Oracle SQL convert date format from DD-Mon-YY to YYYYMM - sql

I have a to compare dates in 2 tables but the problem is that one table has the date in DD-Mon-YY format and the other in YYYYMM format.
I need to make both of them YYYYMM for the comparison.
I need to create something like this:
SELECT * FROM offers
WHERE offer_date = (SELECT to_date(create_date, 'YYYYMM') FROM customers where id = '12345678')
AND offer_rate > 0
where create_date is something like 12-Mar-2006 and offer_date is something like 200605
Any ideas where I need to adapt this query??

As offer_date is an number, and is of lower accuracy than your real dates, this may work...
- Convert your real date to a string of format YYYYMM
- Conver that value to an INT
- Compare the result you your offer_date
SELECT
*
FROM
offers
WHERE
offer_date = (SELECT CAST(to_char(create_date, 'YYYYMM') AS INT) FROM customers where id = '12345678')
AND offer_rate > 0
Also, by doing all the manipulation on the create_date you only do the processing on one value.
Additionally, had you manipulated the offer_date you would not be able to utilise any index on that field, and so force SCANs instead of SEEKs.

Am I missing something? You can just convert offer_date in the comparison:
SELECT *
FROM offers
WHERE to_char(offer_date, 'YYYYMM') = (SELECT to_date(create_date, 'YYYYMM') FROM customers where id = '12345678') AND
offer_rate > 0

Related

storing date in 'CCYYMMDD' format in Teradata

I would like to store dates in the format CCYYMMDD in Teradata, but I fail to do so. Find below what I tried so far:
query 1:
SEL CAST(CAST(CURRENT_DATE AS DATE FORMAT 'YYYYMMDD') AS VARCHAR(8))
-- Output: 20191230 ==> this works!
query 2:
SEL CAST(CAST(CURRENT_DATE AS DATE FORMAT 'CCYYMMDD') AS VARCHAR(8))
-- output: SELECT Failed. [3530] Invalid FORMAT string 'CCYYMMDD'.
It seems that the CCYYMMDD is not available in Teradata right away. Is there a workaround?
Tool used: Teradata SQL assistant
Internally, dates are stored as integers in Teradata. So when you say you want to store them in a different format, I don't think you can do that. But you can choose how to display / return the values.
I'm sure there's a cleaner way to get the format you want, but here's one way:
WITH cte (mydate) AS (
SELECT CAST(CAST(CURRENT_DATE AS DATE FORMAT 'YYYYMMDD') AS CHAR(8)) AS mydate
)
SELECT
CAST(
(CAST(SUBSTRING(mydate FROM 1 FOR 2) AS INTEGER) + 1) -- generate "century" value
AS CHAR(2) -- cast value as string
) || SUBSTRING(mydate FROM 3) AS new_date -- add remaining portion of date string
FROM cte
SQL Fiddle - Postgres
You'd have to add some extra logic to handle years before 1000 and after 9999. I don't have a TD system to test, but give it a try and let me know.

run this query from oacle in postgresql?

I can not convert this query from oracle to posgresql. Any help would be appreciated.
Select tdcollid, tddate, tdentry, tdlng, tdlat, tdvpid
From Tracking where Tdcollid = 'jperez'
And Trunc(Tddate) = Trunc(To_Date('14-DEC-16','yyyy-MM-DD'))
order by Tddate
You can do:
Select tdcollid, tddate, tdentry, tdlng, tdlat, tdvpid
From Tracking
where Tdcollid = 'jperez' And
ttdate >= '2016-12-14'::date and
ttdate < '2016-12-14'::date + interval '1 day'
order by Tddate;
Note that the date comparisons are arranged so they can use an index (if appropriate). You can use the same logic as ttdate::date = '2016-12-14'::date if this is not a concern.
Try something like this:
SELECT tdcollid, tddate, tdentry, tdlng, tdlat, tdvpid
FROM tracking
WHERE tdcollid = 'jperez'
AND tddate::date = '2016-12-14'::date
ORDER BY tddate
If tddate is a timestamp, casting it to date with ::date will do the same as Oracle's TRUNC(timestamp). Also date constants should be preferably in ISO-8601 format.

How to compare one field to another using LIKE

I want to so something like the following:
SELECT * FROM TABLE1
WHERE DATE1 LIKE DATE2 + '%'
However, when I try this I get the following error:
"5407: Invalid operation for DateTime or Interval"
I am working in Terdata SQL Assistant
You can't use like to compare dates, like is to compare string (varchar), then you can cast this dates to varchar or better way is cast both dates to the same format, for example:
SELECT * FROM TABLE1
WHERE convert(varchar, DATE1, 103) = convert(varchar, DATE2, 103)
This way cast dates to format: DD/MM/YYYY
If you wanna cast to another formats I let you a link that explain more types: https://www.mssqltips.com/sqlservertip/1145/date-and-time-conversions-using-sql-server/
You could potentially just format the dates the same way to compare them.
WHERE FORMAT(DATE1, 'dd/mm/yyyy') = FORMAT(DATE2, 'dd/mm/yyyy')
date2 is less than 1 day later
where datediff(d,date1,date2) < 1
Since your using like ... you could mean within a day before or after.
abs(datediff(d,date1,date2)) < 1

