How to add users to LDAP Groups using PDI tool with the help of component "LDAP Output"?
You need to input steps: One to read the users and one to read the groups. How you join these two step depends on the LDAP server you use.
You can either join:
through the memberof attribute of the user. This is what ActiveDirectory does.
or by the member attribute of the group. This is what most Unix-based diretory servers do,
In either case the attribute contains the distinguished name of the other entity (e.g. memberOf refers to the DN of group he is a memeber of).
Related
My question is very similar to how to get groups of a user in ldap but I want to be able to search a group whose member has attribute foo with value bar
ie, from the previous question instead of doing (&(objectClass=groupOfNames)(member=cn=root,ou=django,dc=openldap))
I want to do something like
(&(objectClass=groupOfNames)(member=sn=bar))
but it seems only the full DN can be used for such query. Is there another way to find groups for user matching a pattern?
Since memberOf is available to you, you can search for the users instead of the groups:
(&(objectClass=person)(sn=bar))
(You might have to change the objectClass depending on what it is for users. I'm used to Active Directory, not OpenLDAP.)
Then you can read the memberOf attribute of the users you find.
Update: If you just want to find members of that group with that attribute then you can do it in one query by using memberOf in the query, and looking for the DN of the group:
(&(objectClass=person)(sn=bar)(memberOf=CN=MyGroup,DC=whatever))
I am new to LDAP (AD) and I wonder how can I retrieve all users of a group if the users itself doesn't have the "memberof" attribute (which should link to the group I think)?
Following LDAP Structure
- Users
- UserA (memberof=Group1)
- UserB (memberof=Group1,memberof=Group2)
- UserN ...
- Groups
- Group1 (member=UserA,member=UserB)
- Group2 (member=UserB)
- GroupX ...
- AppGroups
- App1 (member=UserA,member=UserB)
- AppX ...
So how can I query only the users which are members of App1 group from AppGroups if the users don't have the attributes memberof for this group?
I am trying to achive this with Alfresco. Querying the groups is no problem but I can't find a way to also sync the users (and only the users of the group App1)?
Thank you in advance!
You can either form a query that asks the server to retrieve all users whose memberof attribute contains your group's distinguished name, or, you can turn the logic around and ask the server to give you the member attribute of the group. The member attribute on a group contains all members' distinguished names. You can then obtain additional information about the users by reading the objects one-by-one.
Performance-wise, this is much slower, but if there is no memberof attribute on the users themselves, this might be the only option for you.
The 'memberOf' attribute is supported by the memberOf overlay, if:
you have configured it
you have modified the memberships of this DN since you installed the overlay. It isn't retrospective.
What is the search filter to list users belong to specific group like "engineering" in a ldap server which don't have backlink enabled.
For example, if backlink enabled i can use following filter,
(&(objectClass=person)(memberOf=cn=engineering,ou=Groups,o=company,o=com))
Wanted to know corresponding search query without using memberOf attribute.
Thanks
DarRay
Try your filter as:
(&(objectClass=group)(cn=engineering))
using a base of
ou=Groups,o=company,o=com
and a scope of subtree
Returning attribute "member"
Or even more efficient:
(objectClass=group)
With a base of
cn=engineering,ou=Groups,o=company,o=com
and a scope of base
Returning attribute "member"
-jim
The main question is: How are the users linked to groups?
One way is by specifying the users as attributes in the group. That can be done either via the uniqueMember- or the memberUid-Attribute. To find the users of a certain group you will have to use two queries. One query will retrieve the DNs or UIDs of the users of a group by fetching the uniqueMember or memberUid attribute of the group in question depending on your setup. Then you can retrieve the users by either using (&(objectclass=person)(uid=<uid>)) or (&(objectclass=person)(dn=<dn>)).
The other way is by storing the grous as attributes in the user, which you described above.
Hope that helps.
I can succesfully authenticate my application with ApacheDS
But now i use only one domain.
I want to add subdomains or sub organizations under root domain.
For example a root organization as
dc=example,dc=com
and sub organizations dc=x
another sub organization dc=y
Now i can authenticate users using uid attribute
like:
user-search-filter="(uid={0})"
i use login name like user1, without an # extension
But i want to have suborganizations and i want to use user1#x.example.com
Is it possible and how?
My application is a spring application but i think subject is independent from my application side.
The attribute defined in the LDAP standards track for email addresses is mail, rfc822mailbox, or 0.9.2342.19200300.100.1.3 as defined in RFC4524. Perhaps your filter should be an attribute assertion using one of those types, for example, user-search-filter="mail={0}".
I am not sure what is meant by "manually". LDAP does not have a concept of organizations, only entries that might belong to an organization. These entries might have a mail attribute if the entry belongs to an objectClass that allows or requires the mail attribute. In other words, if your filter is mail={0} (which might become mail=user1#x.example.com), then a search using that filter (given the appropriate base object and scope) will return all entries that have a mail attribute with the value user1#x.example.com irrespective of where that user is located and irrespective of the value of the uid attribute.
If the users in an organization can identified some other way, perhaps by organization or other attribute, then the filter could be:
(&(uid={0})(o=x))
or
(&(uid={0})(o=y))
One way or another, the users' entry must be identifiable by the contents of the entry. The primary key in an LDAP database is the distinguished name (uid=abc,dc=x,dc=example,dc=com) but attributes in the entry can be used to tighten the filter. Some alternatives are:
use unique identifiers (all uid or mail values are unique in the database, therefore, only one is ever returned to a search request)
use an attribute to identify users in an organization (like o in the example filters above)
use a dynamic group to generate a list of users in an organization.
consider using an extensible match filter to make values in the distinguished names be part of the filtering process
see also
using ldapsearch - the article is about the ldapsearch command line tool, but the concepts are useful when constructing search requests
mastering search filters
Is there any LDAP command to delete all users attached to a specific group. Assume there are user1,user2,user3 assigned to group G1 . I want to delete all the users attached to group G1
Users are not attached to a group, entries are members of a group. To delete all entries that are members
of a group, execute a search that will return all of distinguished names that are members of the group:
make the base object of the search the distinguished name of the group
use (&) or (objectClass=*) for the filter. Some directory servers, for example Sun DSEE in certain
versions fail to properly parse the filter (&)
use base for the search scope
request the attribute type whose values are the distinguished names of the members of the groups. This varies,
but could be something like uniqueMember
Then, transmit a delete request for each distinguished name returned from the above search.
Some servers support referential integrity, if so, the members of the group will be deleted
at the same time as the entries are deleted.
See also
LDAP: Programming Practices
LDAP: Search best practices