I'm trying to write this query, that would calculate the average value of all the columns except the one that contains the type value, which I'm grouping the whole query by.
So for 4 types for example, each column in the resulting table will contain the average of all the other three type's values, i need to exclude the current type's rows.
As an example, if I was to calculate each type's average value for itself, the query would look like:
SELECT
SUM(some value) / COUNT(TYPE)
FROM TEMPTABLE
GROUP BY TYPE
Now I'm trying to calculate the other three's total average. Thanks.
You can do one query to get the distinct types, and LEFT JOIN the same table, checking for type-inequality:
SELECT t1.type,
SUM(t2.some_value) / COUNT(t2.type)
FROM ( SELECT DISTINCT type FROM temptable ) t1
LEFT JOIN temptable t2 ON ( t1.type <> t2.type )
GROUP BY t1.type
Since you only want the average, you could replace the line
FROM ( SELECT DISTINCT type FROM temptable ) t1
by
FROM temptable t1
but the first solution might perform better, since the number of rows is reduced earlier.
The starting point here is to make a cartesian join between your types and your temptable (guessing your tables structure is : type(id, type), valueTable(id, type_id, some_value))
The following query
SELECT t.type, SUM(vt.someValue) /
COUNT (*) AS sum FROM type t,
valueTable vt WHERE vt.type_id != t.id
GROUP BY t.type
should do the trick.
Will this do what you need?
(Possibly with another CASE statement to avoid divide by zero errors if there is a possibility none of a type might be returned, I've also not explicitly accounted for the case that type is NULL)
SELECT
SUM(CASE WHEN TYPE <> 'Type1' THEN someValue ELSE 0 END) /
SUM(CASE WHEN TYPE = 'Type1' THEN 1 ELSE 0 END) AS T1,
SUM(CASE WHEN TYPE <> 'Type2' THEN someValue ELSE 0 END) /
SUM(CASE WHEN TYPE = 'Type2' THEN 1 ELSE 0 END) AS T2,
SUM(CASE WHEN TYPE <> 'Type3' THEN someValue ELSE 0 END) /
SUM(CASE WHEN TYPE = 'Type3' THEN 1 ELSE 0 END) AS T3,
SUM(CASE WHEN TYPE <> 'Type4' THEN someValue ELSE 0 END) /
SUM(CASE WHEN TYPE = 'Type4' THEN 1 ELSE 0 END) AS T4
FROM TEMPTABLE
I think that you can just use this:
SELECT type, avg(col_01)
FROM myTable
GROUP BY type
Should work on Sybase too:
SELECT
SUM(some value) / SUM(CASE WHEN TYPE = 1 THEN 1 ELSE 0 END)
FROM TEMPTABLE
GROUP BY TYPE
Related
I'm struggling with a grouping query.
I have simple table named CarParts where some car elements stored in it.
Some of those elements are available (with Type prefix "05") and some are blocked (Type prefix "01").
I want to write select query that would group my table CarParts by SerialNr and Type as shown below on the right side.
Do you want conditional aggregation?
select serialnr, name,
sum(case when type like '%-05' then amount else 0 end) as [05-available],
sum(case when type like '%-01' then amount else 0 end) as [01-blocked]
from carparts
group by serialnr, name;
You can use PIVOT to get your desired result as below-
SELECT SerialNr,
ISNULL([05-Available],0) [05-Available],
ISNULL([01-Available],0) [01-Available],
Name
FROM
(
SELECT SerialNr,Amount,Name,RIGHT( Type,2) +'-Available' AS P_Column
FROM CarParts
) AS P
PIVOT
(
SUM(Amount)
FOR P_Column IN ([01-Available],[05-Available])
) AS PVT
you can use case when
select SerialNr,Name,
sum(case when right([Type],2)='01' then amount else 0 end) as blocked_01
sum(case when right([Type],2)='05' then amount else 0 end) as availabe_05
from tbale_name group by SerialNr,Name
select SerialNr,
sum(case when Type like '%-05' then Amount else 0 end) as '05-available',
sum(case when Type like '%-01' then Amount else 0 end) as '01-blocked',
Name
from carparts
group by SerialNr, Name
I have following table named as 'Table',
Where I want result like following table where if you take first row and last three columns I want value to be 56.
I want sql server code for above table 'Table' and result to be second table. Here MaxV-1 and MaxV-2 are dependent on 'Number' column. MaxV-1 is max value out of FirstV, SecondV and ThirdV when Number is equal to 1 and same logic for MaxV-2.
