i got an Address Table with Primary and Secondary Company locations, example:
ADDRESSES:
ID CompanyName AdressType MainID Location
1 ExampleCompany H 0 Germany
2 ExampleCompany N 1 Sweden
3 ExampleCompany N 1 Germany
and we got another Contacts Table including the latest Contact to each of the Company Locations
Contacts
ID SuperID Datecreate Notes
1 1 10.04.2018 XY
2 3 09.04.2018 YX
3 2 11.04.2018 XX
Now we want to select the latest Contact per Company and sort them so we got a list of all our customers that we did not contact in a long time.
i thought about something like this:
SELECT
ADDRH.ID,
ADDRH.COMPANY1,
TOPCONT.ID,
TOPCONT.DATECREATE,
TOPCONT.NOTES0
FROM dbo.ADDRESSES ADDRH
OUTER APPLY (SELECT TOP 1 ID, SUPERID, DATECREATE, CREATEDBY, NOTES0 FROM DBO.CONTACTS CONT WHERE ADDRH.ID = CONT.SUPERID ORDER BY DATECREATE DESC) TOPCONT
WHERE
TOPCONT.ID IS NOT NULL
ORDER BY TOPCONT.DATECREATE
But this is still missing the fact that we got the same company multiple times in the addresses table. how can i create a list that got each company with the latest contact?
Thanks for your help
Greetings
Well, you have to remove duplicates from address as well. Because of the structure of your data, I think the best approach is to use row_number():
SELECT ac.*
FROM (SELECT a.ID, a.COMPANY1, c.ID, c.DATECREATE, c.NOTES0,
ROW_NUMBER() OVER (PARTITION BY a.COMPANY1 ORDER BY c.DATECREATE DESC) as seqnum
FROM dbo.ADDRESSES a JOIN
DBO.CONTACTS c
ON a.ID = c.SUPERID
WHERE c.ID IS NOT NULL
) ac
WHERE seqnum = 1
ORDER BY c.DATECREATE;
Related
I try to create a query who select the contacts information (table invoice_contacts), and the adresses (table invoice_adresses) associate to the contact which is the most used in the (table invoice_compta)
For exemple I have two contact :
Mike
John
Mike have 2 adresses :
Paris
London
Mike have 1 invoice with Paris, and 5 invoice with London, so I want the adresse of London associate to Mike.
I have try this query with an subquery which count all adresses associate to the contact for an adresses (with NB_ADRESSES), and select only the biggest (with order by NB_ADRESSES desc and limit 1), it's seem wells but I have an error when I do where ia2.ID_CONTACT = ic.ID_CONTACT ic.ID_CONTACT is not found.. (and I need to associate the contact to the subquery).
select ic.*,
ia.*
from invoice_contacts ic
left join invoice_adresses ia on ia.ID_CONTACT = ic.ID_CONTACT
and ia.ID_ADRESSE in (
select ia3.ID_ADRESSE
from (
select ia2.ID_ADRESSE,
count(*) as NB_ADRESSES
from invoice_adresses ia2
left join invoice_comptas ico on ico.ID_ADRESSE_CONTACT = ia2.ID_ADRESSE
where ia2.ID_CONTACT = ic.ID_CONTACT
group by ia2.ID_ADRESSE
order by NB_ADRESSES desc
limit 1
) as ia3
)
group by ic.ID_CONTACT
order by CONTACT_TITRE asc
I also have try with "exist" or "inner join" instead of "in" but I doesn't find good results, so the best way seems it to be with this query for me, but I don't found the solution.
I hope you will help me :)
Thanks
UPDATE :
So finally I have found an solution with this query :
select ic.*,
ia.*
from invoice_contacts ic
left join invoice_adresses ia on ia.ID_CONTACT = ic.ID_CONTACT
and ia.ID_ADRESSE = (
select ia3.ID_ADRESSE
from (
select ia2.*,
count(*) as NB_ADRESSES
from invoice_adresses ia2
left join invoice_comptas ico on ico.ID_ADRESSE_CONTACT = ia2.ID_ADRESSE
group by ia2.ID_ADRESSE
) as ia3
where ia3.ID_CONTACT = ic.ID_CONTACT
order by NB_ADRESSES desc
limit 1
)
group by ic.ID_CONTACT
order by CONTACT_TITRE asc
Thanks
Let me rephrase the problem as finding the most common contact/address combination for a given invoice.
