ADI BF533 programmable flag interrupt - embedded

Question

When I press PF8 button, I want the blackfin goes into a ISR and the counter increases 1.
I should clear or set a bit which indicates the processor has entered the ISR, but I don't know how to clear it.
My processor is BF533.
Here is my code:
// prototype
EX_INTERRUPT_HANDLER(FlagA_ISR);
volatile int count = 0;
void main(void)
{
// Register FlagA ISR to interrupt vector group 12
register_handler(ik_ivg12, FlagA_ISR);
// set direction of programmable flag PF8 to input
*pFIO_DIR &= ~PF8;
ssync();
// interrupt enable PF8
*pFIO_INEN |= PF8;
ssync();
// give interrupt when FIO_FLAG_D PF8 changes
*pFIO_MASKA_D |= PF8;
ssync();
// Bind FlagA interrupt to IVG12
*pSIC_IAR2 |= 0x00005000; // flag A IVG12
ssync();
// Enable PFA in system interrupt mask register
*pSIC_IMASK = 0x00080000;
ssync();
// enable IVG12 in core interrupt mask register
*pIMASK |= 0x00001000;
ssync();
// wait for interrupt
while(count < 5);
printf("5 interrupts received");
}
EX_INTERRUPT_HANDLER(FlagA_ISR)
{
count++;
// Needed to clear or set a bit to indicate that the processor has entered the ISR
}

Answer 1

I have just figured out how to solve this question.
The PFx are connected to the FIO_FLAG. We can clear our interrupt status by clearing FIO_FLAG.
Here is the code:
*pFIO_FLAG_D &= ~PF8;
ssync();
//or, you can try:
*pFIO_FLAG_C |= PF8;
ssync();