I have a date column P20210301. How to tranform this date to format 01.03.2021?
This can be done by converting your text to a date datatype using TO_DATE, then converting it to the format you want as a string with TO_CHAR
SELECT TO_CHAR (TO_DATE ('P20210301', '"P"YYYYMMDD'), 'DD.MM.YYYY') AS new_date FROM DUAL;
Database by default date stored in yyyy-mm-dd format so you have to manage a coding side
Note :if you use a PHP language then you use a date() function in PHP.
if any other language use like this:
TO_CHAR ( TO_DATE (str, 'YYYY/MM/DD'), 'DD.MM.YYYY')
Happy Coding...!!
How to convert datetime to timestamp ?
Timestamp like 'yyyy-mm-dd hh:mm:ss.mss'
I try to format this
format(time_field , 'dd.mm.yyyy hh:mm:ss')
but in the end it turns out '1.43.2019 01:43:03'
use MM for month when formatting
SELECT FORMAT(GETDATE(), 'dd.MM.yyyy HH:mm:ss')
use the built in convert function, with a suitable option.
SELECT CONVERT(varchar, getdate(), 21);
https://www.w3schools.com/sql/func_sqlserver_convert.asp
You don't actually need to use format() for this, because the format you want is a "built-in" format for SQL Server's convert() function:
select convert(varchar(255), timefield, 120)
I'm not a big fan on convert() and its arcane formatting options. However, options 120 and 121 are pretty much the ones that I know and use.
I have column of datatype varchar2 for example it store the values in thi format (2002-01-11T00:00:00.000-08:00).
But I want to have the value in the format of this type YYYYMMDD.
I just wanted to have this queried in SQL(Using SQL developer) statement.
My NLS is having the date format of DD-MON-RR and time stamp format is DD-MON-RR HH.MI.SSXFF AM
Can someone help me please.
Thanks in advance.
Use FROM_UNIXTIME
SELECT
FROM_UNIXTIME(timestamp_field) AS formatted_date
FROM
tablename;
SELECT CONVERT(VARCHAR(10), GETDATE(), 112) AS [YYYYMMDD]
select to_char(
to_date(
substr('2002-01-11T00:00:00.000-08:00',1,10)
,'YYYY-MM-DD')
,'YYYYMMDD')
from dual;
20020111
I have the date in the format of yy-mm-dd and I want to convert it to dd-mm-yyyy. I used the following select statement:
select convert(varchar(30), hiredate, 110)
from emp;
But, I keep getting an error that there's a missing expression:
ORA-00936: missing expression
Can someone please guide me?
If the hiredate's data type is DATE, then use to_char function:
select to_char(hiredate, 'dd-mm-yyyy') from emp;
If the hiredate's data type is VARCHAR2 or CHAR, convert it to DATE by to_date then use to_char:
select to_char(to_date(hiredate, 'yy-mm-dd'), 'dd-mm-yyyy') from emp;
I have a date column in a table stored as MM/DD/YYYY format. I have to select and store the same date in another table in YYYY-MM-DD format i.e. XSD Date Format. But I am not able to do it. I am using this query:
select to_date(date_column,'YYYY-MM-DD') from table;
But still I am not able to do it. Giving me error
ORA-01843 : not a valid month
use
select to_char(date_column,'YYYY-MM-DD') from table;
It sounds like you've got it the wrong way round. If your existing data is in MM/DD/YYYY format, then you want:
select to_date(date_column,'MM/DD/YYYY') from table;
to convert the existing data to DATE values. (I do wonder why they're not stored as dates, to be honest...)
If you want to perform the conversion in one step, you might want:
select to_char(to_date(date_column,'MM/DD/YYYY'), 'YYYY-MM-DD') from table;
In other words, for each row, parse it in MM/DD/YYYY format, then reformat it to YYYY-MM-DD format.
(I'd still suggest trying to keep data in its "natural" type though, rather than storing it as text in the first place.)
I assume that you can use the Oracle SQL Developer, which you can download from here.
You can define the date format which you want to work with:
ALTER SESSION SET nls_date_format='yyyy-mm-dd';
With this, now you can perform a query like this:
SELECT * FROM emp_company WHERE JDate = '2014-02-25'
If you want to be more specific you can define the date format like this:
ALTER SESSION SET nls_date_format='yyyy-mm-dd hh24:mi:ss';
To convert a DATE column to another format, just use TO_CHAR() with the desired format, then convert it back to a DATE type:
SELECT TO_DATE(TO_CHAR(date_column, 'DD-MM-YYYY'), 'DD-MM-YYYY') from my_table
select to_date(to_char(ORDER_DATE,'YYYY/MM/DD'))
from ORDERS;
This might help but, at the end you will get a string not the date. Apparently,
your format problem will get solved for sure .