One method is an unpivot and conditional aggreation:
select t.model,
max(case when t.number = 1 then t.pro_code end) as pro_code_1,
max(case when t.number = 2 then t.pro_code end) as pro_code_2,
max(case when t.number = 1 then v.v end) as max_val_1,
max(case when t.number = 2 then v.v end) as max_val_2
from t cross apply
(select max(v.v) as v
from (values (t.firstv), (t.secondv), (t.thirdv)) v(v)
) v
group by t.model;
I want to do something like this:
select id,
count(*) as total,
FOR temp IN SELECT DISTINCT somerow FROM mytable ORDER BY somerow LOOP
sum(case when somerow = temp then 1 else 0 end) temp,
END LOOP;
from mytable
group by id
order by id
I created working select:
select id,
count(*) as total,
sum(case when somerow = 'a' then 1 else 0 end) somerow_a,
sum(case when somerow = 'b' then 1 else 0 end) somerow_b,
sum(case when somerow = 'c' then 1 else 0 end) somerow_c,
sum(case when somerow = 'd' then 1 else 0 end) somerow_d,
sum(case when somerow = 'e' then 1 else 0 end) somerow_e,
sum(case when somerow = 'f' then 1 else 0 end) somerow_f,
sum(case when somerow = 'g' then 1 else 0 end) somerow_g,
sum(case when somerow = 'h' then 1 else 0 end) somerow_h,
sum(case when somerow = 'i' then 1 else 0 end) somerow_i,
sum(case when somerow = 'j' then 1 else 0 end) somerow_j,
sum(case when somerow = 'k' then 1 else 0 end) somerow_k
from mytable
group by id
order by id
this works, but it is 'static' - if some new value will be added to 'somerow' I will have to change sql manually to get all the values from somerow column, and that is why I'm wondering if it is possible to do something with for loop.
So what I want to get is this:
id somerow_a somerow_b ....
0 3 2 ....
1 2 10 ....
2 19 3 ....
. ... ...
. ... ...
. ... ...
So what I'd like to do is to count all the rows which has some specific letter in it and group it by id (this id isn't primary key, but it is repeating - for id there are about 80 different values possible).
http://sqlfiddle.com/#!15/18feb/2
Are arrays good for you? (SQL Fiddle)
select
id,
sum(totalcol) as total,
array_agg(somecol) as somecol,
array_agg(totalcol) as totalcol
from (
select id, somecol, count(*) as totalcol
from mytable
group by id, somecol
) s
group by id
;
id | total | somecol | totalcol
----+-------+---------+----------
1 | 6 | {b,a,c} | {2,1,3}
2 | 5 | {d,f} | {2,3}
In 9.2 it is possible to have a set of JSON objects (Fiddle)
select row_to_json(s)
from (
select
id,
sum(totalcol) as total,
array_agg(somecol) as somecol,
array_agg(totalcol) as totalcol
from (
select id, somecol, count(*) as totalcol
from mytable
group by id, somecol
) s
group by id
) s
;
row_to_json
---------------------------------------------------------------
{"id":1,"total":6,"somecol":["b","a","c"],"totalcol":[2,1,3]}
{"id":2,"total":5,"somecol":["d","f"],"totalcol":[2,3]}
In 9.3, with the addition of lateral, a single object (Fiddle)
select to_json(format('{%s}', (string_agg(j, ','))))
from (
select format('%s:%s', to_json(id), to_json(c)) as j
from
(
select
id,
sum(totalcol) as total_sum,
array_agg(somecol) as somecol_array,
array_agg(totalcol) as totalcol_array
from (
select id, somecol, count(*) as totalcol
from mytable
group by id, somecol
) s
group by id
) s
cross join lateral
(
select
total_sum as total,
somecol_array as somecol,
totalcol_array as totalcol
) c
) s
;
to_json
---------------------------------------------------------------------------------------------------------------------------------------
"{1:{\"total\":6,\"somecol\":[\"b\",\"a\",\"c\"],\"totalcol\":[2,1,3]},2:{\"total\":5,\"somecol\":[\"d\",\"f\"],\"totalcol\":[2,3]}}"
In 9.2 it is also possible to have a single object in a more convoluted way using subqueries in instead of lateral
SQL is very rigid about the return type. It demands to know what to return beforehand.
For a completely dynamic number of resulting values, you can only use arrays like #Clodoaldo posted. Effectively a static return type, you do not get individual columns for each value.
If you know the number of columns at call time ("semi-dynamic"), you can create a function taking (and returning) polymorphic parameters. Closely related answer with lots of details:
Dynamic alternative to pivot with CASE and GROUP BY
(You also find a related answer with arrays from #Clodoaldo there.)
