I'm working on an stm32l467 and trying to run an ISR when i push the user-push-button. Everything looks to be setup correctly. I have looked at the registers in the debugger (Keil uV) and everything looks good, but when i push the button I end up in the default handler and can't understand why the handler is not running.
Running in the debugger i can see that when i push the button, i get an interrupt-pending (EXTI->PR1) flag, but the code then jumps to the the default handler. I can't see what i'm missing. I know there are easier ways to setup interrupts using the HAL layer, i'm just trying to understand what registers must be accessed from a low-level.
Can anyone suggest a missing step to this?
#include <stm32l4xx.h>
#define DELAY 1
void delay1Hz(void);
bool buttonInterrupt = false;
int main(void)
{
__disable_irq();
/* Configure the clocks */
RCC->CR &= 0xFFFFFF07; //Clear ~MSIRANGE bits and MSIRGSEL bit
RCC->CR |= 0x00000088; //Set MSI to 16MHz and MSIRGSEL bit
RCC->AHB2ENR |= 0x00000001; //Enable PA5 clocks
/* Enable PA0 for output */
GPIOA->MODER &= 0xFFFFF3FF; //Clear GPIOA[5] MODER bits
GPIOA->MODER |= 0x00000400; //Enable GPIOA[5] for output
RCC->AHB2ENR |= 0x4; //ENABLE GPIOC port clk
GPIOC->MODER &= 0xF3FFFFFF; //Clear GPIOC[13] for input mode
RCC->APB2ENR |= 1; //Enable SYSCFG clk
SYSCFG->EXTICR[3] &= ~0x00F0; //CLEAR_BIT the EXTI[13] bits
SYSCFG->EXTICR[3] |= 0x20; //Enable GPIOC for EXTI[13]
EXTI->IMR1 |= 0x2000; //Unmask EXTI13
EXTI->FTSR1 |= 0x2000; //Enable falling edge trigger on pb
NVIC_EnableIRQ(EXTI15_10_IRQn); //Enable EXTI15-to-10 interrupts
__enable_irq();
for (;;)
{
if(buttonInterrupt == true) {
//flash LED's (doesn't get here)
}
}
}
void initTim2() {
//timer 2 code - not causing a problem
}
void delay1Hz() {
//delay code - not interrupt controlled
}
/* This doesn't run */
void EXTI15_10_IRQHandler(void) {
buttonInterrupt = true;
EXTI->PR1 = 0x2000;
}
Never mind: There seems to be some problem with a delay i have with timer-2. It's not using interrupts, so i'm surprised it's causing trouble. But if i take it out and use a different delay, the interrupt from the above code works fine. It's an odd one.
Related
I'm using STM32F407G-DISC1 board, SYS_TICK handler is not getting called after enabling flags in SysTick Control and Status Register which is at 0xE000E010 memory mapped location. SysTick Reload Value Register value is set to 15999.
void init_systick_timer(uint32_t tick_hz)
{
uint32_t *pSRVR = (uint32_t*)0xE000E014;
uint32_t *pSCSR = (uint32_t*)0xE000E010;
/* calculation of reload value */
uint32_t count_value = (SYSTICK_TIM_CLK/tick_hz)-1;
//Clear the value of SVR
*pSRVR &= ~(0x00FFFFFFFF);
//load the value in to SVR
*pSRVR |= count_value;
//do some settings
*pSCSR |= ( 1 << 1); //Enables SysTick exception request:
*pSCSR |= ( 1 << 2); //Indicates the clock source, processor clock source
//enable the systick
*pSCSR |= ( 1 << 0); //enables the counter
}
void SysTick_Handler(void)
{
}
I would rather recomment to do not reinvent the wheel and use standard STM provided CMSIS headers.
Your way of defining the registers is incorrect. It will not work correctly if decide to read theis values back. Compiler will simple optimize the reads from the memory out. They have to be volatile.
But abstracting from that you need to enable the interrupt in the NVIC controller. Without that the systick timer will only set the pending flag without invoking the handler.
I want to send 10 bytes of data through UART loopback by interrupt mode. Though I'm able to receive the data, I don't understand why my HAL_UART_RxCpltCallback() is not getting executed. But my HAL_UART_TxCpltCallback(), is getting executed every time after a byte of data is transferred. I've generated code through cubeMX. I've enabled the USART2 global interrupt. My Control Register(CR1) for my USART2 is 0x300c. That is, UE,M,TE,RE bits are only set. The TXIE, TCIE bits are NOT set in the CR1 Register.
Now,
What does "global" in global interrupt mean here? Does that mean an interrupt is generated from any one of the 10 sources(mentioned in the data sheet like, Tx complete, Rx buffer full etc)?
None of the bits corresponding to interrupts are enabled in CR1 register. But the control is going to HAL_UART_TxCpltCallback() every time it transfers a byte of data. Why does this happen?
Please unveil the mystery.
PS: I'm using STM32F407G-DISC1 board, Attolic Truestudio IDE, Ubuntu 16.04 OS.
