Does Kotlin allow you to assign custom value to enum? - kotlin

This is throwing the error: Exception in thread "main" java.lang.IllegalArgumentException: No enum constant Color.red
enum class Color(val value: String = "") {
RED("red"),
YELLOW("yellow"),
BLUE("blue")
}
fun main() {
print(Color.valueOf("red"))
}
The above will only work if I change the print statement to:
print(Color.valueOf("RED"))
Is it possible to use a custom string to assign to an enum value using the valueOf?

As you discovered, the enum valueOf() method looks up by the name of the enum constant, not by any properties you add.
But you can easily add your own lookup method, using whatever criteria you want:
enum class Color(val hue: String) {
RED("red"),
YELLOW("yellow"),
BLUE("blue");
companion object {
fun forHue(hue: String) = values().find{ it.hue == hue }
}
}
A call to Color.forHue("red") returns the Color.RED instance as expected.
(This is probably the simplest approach, but not the most efficient; see answers such as this.)

No, but you can write your own method and get the value by iteration, when, or map.
Also, you cannot override valueOf.

You can implement your own valueOfwhich works case-insensitively:
enum class Color(val value: String = "") {
RED("red"),
YELLOW("yellow"),
BLUE("blue");
companion object {
//TODO: gimme a better name
fun customValueOf(val: String) = valueOf(val.toUpperCase())
}
}

Related

Kotlin delegated property setValue cannot be kept

I am reading this page about Delegated properties in Kotlin doc site.
import kotlin.reflect.KProperty
class Example {
var p: String by Delegate() // 1
override fun toString() = "Example Class"
}
class Delegate() {
operator fun getValue(thisRef: Any?, prop: KProperty<*>): String { // 2
return "$thisRef, thank you for delegating '${prop.name}' to me!"
}
operator fun setValue(thisRef: Any?, prop: KProperty<*>, value: String) { // 2
println("$value has been assigned to ${prop.name} in $thisRef")
}
}
fun main() {
val e = Example()
println(e.p)
e.p = "NEW"
}
The output is:
Example Class, thank you for delegating 'p' to me!
NEW has been assigned to p in Example Class
And I can understand the result.
But my question is, what if I print the e.p again after setting its value as NEW:
fun main() {
val e = Example()
println(e.p)
e.p = "NEW"
println(e.p) // print it again after setting new value on it
}
I expect it to print NEW. But the actual result is, it kept the same as the 1st println: Example Class, thank you for delegating 'p' to me!.
Kotlin playground at here.
Seems like the e.p = "NEW" cannot change the value correctly. What causes that? What do I do if I want to set the value as NEW?
Your delegate class instance completely takes over what the getter and setter of the property do. Since your delegate’s setValue function doesn’t actually store the passed-in value in any internal property, it’s getValue function has no way to retrieve and return it. And indeed, the implementation of getValue() in your code is only generating a String and returning that.
When you get the value of the delegated property, it returns whatever your delegate returns in getValue(), so the behavior is determined by how you program your delegate class.

Difference between member function and property

What is the difference?
val isFinished: Boolean
get() = actor.actions.size == 0
fun isFinished() = actor.actions.size == 0
I have no idea.
I expect them to be the same.
The first statement defines a property and the second statement defines a method.
Assume you define both in a class Foo.
val foo = Foo()
if(foo.isFinished) {} // property
if(foo.isFinished()) {} // method - see () at invocation
Under the hood, both variants call a function.
Class Property
Your first example is a class property:
class MyClass {
val isFinished: Boolean
get() = actor.actions.size == 0
}
This property defines an (optional) explicit get method, often referred to as a "getter". You could also omit the getter and do:
class MyClass {
val isFinished: Boolean = (actor.actions.size == 0) //parens not necessary
}
If omitted, as shown in the last example, the value will rather be a constant value which isn't re-calculated on each access. Both variants serve different use cases but in most cases, the latter will be sufficient.
Regardless, for a client of this class, the property can be accessed like this:
val mc = MyClass()
mc.isFinished
This shows accessing a property in Kotlin.
Class member function
Functions in Kotlin can also define functions, which can be referred to as member functions. Your second example demonstrates this feature:
class MyClass {
fun isFinished() = actor.actions.size == 0
}
Defining a member function is similar to properties with explicit getters but still different for a client, since they have to invoke a function rather than accessing a property:
val mc = MyClass()
mc.isFinished()
Side Note
Note that the shown function utilizes an expression body which is equivalent to the following block body approach:
class MyClass {
fun isFinished() {
return actor.actions.size == 0
}
}
Learn more about functions here.

