Related
I have a column that contains multiple values in a delimited(comma-separated) format -
id | code
------------
1 11,19,21
2 55,87,33
3 3,11
4 11
I want to be able to compare to each value inside the 'code' column as below -
SELECT id FROM myTbl WHERE code = '11'
This should return -
1
3
4
I've tried the solution below but it does not work for all cases -
SELECT id FROM myTbl WHERE POSITION('11' IN code) <> 0
This will work with a 2 digit number like '11' as it will return a value that is <> 0 if it finds a match. But it will fail when searching for say '3' because rows with 'id' 2 and 3 both will be returned.
Here is link that talks about the POSITION function in REDSHIFT.
Any other approach that will solve this problem?
you can get the count of this string
SELECT id FROM myTbl WHERE regexp_count(user_action, '[11]') > 0
I think we can use regexp_substr() as follow.
select tb .id from myTbl tb where '11' in (
select regexp_substr( (select code from myTbl where id=tb.id),'[^,]+', 1, LEVEL) from dual
connect by regexp_substr((select code from myTbl where id=tb.id) , '[^,]+', 1, LEVEL) is not null);
just try this.
Use split_part() function
SELECT distinct id
FROM myTbl
WHERE '11' in ( split_part( code||',' , ',', 1 ),
split_part( code||',' , ',', 2 ),
split_part( code||',' , ',', 3 ) )
This is a very, very bad data model. You should be storing this information in a junction/association table, with one row per value.
But, if you have no choice, you can use like:
SELECT id
FROM myTbl
WHERE ',' || code || ',' LIKE '%,11,%';
I have a SQL query, in where clause "MID = 123". I want to use a parameter for the VALUE and pass multiple values.
Example: now I am passing one VALUE of 123, but I want to pass multiple value like 123, 124, 125 etc. from which the SQL query will take values one by one and pass those to the where clause, and produce the result one by one, like first use value = 123, get the result, when use value = 124 and get results, and last use value = 125 to get results.
I need help with this parameter.
It will be great if we don't change the SQL query but we can parameter the where clause.
NOTE: I am using SQL Developer.
SQL query:
SELECT
'ABC' AS COLUMN_NAME,
(CASE
WHEN to_char(count(ABC)) > 1
AND to_char(max(ABC)) = to_char(min(ABC))
AND to_char(count(ABC)) = count(*)
AND to_char(max(ABC)) IS NULL
THEN 'same'
ELSE 'Diff'
END) AS COMPARISON_VALUE,
(CASE
WHEN to_char(COUNT(ABC)) = 1 OR to_char(min(ABC)) IS NULL
THEN 'No Values'
ELSE to_char(max(ABC))
END) AS TRANSACTION1,
to_char(min(ABC)) AS TRANSACTION2
FROM
ADVICES
WHERE
MID = '123';
One approach would be to specify the test data in a WITH clause and feed it to the query via an outer join. We include the test value as the first column in the result set. This means that every row in the result set will have the associated test value.
WITH testdata(testval) AS
(
SELECT '123' FROM DUAL UNION ALL
SELECT '124' FROM DUAL UNION ALL
SELECT '125' FROM DUAL
)
SELECT
testdata.testval,
...
...
FROM
ADVICES, testdata
WHERE
MID (+) = testdata.testval;
...i am trying to parameter the where clause, for which i want to fetch
parameter data from text or CSV should be fine.
Alternatively, testdata could be a table that's loaded from a CSV file with test values.
You may pass a CSV and use LIKE.
where ','||:var||',' like '%,'||MID||',%'
Example using HR schema
var myvar VARCHAR2
exec :myvar := '101,102,103' --parameter
select employee_id,department_id from employees where
','||:myvar||',' like '%,'||employee_id||',%';
Result
EMPLOYEE_ID DEPARTMENT_ID
----------- -------------
101 90
102 90
103 60
You can write your WHERE clause like the following:
WHERE MID IN
(SELECT
REGEXP_SUBSTR('YOUR_VALUE', '[^,]+', 1, LEVEL)
FROM
DUAL
CONNECT BY
REGEXP_SUBSTR('YOUR_VALUE', '[^,]+', 1, LEVEL) IS NOT NULL);
For checking the solution:
-- With multiple values
DEFINE YOUR_VALUE= '123,124,125';
SELECT
REGEXP_SUBSTR('&YOUR_VALUE', '[^,]+', 1, LEVEL)
FROM
DUAL
CONNECT BY
REGEXP_SUBSTR('&YOUR_VALUE', '[^,]+', 1, LEVEL) IS NOT NULL);
-- OUTPUT --
REGEXP_SUBS
-----------
123
124
125
-- With single value
DEFINE YOUR_VALUE = '123';
SELECT
REGEXP_SUBSTR('&YOUR_VALUE', '[^,]+', 1, LEVEL)
FROM
DUAL
CONNECT BY
REGEXP_SUBSTR('&YOUR_VALUE', '[^,]+', 1, LEVEL) IS NOT NULL;
-- OUTPUT --
REGEXP_SUBS
-----------
123
Cheers!!
