Rows to one column - sql

i have sql query:
DECLARE #StartDate DATETIME,
#EndDate DATETIME;
SELECT #StartDate = DATEADD(yy, DATEDIFF(yy, 0, GETDATE()), 0)
,#EndDate = getdate();
SELECT LEFT(CONVERT(varchar, DATEADD(MM, DATEDIFF(MM, 0, DATEADD(MONTH, x.number, #StartDate)), 0),112),6) AS MonthName --LEFT(CONVERT(varchar, DATEADD(MONTH, x.number, #StartDate)), 0),112),6)
FROM master.dbo.spt_values x
WHERE x.type = 'P'
AND x.number <= DATEDIFF(MONTH, #StartDate, #EndDate)`
i need to do it in this format:
201901, 201902
Thanks


For the older version of SQL Server, you can try like following.
DECLARE #StartDate DATETIME,
#EndDate DATETIME;
SELECT #StartDate = DATEADD(yy, DATEDIFF(yy, 0, GETDATE()), 0)
,#EndDate = getdate();
;with cte as
(
SELECT LEFT(CONVERT(varchar, DATEADD(MM, DATEDIFF(MM, 0, DATEADD(MONTH, x.number, #StartDate)), 0),112),6) AS MonthName
FROM master.dbo.spt_values x
WHERE x.type = 'P'
AND x.number <= DATEDIFF(MONTH, #StartDate, #EndDate)
)
SELECT DISTINCT
STUFF ((
SELECT ', ' + [MonthName]
FROM
cte
ORDER BY [MonthName]
FOR XML PATH('')
),1,2,'' )
AS [MonthName]
For SQL Server 2017+, you can use STRING_AGG like following.
select STRING_AGG (MonthName, ',') as MonthName
FROM CTE


Try this below query:
Select (Stuff((Select ', ' + cast(eid as varchar(10)) From employee FOR XML PATH('')),1,2,''))

Related

DateDiff In months between two different types date formats

I have two date formats, EndDate in YYYYMMDD format and another Monthfirstdate in YYYY-MM-DD FORMAT. I need to get the difference between these two dates.
SET NOCOUNT ON
SET TRANSACTION ISOLATION LEVEL READ UNCOMMITTED
DECLARE #Date DATE = dbo.value('DATE')
SELECT
E.EmployeeID
,E.StartDateKey
,E.EndDateKey
,E.FromDateKey
,E.ToDateKey
INTO #Employee
FROM
dbo.Employee E
---clean--
DECLARE #StartDate DATE = (SELECT DATEADD(YY, DATEDIFF(YY, 0, #Date) - 1, 0))
DECLARE #EndDate DATE = DATEADD(S, -1, DATEADD(MM, DATEDIFF(MM, 0, #Date) + 3, 0))
SELECT
E.EmployeeID
,CAST(CONVERT(VARCHAR(10), E.StartDateKey, 112) AS INT) AS _EmployeeStartDateKey
,CAST(CONVERT(VARCHAR(10), E.EndDateKey, 112) AS INT) AS _EmployeeFinishDateKey
,CAST(CONVERT(VARCHAR, D.MonthFirstDay, 112) AS INT) AS _DateKey
,???? AS [Tenure]
FROM #Employee AS E
INNER JOIN dbo.Date D ON
D.DateKey BETWEEN E.FromDateKey AND E.ToDateKey
WHERE
D.DateKey BETWEEN #tartDate AND #EndDate
AND D.DayOfMonth = 1

You can try below query in SQL Server:
DECLARE
#firstDate DATETIME = '2022-12-01',
#dateinStringFormat VARCHAR(20)= '20121201',
#endDate DATETIME;
--Converting date string to Datetime format(YYYY-MM-DD)
SELECT #endDate = CONVERT(CHAR(10), CONVERT(datetime, #dateinStringFormat), 120);
--Now, Calculating the date difference in Month
SELECT DATEDIFF(MONTH, #endDate, #firstDate) AS DateDiff;

How to get list of 2nd and 4th Saturday dates in SQL Server?

I am almost a newbie to writing SQL queries.
In the context of SQL Server, how to get list of 2nd and 4th Saturday dates
in the year 2016?