How do I create an enum from an Int in Kotlin?

I have this enum:
enum class Types(val value: Int) {
FOO(1)
BAR(2)
FOO_BAR(3)
}
How do I create an instance of that enum using an Int?
I tried doing something like this:
val type = Types.valueOf(1)
And I get the error:
Integer literal does not conform to the expected type String
enum class Types(val value: Int) {
FOO(1),
BAR(2),
FOO_BAR(3);
companion object {
fun fromInt(value: Int) = Types.values().first { it.value == value }
}
}
You may want to add a safety check for the range and return null.
Enum#valueOf is based on name. Which means in order to use that, you'd need to use valueof("FOO"). The valueof method consequently takes a String, which explains the error. A String isn't an Int, and types matter. The reason I mentioned what it does too, is so you know this isn't the method you're looking for.
If you want to grab one based on an int value, you need to define your own function to do so. You can get the values in an enum using values(), which returns an Array<Types> in this case. You can use firstOrNull as a safe approach, or first if you prefer an exception over null.
So add a companion object (which are static relative to the enum, so you can call Types.getByValue(1234) (Types.COMPANION.getByValue(1234) from Java) over Types.FOO.getByValue(1234).
companion object {
private val VALUES = values()
fun getByValue(value: Int) = VALUES.firstOrNull { it.value == value }
}
values() returns a new Array every time it's called, which means you should cache it locally to avoid re-creating one every single time you call getByValue. If you call values() when the method is called, you risk re-creating it repeatedly (depending on how many times you actually call it though), which is a waste of memory.
Admittedly, and as discussed in the comments, this may be an insignificant optimization, depending on your use. This means you can also do:
companion object {
fun getByValue(value: Int) = values().firstOrNull { it.value == value }
}
if that's something you'd prefer for readability or some other reason.
The function could also be expanded and check based on multiple parameters, if that's something you want to do. These types of functions aren't limited to one argument.
If you are using integer value only to maintain order, which you need to access correct value, then you don't need any extra code. You can use build in value ordinal. Ordinal represents position of value in enum declaration.
Here is an example:
enum class Types {
FOO, //Types.FOO.ordinal == 0 also position == 0
BAR, //Types.BAR.ordinal == 1 also position == 1
FOO_BAR //Types.FOO_BAR.ordinal == 2 also position == 2
}
You can access ordinal value simply calling:
Types.FOO.ordinal
To get correct value of enum you can simply call:
Types.values()[0] //Returns FOO
Types.values()[1] //Returns BAR
Types.values()[2] //Returns FOO_BAR
Types.values() returns enum values in order accordingly to declaration.
Summary:
Types.values(Types.FOO.ordinal) == Types.FOO //This is true
If integer values don't match order (int_value != enum.ordinal) or you are using different type (string, float...), than you need to iterate and compare your custom values as it was already mentioned in this thread.
It really depends on what you actually want to do.
If you need a specific hardcoded enum value, then you can directly use Types.FOO
If you are receiving the value dynamically from somewhere else in your code, you should try to use the enum type directly in order not to have to perform this kind of conversions
If you are receiving the value from a webservice, there should be something in your deserialization tool to allow this kind of conversion (like Jackson's #JsonValue)
If you want to get the enum value based on one of its properties (like the value property here), then I'm afraid you'll have to implement your own conversion method, as #Zoe pointed out.
One way to implement this custom conversion is by adding a companion object with the conversion method:
enum class Types(val value: Int) {
FOO(1),
BAR(2),
FOO_BAR(3);
companion object {