You can change your where clause to -
WHERE
MID IN (YOUR_PARAMETER);
When you will pass multiple values, it will simply converted to OR condition and will fetch the results.
I just had this idea of how can i loop in sql?
For example
I have this column
PARAMETER_VALUE
E,C;S,C;I,X;G,T;S,J;S,F;C,S;
i want to store all value before (,) in a temp column also store all value after (;) into another column
then it wont stop until there is no more value after (;)
Expected Output for Example
COL1 E S I G S S C
COL2 C C X T J F S
etc . . .
You can get by using regexp_substr() window analytic function with connect by level <= clause
with t1(PARAMETER_VALUE) as
(
select 'E,C;S,C;I,X;G,T;S,J;S,F;C,S;' from dual
), t2 as
(
select level as rn,
regexp_substr(PARAMETER_VALUE,'([^,]+)',1,level) as str1,
regexp_substr(PARAMETER_VALUE,'([^;]+)',1,level) as str2
from t1
connect by level <= regexp_count(PARAMETER_VALUE,';')
)
select listagg( regexp_substr(str1,'([^;]+$)') ,' ') within group (order by rn) as col1,
listagg( regexp_substr(str2,'([^,]+$)') ,' ') within group (order by rn) as col2
from t2;
COL1 COL2
------------- -------------
E S I G S S C C C X T J F S
Demo
Assuming that you need to separate the input into rows, at the ; delimiters, and then into columns at the , delimiter, you could do something like this:
-- WITH clause included to simulate input data. Not part of the solution;
-- use actual table and column names in the SELECT statement below.
with
t1(id, parameter_value) as (
select 1, 'E,C;S,C;I,X;G,T;S,J;S,F;C,S;' from dual union all
select 2, ',U;,;V,V;' from dual union all
select 3, null from dual
)
-- End of simulated input data
select id,
level as ord,
regexp_substr(parameter_value, '(;|^)([^,]*),', 1, level, null, 2) as col1,
regexp_substr(parameter_value, ',([^;]*);' , 1, level, null, 1) as col2
from t1
connect by level <= regexp_count(parameter_value, ';')
and id = prior id
and prior sys_guid() is not null
order by id, ord
;
ID ORD COL1 COL2
--- --- ---- ----
1 1 E C
1 2 S C
1 3 I X
1 4 G T
1 5 S J
1 6 S F
1 7 C S
2 1 U
2 2
2 3 V V
3 1
Note - this is not the most efficient way to split the inputs (nothing will be very efficient - the data model, which is in violation of First Normal Form, is the reason). This can be improved using standard instr and substr, but the query will be more complicated, and for that reason, harder to maintain.
I generated more input data, to illustrate a few things. You may have several inputs that must be broken up at the same time; that must be done with care. (Note the additional conditions in CONNECT BY). I also illustrate the handling of NULL - if a comma comes right after a semicolon, that means that the "column 1" part of that pair must be NULL. That is shown in the output.
I have a Table - Product In Oracle, wherein p_spc_cat_id is stored as comma separated values.
p_id p_name p_desc p_spc_cat_id
1 AA AAAA 26,119,27,15,18
2 BB BBBB 0,0,27,56,57,4
3 BB CCCC 26,0,0,15,3,8
4 CC DDDD 26,0,27,7,14,10
5 CC EEEE 26,119,0,48,75
Now I want to search p_name which have p_spc_cat_id in '26,119,7' And this search value are not fixed it will some time '7,27,8'. The search text combination change every time
my query is:
select p_id,p_name from product where p_spc_cat_id in('26,119,7');
when i execute this query that time i can't find any result
I am little late in answering however i hope that i understood the question correctly.
Read further if: you have a table storing records like
1. 10,20,30,40
2. 50,40,20,70
3. 80,60,30,40
And a search string like '10,60', in which cases it should return rows 1 & 3.
