I am looking to use VBA to update links for an external input file. I am a developer and the path for the linked input file I use will not be the same as the end user will need once it is placed in a production folder.
Is there a way to update the linked file location using VBA? I already have code that allows the user to specify the input file location and that information is saved in the [InputFolder] of the [Defaults] table. Is there a way to use VBA to update the Linked Table using the InputFolder field info?
The stored InputFolder data looks like this:
C:\Users\CXB028\OneDrive - Comerica\Projects\HR\Input Data
The new folder info would have a network drive location path defined that I do not have access to but the user would.
Here is the code I use to define and store the Input Folder location:
Private Sub btnInputFldr_Click()
On Error GoTo Err_Proc
Const msoFileDialogFolderPicker As Long = 4
Dim objfiledialog As Object
Dim otable As DAO.TableDef
Dim strPathFile As String, strFile As String, strpath As String
Dim strTable As String
Dim fldr As Object
Set fldr = Application.FileDialog(msoFileDialogFolderPicker)
With fldr
.Title = "Choose Folder"
.Show
.InitialFileName = "" 'DFirst("InputFolder", "Defaults")
If .SelectedItems.Count = 0 Then
Exit Sub
Else
CurrentDb.Execute "UPDATE Defaults SET InputFolder='" & .SelectedItems(1) & "';"
End If
End With
Me.txtInputFldr.Requery
Exit Sub
Err_Proc:
MsgBox "Error " & Err.Number & ": " & Err.Description, vbCritical, "Process Error"
End Sub
The linked table (an external excel spreadsheet) needs to be re-linked after the database is moved to the production location using VBA code when the new Input Folder is redefined.
I found some very simple and short code the worked great!! Please see below.
On Error Resume Next
'Set new file path location if the TABLE.FIELDNAME location exists
Set tbl = db.TableDefs("ENTER THE LINKED TABLE NAME HERE")
filePath = DLookup("ENTER YOUR LOOKUP TABLE FIELD NAME HERE", "ENTER YOUR LOOKUP TABLE NAME HERE") & "\ENTER YOUR EXCEL SPREADSHEET NAME HERE.XLSX"
tbl.Connect = "Excel 12.0 Xml;HDR=YES;IMEX=2;ACCDB=YES;DATABASE=" & filePath
tbl.RefreshLink
On Error GoTo 0
Hope someone else finds this as useful as I did!
Related
I want to create a new word file called "xxx_def_xxx" from selected word file called "xxx_docu_xxx".
So I select a file from dialog -> do something -> SaveAs with new file name.
It does work, but I'm getting "run time error 4160: Bad file name" if I select the file created from others, i.e., if the author is not me but another person.
I was struggling with this problem for couple of days but couldn't solve it.
Any help will be really thankful!
Private Sub CommandButton1_Click()
Dim fileOpen As FileDialog
Dim docuName As String, defName As String
Dim docu As Document
Set fileOpen = Application.FileDialog(FileDialogType:=msoFileDialogOpen)
With fileOpen
.Filters.Clear
.Filters.Add "Word Documents", "*.docx*"
.Title = "Select the docu"
.AllowMultiSelect = False
If .Show = -1 Then
docuName = .SelectedItems(1)
Else
Exit Sub
End If
End With
Set docu = Documents.Open(docuName)
'do something: remove or edit some texts in the file
defName = Replace(docu.Name, "docu", "def")
docu.SaveAs docu.Path & "\" & defName
docu.Saved = True
docu.Close
End Sub
I am trying to upload multiple files at once into an access database via the use of a button. However only one file will upload at a time.
When the button is clicked it calls a sub procedure. My code is below:
Private Sub btnImport_Click()
'Calls the procdure that imports raw files
Call Module1.ImportRawFiles
End Sub
Public Sub ImportRawFiles()
Dim oFileDiag As Office.FileDialog
Dim path As String: path = ""
Dim oFSO As New FileSystemObject
Dim FileSelected As Variant
Set oFileDiag = Application.FileDialog(msoFileDialogFilePicker) ''Picks file to import
oFileDiag.AllowMultiSelect = True ''Allows multiple files to be selected
oFileDiag.Title = "Please select the reports to upload"
oFileDiag.Filters.Clear
oFileDiag.Filters.Add "Excel Spreadsheets", "*.xlsx, *.xls" ''Only allows xlsx and xls file types to upload
If oFileDiag.Show Then
For Each FileSelected In oFileDiag.SelectedItems
Form_Homepage.txtFileName = FileSelected
Next
End If
If Nz(Form_Homepage.txtFileName, "") = "" Then
MsgBox "No files selected please select a file"
Exit Sub
End If
If oFileDiag.SelectedItems.Count > 0 Then path = oFileDiag.SelectedItems(1)
If Len(path) > 0 Then
DoCmd.TransferSpreadsheet acImport, acSpreadsheetTypeExcel12, oFSO.GetFileName(Form_Homepage.txtFileName), path, 1
MsgBox "The " & oFSO.GetFileName(Form_Homepage.txtFileName) & " file has been uploaded"
Else
MsgBox "File not found"
End If
Does anyone know why only one file is uploading?
