I want to create a random selected cross-joined table which auto increments its own id and joins on it.
Let's say my tables looking like this.
Person
Firstname, Lastname
Hans | Müller
Joachim | Bugert
Address
City, Street, StreetNumber
Hamburg | Wandsbeckerstr. | 2
Berlin | Konradstraße | 13
Now I want to join the tables with a auto generated ID and they should be random selected.
The final table should look like this
ID,Firstname,Lastname, City, Street, StreetNumber
1 |Hans|Bugert|Berlin|Wandsbeckerstr|2
2|Joachim|Müller|Hamburg|Konradstraße | 13
What I already tried or used:
Here I auto-generate the ID where I want to join the tables on
select GENERATED_PERIOD_START as ID FROM SERIES_GENERATE_INTEGER(1,1,10)
The problem is cross join and inner join isn't working for me because it always joins everything with everything or its not joining on the same ID.
SELECT Person."Firstname", Person."Lastname", Address."City",Address."Street", Address."StreetNumber"
FROM
( select GENERATED_PERIOD_START as ID FROM SERIES_GENERATE_INTEGER(1,1,10)
) autoGenID
inner JOIN
(select "Firstname" ,"Lastname" FROM Person ORDER BY RAND()) Person
inner JOIN
(select "City", "Street", "StreetNumber", FROM Address ORDER BY RAND()) Address
JOIN ON autoGenID."ID"=?????
Here is my problem I can't just select random data and select that on my auto generated ID.
Thanks for your help or ideas how to solve this!
I think you want:
SELECT p."Firstname", p."Lastname", a."City", a."Street", a."StreetNumber"
FROM (SELECT p.*,
ROW_NUMBER() OVER (ORDER BY RAND()) as seqnum
FROM Person p
) p JOIN
(SELECT a.*,
ROW_NUMBER() OVER (ORDER BY RAND()) as seqnum
FROM Address a
) a
ON p.seqnum = a.seqnum;
Related
i got an Address Table with Primary and Secondary Company locations, example:
ADDRESSES:
ID CompanyName AdressType MainID Location
1 ExampleCompany H 0 Germany
2 ExampleCompany N 1 Sweden
3 ExampleCompany N 1 Germany
and we got another Contacts Table including the latest Contact to each of the Company Locations
Contacts
ID SuperID Datecreate Notes
1 1 10.04.2018 XY
2 3 09.04.2018 YX
3 2 11.04.2018 XX
Now we want to select the latest Contact per Company and sort them so we got a list of all our customers that we did not contact in a long time.
i thought about something like this:
SELECT
ADDRH.ID,
ADDRH.COMPANY1,
TOPCONT.ID,
TOPCONT.DATECREATE,
TOPCONT.NOTES0
FROM dbo.ADDRESSES ADDRH
OUTER APPLY (SELECT TOP 1 ID, SUPERID, DATECREATE, CREATEDBY, NOTES0 FROM DBO.CONTACTS CONT WHERE ADDRH.ID = CONT.SUPERID ORDER BY DATECREATE DESC) TOPCONT
WHERE
TOPCONT.ID IS NOT NULL
ORDER BY TOPCONT.DATECREATE
But this is still missing the fact that we got the same company multiple times in the addresses table. how can i create a list that got each company with the latest contact?
Thanks for your help
Greetings
Well, you have to remove duplicates from address as well. Because of the structure of your data, I think the best approach is to use row_number():
SELECT ac.*
FROM (SELECT a.ID, a.COMPANY1, c.ID, c.DATECREATE, c.NOTES0,
ROW_NUMBER() OVER (PARTITION BY a.COMPANY1 ORDER BY c.DATECREATE DESC) as seqnum
FROM dbo.ADDRESSES a JOIN
DBO.CONTACTS c
ON a.ID = c.SUPERID
WHERE c.ID IS NOT NULL
) ac
WHERE seqnum = 1
ORDER BY c.DATECREATE;
I have tables:
Person
-------------
ID | name
Notes
---------------------------
targetID | Content | Date
CallHistory
--------------------------
CallerID | CalleeID | Date
Now say I have a Person and a Spouse (which is on the same Person table).
They have corresponding notes and callhistory.
What I want is to Select the most recent date from either the spouse or person's most recent date (call or note)
Ive tried:
SELECT top 1 Date, ID from (select TargetID as ID, Date from notes
union
SELECT CalleeID as ID, Date from Callhistory)
WHERE ID in (person.ID, spouse.ID)
but without luck.
