input :
+------+------------+--------------+------------+
| NAME | Date | Amount_start | Amount_END |
+------+------------+--------------+------------+
| AAA | 2016-10-06 | 20 | 4 |
| AAA | 2016-10-07 | 30 | 6 |
| AAA | 2016-10-08 | 7 | 8 |
| AAA | 2016-10-09 | 380 | 9 |
| ... | ... | ... | ... |
| ZZZ | 2016-10-06 | 10 | 20 |
| ZZZ | 2016-10-07 | 11 | 6 |
+------+------------+--------------+------------+
output:
+------+--------------+------------+
| NAME | Amount_start | Amount_END |
+------+--------------+------------+
| AAA | 20 | 9 |
| ... | ... | ... |
| ZZZ | 10 | 6 |
+------+--------------+------------+
output : In one row need to take Amount_start of starting date and
Amount_end of End date of that employee
Just use row_number() and conditional aggregation:
select t.name,
max(case when seqnum_a = 1 then amount_start end) as amount_start,
max(case when seqnum_d = 1 then amount_end end) as amount_end
from (select t.*,
row_number() over (partition by name order by date asc) as seqnum_a,
row_number() over (partition by name order by date desc) as seqnum_d
from t
) t
group by name;
Related
I have following table,
+------+-------------+----------+---------+
| id | date | amount | amount2 |
+------+-------------+----------+---------+
| | | | 500 |
| 1 | 1/1/2020 | 1000 | |
+------+-------------+----------+---------+
| | | | 100 |
| 1 | 1/3/2020 | 1558 | |
+------+-------------+----------+---------+
| | | | 200 |
| 1 | 1/3/2020 | 126 | |
+------+-------------+----------+---------+
| | | | 500 |
| 2 | 2/5/2020 | 4921 | |
+------+-------------+----------+---------+
| | | | 100 |
| 2 | 2/5/2020 | 15 | |
+------+-------------+----------+---------+
| | | | 140 |
| 2 | 1/1/2020 | 5951 | |
+------+-------------+----------+---------+
| | | | 10 |
| 2 | 1/2/2020 | 1588 | |
+------+-------------+----------+---------+
| | | | 56 |
| 2 | 1/3/2020 | 1568 | |
+------+-------------+----------+---------+
| | | | 45 |
| 2 | 1/4/2020 | 12558 | |
+------+-------------+----------+---------+
I need to get each Id's max date and its amount and amount2 summations, how can I do this. according to above data, I need following output.
+------+-------------+----------+---------+
| | | | 300 |
| 1 | 1/3/2020 | 1684 | |
+------+-------------+----------+---------+
| | | | 600 |
| 2 | 2/5/2020 | 4936 | |
+------+-------------+----------+---------+
How can I do this.
Aggregate and use MAX OVER to get the IDs' maximum dates:
select id, [date], sum_amount, sum_amount2
from
(
select
id, [date], sum(amount) as sum_amount, sum(amount2) as sum_amount2,
max([date]) over (partition by id) as max_date_for_id
from mytable group by id, [date]
) aggregated
where [date] = max_date_for_id
order by id;
first is to use dense_rank() to find the row with latest date
dense_rank () over (partition by id order by [date] desc)
after that, just simply group by with sum() on the amount
select id, [date], sum(amount), sum(amount2)
from
(
select *,
dr = dense_rank () over (partition by id order by [date] desc)
from your_table
) t
where dr = 1
group by id, [date]
I have table like :
+-------+--------+----------+------------+-------+
| cd_hs | cd_cnt | name_cnt | dates | value |
+-------+--------+----------+------------+-------+
| 1 | 1 | aaa | 2018-06-01 | 50 |
| 1 | 2 | bbb | 2018-07-01 | 150 |
| 1 | 3 | ccc | 2018-08-01 | 20 |
| 1 | 1 | aaa | 2018-06-02 | 40 |
| 1 | 2 | bbb | 2018-07-02 | 70 |
| 1 | 3 | ccc | 2018-08-02 | 80 |
+-------+--------+----------+------------+-------+
Actually I have more data but I am just show the sample and what I want to do is
I want to group by cd_hs, name_cnt and based on year in dates column and do sum(value) but I have the 2 condition. First is to show value with condition cd_cnt with 1 and 2 and second condition cd_cnt without 1 and 2 so meaning I have much value other than 1 and 2 and do aliasing as other in one column
Expected Result :
+-------+------+----------+-------------+
| cd_hs | year | name_cnt | total_value |
+-------+------+----------+-------------+
| 1 | 2018 | aaa | 90 |
| 1 | 2018 | bbb | 220 |
| 1 | 2018 | other | 100 |
+-------+------+----------+-------------+
how can I do that? I am new in query and don't know what to do..