Done as a derived table simply to show the logic but you can reduce if you prefer:
select *
from (
select d2016,
datename( weekday, d2016 ) as wkdy,
row_number( ) over ( partition by datepart( month, d2016 ), datename( weekday, d2016 ) order by d2016 ) as rn_dy_mth
from (
select dateadd( day, rn, cast( '2016-01-01' as date ) ) as d2016
from (
select row_number() over( order by object_id ) - 1 as rn
from sys.columns
) as rn
) as dy
) as dy_mth
where rn_dy_mth in ( 2, 4 )
and wkdy = 'Saturday'
order by d2016

--DEFINE LIMITS FOR DAY
DECLARE #TODATE DATETIME, #FROMDATE DATETIME
SET #FROMDATE ='2010-01-01'
SET #TODATE = '2017-12-31'
;WITH DATESEQUENCE( [DATE] ) AS
(
SELECT #FROMDATE AS [DATE]
UNION ALL
SELECT DATEADD(DAY, 1, [DATE])
FROM DATESEQUENCE
WHERE DATE < #TODATE
)
, DATESATURDAY AS
(SELECT CAST(CAST(YEAR([DATE]) AS VARCHAR)+
(CASE WHEN DATEPART(M,[DATE])<=9 THEN '0'+CAST(DATEPART(M,[DATE]) AS VARCHAR)
ELSE CAST(DATEPART(M,[DATE]) AS VARCHAR) END ) AS NUMERIC) AS MONTH_ID
,CONVERT(VARCHAR,[DATE],106) AS DAY_DESC
,UPPER(DATENAME(DW,[DATE]))AS DAY_NAME
FROM DATESEQUENCE )
,SECOND_FOURTH_SATURDAY AS
(SELECT *
,ROW_NUMBER() OVER (PARTITION BY MONTH_ID ORDER BY DAY_NAME) FALL_IN
FROM DATESATURDAY
WHERE DAY_NAME='SATURDAY')
SELECT * FROM SECOND_FOURTH_SATURDAY
WHERE FALL_IN IN(2,4)
OPTION (MAXRECURSION 10000)

You can get any Saturday of a month using the Following Query in SQL.
Here I'm Getting on Current Date, You can set your own selected date to get a Specific month Saturday
select DATEADD(dd, (14 - ##DATEFIRST - DATEPART(dw, DATEADD(MONTH, DATEDIFF(mm, 0,getdate()), 0))) % 7, DATEADD(MONTH, DATEDIFF(mm, 0, getdate()), 0)) as FirstSaturday,
DATEADD(dd,7,DATEADD(dd, (14 - ##DATEFIRST - DATEPART(dw, DATEADD(MONTH, DATEDIFF(mm, 0, getdate()), 0))) % 7, DATEADD(MONTH, DATEDIFF(mm, 0, getdate()), 0))) as SecondSaturday,
DATEADD(dd,14,DATEADD(dd, (14 - ##DATEFIRST - DATEPART(dw, DATEADD(MONTH, DATEDIFF(mm, 0, getdate()), 0))) % 7, DATEADD(MONTH, DATEDIFF(mm, 0, getdate()), 0))) as ThirdSaturday,
DATEADD(dd,21,DATEADD(dd, (14 - ##DATEFIRST - DATEPART(dw, DATEADD(MONTH, DATEDIFF(mm, 0, getdate()), 0))) % 7, DATEADD(MONTH, DATEDIFF(mm, 0, getdate()), 0))) as LastSaturday

Calculate month number,month name, first day of month(date) and last day of month(date) using common table expression in sql server?

declare #start_date as datetime = '12/31/2014'
declare #end_date as datetime = '02/15/2015'
;with cte as (
select
datename(month,#start_date) as [mnth_nm],
month(#start_date) as [mnth_no],
#start_date as dat,
DATEADD(DAY, -1 * DAY(#start_date) + 1, #start_date) as [first_day],
DATEADD(dd, -DAY(DATEADD(mm, 1, #start_date)), DATEADD(mm, 1, #start_date)) as [last_day]
union all
select
datename(month, DateAdd(Month, 1, dat)),
month(dat) + 1 as [mnth_no],
DateAdd(Month, 1, dat),
DATEADD(MONTH, 1, [first_day]),
DATEADD(dd, -DAY(DATEADD(mm, 1, dat)),
DATEADD(mm, 1, dat)) + 1
from
cte
where
DateAdd(Month,1,dat) < #end_date
)
select
[mnth_nm], [mnth_no], #start_date, [first_day], [last_day]
from
CTE
In above CTE the required output should give december, january and february month output based on my start and end date.

