I can not convert this query from oracle to posgresql. Any help would be appreciated.
Select tdcollid, tddate, tdentry, tdlng, tdlat, tdvpid
From Tracking where Tdcollid = 'jperez'
And Trunc(Tddate) = Trunc(To_Date('14-DEC-16','yyyy-MM-DD'))
order by Tddate
You can do:
Select tdcollid, tddate, tdentry, tdlng, tdlat, tdvpid
From Tracking
where Tdcollid = 'jperez' And
ttdate >= '2016-12-14'::date and
ttdate < '2016-12-14'::date + interval '1 day'
order by Tddate;
Note that the date comparisons are arranged so they can use an index (if appropriate). You can use the same logic as ttdate::date = '2016-12-14'::date if this is not a concern.
Try something like this:
SELECT tdcollid, tddate, tdentry, tdlng, tdlat, tdvpid
FROM tracking
WHERE tdcollid = 'jperez'
AND tddate::date = '2016-12-14'::date
ORDER BY tddate
If tddate is a timestamp, casting it to date with ::date will do the same as Oracle's TRUNC(timestamp). Also date constants should be preferably in ISO-8601 format.
Related
date column - datetime type.
My query is:
select * from car_db.car_parts where date::text LIKE '2018-07-06%'
How i select where date <= 'YEAR-MONTH-DAY', and ignore time?
I will be grateful...
First, Postgres doesn't offer a datetime type. The type is called timestamp. Also, Postgres has the very convenient function date_trunc(), so you can use that:
select *
from car_db.car_parts
where date_trunc('day', date) = '2018-07-06'::date;
However, this method -- or any method with a functional call or type conversion -- can affect index usage. I strongly recommend:
where date >= '2018-07-06'::date and
date < '2018-07-07'::date
Try the following. Also, you should not name your column as date.
select * from car_db.car_parts where cast("date" as date) < '2018-07-06'
So, i´m trying to select rows between two dates.
In db, the dates also have time.
Therefor i need to use LIKE.
SQL
$query = "SELECT * FROM table WHERE date >= LIKE :selectedDateFrom AND <= LIKE :selectedDateTo";
$query_params = array(':selectedDateFrom' => $selectedDateFrom.="%", ':selectedDateTo' => $selectedDateTo.="%");
This one returns error!
How should it look like?
In db, the dates also have time.
Therefor i need to use LIKE.
No, you don't.
To select all date/times where the date component is between (from) and (to), inclusive, you can write it as
SELECT *
FROM table
WHERE date >= :selectedDateFrom
AND date < :selectedDateToPlusOne
(Note the < instead of <=, and set the second parameter to one day after the last day you want to include in your results.) This works even when the column includes times.
you can't use like with dates in SQL
SO use this:
$query = "SELECT * FROM table WHERE date >= :selectedDateFrom AND date <= :selectedDateTo";
You'd strip the time part from a datetime with DATE().
SELECT *
FROM mytable
WHERE date(mydate) >= :selectedDateFrom
AND date(mydate) <= :selectedDateTo;
Or with BETWEEN for better readability:
SELECT *
FROM mytable
WHERE date(mydate) BETWEEN :selectedDateFrom AND :selectedDateTo;
I have a set of dates that are in the format DD-MMM-YYYY. I need to be able to compare dates by using only the DD-MMM part of the date, since the year isn't important.
How would I achieve this?
I have tried reading up on the DATEPART function (edit: which evidently wouldn't work) but I can only theoretically get that to return either the DD or the MMM parts, not both of them at once.
Edit: added oracle tag. Sorry.
Example of date field: 01-MAR-1994
If your column is of type DATE then it doesn't have a format.
If I understand you right, then you want to view the mon-dd part only, so you need to convert it with TO_CHAR function,
i.e.:
select to_char(your_date_column, 'mon-dd') from your_table
Convert your dates using the following format, it will only month and the date part. You have to replace getdate() with you date fields.:
select convert(varchar(5),getdate(),110)
Assuming that you are using SQL Server or Oracle since you attempted using DATEPART, you can just get the day and month using the DAY() and MONTH() functions. Assuming, again, that the dates you are comparing are in two different tables, it would look similar to this:
SELECT MONTH(t1.date), DAY(t2.date)
FROM table AS t1
INNER JOIN table2 AS t2
ON t1.key = t2.key
WHERE MONTH(t1.date) = MONTH(t2.date)
AND DAY(t1.date) = DAY(t2.date)
EDIT: If you are just comparing rows in the same table, you only need a very simple query.
