I have created a column with
day_endnav double precision
When I insert a number: 58.320856084100 in database its stored as 58.3208560841 .
The 2 zeros at the end are removed.
Is there any way to say to mariadb to keep what is entered as it is. Not to roundof or removed zeros at the end?
The two zeros were not "removed". DOUBLE has 53 significant bits, which is about 16 significant decimal digits. The display of the number probably decided they were irrelevant. What tool displayed them?
Whether you insert 58.320856084100 or 58.32085608410000000000000, you will get the same value stored into DOUBLE.
Trailing zeros (at least after the decimal point) have no mathematical meaning to FLOAT or DOUBLE. If you have some meaning, then I guess you need to store it as a string, or DECIMAL.
DECIMAL(mm, 12) will store and display 58.320856084100 (if mm >= 14). However, DECIMAL is "fixed-point". That is, DECIMAL(20,12) will always have exactly 12 decimal places, no more, no fewer.
Please state your goal; maybe I have not touched on that point yet.
Related
I'm storing a value (0.15) as a Real datatype in a Quantity field in SQL.
Just playing around, when I cast as numeric, there are some very slight changes to scale.
I'm unsure why this occurs, and why these particular numbers?
select CAST(Quantity AS numeric(18,18)) -- Quantity being 0.15
returns
0.150000005960464480
Real and float are approximate numerics, not exact ones. If you need exact ones, use DECIMAL.
The benefit of the estimated ones is that they allow storing very large numbers using fewer storage bytes.
https://learn.microsoft.com/en-us/sql/t-sql/data-types/float-and-real-transact-sql?view=sql-server-2017
PS:Numeric and decimal are synonymous.
PS2: See Eric's Postpischil clarification comment below:
"Float and real represent a number as a significand multiplied by a power of two. decimal represents a number as a significand multiplied by a power of ten. Both means of representation are incapable of representing all real numbers, and both means of representation are subject to rounding errors. As I wrote, dividing 1 by 3 in a decimal format will have a rounding error"
Say I have test results values for a lab procedure that come in as 103. What would be the best way to store this in SQL Server? I would think since this is numerical data it would be improper to just store it as string text and then program around calculating the data value from the string.
If you want to use your data in numeric calculations, it is probably best to represent your data using once of SQL servers native numeric data type. Since you show scientific notation, it is likely you will want to use either REAL or FLOAT.
Real is basically 7 decimal digits of precision and float has 15 digits of precision (at least this is how they are normally used). You can actually specify reduced precision for FLOAT, but in practice most people just use REAL in that case. REAL takes 4 bytes of storage, and FLOAT requires 8 bytes.
The other numeric types are for fixed decimal point arithmetic.
Numbers in scientific notation like this have three pieces of information:
The significand
The precision of the significand
The exponent of 10
Presuming we want to keep all this information as exact as possible, it may be best to store these in three non-floating point columns (floating-point values are inexact):
DECIMAL significand
INT precision (# of decimal places)
INT exponent
The downside to the approach of separating these parts out, of course, is that you'll have to put the values back together when doing calculations -- but by doing that you'll know the correct number of significant figures for the result. Storing these three parts will also take up 25 bytes per value (17 for the DECIMAL, and 4 each for the two INTs), which may be a concern if you're storing a very large quantity of values.
Update per explanatory comments:
Given that your goal is to store an exponent from 1-8, you really only need to store the exponent, since you know the mantissa is always 10. Therefore, if your value is always going to be a whole number, you can just use a single INT column; if it will have decimal places, you can use a FLOAT or REAL per Gary Walker, or use a DECIMAL to store a precise decimal to a specified number of places.
If you specify a DECIMAL, you can provide two arguments in the column type; the first is the total number of digits to be stored, while the second is the number of digits to the right of the decimal point. So if your values are going to be accurate to the tenths place, you might create a column of DECIMAL(2,1). SQL Server MSDN documentation: DECIMAL and NUMERIC types
I have tried to find information and how.
But it did not contain any information that would help.
With T-SQL, I want to convert negative decimal to binary
and convert it back.
Sample value: -9223372036854775543
I try in convert with Calculater this value to Bin result is ...
1000000000000000000000000000000000000000000000000000000100001001
and Convert back to Dec. It's OK.
How i can Convert like this with T-SQL(SQL2008) Script/Function ?
Long time to find information for how to.
Anyone who knows about this, please help.
There is no build in functionality.
for INT and BIGINT you can use CONVERT(VARCHAR(100),CAST(3 AS VARBINARY(100)),2) to get the hex representation as a string. then you can do a simple search replace as every hex digit represents exactly 4 binary digits. However, with values outside of the BIGINT range there is no standard as to how they are represented internally. You might get the right result or not and that behavior might even change between versions.
There is also no standard as to how negative numbers are represented. Most implementations of integers use the two's-complement representation. In that representation the top most bit indicates the sign of the number. How many bits you have is a metter of convention and fully dependent on your environment.
In mathematics -3 woud be -11 in binary and not 11111101.
To solve your problem you can either use a CLR function or you go through your number the old fashioned way:
Is it odd? -> output a 1
Is it even? -> output a 0
integer divide by 2
repeat until the value is 0
This will give you the digits in opposite order, so you have to flip the result. To get the two's-complement representation of a negative number n calculate 1-n, convert the result to binary using the above algorithm but with reversed digits (0 instead of 1 and vice versa). After flipping the digits into the right order prepend with enough 1s to fill your "box".
I am pulling financial data into Matlab from SQL, where it is unfortunately stored as a 'Real' (which is an approximate data-type).
For example, a value got loaded into SQL as "96.194" which is the correct value (this could have any number of decimals 1-5). I know in SQL it is stored as something like 96.19400024 because it is an approximation, but SQL Server somehow knows to display it as 96.194.
When I pull it into matlab, it gets pulled in as 96.194, which is what I want. Unfortunately, it turns out it's not actually 96.194, as demonstrated:
>>price
price =
96.194
>> price==96.194
ans =
0
>> class(price)
ans =
single
>> double(price)
ans =
96.1940002441406
So my question is, is there a way to convert a single to a double exactly as it appears as a single (i.e. truncate all the decimals which are the approximation? Note: I cannot just round it because I don't know how many decimals it's supposed to have.
The vpa function lets you specify a number of significant (nonzero) digits that is different from the current digits setting. For example:
vpa(price, num_of_digits_required)
or in your case:
vpa(double(price),7)
(6 or 8 significant digits will yield the same result)
Edit
To use vpa you'll need the Symbolic Math Toolbox, there are alternatives found on the web, such as this FEX file.
Single precision floating point values have only about 7 digits of precision (23 bit fractional component, log10(2^24) ≈ 7.225 decimal digits) so you could round off all but the 7 most significant digits.
Help says:
By default, the maximum precision
returns 38.
Examples:
SELECT ##MAX_PRECISION
Of course it is. That should mean, you can somehow change it, right? But I can't find an option for it. Is there some hidden crypted registry key or something?
The problem is that not all applications support precision > 24 and treat such values as text O_o But aggregate functions always return max precision if they not forced to something else.
For example, i need only 15 digits in all queries that return decimals, and don't want to manually CAST every SUM/MIN/MAX operator to decimal(10, 5)...
The MAX_PRECISION simply reflects the maximum internal size of your SQL-Server's representation of floating point numbers. Thus you cannot change it. It's like a parameter telling you that you have 4 GB of memory installed. There is no registry hack to change that amount :-)
However you can specify less than this value in the column datatype or, as you pointed out, you can convert the results.