Oracle use LIKE '%' on DATE

My table myTab has the column startDate, which has the datatype "DATE". The data in this column are stored like dd.mm.yyyy.
Now I'm trying to get data with this query:
SELECT * FROM myTab WHERE startDate like '%01.2015"
Somehow it doesn't work and I don't know why.
Hope someone can help.
To make a text search on the date you would have to convert the date to text.
It's more efficient if you calculate the first and last date for what you want to find and get everything between them. That way it's done as numeric comparisons instead of a text pattern match, and it can make use of an index if there is one:
SELECT * FROM myTab WHERE startDate >= DATE '2015-01-01' AND startDate < DATE '2015-02-01'
SELECT * FROM myTab WHERE TO_CHAR(startDate,'dd.mm.yyyy') LIKE '%01.2015'
If the field type is "DATE" then the value isn't stored as a string, it's a number managed by Oracle, so you have to convert it to a string:
SELECT * FROM myTab WHERE to_char(startDate, 'MM.YYYY') = '01.2015';
You can also use date ranges in SQL queries:
SELECT * FROM myTab
WHERE startDate
BETWEEN to_date('01.01.2015', 'DD.MM.YYYY')
AND to_date('31.01.2015', 'DD.MM.YYYY');
Regarding you actual question "Somehow it doesn't work and I don't know why."
Oracle make an implicit conversion from DATE to VARHCAR2, however it uses the default NLS_DATE_FORMAT which is probably different to what you use in your query.
The data in this column are stored like dd.mm.yyyy.
Oracle does not store date in the format you see. It stores it internally in proprietary format in 7 bytes with each byte storing different components of the datetime value.
WHERE startDate like '%01.2015"
You are comparing a DATE with a STRING, which is pointless.
From performance point of view, you should use a date range condition so that if there is any regular INDEX on the date column, it would be used.
SELECT * FROM table_name WHERE date_column BETWEEN DATE '2015-01-01' AND DATE '2015-02-01'
To understand why a Date range condition is better in terms of performance, have a look at my answer here.
I solved my problem that way. Thank you for suggestions for improvements. Example in C#.
string dd, mm, aa, trc, data;
dd = nData.Text.Substring(0, 2);
mm = nData.Text.Substring(3, 2);
aa = nData.Text.Substring(6, 4);
trc = "-";
data = aa + trc + mm + trc + dd;
"Select * From bdPedidos Where Data Like '%" + data + "%'";
To provide a more detailed answer and address this https://stackoverflow.com/a/42429550/1267661 answer's issue.
In Oracle a column of type "date" is not a number nor a string, it's a "datetime" value with year, month, day, hour, minute and seconds.
The default time is always midnight "00:00:00"
The query:
Select * From bdPedidos Where Data Like '%" + data + "%'"
won't work in all circumstances because a date column is not a string, using "like" forces Oracle to do a conversion from date value to string value.
The string value may be year-month-day-time or month-day-year-time or day-month-year-time, that all depends how a particular Oracle instance has set the parameter NLS_DATE_FORMAT to show dates as strings.
The right way to cover all the possible times in a day is:
Select *
From bdPedidos
Where Data between to_date('" + data + " 00:00:00','yyyy-mm-dd hh24:mi:ss')
and to_date('" + data + " 23:59:59','yyyy-mm-dd hh24:mi:ss')
SELECT * FROM myTab WHERE startDate like '%-%-2015';
This will search for all dates in 2015. If this doesn't work, try:
SELECT * FROM myTab WHERE startDate like '%-%-15';

sqlite select with condition on date

I have an sqlite table with Date of Birth. I would like to execute a query to select those records where the age is more than 30.
I have tried the following but it doesn't work:
select * from mytable where dob > '1/Jan/1980'
select * from mytable where dob > '1980-01-01'
Some thing like this could be used:
select dateofbirth from customer Where DateofBirth BETWEEN date('1004-01-01') AND date('1980-12-31');
select dateofbirth from customer where date(dateofbirth)>date('1980-12-01');
select * from customer where date(dateofbirth) < date('now','-30 years');
If you are using Sqlite V3.7.12 or greater
Dont use date(dateofbirth) just use dateofbirth. So your query would look like this:
select * from customer where dateofbirth < date('now','-30 years');
Using the magic docs at the sqlite website:
select * from mytable where dob < date('now','-30 years');
Try writing using the date format 'YYYY-MM-DD'
select * from mytable where dob > '1980-01-01'
A more programic way would be something like this:
select * from mytable where datediff(dob, now()) > 30
You'll Need to find specific syntax for sqlite.
select * from mytable where date(dob) > date('1980-01-10')
QLite3 has some cool new date functions. Per the docs site you can use date(), time(), datetime(), julianday(), unixepoch(), or strftime() depending on how your column data is formatted.
If you use strftime(), like my suggestion below, then you have to make sure that your column data is formatted the same way as your strftime string.
You would probably want something like:
SELECT * FROM mytable WHERE dob < strftime("%m/%d/%Y", 'now', '-30 year');
Note that you might have to change the format string here to match your own.
And here's some code that I use personally to give you a better idea of how powerful it is. It lets me get all the orders from the previous 3 months, not including this month.
SELECT * FROM orders WHERE SHIPPEDDATE > strftime('%m/%d/%Y', 'now', 'start of month', '-3 month');
The modifiers are very powerful with sqlite. The first string inside strftime() is the format, the 2nd string is when you want the date to start. 'Start of month' puts the day to 1, and '-3 month' goes back 3 months. So if I ran that today (08/03/2022), the date it uses would be 05/01/2022.