Please try below, it worked for my small table & data.
create table Temp_Table_Name (some_id number(6), Ab varchar2(100))
insert into Temp_Table_Name values (1,'112,120')
insert into Temp_Table_Name values (2,'7,8,100,26')
Firstly lets breakdown the logic:
The table contains comma separated data in one of the columns[Column AB].
We have a comma separated string which we need to search individually in that string column. ['26,119,7,18'-X_STRING]
ID column is primary key in the table.
1.) Lets multiple each record in the table x times where x is the count of comma separated values in the search string [X_STRING]. We can use below query to create the cartesian join sub-query table.
Select Rownum Sequencer,'26,119,7,18' X_STRING
from dual
CONNECT BY ROWNUM <= (LENGTH( '26,119,7,18') - LENGTH(REPLACE( '26,119,7,18',',',''))) + 1
Small note: Calculating count of comma separated values =
Length of string - length of string without ',' + 1 [add one for last value]
2.) Create a function PARSING_STRING such that PARSING_STRING(string,position). So If i pass:
PARSING_STRING('26,119,7,18',3) it should return 7.
CREATE OR REPLACE Function PARSING_STRING
(String_Inside IN Varchar2, Position_No IN Number)
Return Varchar2 Is
OurEnd Number; Beginn Number;
Begin
If Position_No < 1 Then
Return Null;
End If;
OurEnd := Instr(String_Inside, ',', 1, Position_No);
If OurEnd = 0 Then
OurEnd := Length(String_Inside) + 1;
End If;
If Position_No = 1 Then
Beginn := 1;
Else
Beginn := Instr(String_Inside, ',', 1, Position_No-1) + 1;
End If;
Return Substr(String_Inside, Beginn, OurEnd-Beginn);
End;
/
3.) Main query, with the join to multiply records.:
select t1.*,PARSING_STRING(X_STRING,Sequencer)
from Temp_Table_Name t1,
(Select Rownum Sequencer,'26,119,7,18' X_STRING from dual
CONNECT BY ROWNUM <= (Select (LENGTH( '26,119,7,18') - LENGTH(REPLACE(
'26,119,7,18',',',''))) + 1 from dual)) t2
Please note that with each multiplied record we are getting 1 particular position value from the comma separated string.
4.) Finalizing the where condition:
Where
/* For when the value is in the middle of the strint [,value,] */
AB like '%,'||PARSING_STRING(X_STRING,Sequencer)||',%'
OR
/* For when the value is in the start of the string [value,]
parsing the first position comma separated value to match*/
PARSING_STRING(AB,1) = PARSING_STRING(X_STRING,Sequencer)
OR
/* For when the value is in the end of the string [,value]
parsing the last position comma separated value to match*/
PARSING_STRING(AB,(LENGTH(AB) - LENGTH(REPLACE(AB,',',''))) + 1) =
PARSING_STRING(X_STRING,Sequencer)
5.) Using distinct in the query to get unique ID's
[Final Query:Combination of all logic stated above: 1 Query to find them all]
select distinct Some_ID
from Temp_Table_Name t1,
(Select Rownum Sequencer,'26,119,7,18' X_STRING from dual
CONNECT BY ROWNUM <= (Select (LENGTH( '26,119,7,18') - LENGTH(REPLACE( '26,119,7,18',',',''))) + 1 from dual)) t2
Where
AB like '%,'||PARSING_STRING(X_STRING,Sequencer)||',%'
OR
PARSING_STRING(AB,1) = PARSING_STRING(X_STRING,Sequencer)
OR
PARSING_STRING(AB,(LENGTH(AB) - LENGTH(REPLACE(AB,',',''))) + 1) = PARSING_STRING(X_STRING,Sequencer)
You can use like to find it:
select p_id,p_name from product where p_spc_cat_id like '%26,119%'
or p_spc_cat_id like '%119,26%' or p_spc_cat_id like '%119,%,26%' or p_spc_cat_id like '%26,%,119%';
Use the Oracle function instr() to achieve what you want. In your case that would be:
SELECT p_name
FROM product
WHERE instr(p_spc_cat_id, '26,119') <> 0;
Oracle Doc for INSTR
If the string which you are searching will always have 3 values (i.e. 2 commas present) then you can use below approach.
where p_spc_cat_id like regexp_substr('your_search_string, '[^,]+', 1, 1)
or p_spc_cat_id like regexp_substr('your_search_string', '[^,]+', 1, 2)
or p_spc_cat_id like regexp_substr('your_search_string', '[^,]+', 1, 3)
If you cant predict how many values will be there in your search string
(rather how many commas) in that case you may need to generate dynamic query.
Unfortunately sql fiddle is not working currently so could not test this code.