EDIT: This select is inside a select statement:
select p.*, SELECT top 1 Date, ID from (select TargetID as ID, Date from notes
union
SELECT CalleeID as ID, Date from Callhistory)
WHERE ID in (person.ID, spouse.ID) as RecentContactDate
From Person person
LEFT JOIN PersonRelationship pr on person.ID = pr.ID AND pr.Type = 3 -- spouse
LEFT JOIN Person spouse on pr.RelatedID = spouse.ID
......
Im getting Ambigous column name Date error.
any ideas?
#Sven's answer on this post has helped me solve my problem: SQL MAX of multiple columns?
What I've done is join the two tables from the two persons into a single row (need to get the MAX dates for each person's tables - CallHistory and Notes). Then get the MAX out of that four columns. So here's the fix:
select p.*,
(SELECT Max(v)
FROM (VALUES (pNote.Date), (pCh.Date), (sNote.Date),(sCh.Date)) AS value(v)) as [MaxDate]
WHERE ID in (person.ID, spouse.ID) as RecentContactDate
From Person person
LEFT JOIN PersonRelationship pr on person.ID = pr.ID AND pr.Type = 3 -- spouse
LEFT JOIN Person spouse on pr.RelatedID = spouse.ID
LEFT JOIN (SELECT ID, MAX(Date) from Notes) pNote on pNote.targetID = person.ID
LEFT JOIN (SELECT ID, MAX(Date) from CallHistory) pCh on person.ID = ch.CalleeID
LEFT JOIN (SELECT ID, MAX(Date) from Notes) sNote on spouse.ID = pNote.targetID
LEFT JOIN (SELECT ID, MAX(Date) from CallHistory) sCh on spouse.ID = ch.CalleeID
I hope this will help anyone in the future.
I have 3 tables:
Person (with a column PersonKey)
Telephone (with columns Tel_NumberKey, Tel_Number, Tel_NumberType e.g. 1=home, 2=mobile)
xref_Person+Telephone (columns PersonKey, Tel_NumberKey, CreatedDate, ModifiedDate)
I'm looking to get the most recent (e.g. the highest Tel_NumberKey) from the xref_Person+Telephone for each Person and use that Tel_NumberKey to get the actual Tel_Number from the Telephone table.
The problem I am having is that I keep getting duplicates for the same Tel_NumberKey. I also need to be sure I get both the home and mobile from the Telephone table, which I've been looking to do via 2 individual joins for each Tel_NumberType - again getting duplicates.
Been trying the following but to no avail:
-- For HOME
SELECT
p.PersonKey, pn.Phone_Number, pn.Tel_NumberKey
FROM
Persons AS p
INNER JOIN
xref_Person+Telephone AS x ON p.PersonKey = x.PersonKey
INNER JOIN
Telephone AS pn ON x.Tel_NumberKey = pn.Tel_NumberKey
WHERE
pn.Tel_NumberType = 1 -- e.g. Home phone number
AND pn.Tel_NumberKey = (SELECT MAX(pn1.Tel_NumberKey) AS Tel_NumberKey
FROM Person AS p1
INNER JOIN xref_Person+Telephone AS x1 ON p1.PersonKey = x1.PersonKey
INNER JOIN Telephone AS pn1 ON x1.Tel_NumberKey = pn1.Tel_NumberKey
WHERE pn1.Tel_NumberType = 1
AND p1.PersonKey = p.PersonKey
AND pn1.Tel_Number = pn.Tel_Number)
ORDER BY
p.PersonKey
And have been looking over the following links but again keep getting duplicates.
SQL select max(date) and corresponding value
How can I SELECT rows with MAX(Column value), DISTINCT by another column in SQL?
SQL Server: SELECT only the rows with MAX(DATE)
Am sure this must be possible but been at this a couple of days and can't believe its that difficult to get the most recent / highest value when referencing 3 tables. Any help greatly appreciated.
select *
from
( SELECT p.PersonKey, pn.Phone_Number, pn.Tel_NumberKey
, row_number() over (partition by p.PersonKey, pn.Phone_Number order by pn.Tel_NumberKey desc) rn
FROM
Persons AS p
INNER JOIN
xref_Person+Telephone AS x ON p.PersonKey = x.PersonKey
INNER JOIN
Telephone AS pn ON x.Tel_NumberKey = pn.Tel_NumberKey
WHERE
pn.Tel_NumberType = 1
) tt
where tt.rn = 1
ORDER BY
tt.PersonKey
you have to use max() function and then you have to order by rownum in descending order like.
select f.empno
from(select max(empno) empno from emp e
group by rownum)f
order by rownum desc
It will give you all employees having highest employee number to lowest employee number. Now implement it with your case then let me know.
I have Parent table and multiple child tables with foreign key constraint.
