How would I get the coordinates of my onTouchEnd event. So I touch or move figure anywhere within the display and I can retrieve the X, Y positioning of where it happened. onResponderRelease is not triggered in a onTouchEnd on Android,
I've included example implementations for all of the gesture response event handlers, but have commented out most of them on my View to just provide the basic functionality: subscribing to all touch and move events
pseudo code would look like this :
<View
style={this.props.style}
ref={this._saveRef}
onStartShouldSetResponder={(event) => {
return this.handleDoubleTap({nativeEvent:
event.nativeEvent});
}}
onResponderGrant={this._onTouchStart}
onResponderMove={this._onTouchMove}
onResponderRelease={this._onTouchEnd}
onResponderTerminate={this._onTouchEnd} // When
onResponderRelease can't call by some reason
>
{this.props.children}
</View>
Responder Event Handler Methods :
if (this.isDoubleTap) {
return false;
}
this.context.setScroll && this.context.setScroll(false);
const currentTouchTimeStamp = Date.now();
this._prevTouchInfo = {
prevTouchX: nativeEvent.pageX,
prevTouchY: nativeEvent.pageY,
prevTouchTimeStamp: currentTouchTimeStamp
};
this.props.onStart(nativeEvent);
};
_onTouchMove = ({nativeEvent}) => {
if (nativeEvent.touches.length <= 1) {
if (this.isDoubleTap) {
return false;
}
const self = this;
const gesture = {
x0: this._prevTouchInfo.prevTouchX,
x1: nativeEvent.pageX,
y0: this._prevTouchInfo.prevTouchY,
y1: nativeEvent.pageY,
dx: nativeEvent.pageX - this._prevTouchInfo.prevTouchX,
dy: nativeEvent.pageY - this._prevTouchInfo.prevTouchY
};
InteractionManager.runAfterInteractions(function () {
self.props.onMove(nativeEvent, gesture);
});
}
};
_onTouchEnd = ({nativeEvent}) => {
nativeEvent.touches.length === 0 && this.context.setScroll && this.context.setScroll(true);
this.props.onEnd(nativeEvent);
};
}
I am Developing an Application in React native.Actually when i am touch on Particular Position On view, getting the Corresponding x and y co-ordinates. App UI would look like this:
If this is still not enough functionality for android (eg. if you need multi-touch info), refer to PanResponde
Related
I'm building an app with react-navigation-4.2.1. The app has multiple stack navigators. So there are a lots of navigation.push('Routename') calls.
Trouble is when the control surface (i.e. TouchableOpacity) is tapped rapidly multiple times (first one, and the rest during screen transition) I end up pushing multiple screens into the stack. Is there a way to restrict the surface to the first tap/call of push()?
The component below is what i use to make things touchable. it handle multiple touches in small period of time.
Use component below instead of TouchableOpacity. wrap any thing you want with this component and it will be touchable.
<SafeTouch
onPress={...}
>
<Text> hey! im a touchable text now</Text>
</SafeTouch>
The component below is written used TypeScirpt.
every touch within 300ms after first touch will be ignored(thats where help you with your problem).
import * as React from 'react'
import { TouchableOpacity } from 'react-native'
interface ISafeTouchProps {
onPress: () => void
onLongPress?: () => void
onPressIn?: () => void
onPressOut?: () => void,
activeOpacity?: number,
disabled?: boolean,
style: any
}
export class SafeTouch extends React.PureComponent<ISafeTouchProps> {
public static defaultProps: ISafeTouchProps = {
onPress: () => { },
onLongPress: () => { },
onPressIn: () => { },
onPressOut: () => { },
disabled: false,
style: null
}
private isTouchValid: boolean = true
private touchTimeout: any = null
public constructor(props: ISafeTouchProps) {
super(props)
{// Binding methods
this.onPressEvent = this.onPressEvent.bind(this)
}
}
public render(): JSX.Element {
return (
<TouchableOpacity
onPress={this.onPressEvent}
onLongPress={this.props.onLongPress}
onPressIn={this.props.onPressIn}
onPressOut={this.props.onPressOut}
activeOpacity={this.props.activeOpacity}
disabled={this.props.disabled}
style={[{minWidth: 24, minHeight: 24}, this.props.style]}
>
{
this.props.children
}
</TouchableOpacity>
)
}
public componentWillUnmount() {
this.clearTimeoutIfExists()
}
private onPressEvent(): void {
requestAnimationFrame(() => {
if (this.isTouchValid === false) {
return
}
this.isTouchValid = false
this.clearTimeoutIfExists()
this.touchTimeout = setTimeout(() => {
this.isTouchValid = true
}, 300)
if (typeof this.props.onPress === 'function') {
this.props.onPress()
}
})
}
private clearTimeoutIfExists(): void {
if (this.touchTimeout != null) {
clearTimeout(this.touchTimeout)
this.touchTimeout = null
}
}
}
This is the proper behavior for Push and it is not a bug if you want
to avoid the duplicate screen on double tab you can just use navigation.navigate.