Your question is a bit confusing considering your spec doesn't seem to exactly line up with what you requested.
If the sample result you've provided is actually what you're looking for, a simple SUM and GROUP BY should do the trick here:
SELECT cd_hs, EXTRACT(YEAR from dates) as year, name_cnt, SUM(value_)
FROM foo
GROUP BY cd_hs, EXTRACT(YEAR from dates), name_cnt
Result:
| cd_hs | year | name_cnt | sum |
|-------|------|----------|-----|
| 1 | 2018 | aaa | 90 |
| 1 | 2018 | bbb | 220 |
| 1 | 2018 | ccc | 100 |
SQLFiddle
Since you mentioned you wanted two different totals with two separate conditions, you could use JOIN in conjunction with some well-crafted subqueries:
SELECT a.cd_hs, EXTRACT(YEAR FROM a.dates), a.name_cnt, COALESCE(b.total_a, 0) as "Total A", COALESCE(c.total_b, 0) as "Total B"
FROM foo a
LEFT JOIN (
SELECT b.cd_hs, b.name_cnt, EXTRACT(YEAR FROM b.dates), SUM(value_) as total_a
FROM foo b
WHERE b.cd_cnt NOT IN (1, 2)
GROUP BY b.cd_hs, b.name_cnt, EXTRACT(YEAR from b.dates)
) b ON a.cd_hs = b.cd_hs AND a.name_cnt = b.name_cnt
LEFT JOIN (
SELECT c.cd_hs, c.name_cnt, EXTRACT(YEAR FROM c.dates), SUM(value_) as total_b
FROM foo c
WHERE c.cd_cnt IN (1, 2)
GROUP BY c.cd_hs, c.name_cnt, EXTRACT(YEAR from c.dates)
) c ON a.cd_hs = c.cd_hs AND a.name_cnt = c.name_cnt
This particular solution is readable and will get you to the correct end result but will most likely not be scalable in its current form.
Result:
| cd_hs | date_part | name_cnt | Total A | Total B |
|-------|-----------|----------|---------|---------|
| 1 | 2018 | aaa | 0 | 90 |
| 1 | 2018 | bbb | 0 | 220 |
| 1 | 2018 | ccc | 100 | 0 |
| 1 | 2018 | aaa | 0 | 90 |
| 1 | 2018 | bbb | 0 | 220 |
| 1 | 2018 | ccc | 100 | 0 |
SQLFiddle
I have a table like this:
| id | name | segment | date_created | question | answer |
|----|------|---------|--------------|----------|--------|
| 1 | John | 1 | 2018-01-01 | 10 | 28 |
| 1 | John | 1 | 2018-01-01 | 14 | 37 |
| 1 | John | 1 | 2018-01-01 | 9 | 83 |
| 2 | Jack | 3 | 2018-03-11 | 22 | 13 |
| 2 | Jack | 3 | 2018-03-11 | 23 | 16 |
And I want to show this information in a single row, transpose all the questions and answers as columns:
| id | name | segment | date_created | question_01 | answer_01 | question_02 | answer_02 | question_03 | answer_03 |
|----|------|---------|--------------|-------------|-----------|-------------|-----------|-------------|-----------|
| 1 | John | 1 | 2018-01-01 | 10 | 28 | 14 | 37 | 9 | 83 |
| 2 | Jack | 3 | 2018-03-11 | 22 | 13 | 23 | 16 | | |
The number os questions/answers for the same ID is known. Maximum of 15.
I'm already tried using crosstab, but it only accepts a single value as category and I can have 2 (question/answer). Any help how to solve this?
You can try to use row_number to make a number in subquery then, do Aggregate function condition in the main query.
SELECT ID,
Name,
segment,
date_created,
max(CASE WHEN rn = 1 THEN question END) question_01 ,
max(CASE WHEN rn = 1 THEN answer END) answer_01 ,
max(CASE WHEN rn = 2 THEN question END) question_02,
max(CASE WHEN rn = 2 THEN answer END) answer_02,
max(CASE WHEN rn = 3 THEN question END) question_03,
max(CASE WHEN rn = 3 THEN answer END) answer_03
FROM (
select *,Row_number() over(partition by ID,Name,segment,date_created order by (select 1)) rn
from T
) t1
GROUP BY ID,Name,segment,date_created
sqlfiddle
[Results]:
| id | name | segment | date_created | question_01 | answer_01 | question_02 | answer_02 | question_03 | answer_03 |
|----|------|---------|--------------|-------------|-----------|-------------|-----------|-------------|-----------|
| 1 | John | 1 | 2018-01-01 | 1 | 28 | 14 | 37 | 9 | 83 |
| 2 | Jack | 3 | 2018-03-11 | 22 | 13 | 23 | 16 | (null) | (null) |
For this Table:
+----+--------+-------+
| ID | Status | Value |
+----+--------+-------+
| 1 | 1 | 4 |
| 2 | 1 | 7 |
| 3 | 1 | 9 |
| 4 | 2 | 1 |
| 5 | 2 | 7 |
| 6 | 1 | 8 |
| 7 | 1 | 9 |
| 8 | 2 | 1 |
| 9 | 0 | 4 |
| 10 | 0 | 3 |
| 11 | 0 | 8 |
| 12 | 1 | 9 |
| 13 | 3 | 1 |
+----+--------+-------+
I need to sum sequential groups with the same Status to produce this result.