You are looping through all selected files to assign Form_Homepage.txtFileName but then not doing anything else in that same loop:
If oFileDiag.Show Then
For Each FileSelected In oFileDiag.SelectedItems
Form_Homepage.txtFileName = FileSelected
Next
End If
So by end of the loop, the last selected file is assigned, ignoring all the others, then your later logic statements only perform on that one file.
One solution would be to move your action logic up to the same loop. So move your IF statements into the assignment loop, that way they operate on each iterative assignment of your variable.
This question already has answers here:
Filepicker VBA to select file and store the file name not working
(2 answers)
Closed 3 years ago.
I am trying to write a macro that allows a user to select a .oft from a directory. I have been able to get a simple macro working that will open a specific .oft and modify the "from" field - this is what I have so far.
Sub EmailTemplateW10()
Set msg = Application.CreateItemFromTemplate("c:\test\test.oft")
msg.SentOnBehalfOfName = "user#domain.com"
msg.Display
Set msg = Nothing
End Sub
That works great, but there are numerous .oft files in the directory I am working with. I did find some articles that talk about setting up a toolbar with drop-downs and creating a macro for each .oft in the directory. I assume there has to be a better way than making a macro for each template.
I tried using this :
Sub EmailTemplateW10()
Set msg = Application.CreateItemFromTemplate(Demo)
msg.SentOnBehalfOfName = "user#domain.com"
msg.Display
Set msg = Nothing
End Sub
Function Demo()
Call Shell("explorer.exe" & " " & "C:\test\", vbNormalFocus)
End Function
Windows Explorer will come up - but the macro throws an error and stops when you acknowledge the error.
Is there perhaps some way to have the user select the file through explorer.exe and save the path of the selected file to a variable, and then pipe that into .CreateItemFromTemplate?
After some digging around I got this to work. I am obviously a VBA noob so i take no credit for the code - I was just able to mash it together and get it to work. Maybe someone in the future will find it helpful.
Public Function aBrowseForFile(aStartFolder As String) As String
On Error GoTo Err_txtBrowseForFile
Dim xlApp As Object
Set xlApp = CreateObject("Excel.Application")
xlApp.Visible = False
Dim fDialog As Office.FileDialog
Dim varfile As Variant
Dim strPath As String
Dim strFilter As String, strFileName As String
Dim Main_Dir As String, DefFolder As String
Set fDialog = xlApp.Application.FileDialog(msoFileDialogFilePicker)
With fDialog
.InitialView = msoFileDialogViewThumbnail
.AllowMultiSelect = False
.Title = "Please select one or more files"
.InitialFileName = aStartFolder
.InitialView = msoFileDialogViewThumbnail
.Filters.Clear
.Filters.Add "all files", "*.*"
If .Show = True Then
aBrowseForFile = .SelectedItems(1)
Else
MsgBox "You clicked Cancel in the file dialog box."
End If
End With
Exit_txtBrowseForFile:
Exit Function
Err_txtBrowseForFile:
MsgBox Err.Description, vbCritical, "MyApp"
Resume Exit_txtBrowseForFile
End Function
Sub EmailTemplateW10()
Dim MyFileURL As String
MyFileURL = aBrowseForFile("C:\users\")
Set msg = Application.CreateItemFromTemplate(MyFileURL)
msg.SentOnBehalfOfName = "user#domain.com"
msg.Display
Set msg = Nothing
End Sub
I have a split database where both the front end and back end are accdb files. Because one of my tables uses the AppendOnly = Yes property, I cannot use the link table manager or the refreshlink property when I move the backend. The backend moves from time to time because my IT loves to reshuffle servers.
So my solution is to write a function which prompts for the backend location, deletes all the currently linked tables, and then loops through all the backend tables and links them to the frontend. On this last part I receive a run time error 3170 could not find suitable ISAM. I don't know why.
Code is below:
Public Function MoveDB()
'this function will replace the linked table manager. It will open a file select dialog box to allow the user to pick the new location of the DB backend.
'It will then break all the current links and then recreate them. We need to do this vice use the relink function because the cases table uses AutoAppend which stores old path data
' and breaks the relink function which is why linked table manager does not work.
' FileDialog Requires a reference to Microsoft Office 11.0 Object Library.
'variables to get the database path
Dim fDialog As Office.FileDialog
Dim varFile As Variant
Dim DriveLetter As String
Dim NetworkPath As String
Dim DrivePath As String
Dim SubPath As String
'variables to link the database
Dim db As DAO.Database
Dim BEdb As DAO.Database
Dim oldtdf As DAO.TableDef
Dim tblName As String
Dim newtdf As DAO.TableDef
Dim BEtdf As DAO.TableDef
Set db = CurrentDb()
' Set up the File Dialog.
