I have following table named as 'Table',
Where I want result like following table where if you take first row and last three columns I want value to be 56.
I want sql server code for above table 'Table' and result to be second table. Here MaxV-1 and MaxV-2 are dependent on 'Number' column. MaxV-1 is max value out of FirstV, SecondV and ThirdV when Number is equal to 1 and same logic for MaxV-2.
One method is an unpivot and conditional aggreation:
select t.model,
max(case when t.number = 1 then t.pro_code end) as pro_code_1,
max(case when t.number = 2 then t.pro_code end) as pro_code_2,
max(case when t.number = 1 then v.v end) as max_val_1,
max(case when t.number = 2 then v.v end) as max_val_2
from t cross apply
(select max(v.v) as v
from (values (t.firstv), (t.secondv), (t.thirdv)) v(v)
) v
group by t.model;
Related
I am stuck with a specific scenario of flattening the data and need help for it. I need the output as flattened data where the column values are not fixed. Due to this I want to restrict the output to fixed set of columns.
Given Table 'test_table'
ID
Name
Property
1
C1
xxx
2
C2
xyz
2
C3
zz
The scenario is, column Name can have any no. of values corresponding to an ID. I need to flatten the data based in such a way that there is one row per ID field. Since the Name field varies with each ID, I want to flatten it for fix 3 columns like Co1, Co2, Co3. The output should look like
ID
Co1
Co1_Property
Co2
Co2_Property
Co3
Co3_Property
1
C1
xxx
null
null
2
C2
xyz
C3
zz
Could not think of a solution using Pivot or aggregation. Any help would be appreciated.
You can use arrays:
select id,
array_agg(name order by name)[safe_ordinal(1)] as name_1,
array_agg(property order by name)[safe_ordinal(1)] as property_1,
array_agg(name order by name)[safe_ordinal(2)] as name_2,
array_agg(property order by name)[safe_ordinal(2)] as property_2,
array_agg(name order by name)[safe_ordinal(3)] as name_3,
array_agg(property order by name)[safe_ordinal(3)] as property_3
from t
group by id;
All current answers are too verbose and involve heavy repetition of same fragments of code again and again and if you need to account more columns you need to copy paste and add more lines which will make it even more verbose!
My preference is to avoid such type of coding and rather use something more generic as in below example
select * from (
select *, row_number() over(partition by id) col
from `project.dataset.table`)
pivot (max(name) as name, max(property) as property for col in (1, 2, 3))
If applied to sample data in your question - output is
If you want to change number of output columns - you just simply modify for col in (1, 2, 3) part of query.
For example if you would wanted to have 5 columns - you would use for col in (1, 2, 3, 4, 5) - that simple!!!
The standard practice is to use conditional aggregation. That is, to use CASE expressions to pick which row goes to which column, then MAX() to collapse multiple rows into individual rows...
SELECT
id,
MAX(CASE WHEN name = 'C1' THEN name END) AS co1,
MAX(CASE WHEN name = 'C1' THEN property END) AS co1_property,
MAX(CASE WHEN name = 'C2' THEN name END) AS co2,
MAX(CASE WHEN name = 'C2' THEN property END) AS co2_property,
MAX(CASE WHEN name = 'C3' THEN name END) AS co3,
MAX(CASE WHEN name = 'C3' THEN property END) AS co3_property
FROM
yourTable
GROUP BY
id
Background info:
Not having an ELSE in the CASE expression implicitly means ELSE NULL
The intention is therefore for each column to recieve NULL from every input row, except for the row being pivoted into that column
Aggregates, such as MAX() essentially skip NULL values
MAX( {NULL,NULL,'xxx',NULL,NULL} ) therefore equals 'xxx'
A similar approach "bunches" the values to the left (so that NULL values always only appears to the right...)
That approach first uses row_number() to give each row a value corresponding to which column you want to put that row in to..
WITH
sorted AS
(
SELECT
*,
ROW_NUMBER() OVER (PARTITION BY id ORDER BY name) AS seq_num
FROM
yourTable
)
SELECT
id,
MAX(CASE WHEN seq_num = 1 THEN name END) AS co1,
MAX(CASE WHEN seq_num = 1 THEN property END) AS co1_property,
MAX(CASE WHEN seq_num = 2 THEN name END) AS co2,
MAX(CASE WHEN seq_num = 2 THEN property END) AS co2_property,
MAX(CASE WHEN seq_num = 3 THEN name END) AS co3,
MAX(CASE WHEN seq_num = 3 THEN property END) AS co3_property
FROM
yourTable
GROUP BY
id
I have a simple table that looks like the following PNG file from the following join:
SELECT *
FROM tableA A
JOIN tableB B ON B.Main_SPACE_ID = A.Main_SPACE_ID
Table A contains Guest_ON and User_Controls (last 2 columns) and Table B contains Trigger_ON and DOCX_ON.
