GROUP BY in CROSS APPLY - sql

Question

Let us have two tables
create table A (
fkb int,
groupby int
);
create table B (
id int,
search int
);
insert into A values (1, 1);
insert into B values (1, 1);
insert into B values (2, 1);
then the following query
select B.id, t.max_groupby - B.search diff
from B
cross apply (
select max(A.groupby) max_groupby
from A
where A.fkb = B.id
) t
return the expected result as follows
id diff
---------
1 0
2 NULL
However, when I add the group by A.fkb into the cross apply, the B row where the corresponding A.fkb does not exist, disappear.
select B.id, t.max_groupby - B.search diff
from B
cross apply (
select max(A.groupby) max_groupby
from A
where A.fkb = B.id
group by A.fkb
) t
I was testing on SQL Server as well as on PostgreSQL (with cross join lateral instead of cross apply). Why the group by makes the row disappear? It seems that the cross apply behaves as an outer join in the first case and as an inner join in the latter case. However, it is not clear to me why.

Answer 1

You can see this when you look at the result of the inner query separately:
select max(A.groupby) max_groupby
from A
where A.fkb = 2;
returns a single row with max_groupby = null:
max_groupby
-----------
(null)
However as there is no row with A.fkb = 2 grouping by it yields an empty result which you can see when you run:
select max(A.groupby) max_groupby
from A
where A.fkb = 2
group by A.fkb
and thus the cross join does not return return rows for fkb = 2
You need to use an outer join in order to include the row from B.
In Postgres you would have to write this as:
select B.id, t.max_groupby - B.search diff
from B
left join lateral (
select max(A.groupby) max_groupby
from A
where A.fkb = B.id
group by A.fkb
) t on true
I don't know what the equivalent to left join lateral would be in SQL Server. on true would need to be written as on 1=1.

Answer 2

It happens because:
GROUP BY returns nothing when A.fkb = 2
without GROUP BY returns NULL
So your query CROSS APPLY returns different results.
select B.id, t.max_groupby - B.search diff
from B
outer apply (
select max(A.groupby) max_groupby
from A
where A.fkb = B.id
group by A.fkb
) t
OUTPUT:
id diff
1 0
2 NULL