private val types = values().associate { it.value to it }
fun findByValue(value: Int): Types? = types[value]
}
}
Companion objects in Kotlin are meant to contain members that belong to the class but that are not tied to any instance (like Java's static members).
Implementing the method there allows you to access your value by calling:
var bar = Types.findByValue(2) ?: error("No Types enum value found for 2")
Note that the returned value is nullable, to account for the possibility that no enum value corresponds to the parameter that was passed in. You can use the elvis operator ?: to handle that case with an error or a default value.
If you hate declaring for each enum type a companion object{ ... } to achieve EMotorcycleType.fromInt(...). Here's a solution for you.
EnumCaster object:
object EnumCaster {
inline fun <reified E : Enum<E>> fromInt(value: Int): E {
return enumValues<E>().first { it.toString().toInt() == value }
}
}
Enum example:
enum class EMotorcycleType(val value: Int){
Unknown(0),
Sport(1),
SportTouring(2),
Touring(3),
Naked(4),
Enduro(5),
SuperMoto(6),
Chopper(7),
CafeRacer(8),
.....
Count(9999);
override fun toString(): String = value.toString()
}
Usage example 1: Kotlin enum to jni and back
fun getType(): EMotorcycleType = EnumCaster.fromInt(nGetType())
private external fun nGetType(): Int
fun setType(type: EMotorcycleType) = nSetType(type.value)
private external fun nSetType(value: Int)
---- or ----
var type : EMotorcycleType
get() = EnumCaster.fromInt(nGetType())
set(value) = nSetType(value.value)
private external fun nGetType(): Int
private external fun nSetType(value: Int)
Usage example 2: Assign to val
val type = EnumCaster.fromInt<EMotorcycleType>(aValidTypeIntValue)
val typeTwo : EMotorcycleType = EnumCaster.fromInt(anotherValidTypeIntValue)
A naive way can be:
enum class Types(val value: Int) {
FOO(1),
BAR(2),
FOO_BAR(3);
companion object {
fun valueOf(value: Int) = Types.values().find { it.value == value }
}
}
Then you can use
var bar = Types.valueOf(2)
Protocol orientated way with type-safety
interface RawRepresentable<T> {
val rawValue: T
}
inline fun <reified E, T> valueOf(value: T): E? where E : Enum<E>, E: RawRepresentable<T> {
return enumValues<E>().firstOrNull { it.rawValue == value }
}
enum class Types(override val rawValue: Int): RawRepresentable<Int> {
FOO(1),
BAR(2),
FOO_BAR(3);
}
Usage
val type = valueOf<Type>(2) // BAR(2)
You can use it on non-integer type, too.
I would build the 'reverse' map ahead of time. Probably not a big improvement, but also not much code.
enum class Test(val value: Int) {
A(1),
B(2);
companion object {
val reverseValues: Map<Int, Test> = values().associate { it.value to it }
fun valueFrom(i: Int): Test = reverseValues[i]!!
}
}
Edit: map...toMap() changed to associate per #hotkey's suggestion.
try this...
companion object{
fun FromInt(v:Int):Type{
return Type::class.java.constructors[0].newInstance(v) as Type
}
}
This is for anyone looking for getting the enum from its ordinal or index integer.
enum class MyEnum { RED, GREEN, BLUE }
MyEnum.values()[1] // GREEN
Another solution and its variations:
inline fun <reified T : Enum<T>> enumFromIndex(i: Int) = enumValues<T>()[i]
enumFromIndex<MyEnum>(1) // GREEN
inline fun <reified T : Enum<T>> enumFromIndex(i: Int) = enumValues<T>().getOrNull(i)
enumFromIndex<MyEnum>(3) ?: MyEnum.RED // RED
inline fun <reified T : Enum<T>> enumFromIndex(i: Int, default: T) =
enumValues<T>().getOrElse(i) { default }
enumFromIndex(2, MyEnum.RED) // BLUE
It is an adapted version of another answer. Also, thanks to Miha_x64 for this answer.
Another option...
enum class Types(val code: Int) {
FOO(1),
BAR(2),
FOO_BAR(3);
companion object {
val map = values().associate { it.code to it }
// Get Type by code with check existing codes and default
fun getByCode(code: Int, typeDefault_param: Types = FOO): Types {
return map[code] ?: typeDefault_param
}
}
}
fun main() {
println("get 3: ${Types.getByCode(3)}")
println("get 10: ${Types.getByCode(10)}")
}
get 3: FOO_BAR
get 10: FOO

Can a field be cast to non null version of itself?