Your remaining option is to use two round-trips to the server. The first to determine the the actual query with the actual return type. The second to execute the query based on the first call.
Else, you have to go with a static query. While doing that, I see two nicer options for what you have right now:
1. Simpler expression
select id
, count(*) AS total
, count(somecol = 'a' OR NULL) AS somerow_a
, count(somecol = 'b' OR NULL) AS somerow_b
, ...
from mytable
group by id
order by id;
How does it work?
Compute percents from SUM() in the same SELECT sql query
SQL Fiddle.
2. crosstab()
crosstab() is more complex at first, but written in C, optimized for the task and shorter for long lists. You need the additional module tablefunc installed. Read the basics here if you are not familiar:
PostgreSQL Crosstab Query
SELECT * FROM crosstab(
$$
SELECT id
, count(*) OVER (PARTITION BY id)::int AS total
, somecol
, count(*)::int AS ct -- casting to int, don't think you need bigint?
FROM mytable
GROUP BY 1,3
ORDER BY 1,3
$$
,
$$SELECT unnest('{a,b,c,d}'::text[])$$
) AS f (id int, total int, a int, b int, c int, d int);
SELECT COUNT(Type) from House where Type = 1
SELECT COUNT(Type) from House where Type = 2
SELECT COUNT(Type) from House where Type = 3
My question is: I want to join the above 3 statements to get: 3 columns i.e. eg:
ColumnType1: '50', ColumnType2: '60', columnType3: '45'
thanks
You can create the columns using an aggregate function with a CASE expression:
SELECT
count(case when Type = 1 then Type end) as type_1,
count(case when Type = 2 then Type end) as type_2,
count(case when Type = 3 then Type end) as type_3
from House
You can use a case and add up if the Type matches
SELECT sum(case when Type = 1 then 1 else 0 end) as type_1,
sum(case when Type = 2 then 1 else 0 end) as type_2,
sum(case when Type = 3 then 1 else 0 end) as type_3
from House
There is a cleaner type of SQL which can give you this answer, but you will have each type on a different row:
SELECT Type, COUNT(Type) FROM House GROUP BY Type
It has the disadvantage of not giving you columns as you asked for; but the advantage is that it works for any number of different types without needing to change the query.
SELECT
COUNT(Type) as val1,
(SELECT COUNT(Type) from House where Type = 2) as val2,
(SELECT COUNT(Type) from House where Type = 3) as val3
from House where Type = 1
I want to add some calculation inside my case statement to dynamically create the contents of a new column but I get the error:
Column 'Test1.qrank' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause.
This is the code I'm working on
case
when test1.TotalType = 'Average' then Test2.avgscore
when test1.TotalType = 'PercentOfTot' then (cnt/SUM(test1.qrank))
else cnt
end as displayscore
I did try to group but it didn't work.
Any hints?
The error you posted can happen when you're using a clause in the GROUP BY statement without including it in the select.
Example
This one works!
SELECT t.device,
SUM(case when transits.direction = 1 then 1 else 0 end) ,
SUM(case when transits.direction = 0 then 1 else 0 end) from t1 t
where t.device in ('A','B') group by t.device
This one not (omitted t.device from the select)
SELECT
SUM(case when transits.direction = 1 then 1 else 0 end) ,
SUM(case when transits.direction = 0 then 1 else 0 end) from t1 t
where t.device in ('A','B') group by t.device
This will produce your error complaining that I'm grouping for something that is not included in the select
Please, provide all the query to get more support.
You could use a Common Table Expression to create the SUM first, join it to the table, and then use the WHEN to to get the value from the CTE or the original table as necessary.
WITH PercentageOfTotal (Id, Percentage)
AS
(
SELECT Id, (cnt / SUM(AreaId)) FROM dbo.MyTable GROUP BY Id
)
SELECT
CASE
WHEN o.TotalType = 'Average' THEN r.avgscore
WHEN o.TotalType = 'PercentOfTot' THEN pt.Percentage
ELSE o.cnt
END AS [displayscore]
FROM PercentageOfTotal pt
JOIN dbo.MyTable t ON pt.Id = t.Id
If you're using SQL Server 2005 or above, you can use the windowing function SUM() OVER ().
case
when test1.TotalType = 'Average' then Test2.avgscore
when test1.TotalType = 'PercentOfTot' then (cnt/SUM(test1.qrank) over ())
else cnt
end as displayscore
But it'll be better if you show your full query to get context of what you actually need.