For military time formatting,
select TO_CHAR(SYSDATE, 'yyyy-mm-dd hh24:mm:ss') from DUAL
--2018-07-10 15:07:15
If you want your date to round DOWN to Month, Day, Hour, Minute, you can try
SELECT TO_CHAR( SYSDATE, 'yyyy-mm-dd hh24:mi:ss') "full-date" --2018-07-11 10:40:26
, TO_CHAR( TRUNC(SYSDATE, 'year'), 'yyyy-mm-dd hh24:mi:ss') "trunc-to-year"-- 2018-01-01 00:00:00
, TO_CHAR( TRUNC(SYSDATE, 'month'), 'yyyy-mm-dd hh24:mi:ss') "trunc-to-month" -- 2018-07-01 00:00:00
, TO_CHAR( TRUNC(SYSDATE, 'day'), 'yyyy-mm-dd hh24:mi:ss') "trunc-to-Sunday" -- 2018-07-08 00:00:00
, TO_CHAR( TRUNC(SYSDATE, 'dd'), 'yyyy-mm-dd hh24:mi:ss') "trunc-to-day" -- 2018-07-11 00:00:00
, TO_CHAR( TRUNC(SYSDATE, 'hh'), 'yyyy-mm-dd hh24:mi:ss') "trunc-to-hour" -- 2018-07-11 10:00:00
, TO_CHAR( TRUNC(SYSDATE, 'mi'), 'yyyy-mm-dd hh24:mi:ss') "trunc-to-minute" -- 2018-07-11 10:40:00
from DUAL
For formats literals, you can find help in
https://docs.oracle.com/cd/B28359_01/server.111/b28286/functions242.htm#SQLRF52037
You can do this simply by :
select to_char(to_date(date_column, 'MM/DD/YYYY'), 'YYYY-MM-DD') from table
According to the comments, the data-type in the datatable is DATE.
So you should simply use:
"select date_column from table;"
Now if you execute the select you will get back a date data-type, which should be what you need for the .xsd.
Culture-dependent formating of the date should be done in the GUI (most languages have convenient ways to do so), not in the select-statement.
Basically , Data in a Date column in Oracle can be stored in any user defined format or kept as default.
It all depends on NLS parameter.
Current format can be seen by : SELECT SYSDATE FROM DUAL;
If you try to insert a record and insert statement is NOT in THIS format then it will give :
ORA-01843 : not a valid month error.
So first change the database date format before insert statements ( I am assuming you have bulk load of insert statements) and then execute insert script.
Format can be changed by :
ALTER SESSION SET nls_date_format = 'mm/dd/yyyy hh24:mi:ss';
Also You can Change NLS settings from SQL Developer GUI , (Tools > preference> database > NLS)
Ref: http://oracle.ittoolbox.com/groups/technical-functional/oracle-sql-l/how-to-view-current-date-format-1992815
This worked for me! You can convert to datatype you want be it a date or string
to_char(TO_DATE(TO_CHAR(end_date),'MM-DD-YYYY'),'YYYY-MM-DD') AS end_date
Late reply but for.databse-date-type the following line works.
SELECT to_date(t.given_date,'DD/MM/RRRR') response_date FROM Table T
given_date's column type is Date
Just to piggy back off of Yahia, if you have a timestamp you can use this function to cast exclusively as date, removing the timestamps.
TO_CHAR(CAST(DateTimeField AS DATE), 'YYYY-MM-DD') AS TrackerKey__C
Or in my case I need the below format
TO_CHAR(CAST(DateTimeField AS DATE), 'YYYYMMDD') AS TrackerKey__C
SELECT TO_DATE(TO_CHAR(date_column,'MM/DD/YYYY'), 'YYYY-MM-DD')
FROM table;
if you need to change your column output date format just use to_char this well get you a string, not a date.
use
SELECT STR_TO_DATE(date_column,'%Y-%m-%d') from table;
also gothrough
http://dev.mysql.com/doc/refman/5.0/en/date-and-time-functions.html