+--------+------------+
| Status | Sum(Value) |
+--------+------------+
| 1 | 20 |
| 2 | 8 |
| 1 | 17 |
| 2 | 1 |
| 0 | 15 |
| 1 | 9 |
| 3 | 1 |
+--------+------------+
How can I do that in SQL Server?
NB: The values in the ID column are contiguous.
Per the tag I added to your question this is a gaps and islands problem.
The best performing solution will likely be
WITH T
AS (SELECT *,
ID - ROW_NUMBER() OVER (PARTITION BY [STATUS] ORDER BY [ID]) AS Grp
FROM YourTable)
SELECT [STATUS],
SUM([VALUE]) AS [SUM(VALUE)]
FROM T
GROUP BY [STATUS],
Grp
ORDER BY MIN(ID)
If the ID values were not guaranteed contiguous as stated then you would need to use
ROW_NUMBER() OVER (ORDER BY [ID]) -
ROW_NUMBER() OVER (PARTITION BY [STATUS] ORDER BY [ID]) AS Grp
Instead in the CTE definition.
SQL Fiddle
Iam experiencing an issue in oracle analytic functions
I want the rank in oracle to be displayed sequentialy but require a cyclic fashion.But this ranking should happen within a group.
Say I have 10 groups
In 10 groups each group must be ranked in till 9. If greater than 9 the rank value must start again from 1 and then end till howmuch so ever
emp id date1 date 2 Rank
123 13/6/2012 13/8/2021 1
123 14/2/2012 12/8/2014 2
.
.
123 9/10/2013 12/12/2015 9
123 16/10/2013 15/10/2013 1
123 16/3/2014 15/9/2015 2
In the above example the for the group of rows of the empid 123 i have split the rank in two subgroup fashion.Sequentially from 1 to 9 is one group and for the rest of the rows the rank again starts from 1.How to achieve this in oracle rank functions.
as per suggestion from Egor Skriptunoff above:
select
empid, date1, date2
, row_number() over(order by date1, date2) as "rank"
, mod(row_number() over(order by date1, date2)-1, 9)+1 as "cycle_9"
from yourtable
example result
| empid | date1 | date2 | rn | ranked |
|-------|----------------------|----------------------|----|--------|
| 72232 | 2016-10-26T00:00:00Z | 2017-03-07T00:00:00Z | 1 | 1 |
| 04365 | 2016-11-03T00:00:00Z | 2017-07-29T00:00:00Z | 2 | 2 |
| 79203 | 2016-12-15T00:00:00Z | 2017-05-16T00:00:00Z | 3 | 3 |
| 68638 | 2016-12-18T00:00:00Z | 2017-02-08T00:00:00Z | 4 | 4 |
| 75784 | 2016-12-24T00:00:00Z | 2017-11-18T00:00:00Z | 5 | 5 |
| 72836 | 2016-12-24T00:00:00Z | 2018-09-10T00:00:00Z | 6 | 6 |
| 03679 | 2017-01-24T00:00:00Z | 2017-10-14T00:00:00Z | 7 | 7 |
| 43527 | 2017-02-12T00:00:00Z | 2017-01-15T00:00:00Z | 8 | 8 |
| 03138 | 2017-02-26T00:00:00Z | 2017-01-30T00:00:00Z | 9 | 9 |
| 89758 | 2017-03-29T00:00:00Z | 2018-04-12T00:00:00Z | 10 | 1 |
| 86377 | 2017-04-14T00:00:00Z | 2018-10-07T00:00:00Z | 11 | 2 |
| 49169 | 2017-04-28T00:00:00Z | 2017-04-21T00:00:00Z | 12 | 3 |
| 45523 | 2017-05-03T00:00:00Z | 2017-05-07T00:00:00Z | 13 | 4 |
SQL Fiddle