I have a data class
data class MyModel(private val _data: MyData? = null)
And I want to ensure my data is only accessible when it is not null, else throw.
I use the below which is good.
fun getData(): MyData {
return checkNotNull(_data) { "data shouldn't be null" }
}
However, if I follow the guide as per Override getter for Kotlin data class, the below complaints I need to return MyData? instead of MyData
val data = _data
get(): MyData {
return checkNotNull(field) { "data shouldn't be null" }
}
Is it true that field can't be cast to the Non-null version of it when return?
If your goal is to declare a getter for a Any? property that returns a Any, it's not possible. You'll get the following error:
Getter return type must be equal to the type of the property
So attempting to do something like
val test : String?
get() : String = "hi"
Wouldn't work.
However, you could hide the nullable property and expose a non-nullable property which references the nullable value via casting:
private val test : String? = "hi"
val testNotNull : String = test as String
If test referenced null, an exception will be thrown.
For example:
fun main(args: Array<String>) = print(Demo().testNotNull)
class Demo(private var test: String? = "hi") {
val testNotNull : String
. get() = test as String
}
You can test this snippit out at try.kotlin.org
Although this is not safe. You should rethink your design. If you're not interoping with Java, you shouldn't punish yourself with nullable types.
I don’t think you can. What you did with the fun getData() is a valid approach IMO. Or you could just not use a data class and create a normal class, obviously.
What I think it may work is with something like this:
typealias notNullType = MyData
data class Test(private val _value: MyData? = null) {
val v: notNullType = _value as notNullType
get() { return field }
}
This would totally allow you to do:
fun play() {
val t = Test(null)
print(t.v) //see what I did? :-)
}
THAT BEING SAID… I don’t think “hiding” the ? optional is necessarily a good idea.
It doesn't necessarily mean that the MyData class is null if you cast it like MyData?
The '?' Just allows the object to be null in the instance that it actually becomes null to avoid an exception at runtime.
You can make your class nullable and it can still contain your data.

Passing parameters to a custom getter in kotlin

I have been reading about properties in Kotlin, including custom getters and setters.
However, I was wondering if it is possible to create a custom getter with extra parameters.
For example, consider the following method in Java:
public String getDisplayedValue(Context context) {
if (PrefUtils.useImperialUnits(context)) {
// return stuff
} else {
// return other stuff
}
}
Note that the static method in PrefUtils has to have Context as a parameter, so removing this is not an option.
I would like to write it like this in Kotlin:
val displayedValue: String
get(context: Context) {
return if (PrefUtils.useImperialUnits(context)) {
// stuff
} else {
// other stuff
}
}
But my IDE highlights all of this in red.
I am aware I can create a function in my class to get the displayed value, but this would mean I would have to use .getDisplayedValue(Context) in Kotlin as well instead of being able to refer to the property by name as in .displayedValue.
Is there a way to create a custom getter like this?
EDIT: If not, would it be best to write a function for this, or to pass Context into the parameters of the class constructor?
As far as I know, property getter cannot have parameter. Write a function instead.
You can do this by having a property that returns an intermediate object that has a get and/or set operator with the parameters that you want, rather than returning the value directly.
Having that intermediate object be an inner class instance may be useful for providing easy access to the parent object. However, in an interface you can't use inner classes so in that case you might need to provide an explicit constructor parameter referencing the parent object when constructing your intermediate object.
For instance:
class MyClass {
inner class Foo {
operator fun get(context: Context): String {
return if (PrefUtils.useImperialUnits(context)) {
// return stuff
} else {
// return other stuff
}
}
}
val displayedValue = Foo()
}
...
val context : Context = whatever
val mc : MyClass = whatever
val y: String = mc.displayedValue[context]
You can do for example:
val displayedValue: String by lazy {
val newString = context.getString(R.string.someString)
newString
}