School Table
School ID EduDetails Genders Address_id EDUTYPE
1 2 M 3 FGN
And the child tables like
Education Details
EDU ID EducationType
2 Online
AKA Name
School Id AKA Name
1 Test School
1 School Test
Gender Table
Gender ID Gender Desc
M Male
I am using Left outer join for the parent and school table to fetch the results.
But My issue is, If AKA table has 5 counts matching the school Id and Gender table has only 1 records for that school Id.
So the results comes with 5 duplicate rows with school Information and also other child table information.
Is there any workaround to fix this issue. I tried using subquery and row_number over by function. But it is not working for me. Can anybody help me to solve this issue.
Thanks in advance for your time in looking this issue.
My required output should be like this
School_id AKA Name GenderDesc EductaionType
1 Test School Male Online
1 School Test
So I need to have Null values for the not matching records.
Since you want all the records in the AKA Name table, I've joined on that getting a Row_Number for each row. Then using that Row_Number, LEFT JOIN on the other tables.
SELECT S.SchoolId,
SA.AKAName,
G.GenderName,
ED.EducationType
FROM School s
JOIN
(SELECT SchoolId,
AKAName,
ROW_NUMBER() OVER (PARTITION BY SchoolId ORDER BY AKAName) rn
FROM SchoolAKA
) SA ON S.SchoolID = SA.SchoolId
LEFT JOIN
(SELECT EDUID,
EducationType,
ROW_NUMBER() OVER (ORDER BY EducationType) rn
FROM EduDetails
) ED ON S.EDUID = ED.EDUID AND SA.rn = ED.rn
LEFT JOIN
(SELECT GenderId,
GenderName,
ROW_NUMBER() OVER (ORDER BY GenderName) rn
FROM Genders
) G ON S.GenderId = G.GenderId AND SA.rn = G.rn
Here is the SQL Fiddle.
And here are the results:
SCHOOLID AKANAME GENDERNAME EDUCATIONTYPE
1 School Test Male Online
1 Test School (null) (null)
I have two tables, and am doing an ordered select on each of them. I wold like to see the results of both orders in one result.
Example (simplified):
"SELECT * FROM table1 ORDER BY visits;"
name|# of visits
----+-----------
AA | 5
BB | 9
CC | 12
.
.
.
"SELECT * FROM table2 ORDER BY spent;"
name|$ spent
----+-------
AA | 20
CC | 30
BB | 50
.
.
.
I want to display the results as two columns so I can visually get a feeling if the most frequent visitors are also the best buyers. (I know this example is bad DB design and not a real scenario. It is an example)
I want to get this:
name by visits|name by spent
--------------+-------------
AA | AA
BB | CC
CC | BB
I am using SQLite.
Select A.Name as NameByVisits, B.Name as NameBySpent
From (Select C.*, RowId as RowNumber From (Select Name From Table1 Order by visits) C) A
Inner Join
(Select D.*, RowId as RowNumber From (Select Name From Table2 Order by spent) D) B
On A.RowNumber = B.RowNumber
Try this
select
ISNULL(ts.rn,tv.rn),
spent.name,
visits.name
from
(select *, (select count(*) rn from spent s where s.value>=spent.value ) rn from spent) ts
full outer join
(select *, (select count(*) rn from visits v where v.visits>=visits.visits ) rn from visits) tv
on ts.rn = tv.rn
order by ISNULL(ts.rn,tv.rn)
It creates a rank for each entry in the source table, and joins the two on their rank. If there are duplicate ranks they will return duplicates in the results.
I know it is not a direct answer, but I was searching for it so in case someone needs it: this is a simpler solution for when the results are only one per column:
select
(select roleid from role where rolename='app.roles/anon') roleid, -- the name of the subselect will be the name of the column
(select userid from users where username='pepe') userid; -- same here
Result:
roleid | userid
--------------------------------------+--------------------------------------
31aa33c4-4e66-4da3-8525-42689e46e635 | 12ad8c95-fbef-4287-9834-7458a4b250ee
For RDBMS that support common table expressions and window functions (e.g., SQL Server, Oracle, PostreSQL), I would use:
WITH most_visited AS
(
SELECT ROW_NUMBER() OVER (ORDER BY num_visits) AS num, name, num_visits
FROM visits
),
most_spent AS
(
SELECT ROW_NUMBER() OVER (ORDER BY amt_spent) AS num, name, amt_spent
FROM spent
)
SELECT mv.name, ms.name
FROM most_visited mv INNER JOIN most_spent ms
ON mv.num = ms.num
ORDER BY mv.num
Just join table1 and table2 with name as key like bellow:
select a.name,
b.name,
a.NumOfVisitField,
b.TotalSpentField
from table1 a
left join table2 b on a.name = b.name