SELECT p_id,p_name
FROM product
WHERE p_spc_cat_id
LIKE '%'||'&i_str'||'%'`
where i_str is 26,119,7 or 7,27,8
This solution uses CTE's. "product" builds the main table. "product_split" turns products into rows so each element in p_spc_cat_id is in it's own row. Lastly, product_split is searched for each value in the string '26,119,7' which is turned into rows by the connect by.
with product(p_id, p_name, p_desc, p_spc_cat_id) as (
select 1, 'AA', 'AAAA', '26,119,27,15,18' from dual union all
select 2, 'BB', 'BBBB', '0,0,27,56,57,4' from dual union all
select 3, 'BB', 'CCCC', '26,0,0,15,3,8' from dual union all
select 4, 'CC', 'DDDD', '26,0,27,7,14,10' from dual union all
select 5, 'CC', 'EEEE', '26,119,0,48,75' from dual
),
product_split(p_id, p_name, p_spc_cat_id) as (
select p_id, p_name,
regexp_substr(p_spc_cat_id, '(.*?)(,|$)', 1, level, NULL, 1)
from product
connect by level <= regexp_count(p_spc_cat_id, ',')+1
and prior p_id = p_id
and prior sys_guid() is not null
)
-- select * from product_split;
select distinct p_id, p_name
from product_split
where p_spc_cat_id in(
select regexp_substr('26,119,7', '(.*?)(,|$)', 1, level, NULL, 1) from dual
connect by level <= regexp_count('26,119,7', ',') + 1
)
order by p_id;
P_ID P_
---------- --
1 AA
3 BB
4 CC
5 CC
SQL>
I have an issue where in my data I will have a record returned where a column value will look like
-- query
Select col1 from myTable where id = 23
-- result of col1
111, 104, 34, 45
I want to feed these values to an in clause. So far I have tried:
-- Query 2 -- try 1
Select * from mytableTwo
where myfield in (
SELECT col1
from myTable where id = 23)
-- Query 2 -- try 2
Select * from mytableTwo
where myfield in (
SELECT '''' +
Replace(col1, ',', ''',''') + ''''
from myTable where id = 23)
-- query 2 test -- This works and will return data, so I verify here that data exists
Select * from mytableTwo
where myfield in ('111', '104', '34', '45')
Why aren't query 2 try 1 or 2 working?
You don't want an in clause. You want to use like:
select *
from myTableTwo t2
where exists (select 1
from myTable t
where id = 23 and
', '+t.col1+', ' like '%, '+t2.myfield+', %'
);
This uses like for the comparison in the list. It uses a subquery for the value. You could also phrase this as a join by doing:
select t2.*
from myTableTwo t2 join
myTable t
on t.id = 23 and
', '+t.col1+', ' like '%, '+t2.myfield+', %';
However, this could multiply the number of rows in the output if there is more than one row with id = 23 in myTable.
If you observe closely, Query 2 -- try 1 & Query 2 -- try 2 are considered as single value.
like this :
WHERE myfield in ('111, 104, 34, 45')
which is not same as :
WHERE myfield in ('111', '104', '34', '45')
So, If you intend to filter myTable rows from MyTableTwo, you need to extract the values of fields column data to a table variable/table valued function and filter the data.
I have created a table valued function which takes comma seperated string and returns a table value.
you can refer here T-SQL : Comma separated values to table
Final code to filter the data :
DECLARE #filteredIds VARCHAR(100)
-- Get the filter data
SELECT #filteredIds = col1
FROM myTable WHERE id = 23
-- TODO : Get the script for [dbo].[GetDelimitedStringToTable]
-- from the given link and execute before this
SELECT *
FROM mytableTwo T
CROSS APPLY [dbo].[GetDelimitedStringToTable] ( #filteredIds, ',') F
WHERE T.myfield = F.Value
Please let me know If this helps you!
I suppose col is a character type, whose result would be like like '111, 104, 34, 45'. If this is your situation, it's not the best of the world (denormalized database), but you can still relate these tables by using character operators like LIKE or CHARINDEX. The only gotcha is to convert the numeric column to character -- the default conversion between character and numeric is numeric and it will cause a conversion error.
Since #Gordon, responded using LIKE, I present a solution using CHARINDEX:
SELECT *
FROM mytableTwo tb2
WHERE EXISTS (
SELECT 'x'
FROM myTable tb1
WHERE tb1.id = 23
AND CHARINDEX(CONVERT(VARCHAR(20), tb2.myfield), tb1.col1) > 0
)