Issue:
What I am trying to do is count all the True's for each tableB.Subspace_ID and the DISTINCT trues for tableA.Main_SPACE_ID.
The problem is that subspace_ID from table B lives within the main_space_id from table A and therefore creates a situation where I am double counting.
I only want to count the trues for a distinct Main_space ID
Current Data Model
Desired Output:
From the above screenshot, I am trying to get a count of true values without double counting in the case for tableA_MAIN_SPACE_ID.
As you can see, each row is counted for true values as it relates to the subspace_ID (table B) for totals of 12 and 8 (1 if True, 0 if False) and for tableA, I am only counting distinct values so we only count Trues for a single MainspaceID and avoid recounting them.
If someone can advise on how to get this output from my current data model that would be very helpful!
My attempt as follows double counts trues for the Main space ID column..
SELECT
count(CASE WHEN B.TRIGGER_ON THEN 1 END) as TRIGGER_ON,
count(CASE WHEN B.DOCX_ON THEN 1 END) as DOCX_ON,
count(CASE WHEN A.GUEST_ON THEN 1 END) as SPRINTS,
count(CASE WHEN A.USER_CONTROLS THEN 1 END) as SPRINTS
FROM DataModel
What I am trying to do is count all the True's for each tableB.Subspace_ID and the DISTINCT trues for tableA.Main_SPACE_ID.
You can use conditional aggregation. In Snowflake, you can use the convenient COUNT_IF() for the first two columns. However, for the second two, you need COUNT(DISTINCT) with conditional logic:
SELECT COUNT_IF( B.Trigger_on ) as Trigger_On,
COUNT_IF( B. DOCX_ON ) as DOCX_ON,
COUNT(DISTINCT CASE WHEN A.GUEST_ON THEN A.Main_SPACE_ID END) as GUEST_ON,
COUNT(DISTINCT CASE WHEN A. USER_CONTROLS THEN A.Main_SPACE_ID END) as USER_CONTROLS
FROM tableA A JOIN
tableB B
ON B.Main_SPACE_ID = A.Main_SPACE_ID;
Mabye:
SELECT
COUNT(CASE WHEN B.TRIGGER_ON THEN 1 END) AS TRIGGER_ON,
COUNT(CASE WHEN B.DOCX_ON THEN 1 END) AS DOCX_ON,
(SELECT COUNT(*) FROM (SELECT DISTINCT A.MAIN_SPACE_ID, A.GUEST_ON FROM DataModel WHERE A.GUEST_ON = TRUE) A) AS GUEST_ON
(SELECT COUNT(*) FROM (SELECT DISTINCT A.USER_CONTROLS, A.GUEST_ON FROM DataModel WHERE A.USER_CONTROLS = TRUE) A) AS USER_CONTROLS
FROM DataModel
I have a historization table called CUR_VALID. This table looks something like this:
ID CUR_VALID
1 N
1 N
1 Y
2 N
2 Y
3 Y
For every ID there needs to be one Y. If there is no Y or multiple Y there is something wrong. The statment for checking if there are multiple Y I already got. Now I only need to check for every ID if there is one Y existing. Im just not sure how to do that. This is what I have so far. So how do I check if the Value 'Y' exists?
SELECT Count(1) [Number of N]
,MAX(CUR_VALID = 'N')
,[BILL_ID]
,[BILL_MONTH]
,[BILL_SRC_ID]
FROM db.dbo.table
GROUP BY [BILL_ID]
,[BILL_MONTH]
,[BILL_SRC_ID]
Having MAX(CUR_VALID = 'N') > 1
Why are you fiddling with 'N' when you are interested in 'Y'?
Use conditional aggregation to get the count of the value your are interested in.
SELECT
COUNT(*) AS number_of_all,
COUNT(CASE WHEN cur_valid = 'Y' THEN 1 END) AS number_of_y,
COUNT(CASE WHEN cur_valid = 'N' THEN 1 END) AS number_of_n,
bill_id,
bill_month,
bill_src_id,
FROM db.dbo.table
GROUP BY bill_id, bill_month, bill_src_id;
Add a HAVING clause in order to get only valid
HAVING COUNT(CASE WHEN cur_valid = 'Y' THEN 1 END) = 1
or invalid
HAVING COUNT(CASE WHEN cur_valid = 'Y' THEN 1 END) <> 1
bills.
The following query will give you the list of id for which your integrity condition is not met: For every ID there needs to be one Y. If there is no Y or multiple Y there is something wrong.
select T1.id from table T1 where (select count(*) from table T2 where T2.id=T1.id and T2.CUR_VALID='Y')!=1
This query returns both not having at least one 'Y' value and more than one 'Y' value ID's.
