Results of multiple queries with aggregates combined - sql

Question

I have 2 seperate select statements, using aggregate functions in each. I would like to be able to take the results and combine them.
table_a
id int
entered_date datetime (holds utc stamp)
balance money
group_id int
table_b
id int
entered_date date
balance money
transaction_type int
query 1:
select convert(date,entered_date), sum(balance) as earned
from table_a
where group_id in (1, 2, 3, 4)
group by convert(date,entered_Date)
query 2:
select convert(date,entered_date), sum(balance) as spent
where transaction_type = 2
group by convert(date,entered_Date)
results:
query 1:
2012-05-13, 5000
2012-05-14, 12000
...
query 2:
2012-05-13, 9000
2012-05-14, 55856
...
I would like to return one row for each record without using temp tables. The result set should have a date, then earned vs. spent. I have a report running using union to get the totals and that is fine, but i need to generate a result set with 1 record and a earned vs against line. Any help with this is appreciated.

Answer 1

Try:
;With AllDates AS
(
select convert(date,entered_date) As EnteredDate
from table_a
where group_id in (1, 2, 3, 4)
group by convert(date,entered_Date)
UNION
select convert(date,entered_date)
from table_b
where transaction_type = 2
group by convert(date,entered_Date)
)
, AllEarned AS (
select convert(date,entered_date) AS EnteredDate, sum(balance) as Earned
from table_a
where group_id in (1, 2, 3, 4)
group by convert(date,entered_Date)
)
, AllSpent AS (
select convert(date,entered_date) AS EnteredDate, sum(balance) as Spent
from table_b
where transaction_type = 2
group by convert(date,entered_Date)
)
SELECT
d.EnteredDate, e.Earned, s.Spent
FROM AllDates d
LEFT OUTER JOIN AllEarned e ON d.EnteredDate=e.EnteredDate
LEFT OUTER JOIN AllSpent s ON d.EnteredDate=s.EnteredDate
ORDER BY 1,2,3

Answer 2

You can combine these using logic, assuming that both are from the same table
(the second query is missing the from statement):
select convert(date,entered_date),
sum(case when group_id in (1, 2, 3, 4) then balance end) as earned,
sum(case when transaction_type = 2 then balance end) as spend
from table_a
group by convert(date,entered_Date)

Answer 3

SELECT
CASE WHEN a.a_date IS NULL THEN b.a_date ELSE a.a_date END as a_data,
a.earned,
b.spent
FROM
(select
convert(date,entered_date) as a_date,
sum(balance) as earned
from table_a
where group_id in (1, 2, 3, 4)
group by entered_Date) A
FULL OUTER JOIN
(select
convert(date,entered_date) as a_date,
sum(balance) as spent
from table_a
where transaction_type = 2
group by entered_Date) B
ON A.a_date=b.a_date
Or using FULL OUTER JOIN if there are data that don't meet both conditions. And using CASE WHEN a.a_date IS NULL THEN b.a_date ELSE a.a_date END as a_data

Answer 4

Assuming earned amounts are from table_a and spent amounts are from table_b,
; WITH a AS (
select entered_date=convert(date,entered_date), balance as earned, 0 AS spent
from table_a
where group_id in (1, 2, 3, 4)
UNION ALL
select entered_date=convert(date,entered_date), 0 AS earned, balance as spent
from table_b
where transaction_type = 2
)
SELECT entered_date
, earned=SUM(earned)
, spent=SUM(spent)
FROM a
GROUP BY entered_date