER_ID , bc.creator_user_id as bc_creator_user_id,
b.TITLE as BlogTitle, be.TITLE as be_TITLE,
be.DESCRIPTION as be_DESCRIPTION, bc.DESCRIPTION as bc_DESCRIPTION
FROM users u
INNER JOIN insti_roles ir on u.insti_roles_pk1 = ir.pk1
INNER JOIN crs_users cu ON u.pk1 = cu.users_pk1
INNER JOIN crs_mast cm on cu.crsmast_pk1 = cm.pk1
INNER JOIN blogs b on b.crsmast_pk1 = cm.pk1
INNER JOIN blog_entry be on b.pk1=be.blog_pk1 AND be.creator_user_id = cu.pk1
LEFT JOIN blog_CMT bc on be.pk1=bc.blog_entry_pk1 and bc.CREATOR_USER_ID=cu.pk1
JOIN gradeledger_mast gm ON gm.crsmast_pk1 = cm.pk1 and b.grade_handler = gm.linkId
WHERE cu.ROLE='S' AND BE.STATUS='2' AND B.ALLOW_GRADING='Y' AND u.row_status='0'
AND u.available_ind ='Y' and cm.row_status='0' and and u.batch_uid='userA_157'
I am getting a resultset for the above query with multiple date columns which I want > > to input into a single columnn. The dates have to be the most recent, i.e. max of the dates in the date columns.
I have successfully done the Unpivot by using a view to store the above
resultset and put all the dates in one column. However, I do not
want to use a view or a table to store the resultset and then do
Unipivot simply because I cannot keep creating views for every user
one would query for.
The max(date_value) from the date columns need to be put in one single column. They are as follows:
* 1) b.entry_mod_date, 2) b.cmt_mod_date ,3) be.cmt_mod_date , 4) b.update_Date ,5) be.update_date, 6) bc.creation_date *
Apologies that I could not provide the desc of all the tables and the
fields being used.
Any help to get the above mentioned max of the dates from these
multiple date columns into a single column without using a view or a
table would be greatly appreciated.*
It is not clear what results you want, but the easiest solution is to use greatest().
with t as (
YOURQUERYHERE
)
select t.*,
greatest(entry_mod_date, cmt_mod_date, cmt_mod_date, update_Date,
update_date, bc.creation_date
) as greatestdate
from t;
select <columns>,
case
when greatest (b_ENTRY_mod_DATE) >= greatest (BlogCmtModDate) and greatest(b_ENTRY_mod_DATE) >= greatest(BlogUpDate)
then greatest( b_ENTRY_mod_DATE )
--<same implementation to compare each time BlogCmtModDate and BlogUpDate separately to get the greatest then 'date'>
,<columns>
FROM table
<rest of the query>
UNION ALL
Select <columns>,
case
when greatest (be_cmnt_mod_Date) >= greatest (be_UPDATE_DATE)
then greatest( be_cmnt_mod_Date )
when greatest (be_UPDATE_DATE) >= greatest (be_cmnt_mod_Date)
then greatest( be_UPDATE_DATE )
,<columns>
FROM table
<rest of the query>
UNION ALL
Select <columns>,
GREATEST(bc_creation_date)
,<columns>
FROM table
<rest of the query>