Im using cat /etc/inetd.conf | grep '#'chargen
and I receive
#chargen stream tcp nowait root internal
#chargen dgram udp wait root internal
how I can extract only once word #chargen from this output:
#chargen
Could you please try following.
awk '/^#chargen/{print $1; exit}' Input_file
or
grep -m1 -o '#chargen' /etc/inetd.conf
Related
Problem Set (Raspberry Pi OS):
I have a file example.conf that contains a line IPv4addr=XXXXX. I am attempting to change this to the IP that is generated the in the command
ipTest=$(ip --brief a show | grep eth0 | awk '{ print $3 }')
I want to automate this file change during a script install.sh, the line I am attempting is:
IPtest=$(ip --brief a show | grep eth0 | awk '{ print $3 }')
sudo sed -e "/IPv4addr/s/[^=]*$/$IPtest/" example.conf
Returns error:
sed: -e expression #1, char 32: unknown option to `s'
A simple line in that code works, such as SimpleTest='Works'
Any thoughts? I am open to other solutions as well, however I am not an experienced linux user so I am using the tools I know to work with other problem sets.
$IPtest contains the / character; try something like this:
IPtest=$(ip --brief a show | grep eth0 | awk '{ print $3 }')
sudo sed -e '/IPv4addr/s#[^=]*$#'"$IPtest"'#' example.conf
You can shorten your variable and allow awk to do the job of grep at the same time
IPtest=$(ip --brief a s | awk '/eth0/{print $3}')
Using sed grouping and back referencing
sed -i.bak "s|\([^=]*.\).*|\1$IPtest|" example.conf
I've searched all over and couldn't find a solution.
How would I awk or grep the following:
$ mbimcli -d /dev/cdc-wdm0 -p --query-ip-configuration
[/dev/cdc-wdm0] IPv4 configuration available: 'address, gateway, dns'
IP [0]: '11.22.333.44/55'
Gateway: '14.13.198.4'
DNS [0]: '172.17.1.101'
DNS [1]: '172.17.1.102'
DNS [2]: '172.17.1.101'
DNS [3]: '172.17.1.102'
So that I end up with:
11.22.33.44/55
I've tried a bunch of different combinations with both grep and awk and couldn't find a solution.
Using cat file as I don't have mbimcli -d /dev/cdc-wdm0 -p --query-ip-configuration:
$ cat file | awk -F"'" '/IP \[/{print $2}'
11.22.333.44/55
$ cat file | awk -F"'" '/Gateway/{print $2}'
14.13.198.4
or maybe this is all you need if the output of that command always looks like the example you posted:
$ cat file | awk -v RS= -F"'" '{print $5}'
11.22.333.44/55
$ cat file | awk -v RS= -F"'" '{print $8}'
14.13.198.4
You can do this in a single awk:
mbimcli -d /dev/cdc-wdm0 -p --query-ip-configuration |
awk '$1 == "IP" {gsub(/\047/, "", $NF); print $NF}'
11.22.333.44/55
something like this:
grep '[0-9]' file_with_text | awk '{print $NF}
grep [0-9] only lines with numbers and pipe the output into awk.
The $NF will return the last element.
If you want only the line that has the /, just add it to grep [0-9]/.
Also, for a complete answer, you can pipe the output of the command into grep:
mbimcli -d /dev/cdc-wdm0 -p --query-ip-configuration | grep '[0-9]/' | awk '{print $NF}
I would harness tr for preprocessing and GNU AWK for processing, let file.txt content be
IP [0]: '11.22.333.44/55'
Gateway: '14.13.198.4'
DNS [0]: '172.17.1.101'
DNS [1]: '172.17.1.102'
DNS [2]: '172.17.1.101'
DNS [3]: '172.17.1.102'
then
cat file.txt | tr -d "'" | awk '/IP/{print $NF}'
output
11.22.333.44/55
Explanation: use tr to delete ' then awk to print last column ($NF) if row contain IP.
(tested in tr (GNU coreutils) 8.30 and GNU Awk 5.0.1)
I want print only port number 8443, using below command but unfortunately my command was not helping me to print only port number.
$ netstat -tupln | grep '8443' | awk --field-separator=":" '{print $2}'
8443 0.0.0.0
Can you please some one help me on this?
You can use a pattern as your field separator:
netstat -tupln | awk -F '[ :]+' '/8443/{print $5}'
The Xcode console has a 'Debugger output' filter. I understand this is for use with lldb, and that you can get messages to print to this output by using breakpoints. My question is not how to do that.
My question is: what is the underlying mechanism Xcode itself uses to write lldb messages to Debugger Output (not Target Output)? Is there a variable similar to stdout or stderr that writes here? Is it possible, from Xcode target code (Swift/Obj-C/C), to write to this output?
Looks like Xcode uses a tty to communicate with lldb, and you can interface with the Debugger Output using that:
echo "Wheeeeeeee" > $(lsof -p $(ps -A | grep -m1 MacOS/Xcode | awk '{print $1}') | grep -m2 dev/ttys | tail -1 | awk '{print $9}')
Breaking the above down:
$ ps -A | grep -m1 MacOS/Xcode | awk '{print $1}'
21280
This gives the process ID of Xcode (21280). Using this, we can find the files it has open:
$ lsof -p 21280 | grep /dev/ttys
Xcode 21280 tres 47u CHR 16,3 0t0 3569 /dev/ttys003
Xcode 21280 tres 58u CHR 16,5 0t0 3575 /dev/ttys005
The one with the highest number (/dev/ttys005 in this case) is the one we want, so let's extract it. tail -1 will give us the last line of output, and awk '{print $9}' will give us the 9th item on the line, which is what we want!
$ lsof -p 21280 | grep /dev/ttys | tail -1 | awk '{print $9}'
/dev/ttys005
Now we can use this to write whatever we want:
I am trying to create an Ansible playbook to pull out MTU size for exact NIC (unfortunately i have 5k VMs and this exact NIC does not have the same name on all VMs). I need to parse IP from file to variable and grep by that.
My command i will use in playbook:
/sbin/ifconfig -a | grep -C 1 $IP | grep MTU | awk '{print $5}' | cut -c 5-10
And output should be looking like this:
9000
This one gnu awk command should do:
ifconfig -a | awk -v ip="$IP" -v RS= -F'MTU:' '$0~ip {split($2,a," ");print a[1]}'
9216
Another variations
ifconfig -a | awk -v ip="$IP" 'f {split($6,a,":");print a[2];exit} $0~ip{f=1}'
ifconfig -a | awk -v ip="$IP" 'f {print substr($6,5,99);exit} $0~ip{f=1}'
9216