To avoid pushing the screen more than once when clicking in the same button in a short span of time, I created a generic hook to avoid running a function more than once (accepting an interval to allow run again):
export const useCallOnce = <T extends unknown[], K>(
fn: (...args: T) => K,
allowAfter?: number,
) => {
const ref = React.useRef<number | undefined>();
const resultFn = (...args: T) => {
const now = new Date().getTime();
if (!ref.current || (allowAfter && ref.current + allowAfter < now)) {
ref.current = now;
return fn(...args);
}
};
return resultFn;
};
Then, you can just call it as in the following example:
const navigation = useNavigation<NativeStackNavigationProp<{ ExampleScreen: undefined }>>();
const push = useCallOnce(() => navigation.push('ExampleScreen'), 500);
// just call on the button click event as: onSomeEvent={() => push()}
You can create a generic button component that accept the push parameters with the hook above, similar to the example, and use this button whenever you want a button to navigate between pages.
I need to perform different action on single and double tap on a view. On double tap I need to like the image just like Instagram double tap experience. On single tap I need to open a modal.
For double tap I have used TapGestureHandler which works perfect
<TapGestureHandler
ref={this.doubleTapRef}
maxDelayMs={200}
onHandlerStateChange={this.onProductImageDoubleTap}
numberOfTaps={2}
>
<SomeChildComponent ...
But when I add any Touchable to detect single tap in the
<TouchableWithoutFeedback onPress={this.imageTapped}>
on double tapping the this.imageTapped function is called twice along with this.onProductImageDoubleTap. Is there any way to cancel tap on touchable when two taps are done is quick succession
The best solution is not using state, since setting state is asynchronous.Works like a charm for me on android !
let lastPress = 0;
const functionalComp = () => {
const onDoublePress = () => {
const time = new Date().getTime();
const delta = time - lastPress;
const DOUBLE_PRESS_DELAY = 400;
if (delta < DOUBLE_PRESS_DELAY) {
// Success double press
console.log('double press');
}
lastPress = time;
};
return <View
onStartShouldSetResponder =
{(evt) => onDoublePress()}>
</View>
}
2022 update
This is a performant native solution without any JS thread blocking calculation!
Many more tips here
const tap = Gesture.Tap()
.numberOfTaps(2)
.onStart(() => {
console.log('Yay, double tap!');
});
return (
<GestureDetector gesture={tap}>
{children}
</GestureDetector>
);
The best solution is use react-native-gesture-handler
https://github.com/software-mansion/react-native-gesture-handler
Here is my solution -
import {State, TapGestureHandler} from 'react-native-gesture-handler';
export const DoubleTap = ({children}: any) => {
const doubleTapRef = useRef(null);
const onSingleTapEvent = (event: any) => {
if (event.nativeEvent.state === State.ACTIVE) {
console.log("single tap 1");
}
};
const onDoubleTapEvent = (event: any) => {
if (event.nativeEvent.state === State.ACTIVE) {
console.log("double tap 1");
}
};
return (
<TapGestureHandler
onHandlerStateChange={onSingleTapEvent}
waitFor={doubleTapRef}>
<TapGestureHandler
ref={doubleTapRef}
onHandlerStateChange={onDoubleTapEvent}
numberOfTaps={2}>
{children}
</TapGestureHandler>
</TapGestureHandler>
);
};
Now we will wrap the component where we need to detect the double and single tap : -
<DoubleTap>
<View>
...some view and text
</View>
</DoubleTap>
The package react-native-double-tap seems to be what you are looking for.
since you are asking on handling one tap and double tap, here's a simple code i think should covered your issue
Untested
first defined clickCount:0 in state:
state={clickCount:0, //another state}
then create a function with setTimeout to handling if user tapping once or two times:
handlingTap(){
this.state.clickCount==1 ?
//user tap twice so run this.onProductImageDoubleTap()
this.onProductImageDoubleTap :
//user tap once so run this.imageTapped with setTimeout and setState
//i set 1 sec for double tap, so if user tap twice more than 1 sec, it's count as one tap
this.setState({clickCount:1}, ()=>{
setTimeout(()=>{
this.setState({clickCount:0})
this.imageTapped()
}, 1000)
})
}
<TouchableWithoutFeedback onPress={this.handlingTap()}/>
just used TouchableWithoutFeedback instead of TapGestureHandler
With hooks:
const [lastPressed, setLastPressed] = useState(0);
const handlePress = useCallback(() => {
const time = new Date().getTime();
const delta = time - lastPressed;
setLastPressed(time);
if (lastPressed) {
if (delta < DOUBLE_PRESS_DELAY) {
console.log('double press');
} else {
console.log('single press');
}
}
}, [lastPressed]);
I have modified flix's answer into this. By this way, you can catch one and double click separately. I also changed debounce into 300ms which is fairly well for one and double click.