First, sum up the Y values and relate to each id, then select not 1 ones from that table.
select * from (
select ID, SUM(case when CUR_VALID = 'Y' then 1 else 0 end) as CNT
from table
group by ID
) b where b.CNT <> 1
DBFiddle
As I understand, you want to get all the id for which your integrity check passes. And integrity check for you means, there is only one row with CUR_VALID value equal to Y in the CUR_VALID table.
This can be achieved by a group by clause:
select id from CUR_VALID
where CUR_VALID.CUR_VALID = 'Y'
group by id
having count(CUR_VALID.CUR_VALID) = 1;
I have a sql code which I am using to do pivot. Code is as follows:
SELECT DISTINCT PersonID
,MAX(pivotColumn1)
,MAX(pivotColumn2) --originally these were in 2 separate rows)
FROM(SELECT srcID, PersonID, detailCode, detailValue) FROM src) AS SrcTbl
PIVOT(MAX(detailValue) FOR detailCode IN ([pivotColumn1],[pivotColumn2])) pvt
GROUP BY PersonID
In the source data the ID has 2 separate rows due to having its own ID which separates the values. I have now pivoted it and its still giving me 2 separate rows for the ID even though i grouped it and used aggregation on the pivot columns. Ay idea whats wrong with the code?
So I have all my possible detailCode listed in the IN clause. So I have null returned when the value is none but I want it all summarised in 1 row. See image below.
If those are all the options of detailCode , you can use conditional aggregation with CASE EXPRESSION instead of Pivot:
SELECT t.personID,
MAX(CASE WHEN t.detailCode = 'cas' then t.detailValue END) as cas,
MAX(CASE WHEN t.detailCode = 'buy' then t.detailValue END) as buy,
MAX(CASE WHEN t.detailCode = 'sel' then t.detailValue END) as sel,
MAX(CASE WHEN t.detailCode = 'pla' then t.detailValue END) as pla
FROM YourTable t
GROUP BY t.personID
I'm trying to write this query, that would calculate the average value of all the columns except the one that contains the type value, which I'm grouping the whole query by.
So for 4 types for example, each column in the resulting table will contain the average of all the other three type's values, i need to exclude the current type's rows.
As an example, if I was to calculate each type's average value for itself, the query would look like:
SELECT
SUM(some value) / COUNT(TYPE)
FROM TEMPTABLE
GROUP BY TYPE
Now I'm trying to calculate the other three's total average. Thanks.
You can do one query to get the distinct types, and LEFT JOIN the same table, checking for type-inequality:
SELECT t1.type,
SUM(t2.some_value) / COUNT(t2.type)
FROM ( SELECT DISTINCT type FROM temptable ) t1
LEFT JOIN temptable t2 ON ( t1.type <> t2.type )
GROUP BY t1.type
Since you only want the average, you could replace the line
FROM ( SELECT DISTINCT type FROM temptable ) t1
by
FROM temptable t1
but the first solution might perform better, since the number of rows is reduced earlier.
The starting point here is to make a cartesian join between your types and your temptable (guessing your tables structure is : type(id, type), valueTable(id, type_id, some_value))
The following query
SELECT t.type, SUM(vt.someValue) /
COUNT (*) AS sum FROM type t,
valueTable vt WHERE vt.type_id != t.id
GROUP BY t.type
should do the trick.
Will this do what you need?
(Possibly with another CASE statement to avoid divide by zero errors if there is a possibility none of a type might be returned, I've also not explicitly accounted for the case that type is NULL)
SELECT
SUM(CASE WHEN TYPE <> 'Type1' THEN someValue ELSE 0 END) /
SUM(CASE WHEN TYPE = 'Type1' THEN 1 ELSE 0 END) AS T1,
SUM(CASE WHEN TYPE <> 'Type2' THEN someValue ELSE 0 END) /
SUM(CASE WHEN TYPE = 'Type2' THEN 1 ELSE 0 END) AS T2,
SUM(CASE WHEN TYPE <> 'Type3' THEN someValue ELSE 0 END) /
SUM(CASE WHEN TYPE = 'Type3' THEN 1 ELSE 0 END) AS T3,
SUM(CASE WHEN TYPE <> 'Type4' THEN someValue ELSE 0 END) /
SUM(CASE WHEN TYPE = 'Type4' THEN 1 ELSE 0 END) AS T4
FROM TEMPTABLE
I think that you can just use this:
SELECT type, avg(col_01)
FROM myTable
GROUP BY type
Should work on Sybase too:
SELECT
SUM(some value) / SUM(CASE WHEN TYPE = 1 THEN 1 ELSE 0 END)
FROM TEMPTABLE
GROUP BY TYPE