SQLFiddle
select id, TO_CHAR(most_recent, 'mon-dd')
from (
select id, MAX(date1) AS most_recent
from table1
group by id
)
You can also combine month and day into one integer:
EXTRACT(MONTH FROM datecol) * 100 + EXTRACT(DAY FROM datecol) AS MonthDay
Then it's easier to sort and compare.
select FORMAT(yourcoulmn_name, 'dd/MM') from table
This should do the trick
`select CONVERT(varchar(7),datetime_column,100) from your_table`
date_default_timezone_set("Asia/Kolkata");
$m = date("m");//Month
$d = date("d");//Day
$sql = "SELECT * FROM contactdata WHERE MONTH(date) = '$m' AND DAY(date) = '$d' ";
only checks day and month and returns today, day and month from database
SELECT LEFT(REPLACE(CONVERT(varchar(10),GETDATE()-1,3),'/',''),4)
WOuld this work for you?
FROMAT(DATETIME, 'dd-MMM') = FROMAT(DATETIME, 'dd-MMM') use any format you want
I have a to compare dates in 2 tables but the problem is that one table has the date in DD-Mon-YY format and the other in YYYYMM format.
I need to make both of them YYYYMM for the comparison.
I need to create something like this:
SELECT * FROM offers
WHERE offer_date = (SELECT to_date(create_date, 'YYYYMM') FROM customers where id = '12345678')
AND offer_rate > 0
where create_date is something like 12-Mar-2006 and offer_date is something like 200605
Any ideas where I need to adapt this query??
As offer_date is an number, and is of lower accuracy than your real dates, this may work...
- Convert your real date to a string of format YYYYMM
- Conver that value to an INT
- Compare the result you your offer_date
SELECT
*
FROM
offers
WHERE
offer_date = (SELECT CAST(to_char(create_date, 'YYYYMM') AS INT) FROM customers where id = '12345678')
AND offer_rate > 0
Also, by doing all the manipulation on the create_date you only do the processing on one value.
Additionally, had you manipulated the offer_date you would not be able to utilise any index on that field, and so force SCANs instead of SEEKs.
Am I missing something? You can just convert offer_date in the comparison:
SELECT *
FROM offers
WHERE to_char(offer_date, 'YYYYMM') = (SELECT to_date(create_date, 'YYYYMM') FROM customers where id = '12345678') AND
offer_rate > 0
Suppose I have a date 2010-07-29. Now I would like to check the result of one day ahead. how to do that
For example,
SELECT *
from table
where date = date("2010-07-29")
How to do one day before without changing the string "2010-07-29"?
I searched and get some suggestion from web and I tried
SELECT *
from table
where date = (date("2010-07-29") - 1 Day)
but failed.
MySQL
SELECT *
FROM TABLE t
WHERE t.date BETWEEN DATE_SUB('2010-07-29', INTERVAL 1 DAY)
AND '2010-07-29'
Change DATE_SUB to DATE_ADD if you want to add a day (and reverse the BETWEEN parameters).
SQL Server
SELECT *
FROM TABLE t
WHERE t.date BETWEEN DATEADD(dd, -1, '2010-07-29')
AND '2010-07-29'
Oracle
SELECT *
FROM TABLE t
WHERE t.date BETWEEN TO_DATE('2010-07-29', 'YYYY-MM-DD') - 1
AND TO_DATE('2010-07-29', 'YYYY-MM-DD')
I used BETWEEN because the date column is likely DATETIME (on MySQL & SQL Server, vs DATE on Oracle), which includes the time portion so equals means the value has to equal exactly. These queries give you the span of a day.
If you're using Oracle, you can use the + and - operators to add a number of days to a date.
http://psoug.org/reference/date_func.html
Example:
SELECT SYSDATE + 1 FROM dual;
Will yield tomorrow's date.
If you're not using Oracle, please tell use what you ARE using so we can give better answers. This sort of thing depends on the database you are using. It will NOT be the same across different databases.
Depends of the DateTime Functions available on the RDBMS
For Mysql you can try:
mysql> SELECT DATE_ADD('1997-12-31',
-> INTERVAL 1 DAY);
mysql> SELECT DATE_SUB('1998-01-02', INTERVAL 31 DAY);
-> '1997-12-02'
If youre using MSSQL, you're looking for DateAdd() I'm a little fuzzy on the syntax, but its something like:
Select * //not really, call out your columns
From [table]
Where date = DateAdd(dd, -1, "2010-07-29",)
Edit: This syntax should be correct: it has been updated in response to a comment.
I may have the specific parameters in the wrong order, but that should get you there.
In PL SQL : select sysdate+1 from dual;