Change the where query only:-
DateAdd(Month,0,dat)< #end_date

<b>Got the solution ... </b>
<p>
declare #start_date as datetime = '12/31/2014'
declare #end_date as datetime = '03/15/2015'
;with cte as (
select
datename(month,#start_date) as [mnth_nm],
month(#start_date) as [mnth_no],
#start_date as dat,
DATEADD(DAY, -1 * DAY(#start_date) + 1, #start_date) as [first_day],
DATEADD(dd, -DAY(DATEADD(mm, 1, #start_date)), DATEADD(mm, 1, #start_date)) as [last_day]
union All
select
datename(month, DateAdd(Month, 1, dat)),
month(DateAdd(m,1,dat)) as [mnth_no],
DateAdd(Month, 1, dat),
DATEADD(MONTH, 1, [first_day]),
DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, DATEADD(MONTH, 1, [first_day])) + 1, 0))
from
cte
where
DateAdd(Month,0,dat)< #end_date
)
select
[mnth_nm], [mnth_no], #start_date, [first_day], [last_day]
from
CTE</p>

query for first and last day of month

If I have the name of the month, how can I have the first and last day of that month in SQL?
I have this query to returns the month names:
DECLARE #StartDate DATETIME,
#EndDate DATETIME;
SELECT #StartDate = '20110501'
,#EndDate = '20110801';
SELECT DATENAME(MONTH, DATEADD(MONTH, x.number, #StartDate)) AS MonthName
FROM master.dbo.spt_values x
WHERE x.type = 'P'
AND x.number <= DATEDIFF(MONTH, #StartDate, #EndDate)
Result:
Now, how can i get the first and last day of that months? changing the query.

If you want a more general and simple solution:
DECLARE #startdate AS DATETIME = GETDATE()
SELECT
DATEADD(MONTH, DATEDIFF(MONTH, 0, #startdate) , 0) as startMonth,
DATEADD(SECOND, -1, DATEADD(MONTH, 1, DATEADD(MONTH, DATEDIFF(MONTH, 0, #startdate) , 0) ) ) as endMonth
Gives the result:
startMonth endMonth
----------------------- -----------------------
2013-06-01 00:00:00.000 2013-06-30 23:59:59.000

Try this :-
DECLARE #StartDate DATETIME,
#EndDate DATETIME;
SELECT #StartDate = '20110501'
,#EndDate = '20110801';
SELECT DATENAME(MONTH, DATEADD(MONTH, x.number, #StartDate)) AS MonthName,
CONVERT(VARCHAR(25),
DATEADD(dd,-(DAY(DATEADD(MONTH, x.number, #StartDate))-1),DATEADD(MONTH, x.number, #StartDate)),101) as FirstDay,
CONVERT(VARCHAR(25),DATEADD(dd,-(DAY(DATEADD(mm,1,DATEADD(MONTH, x.number, #StartDate)))),DATEADD(mm,1,DATEADD(MONTH, x.number, #StartDate))),101) as LastDay
FROM master..spt_values x
WHERE x.type = 'P'
AND x.number <= DATEDIFF(MONTH, #StartDate, #EndDate)
Result :-
MonthName FirstDay LastDay
May 05/01/2011 05/31/2011
June 06/01/2011 06/30/2011
July 07/01/2011 07/31/2011
August 08/01/2011 08/31/2011
Result obtained taking the help from this query

This code gives you the first date of Current Month:
DATEADD(MONTH, DATEDIFF(MONTH, 0, GETDATE()), 0)
If you know the Month's number then:
SELECT DATEADD(MONTH, DATEDIFF(MONTH, 0, GETDATE()) + #MonthNumber, 0)
Same goes for Month's end date :
SELECT DATEADD(MILLISECOND, -1,
DATEADD(MONTH, DATEDIFF(MONTH, 0, GETDATE()) - ##MonthNumber+ 1, 0))

