Find the sum of amount for particular transasaction type for 2 consecutive days - sql

Question

I have two tables 1. Transactions and 2. Transaction type
e.g. of transaction table with dummy data
account_key Transaction_key date amount
1 11 03/22/0219 5000
1 12 03/23/2019 6000
1 13 03/22/2019 4000
1 14 03/23/2019 3000
e.g. of Transaction_type table with dummy data
transaction_key transaction_type
11 in
12 in
13 out
14 out
I have to find the ratio of sum of amount for 2 consecutive days of similar transaction type for the same account key. for eg (5000+6000)/(4000+3000)
the database is oracle and datatype is datetime
This is what I have tried
select t1.account_key,
trunc(t1.date),
sum(t1.amount) as in,
sum(t2.amount) as out
from transactions t1
inner join transactions t2 on t1.accountkey=t2.accountkey
where t1.date between '01-jun-2017' and '30-nov-2017'
and t2.date between '01-jun-2017' and '30-nov-2017'
and t1.transaction_key in (select a.transaction_key
from transaction_type a
where a.transaction type in 'in')
and t2.transaction_key in (select b.transaction_key
from transaction_type b
where b.transaction type in 'out')
group by t1.account_key,
trunc(t1.date)
having max(trunc(t1.date))-min(trunc(t1.date)) = 1
and max(trunc(t2.date))-min(trunc(t2.date)) = 1

Answer 1

You can use a WITH clause, also called a "common table expression" or "CTE" to break your problem down into manageable chunks.
Here is one way to do that:
WITH txn_by_date AS (
SELECT t.account_key,
t.txn_date,
tt.transaction_type,
sum(t.amount) amount
FROM txns t
INNER JOIN txn_types tt on tt.transaction_key = t.transaction_key
GROUP BY t.account_key, t.txn_date, tt.transaction_type )
SELECT tin.account_key,
tin.txn_date,
tin.amount amount_in,
tout.txn_date,
tout.amount amount_out,
tin.amount / tout.amount ratio
FROM txn_by_date tin
INNER JOIN txn_by_date tout ON tout.txn_date = tin.txn_date + 1
AND tout.transaction_type = 'out'
AND tout.account_key = tin.account_key
WHERE tin.transaction_type = 'in';
The CTE first computes the total txn amount by account, transaction type, and day. Once you have that, the main SELECT gets each 'in' total, joins it with the 'out' total from the consecutive day, and the computes the ratio.
Here is a full example, with test data (also expressed using the WITH clause):
with txns (account_key, Transaction_key, txn_date, amount) AS
(
SELECT 1, 11, TO_DATE('03/22/2019','MM/DD/YYYY'), 5000 FROM DUAL UNION ALL
SELECT 1, 12, TO_DATE('03/23/2019','MM/DD/YYYY'), 6000 FROM DUAL UNION ALL
SELECT 1, 13, TO_DATE('03/22/2019','MM/DD/YYYY'), 4000 FROM DUAL UNION ALL
SELECT 1, 14, TO_DATE('03/23/2019','MM/DD/YYYY'), 3000 FROM DUAL ),
txn_types ( transaction_key, transaction_type ) AS
(
SELECT 11, 'in' FROM DUAL UNION ALL
SELECT 12, 'out' FROM DUAL UNION ALL
SELECT 13, 'in' FROM DUAL UNION ALL
SELECT 14, 'out' FROM DUAL ),
txn_by_date AS (
SELECT t.account_key,
t.txn_date,
tt.transaction_type,
sum(t.amount) amount
FROM txns t
INNER JOIN txn_types tt on tt.transaction_key = t.transaction_key
GROUP BY t.account_key, t.txn_date, tt.transaction_type )
SELECT tin.account_key,
tin.txn_date,
tin.amount amount_in,
tout.txn_date,
tout.amount amount_out,
tin.amount / tout.amount ratio
FROM txn_by_date tin
INNER JOIN txn_by_date tout ON tout.txn_date = tin.txn_date + 1
AND tout.transaction_type = 'out'
AND tout.account_key = tin.account_key
WHERE tin.transaction_type = 'in';
+-------------+-----------+-----------+------------+------------+-------+
| ACCOUNT_KEY | TXN_DATE | AMOUNT_IN | TXN_DATE_1 | AMOUNT_OUT | RATIO |
+-------------+-----------+-----------+------------+------------+-------+
| 1 | 22-MAR-19 | 9000 | 23-MAR-19 | 9000 | 1 |
+-------------+-----------+-----------+------------+------------+-------+
ALTERNATE VERSION, FOR ANCIENT VERSIONS OF ORACLE
For really old versions of Oracle, you may need to avoid both the WITH clause and ANSI-style joins. Here is the above query rewritten to avoid those features.
SELECT tin.account_key,
tin.txn_date,
tin.amount amount_in,
tout.txn_date,
tout.amount amount_out,
tin.amount / tout.amount ratio
FROM ( SELECT t.account_key,
t.txn_date,
tt.transaction_type,
sum(t.amount) amount
FROM txns t,
txn_types tt
WHERE tt.transaction_key = t.transaction_key
GROUP BY t.account_key, t.txn_date, tt.transaction_type ) tin,
( SELECT t.account_key,
t.txn_date,
tt.transaction_type,
sum(t.amount) amount
FROM txns t,
txn_types tt
WHERE tt.transaction_key = t.transaction_key
GROUP BY t.account_key, t.txn_date, tt.transaction_type ) tout
WHERE tin.transaction_type = 'in'
AND tout.transaction_type(+) = 'out'
AND tout.account_key(+) = tin.account_key;

Answer 2

I would try to use to Temporary Tables. Store the sums of each in Transaction type in two temp tables, then use them to calculate your ratio. I have not tested this query but this is basically what you are looking for:
CREATE PRIVATE TEMPORARY TABLE as In_TempTable
Select T2.Transaction_Type, sum(T1.amount) In_Total
from Transactions T1
left join Transaction_Type T2 on T2.Transaction_key = T1.Transaction_Key
where T1.date between '01-jun-2017' and '30-nov-2017'
AND T2.Transactio_Type = 'In'
group by T2.Transaction_Type;
CREATE PRIVATE TEMPORARY TABLE as Out_TempTable
Select T2.Transaction_Type, sum(T1.amount) Out_Total
from Transactions T1
left join Transaction_Type T2 on T2.Transaction_key = T1.Transaction_Key
where T1.date between '01-jun-2017' and '30-nov-2017'
AND T2.Transactio_Type = 'Out'
group by T2.Transaction_Type;
Select Sum(a.In_Total)/Sum(b.Out_Total)
from In_TempTable a
Full Outer Join Out_TempTable b on b.Transaction_Type = a.Transaction_Type
I would personally change this:
T1.date between '01-jun-2017' and '30-nov-2017'
To something like this
T1.date between startdate and startdate+2
Depending on your needs of course and you will have to declare your startdate