UART_HandleTypeDef huart2;
void SystemClock_Config(void);
static void MX_GPIO_Init(void);
static void MX_USART2_UART_Init(void);
uint8_t tx_data[] = {0,1,2,3,4,5,6,7,8,9};
uint8_t rx_data[10];
int main(void)
{
int i=0;
HAL_Init();
SystemClock_Config();
MX_GPIO_Init();
MX_USART2_UART_Init();
while (1)
{
HAL_UART_Transmit_IT(&huart2, &tx_data[i], 10);
HAL_Delay(1500);
HAL_UART_Receive_IT(&huart2, &rx_data[i] , 10);
HAL_Delay(1500);
if((xferCnt==10) || (rxCnt==10))
break;
else
i++;
}
}
void HAL_UART_TxCpltCallback(UART_HandleTypeDef *huart)
{
xferCnt++;
}
void HAL_UART_RxCpltCallback(UART_HandleTypeDef *huart)
{
rxCnt++;
}
I am using stm32f0 MCU.
I would like to transmit every single byte received from the uart out of the uart. I am enabling an interrupt on every byte received from uart.
My code is quite simple.
uint8_t Rx_data[5];
//Interrupt callback routine
void HAL_UART_RxCpltCallback(UART_HandleTypeDef *huart)
{
if (huart->Instance == USART1) //current UART
{
HAL_UART_Transmit(&huart1, &Rx_data[0], 1, 100);
HAL_UART_Receive_IT(&huart1, Rx_data, 1); //activate UART receive interrupt every time on receiving 1 byte
}
}
My PC transmits ASCII 12345678 to stm32. If things work as expected, the PC should be receiving 12345678 back. However, the PC receives 1357 instead. What is wrong with the code?
Reenabling interrupts may be inefficient. With a couple of modifications it is possible to keep the interrupt active without needing to write the handler all over again. See the example below altered from the stm32cubemx generator.
/**
* #brief This function handles USART3 to USART6 global interrupts.
*/
void USART3_6_IRQHandler(void)
{
InterruptGPS(&huart5);
}
void InterruptGPS(UART_HandleTypeDef *huart) {
uint8_t rbyte;
if (huart->Instance != USART5) {
return;
}
/* UART in mode Receiver ---------------------------------------------------*/
if((__HAL_UART_GET_IT(huart, UART_IT_RXNE) == RESET) || (__HAL_UART_GET_IT_SOURCE(huart, UART_IT_RXNE) == RESET)) {
return;
}
rbyte = (uint8_t)(huart->Instance->RDR & (uint8_t)0xff);
__HAL_UART_SEND_REQ(huart, UART_RXDATA_FLUSH_REQUEST);
// do your stuff
}
static void init_gps() {
__HAL_UART_ENABLE_IT(&huart5, UART_IT_RXNE);
}
You should make a tx array buffer as well, and use interrupt for writing as well (The first write if not enabled yet, should be sent immediately).
There should be examples of this for STM32 around.
You should probably switch the two lines: Transmit and Receive. The Transmit function waits for a timeout to send the character, in meantime the next received character is missed.
I'm trying to set up an external interrupt on my LPC812 uC. I've made the following code
#include "LPC8xx.h"
#define RLED 7 // red LED
bool pause = false;
void PININT0_IRQHandler(void)
{
pause = !pause;
}
int main(void) {
LPC_GPIO_PORT->DIR0 |= 1<<RLED; // set pin as output
LPC_GPIO_PORT->SET0 = 1<<RLED;
NVIC_EnableIRQ(PININT0_IRQn);
while (1)
{
if(!pause)
{
LPC_GPIO_PORT->CLR0 = 1<<RLED;
}
}
}
But it isn't working. Am I missing something?
I'm not familiar with NXP MCUs.
But at least place break piont inside PININT0_IRQHandler, to understand clearly that interrupt is not generated.
Also it will be nice to clear interrupt flag inside handler.
Some peripherals need interrupt permission in peripheral registers in addition to NVIC setup.
Did you setup input pin somewhere?
Your code only initialize GPIO 7 pin as output.
When I press PF8 button, I want the blackfin goes into a ISR and the counter increases 1.
I should clear or set a bit which indicates the processor has entered the ISR, but I don't know how to clear it.
My processor is BF533.
Here is my code:
// prototype
EX_INTERRUPT_HANDLER(FlagA_ISR);
volatile int count = 0;
void main(void)
{
// Register FlagA ISR to interrupt vector group 12
register_handler(ik_ivg12, FlagA_ISR);
// set direction of programmable flag PF8 to input
*pFIO_DIR &= ~PF8;
ssync();
// interrupt enable PF8
*pFIO_INEN |= PF8;
ssync();
// give interrupt when FIO_FLAG_D PF8 changes
*pFIO_MASKA_D |= PF8;
ssync();
// Bind FlagA interrupt to IVG12
*pSIC_IAR2 |= 0x00005000; // flag A IVG12
ssync();
// Enable PFA in system interrupt mask register
*pSIC_IMASK = 0x00080000;
ssync();
// enable IVG12 in core interrupt mask register
*pIMASK |= 0x00001000;
ssync();
// wait for interrupt
while(count < 5);
printf("5 interrupts received");
}
EX_INTERRUPT_HANDLER(FlagA_ISR)
{
count++;
// Needed to clear or set a bit to indicate that the processor has entered the ISR
}
I have just figured out how to solve this question.
The PFx are connected to the FIO_FLAG. We can clear our interrupt status by clearing FIO_FLAG.
Here is the code:
*pFIO_FLAG_D &= ~PF8;
ssync();
//or, you can try:
*pFIO_FLAG_C |= PF8;
ssync();