How to split date ranges based on months in SQL Server 2005

Ex: date range is 01-01-2011 to 01-01-2012, I want the output like this :
01-01-2011 31-01-2011
01-02-2011 28-02-2011
How can I do this ? I'm using SQL Server 2005..
Thanks

Using CTE:
DECLARE #Begin DATETIME
DECLARE #End DATETIME
SELECT #Begin = '20110101', #End = '20120101'
;WITH ranges(DateFrom, DateTo) AS
(
SELECT #Begin, DATEADD(DAY, -1, DATEADD(MONTH, 1, #begin))
UNION ALL
SELECT DATEADD(month, 1, DateFrom), DATEADD(DAY, -1, DATEADD(MONTH, 2, DateFrom))
FROM ranges
WHERE DateFrom < #End
)
SELECT * FROM ranges
OPTION(MAXRECURSION 0)
And not using CTE:
DECLARE #Begin DATETIME
DECLARE #End DATETIME
SELECT #Begin = '20110101', #End = '20120101'
SELECT DATEADD(MONTH, n.Number, #Begin) DateFrom, DATEADD(day, -1, DATEADD(MONTH, n.Number+1, #Begin)) DateTo
FROM master.dbo.spt_values n
WHERE
n.Number < DATEDIFF(MONTH, #begin, #end)
AND n.Type = 'P'
If you need to include January 2012 too, use this
DECLARE #Begin DATETIME
DECLARE #End DATETIME
SELECT #Begin = '20110101', #End = '20120101'
SELECT DATEADD(MONTH, n.Number, #Begin) DateFrom, DATEADD(day, -1, DATEADD(MONTH, n.Number+1, #Begin)) DateTo
FROM master.dbo.spt_values n
WHERE
n.Number <= DATEDIFF(MONTH, #begin, #end)
AND n.Type = 'P'
And CTE:
DECLARE #Begin DATETIME
DECLARE #End DATETIME
SELECT #Begin = '20110101', #End = '20120101'
;WITH ranges(DateFrom, DateTo) AS
(
SELECT #Begin, DATEADD(DAY, -1, DATEADD(MONTH, 1, #begin))
UNION ALL
SELECT DATEADD(month, 1, DateFrom), DATEADD(DAY, -1, DATEADD(MONTH, 2, DateFrom))
FROM ranges
WHERE DATEADD(month, 1, DateFrom) < #End
)
SELECT * FROM ranges
OPTION(MAXRECURSION 0)

>On Providing the Start and End Date range, it can be split into months. This might help.
DECLARE #StartDate datetime
DECLARE #EndDate datetime
DECLARE #tmpStart datetime
DECLARE #tmpEnd datetime
Select #StartDate = '2012-01-01'
Select #EndDate = '2009-01-01'
Select #StartDate = DATEADD(MONTH,1,Convert(DATETIME,Convert(VARCHAR(25), Datepart (YEAR,#StartDate)) + '-' + Convert(VARCHAR(25), Datepart(MONTH, #StartDate)) + '-' + Convert(VARCHAR(25), 1)))
Select #EndDate = DATEADD(MONTH,1,Convert(DATETIME,Convert(VARCHAR(25), Datepart(YEAR, #EndDate)) + '-' + Convert(VARCHAR(25), Datepart(MONTH, #EndDate)) + '-' + Convert(VARCHAR(25), 1)))
Select #EndDate = DATEADD(DD,-1, DATEADD(MM,1,#EndDate))
Select #tmpEnd = #EndDate
Select #tmpStart = Convert(DATETIME,Convert(VARCHAR(25), Datepart(YEAR, #tmpEnd)) + '-' +
Convert(VARCHAR(25), Datepart(MONTH, #tmpEnd)) + '-' + Convert(VARCHAR(25), 1))
Select #StartDate 'Start' , #EndDate 'End'
While #tmpStart <= #StartDate
BEGIN
Select #tmpStart 'tmpStart' , #tmpEnd 'tmpEnd'
Select #tmpStart = DATEADD(MM,1,#tmpStart)
Select #tmpEnd = DATEADD(DD,-1,DATEADD (MM, 1 , #tmpStart))
END