what i'm looking for is a way for a way to check if a string follows a specific format.
Something Like:
if strPhoneNumber = format(XX-XXXX-XXXX) then
MsgBox("Correct")
else
MsgBox("Incorrect")
the specific format is Two Numbers, a Dash, Four Number, A Dash, Four Numbers: eg: 04-9567-3915
Thanks.
You want to parse a Regular Grammar, so use a regular expression:
Dim regex As New Regex( "\d\d\-\d\d\d\d\-\d\d\d\d" );
If regex.IsMatch( strPhoneNumber ) Then
MsgBox("correct")
End If
Related
I am pretty new to using string operations in SQL(Redshift). I want to extract a part of a string from the strings of the following format:
I can have strings of the format:
http://bunnytalks.com/goingOn?name=Bunny&phone=2340
http://bunnytalks.com/goingOn?name=Bunny
http://bunnytalks.com/goingOn?name=Talks/whatson%goingOn%name%Bunny
http://bunnytalks.com/goingOn?name=Talks/whatson%goingOn%name%Bunny&phone=2340
The final output I need from any of the above strings when applying regex:
Bunny
From the above string examples, I can tell that I need a string between the last occurrence of a name followed by either = or % and the end of the string or before &
I need a regex/ any string operations in SQL that can achieve the above operations as shown in examples. Thanks in advance.
Try:
.*name[%=]([^&\n]+)
Regex demo.
.*name - match the last name
[%=] - followed by % or =
([^&\n]+) - match all non-&, non-\n characters as group 1
how do I write a SQL where statement that checks if a string contains some substring and a number. For example:
string: macsea01
where string like 'macsea' plus a number
Regex is the most obvious solution to this question. Without more detail about the specific format of the string, I can suggest the following, which will match a sequence of a letter in the alphabet followed immediately by a digit:
where column_name like '%[a-zA-Z][0-9]%'
If you're literally looking for macsea at the beginning of the string followed by a digit, it would be:
where column_name like 'macsea[0-9]%'
Regex seem to bee a little slippery here, depending on your needs you can for instance divide the string into several parts, first the text part, and take the rest of the string, try to convert it into a number.
Somthing like this (but I think this perticular code is broken
where substring(column_name, 1, 6) = 'macsea' and cast(substring(column_name, 7, 1000) as int) > 0
I am trying to identify a value that is nested in a string using Snowflakes regexp_substr()
The value that I want to access is in quotes:
...
Type:
value: "CategoryA"
...
Edit: This text is nested in a much larger portion of text.
I want to extract CategoryA for all columns using regexp_substr. But I am unsure how.
I have tried:
regexp_substr(col, 'Type\\W+(\\w+)\\W+\\w.+')
and while that gives the portion of the string, I just want what is in quotes and can't figure out how to do so.
You could use regexp_replace() instead:
regexp_replace(col, '(^[^"]*")|("[^"]*$)", '')
The regexp matches on both following conditions, and replaces matching parts with the empty string:
^[^"]*": everything from the beginning of the string to the first double quote
("[^"]*$)": everything from the last double quote to the end of the string
Hi i'm trying to figure out a way to retrieve a word from the like operator.
Ex:
text = "jsoihj a125847 asf"
Dim s as String = text Like "*a######*"
I would like 's' to equal the actual word that has the pattern of " * a###### * " instead of it returning True
As stated in the above comments Like will not give you the string. You could parse the string character by character to find the pattern but this is a natural job for Regex. I am no expert here so I use sites like RegExr to hack out and test the match string.
dim s as string = Regex.Match(text, "([A][0-9])\w+").Value
I'm trying to parse this string 'Smith, Joe M_16282' to get everything before the comma, combined with everything after the underscore.
The resulting string would be: Smith16282
string longName = "Smith, Joe M_16282";
string shortName = longName.Substring(0, longName.IndexOf(",")) + longName.Substring(longName.LastIndexOf("_") + 1);
Notes:
The second "substring" doesn't need a length parameter, because we want everything after the underscore
The LastIndexOf is used instead of IndexOf in case there are other underscores appearing in the name such as "Smith_Jones, Joe M_16282"
This code assumes that there is at least one comma and at least one underscore in the string "longName." If not, the code fails. I will leave that checking to you if you need it.
As others have said, the simple approach for parsing a string like that would be to use the String's various parsing methods, such as IndexOf and SubString. If you want something more powerful and flexible, you may also want to consider using a RegEx replacement. For instance, you could do something like this:
Dim input As String = "Smith, Joe M_16282"
Dim pattern As String = "(.*?),.*?_(.*)"
Dim replacement As String = "$1$2"
Dim output As String = Regex.Replace(input, pattern, replacement)
Or, more simply:
Dim output As String = Regex.Replace("Smith, Joe M_16282", "(.*?),.*?_(.*)", "$1$2")
Here's the meaning of the pattern:
(.*?) - The first group capturing all of the characters before the comma
( - Starts the capturing group
. - This is a wildcard which matches any character
* - Specifies that the previous thing (any character) is repeated any number of times
? - Specifies that the * is non-greedy, meaning it won't match everything until the end of the string--it will only match until it finds the following comma
) - Ends the capturing group
, - The comma to look for
.*? - Says that there will be any number of any characters between the comma and the underscore which we don't care about
. - Any character
* - Any number of times
? - Until you find the underscore
_ - The underscore the look for
(.*) - The second group capturing all of the characters after the underscore
( - Starts the capturing group
. - Any character
* - Any number of times
) - Ends the capturing group
Here's the meaning of the replacement:
$1 - The value of all of the characters found in the first capturing group
$2 - The value of all of the characters found in the second capturing group
RegEx may be overkill for your particular situation, but it is a very handy tool to learn. One major advantage is that you could move the pattern and replacement values out into external settings in the app.config, or somewhere. Then, you could modify the replacement rules without recompiling your application.