How to convert timestamp to datetime - sql

How to convert datetime to timestamp ?
Timestamp like 'yyyy-mm-dd hh:mm:ss.mss'
I try to format this
format(time_field , 'dd.mm.yyyy hh:mm:ss')
but in the end it turns out '1.43.2019 01:43:03'


use MM for month when formatting
SELECT FORMAT(GETDATE(), 'dd.MM.yyyy HH:mm:ss')


use the built in convert function, with a suitable option.
SELECT CONVERT(varchar, getdate(), 21);
https://www.w3schools.com/sql/func_sqlserver_convert.asp


You don't actually need to use format() for this, because the format you want is a "built-in" format for SQL Server's convert() function:
select convert(varchar(255), timefield, 120)
I'm not a big fan on convert() and its arcane formatting options. However, options 120 and 121 are pretty much the ones that I know and use.

Related

Formatting SQL Server date causes datatype issue

When I tried this SQL query
select format(getdate(), 'yyyy-MM-dd HH:mm:ss.fff')
I get this result:
2016-07-01 23:19:16.573
But when I try this, it throws an error:
select format('2016-06-28T23:44:23.7573244Z', 'yyyy-MM-dd HH:mm')
Error:
Argument data type varchar is invalid for argument 1 of format function.
Why is this happening? I think both are almost similar.

You need to first convert the string to a DATETIME object before you call FORMAT:
FORMAT(CONVERT(DATETIME, '2016-06-28T23:44:23.757Z', 127), 'yyyy-MM-dd HH:mm')
If you wanted to use your original input, you might have to STUFF away the extra time data beyond millisecond precision:
FORMAT(CONVERT(DATETIME,
STUFF('2016-06-28T23:44:23.7573244Z', 24, 4, ''),
127), 'yyyy-MM-dd HH:mm')

Convert date time to below format SQL Server

I tried to obtain date in this format:
'05-31-2014 01:20:25 AM'
I used below code:
Sql Fiddle here, but output date strangely changed to a different date: 30-26-2011 01:30:38 AM
select format(CAST('2011-11-26 01:30:38.000' AS datetime), 'mm-dd-yyyy hh:mm:ss tt')
Sql Fiddle here

When using the FORMAT() function, mm is minutes, MM is month, so change to:
SELECT FORMAT(CAST('2011-11-26 01:30:38.000' AS DATETIME), 'MM-dd-yyyy hh:mm:ss tt')
If there's already an appropriate format available via CONVERT(), that is preferable as it performs better than the FORMAT() function.

Which datetime format to use SQL Server

I have a date as a varchar in the form
DD/MM/YYYY HH:MM:SS AM
e.g.
16/3/2012 4:39:26 PM
I can't see a valid format option for CONVERT() in the MSDN page
Am I missing something or will I have to reformat the varchar field first?
Edit:
Corrected the format, sorry about that

Once you get your story straight, you'll want one of these:
-- if you really meant dd/mm/yyyy then:
SELECT CONVERT(DATETIME, '16/3/2012 4:39:26 PM', 103);
-- if you really meant mm/dd/yyyy then:
SELECT CONVERT(DATETIME, '3/16/2012 4:39:26 PM', 101);
But agreed with Madhivanan. Don't store dates using the wrong data type, and if you must, use an unambiguous format!

Always use proper DATETIME datatype to store dates
YYYYMMDD and YYYYMMDD HH:MM:SS are unambiguous date formats
For more information, refer this
http://beyondrelational.com/modules/2/blogs/70/posts/10898/understanding-datetime-column-part-ii.aspx

This will work.
DECLARE #dt varchar(100)='2012/3/16 4:39:26 PM'
select convert(datetime,#dt,101)

How to change the date format from MM/DD/YYYY to YYYY-MM-DD in PL/SQL?

I have a date column in a table stored as MM/DD/YYYY format. I have to select and store the same date in another table in YYYY-MM-DD format i.e. XSD Date Format. But I am not able to do it. I am using this query:
select to_date(date_column,'YYYY-MM-DD') from table;
But still I am not able to do it. Giving me error
ORA-01843 : not a valid month

use
select to_char(date_column,'YYYY-MM-DD') from table;

It sounds like you've got it the wrong way round. If your existing data is in MM/DD/YYYY format, then you want:
select to_date(date_column,'MM/DD/YYYY') from table;
to convert the existing data to DATE values. (I do wonder why they're not stored as dates, to be honest...)
If you want to perform the conversion in one step, you might want:
select to_char(to_date(date_column,'MM/DD/YYYY'), 'YYYY-MM-DD') from table;
In other words, for each row, parse it in MM/DD/YYYY format, then reformat it to YYYY-MM-DD format.
(I'd still suggest trying to keep data in its "natural" type though, rather than storing it as text in the first place.)

I assume that you can use the Oracle SQL Developer, which you can download from here.
You can define the date format which you want to work with:
ALTER SESSION SET nls_date_format='yyyy-mm-dd';
With this, now you can perform a query like this:
SELECT * FROM emp_company WHERE JDate = '2014-02-25'
If you want to be more specific you can define the date format like this:
ALTER SESSION SET nls_date_format='yyyy-mm-dd hh24:mi:ss';

To convert a DATE column to another format, just use TO_CHAR() with the desired format, then convert it back to a DATE type:
SELECT TO_DATE(TO_CHAR(date_column, 'DD-MM-YYYY'), 'DD-MM-YYYY') from my_table

select to_date(to_char(ORDER_DATE,'YYYY/MM/DD'))
from ORDERS;
This might help but, at the end you will get a string not the date. Apparently,
your format problem will get solved for sure .

