I'm creating a form in laravel, and want to create condition on radio buttons to display relevant input fields. For example, if any one select quantity radio button an input field should appear for entering quantity.
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Requirement :
1.I have one add button while clicking that button I need to show one dropdown with three options like (A,B,C) beside that one input text field and delete icon need to show. Consider I have choosen option 'A'.
Note :- Clicking this delete icon will delete the entire row.
2.When I click again Add button then I need to show one more dropdown below the previous one with two options like (B,C) beside that one input text field and delete icon need to show.
Note :- Option selected in previous dropdown won't show in here. Consider I have choosen option 'B'. Clicking this delete icon will delete the entire row.
3.When I click again Add button then I need to show one more dropdown below the previous one with only one option like (C) beside that one input text field and delete icon need to show.
Note :- Option selected in previous two dropdown won't show in here.
Clicking this delete icon will delete the entire row.
4.If user click again Add button then one error message will show only three items can add.
I'm absolute beginner in Vue.Js. I've got stock in this feature in Vue.Js and I would really appreciate your efforts. Thank you!
In my access database, I have 2 seperate forms. The first one has 5 buttons and the other one is filled with comboboxes. Each combobox has 5 different columns to chose from.
I wanna be able to just click on a button and be sent to the other from with the correct column/data piece being shown on my combobox.
The left one is the first form with the buttons, the right one is the form with all of the comboboxes
I have a form panel having fields like textfield and radio buttons.There are some conditions to hide textfield as per the radio button value.
have added custom validation to textfield.Suppose i have enter a invalid value to a text filed, then i clicked the radio button. as per my condition that invalid text field is now invisible.
Except that invisible field all other fields are valid. Now i want to submit the form data.
Is it possible to ignore the invisible field while submitting the form panel data.?
Thanks
Set the field not only to hidden as also to disabled, that will solve this. Or as mentioned in the comment if you just use a custom validation return true.
So I have a page with multiple input forms; is it possible to submit all these forms AT THE SAME TIME with one submit button? Also, each form has its own checkbox, and I want it so that if it is checked, it will NOT submit the data within that form to the PHP script. If the checkbox IS checked, I want it to submit the data within that form. Is this possible?
You could use AJAX or join all forms in one, which u will submit.
I want to have a repeater like DataView or ListView. The first column of each row (named User ID) should be read from a List, and for each user ID, the program should dynamically create three radio buttons like these:
Requirements:
The user must able to change selection of radio buttons.
When the user clicks the submit button, radio values be displayed using the info("") method.
I've already done this by using this example, but when I click the submit button, old selections are shown, and the form gets reset to those old selections.
This example code might be helpful.
ListView doesn't play very well with form components, but it may work if you call ListView.setReuseItems(true);.