I find it hard to follow your query and your table naming. But this is the idea:
select contact, address
from (select contact, address, count(*) as cnt,
row_number() over (partition by contact order by count(*) desc) as seqnum
from invoices
group by contact, address
) ca
where seqnum = 1;
The subquery is counting the number of times a given address (or city if you prefer) occur for each contact. The row_number() enumerates these, so the most common one has a value of "1". The outer query then chooses the most common value.
I want to create a random selected cross-joined table which auto increments its own id and joins on it.
Let's say my tables looking like this.
Person
Firstname, Lastname
Hans | Müller
Joachim | Bugert
Address
City, Street, StreetNumber
Hamburg | Wandsbeckerstr. | 2
Berlin | Konradstraße | 13
Now I want to join the tables with a auto generated ID and they should be random selected.
The final table should look like this
ID,Firstname,Lastname, City, Street, StreetNumber
1 |Hans|Bugert|Berlin|Wandsbeckerstr|2
2|Joachim|Müller|Hamburg|Konradstraße | 13
What I already tried or used:
Here I auto-generate the ID where I want to join the tables on
select GENERATED_PERIOD_START as ID FROM SERIES_GENERATE_INTEGER(1,1,10)
The problem is cross join and inner join isn't working for me because it always joins everything with everything or its not joining on the same ID.
SELECT Person."Firstname", Person."Lastname", Address."City",Address."Street", Address."StreetNumber"
FROM
( select GENERATED_PERIOD_START as ID FROM SERIES_GENERATE_INTEGER(1,1,10)
) autoGenID
inner JOIN
(select "Firstname" ,"Lastname" FROM Person ORDER BY RAND()) Person
inner JOIN
(select "City", "Street", "StreetNumber", FROM Address ORDER BY RAND()) Address
JOIN ON autoGenID."ID"=?????
Here is my problem I can't just select random data and select that on my auto generated ID.
Thanks for your help or ideas how to solve this!
I think you want:
SELECT p."Firstname", p."Lastname", a."City", a."Street", a."StreetNumber"
FROM (SELECT p.*,
ROW_NUMBER() OVER (ORDER BY RAND()) as seqnum
FROM Person p
) p JOIN
(SELECT a.*,
ROW_NUMBER() OVER (ORDER BY RAND()) as seqnum
FROM Address a
) a
ON p.seqnum = a.seqnum;
I have 3 tables. 1 is startups which contains startup id and name, 1 is investor_groups which contains investor id and investor group name, 1 is deals which contains startup_id - The id of the startup that submitted the funding application, and investor_group_id - The id of the investor group that the startup submitted the funding application to.
I have to find the startups which submitted the most applications, and the names of the groups they applied to.
What I'm trying to do is -
SELECT S.name AS Startup_name, COUNT(S.name) as num
FROM deals D
INNER JOIN startups S ON D.startup_id = S.id
INNER JOIN investor_groups I ON D.investor_group_id = I.id
GROUP BY Startup_name
ORDER BY num DESC
LIMIT 2
But this is giving me the result as -
startup_name, num
HJ Inc, 3
smoothies, 3
What I want is -
startup_name, investor_name
HJ Inc, abc
HJ Inc , def
HJ Inc , ghi
smoothies, xyz
smoothies, rst
smoothies, lmn
When I am adding Investor group names in the SELECT statement, its showing me an error that Investor group names need to be in a GROUP BY statement.
The sample data from the tables -
For table 'startups'
startups
For table 'investor_groups'
investor_groups
For table 'deals'
deals
You could try using count() over()
SELECT
S.name AS Startup_name
, I.name AS investor_name
, COUNT(*) over(partition by S.name) AS num
FROM deals D
INNER JOIN startups S ON D.startup_id = S.id
INNER JOIN investor_groups I ON D.investor_group_id = I.id
ORDER BY num DESC, Startup_name, investor_name
I've got 2 tables, one with sales and one with companies:
Sales Table
Transaction_Id Shop_id Sale_date Client_ID
92356 24234 11.09.2018 12356
92345 32121 11.09.2018 32121
94323 24321 11.09.2018 21231
94278 45321 11.09.2018 42123
Company table
Client_ID Company_name
12345 ABC
13322 ABC
32321 BCD
22221 BCD
What I want to achieve is distinct count of Clients from each Company for each pair of shops(Clients who had at least 1 transaction in both of shops) :
Shop_Id_1 Shop_id_2 Company_name Count(distinct Client_id)
12356 12345 ABC 31
12345 14278 ABC 23
14323 12345 BCD 32
14278 12345 BCD 43
I think that I have to use self join, but my queries even with filter for one week is killing DB, any thoughts on that? I'm using Microsoft SQL server 2012.