For military time formatting,
select TO_CHAR(SYSDATE, 'yyyy-mm-dd hh24:mm:ss') from DUAL
--2018-07-10 15:07:15
If you want your date to round DOWN to Month, Day, Hour, Minute, you can try
SELECT TO_CHAR( SYSDATE, 'yyyy-mm-dd hh24:mi:ss') "full-date" --2018-07-11 10:40:26
, TO_CHAR( TRUNC(SYSDATE, 'year'), 'yyyy-mm-dd hh24:mi:ss') "trunc-to-year"-- 2018-01-01 00:00:00
, TO_CHAR( TRUNC(SYSDATE, 'month'), 'yyyy-mm-dd hh24:mi:ss') "trunc-to-month" -- 2018-07-01 00:00:00
, TO_CHAR( TRUNC(SYSDATE, 'day'), 'yyyy-mm-dd hh24:mi:ss') "trunc-to-Sunday" -- 2018-07-08 00:00:00
, TO_CHAR( TRUNC(SYSDATE, 'dd'), 'yyyy-mm-dd hh24:mi:ss') "trunc-to-day" -- 2018-07-11 00:00:00
, TO_CHAR( TRUNC(SYSDATE, 'hh'), 'yyyy-mm-dd hh24:mi:ss') "trunc-to-hour" -- 2018-07-11 10:00:00
, TO_CHAR( TRUNC(SYSDATE, 'mi'), 'yyyy-mm-dd hh24:mi:ss') "trunc-to-minute" -- 2018-07-11 10:40:00
from DUAL
For formats literals, you can find help in
https://docs.oracle.com/cd/B28359_01/server.111/b28286/functions242.htm#SQLRF52037

You can do this simply by :
select to_char(to_date(date_column, 'MM/DD/YYYY'), 'YYYY-MM-DD') from table

According to the comments, the data-type in the datatable is DATE.
So you should simply use:
"select date_column from table;"
Now if you execute the select you will get back a date data-type, which should be what you need for the .xsd.
Culture-dependent formating of the date should be done in the GUI (most languages have convenient ways to do so), not in the select-statement.

Basically , Data in a Date column in Oracle can be stored in any user defined format or kept as default.
It all depends on NLS parameter.
Current format can be seen by : SELECT SYSDATE FROM DUAL;
If you try to insert a record and insert statement is NOT in THIS format then it will give :
ORA-01843 : not a valid month error.
So first change the database date format before insert statements ( I am assuming you have bulk load of insert statements) and then execute insert script.
Format can be changed by :
ALTER SESSION SET nls_date_format = 'mm/dd/yyyy hh24:mi:ss';
Also You can Change NLS settings from SQL Developer GUI , (Tools > preference> database > NLS)
Ref: http://oracle.ittoolbox.com/groups/technical-functional/oracle-sql-l/how-to-view-current-date-format-1992815

This worked for me! You can convert to datatype you want be it a date or string
to_char(TO_DATE(TO_CHAR(end_date),'MM-DD-YYYY'),'YYYY-MM-DD') AS end_date

Late reply but for.databse-date-type the following line works.
SELECT to_date(t.given_date,'DD/MM/RRRR') response_date FROM Table T
given_date's column type is Date

Just to piggy back off of Yahia, if you have a timestamp you can use this function to cast exclusively as date, removing the timestamps.
TO_CHAR(CAST(DateTimeField AS DATE), 'YYYY-MM-DD') AS TrackerKey__C
Or in my case I need the below format
TO_CHAR(CAST(DateTimeField AS DATE), 'YYYYMMDD') AS TrackerKey__C

SELECT TO_DATE(TO_CHAR(date_column,'MM/DD/YYYY'), 'YYYY-MM-DD')
FROM table;

if you need to change your column output date format just use to_char this well get you a string, not a date.

use
SELECT STR_TO_DATE(date_column,'%Y-%m-%d') from table;
also gothrough
http://dev.mysql.com/doc/refman/5.0/en/date-and-time-functions.html

Oracle equivalent to SQL function 'convert'

For e.g in SQL I have:
CONVERT(VARCHAR(10), mydate, 120)
CONVERT(DECIMAL(18,2), cost)
Is there an equivalent for these in Oracle?

This in TSQL:
CONVERT(VARCHAR(10), mydate, 120)
...returns a string, so you should probably use TO_CHAR:
TO_CHAR(mydate, 'yyyy-mm-dd hh24:mi:ss')
You'd use TO_DATE if the value is not already an Oracle DATE data type, using the same format mask:
TO_DATE(mydate, 'yyyy-mm-dd hh24:mi:ss')
...or I would anyways, preferring explicit data type conversion when dealing with temporal data types.
This in TSQL:
CONVERT(DECIMAL(18,2),cost)
...needs to use the CAST function:
CAST(cost AS DECIMAL(18,2))

You want to look at the built-in functions for PLSQL.
to_date('15/11/2010''dd/MM/yyyy')
and
to_number('1234.567','999.99')