state={clickCount:0, //another state}
Binding context into the handlingTap method
constructor(props){
super(props)
this.handlingTap = this.handlingTap.bind(this)
}
With this function you can catch them separately
handlingTap() {
this.state.clickCount === 1
? this.doubleClick() // This catches double click
: this.setState(state => ({ clickCount: state.clickCount + 1 }), () => {
setTimeout(() => {
if (this.state.clickCount !== 2) {
this.oneClick() // this catches one click
}
this.setState({ clickCount: 0 })
}, 300)
})
}
In the button you can use this way
<TouchableWithoutFeedback onPress={this.handlingTap}></TouchableWithoutFeedback>
I've implemented a 2d dragable area chart from react-native-fusioncharts. I am trying to fire an event when the data is changed which works as expected on android but no event will fire on IOS.
I've tried dataplotDragEnd and dataPlotClick but neither fire.
state = {
...,
events: {
dataplotDragEnd: (e, a) => {
Alert.alert("called")
console.log(e.data.endValue)
},
}
}
}
render() {
return (
<FusionCharts
type={this.state.type}
width={this.state.width}
height={this.state.height}
dataFormat={this.state.dataFormat}
dataSource={this.state.dataSource}
events={this.state.events}
libraryPath={this.libraryPath}
/>
)
}
I am expecting an alert message and a console.log from the event firing but am currently getting nothing only on IOS
I make us several Switch Components in one view. When I switch on one switch, I want all others to switch off. Currently, I set the boolean value property via the state. This results in changes happen abruptly because the switch is just re-rendered and not transitioned.
So how would you switch them programmatically?
EDIT 2: I just discovered that it runs smoothly on Android so it looks like an iOS-specific problem.
EDIT: part of the code
_onSwitch = (id, switched) => {
let newFilter = { status: null };
if (!switched) {
newFilter = { status: id };
}
this.props.changeFilter(newFilter); // calls the action creator
};
_renderItem = ({ item }) => {
const switched = this.props.currentFilter === item.id; // the state mapped to a prop
return (
<ListItem
switchButton
switched={switched}
onSwitch={() => this._onSwitch(item.id, switched)}
/>
);
};
I want to border margin of of screen S on phone and tablet to be different. There are variants for tablet landscape and portrait mode.
How to create different margin dimension for the variants on phone, tablet portrait, tablet landscape ?
For those curious how to do on Android , we just create some resource files at the right folder :
values for default
values-sw600dp for tablet default
values-sw600dp-land for tablet landscape
The other answers have already addressed the screen detection task. However, there is still the issue of detecting if the code is running on a Tablet device. You can detect that using the react-native-device-info package, in particular its isTablet method. So, as an example, in your component:
constructor(){
super();
this.state = {orientation: 'UNKNOWN'}
this._onOrientationChanged = this._onOrientationChanged.bind(this);
}
_onOrientationChanged(orientation){
this._setState({orientation})
}
componentDidMount(){
Orientation.addOrientationListener(this._onOrientationChanged);
}
componentWillUnmount(){
Orientation.removeOrientationListener(this._orientationDidChange);
}
render(){
let layoutStyles;
if(DeviceInfo.isTablet()){
layoutStyles = this.state.orientation == 'LANDSCAPE' ? landscapeTabletStyle : portraitTabletLandscape; // Basic example, this might get more complex if you account for UNKNOWN or PORTRAITUPSIDEDOWN
}else{
layoutStyles = this.state.orientation == 'LANDSCAPE' ? landscapeStyle : portraitLandscape;
}
render(){
<View style={[styles.container, layoutStyles]} // And so on...
}
}
Note that the state holds the UNKNOWN value on the beginning. Have a look at the getInitialOrientation() of the package function. I am intentionally leaving that bit out because it simply reads a property that is set when the JS code loads, and I am not sure if that satisfies your usecase (i.e. this is not your first screen). What I usually like to do is store the rotation value in a redux store (where I initialize the orientation value to that of getInitialOrientation() and then subscribe only once to the orientation listener).
I think this library will be helpful for you: https://github.com/yamill/react-native-orientation
You can do something like that with it:
Orientation.getOrientation((err,orientation)=> {
console.log("Current Device Orientation: ", orientation);
if(orientation === 'LANDSCAPE') {
//do stuff
} else {
//do other stuff
}
});
// Extract from the root element in our app's index.js
class App extends Component {
_onLayout = event => this.props.appLayout(event.nativeEvent.layout);
render() {
return (
<View onLayout={this._onLayout}>
{/* Subviews... */}
</View>
);
}
}
export const SET_ORIENTATION = 'deviceStatus/SET_ORIENTATION';
export function appLayout(event: {width:number, height:number}):StoreAction {
const { width, height } = event;
const orientation = (width > height) ? 'LANDSCAPE' : 'PORTRAIT';
return { type: SET_ORIENTATION, payload: orientation };
}
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