Thanks
I think this is a self-join and aggregation, with a twist. The twist is that you want to include the company in each sales record, so it can be used in the self-join:
with sc as (
select s.*, c.company_name
from sales s join
companies c
on s.client_id = c.client_id
)
select sc1.shop_id, sc2.shop_id, sc1.company_name, count(distinct sc1.client_id)
from sc sc1 join
sc sc2
on sc1.client_id = sc2.client_id and
sc1.company_name = sc2.company_name
group by sc1.shop_id, sc2.shop_id, sc1.company_name;
I think there are some issues with your question. I interpreted it as such that the company table contains the shop ID's, not the ClienId's.
First you can create a solution to get the shops as rows for each company. Here I chose a maximum of 5 shops per company. Don't forget the semicolon in the previous statement before the cte's.
WITH CTE_Comp AS
(
SELECT *, ROW_NUMBER() OVER (PARTITION BY CompanyName ORDER BY ShopID) AS RowNumb
FROM Company AS C
)
SELECT C1.ShopID,
C2.ShopID AS ShopID_2,
C3.ShopID AS ShopID_3,
C4.ShopID AS ShopID_4,
C5.ShopID AS ShopID_5,
C1.CompanyName
INTO ShopsByCompany
FROM CTE_Comp AS C1
LEFT JOIN CTE_Comp AS C2 ON C1.CompanyName= C2.CompanyName AND RowNumb = 2
LEFT JOIN CTE_Comp AS C2 ON C1.CompanyName= C3.CompanyName AND RowNumb = 3
LEFT JOIN CTE_Comp AS C2 ON C1.CompanyName= C4.CompanyName AND RowNumb = 4
LEFT JOIN CTE_Comp AS C2 ON C1.CompanyName= C5.CompanyName AND RowNumb = 5
WHERE C1.RowNumb = 1
After that, in a few steps, I think you could get the desired result:
WITH ClientsPerShop AS
(
SELECT ShopID,
COUNT (DISTINCT ClientID) AS TotalClients
FROM Sales
GROUP BY ShopID
)
, ClienstsPerCompany AS
(
SELECT CompanyName,
SUM (TotalClients) AS ClientsPerComp
FROM Company AS C
INNER JOIN ClientsPerShop AS CPS ON C.ShopID = CPS.ShopID
GROUP BY CompanyName
)
SELECT *
FROM ClienstsPerCompany AS CPA
INNER JOIN ShopsByCompany AS SBC ON SBC.CompanyName = CPA.CompanyName
Hopefully this will bring you closer to your solution, best of luck!
I have Parent table and multiple child tables with foreign key constraint.
School Table
School ID EduDetails Genders Address_id EDUTYPE
1 2 M 3 FGN
And the child tables like
Education Details
EDU ID EducationType
2 Online
AKA Name
School Id AKA Name
1 Test School
1 School Test
Gender Table
Gender ID Gender Desc
M Male
I am using Left outer join for the parent and school table to fetch the results.
But My issue is, If AKA table has 5 counts matching the school Id and Gender table has only 1 records for that school Id.
So the results comes with 5 duplicate rows with school Information and also other child table information.
Is there any workaround to fix this issue. I tried using subquery and row_number over by function. But it is not working for me. Can anybody help me to solve this issue.
Thanks in advance for your time in looking this issue.
My required output should be like this
School_id AKA Name GenderDesc EductaionType
1 Test School Male Online
1 School Test
So I need to have Null values for the not matching records.
Since you want all the records in the AKA Name table, I've joined on that getting a Row_Number for each row. Then using that Row_Number, LEFT JOIN on the other tables.
SELECT S.SchoolId,
SA.AKAName,
G.GenderName,
ED.EducationType
FROM School s
JOIN
(SELECT SchoolId,
AKAName,
ROW_NUMBER() OVER (PARTITION BY SchoolId ORDER BY AKAName) rn
FROM SchoolAKA
) SA ON S.SchoolID = SA.SchoolId
LEFT JOIN
(SELECT EDUID,
EducationType,
ROW_NUMBER() OVER (ORDER BY EducationType) rn
FROM EduDetails
) ED ON S.EDUID = ED.EDUID AND SA.rn = ED.rn
LEFT JOIN
(SELECT GenderId,
GenderName,
ROW_NUMBER() OVER (ORDER BY GenderName) rn
FROM Genders
) G ON S.GenderId = G.GenderId AND SA.rn = G.rn
Here is the SQL Fiddle.
And here are the results:
SCHOOLID AKANAME GENDERNAME EDUCATIONTYPE
1 School Test Male Online
1 Test School (null) (null)