Set fDialog = Application.FileDialog(msoFileDialogFilePicker)
With fDialog
' Do not Allow user to make multiple selections in dialog box
.AllowMultiSelect = False
'set the default folder that is opened
.InitialFileName = CurrentProject.Path & "\BE"
' Set the title of the dialog box.
.Title = "Please select the Database Backend"
' Clear out the current filters, and add our own.
.Filters.Clear
.Filters.Add "Access Databases", "*.accdb"
' Show the dialog box. If the .Show method returns True, the
' user picked a file. If the .Show method returns
' False, the user clicked Cancel.
If .Show = True Then
'We need to determine the full network path (including server name) to the DB backend. The reason is that different users may have the share drive mapped with different letters.
'If the backend is mapped using the drive letter of the user moving the DB then other users may not have a valid path. The full network path is universal
'Get the mapped drive letter from the path of the selected DB file
DriveLetter = Left$(Trim(fDialog.SelectedItems(1)), 2)
'Get the path of the selected DB file minus the drive letter
SubPath = Mid$(Trim(fDialog.SelectedItems(1)), 3)
'Get the full network path of the mapped drive letter
DrivePath = GETNETWORKPATH(DriveLetter)
'Combine the drive path and the sub path to get the full path to the selected DB file
NetworkPath = DrivePath & SubPath
'MsgBox (NetworkPath)
Else
MsgBox "You clicked Cancel in the file dialog box."
End If
End With
'Now we need to delete all the linked tables
For Each oldtdf In db.TableDefs
With oldtdf
If oldtdf.Attributes And dbAttachedODBC Or oldtdf.Attributes And dbAttachedTable Then
'this is a linked table
tblName = .Name
DoCmd.DeleteObject acTable, tblName
End If
End With
Next oldtdf
tblName = ""
'Now we link all the tables from the backend to the front end
Set BEdb = OpenDatabase(NetworkPath)
For Each BEtdf In BEdb.TableDefs
tblName = BEtdf.Name
If Left(tblName, 4) <> "~TMP" Then
Set newtdf = db.CreateTableDef(strTable)
newtdf.Connect = "Database = " & NetworkPath
newtdf.SourceTableName = tblName
newtdf.Name = tblName
db.TableDefs.Append newtdf
End If
Next BEtdf
End Function
The error occurs on the
db.TableDefs.Append newtdf
line. I'm looking to either make this code work, or a way around the known bug that prevents refreshing links when using the AppendOnly=Yes property.
Thanks in advance for any help.
I think you are just missing the semicolon on your string and remove extra spaces
newtdf.Connect = ";Database=" & NetworkPath
Alternatively, you can use DoCmd.TransferDatabase method and be sure to leave out the MSys tables as they have no direct application use between split files:
If Left(tblName, 4) <> "~TMP" And Left(tblName, 4) <> "MSys" Then
DoCmd.TransferDatabase acLink, "Microsoft Access", NetworkPath, _
acTable, tblName, tblName, False
End If
found this and worked for me
DAODataSet.SQL.Text := 'SELECT * FROM Country IN "" ";DATABASE=C:\SIMPLE.MDB;PWD=MyPassword"';
DAODataSet.Open;
I am running MS Access 2010. Using VBA I am trying to pull attachments out of MS Exchange 2013 and insert them into the Access table "TBL_APPT_ATTACHMENT".
The table "TBL_APPT_ATTACHMENT" looks like this:
Attachment_title Memo
Attachment_filename Memo
Attachment_blob OLE Object
Everything seems to work correctly except I can not figure out how to save the actual file into the column ATTACHMENT_BLOB. Here is my VBA function that I am calling (See question marks below).
Private Function createRecord(fItem As Outlook.AppointmentItem)
Set rsAtt = CurrentDb.OpenRecordset("TBL_APPT_ATTACHMENT")
rsAtt.OpenRecordset
For Each Attachment In fItem.Attachments
Call MsgBox("FileName: " & Attachment.FileName, vbOKOnly, "Error")
Call MsgBox("DisplayName: " & Attachment.DisplayName, vbOKOnly, "Error")
Call MsgBox("Index: " & Attachment.Index, vbOKOnly, "Error")
rsAtt.AddNew
rsAtt!APPT_ITEM_ID = aID
rsAtt!APPT_FIELD_id = rsOl!ID
rsAtt!ATTACHMENT_TITLE = Attachment.DisplayName
rsAtt!ATTACHMENT_FILENAME = Attachment.FileName
rsAttID = rsAtt!ID
rsAtt.Update
'Save file to harddrive.
filePath = "c:\temp\" + Attachment.FileName
Attachment.SaveAsFile (filePath)
Set rsParent = CurrentDb.OpenRecordset("SELECT ID, ATTACHMENT_BLOB FROM TBL_APPT_ATTACHMENT WHERE ID = " & rsAttID)
rsParent.OpenRecordset
Do While Not rsParent.EOF
rsParent.Edit
'Load file into Database.
'??? This next statement gives me a "Type Mismatch" error. Why?????
Set rsChild = rsParent.Fields("ATTACHMENT_BLOB").Value
rsChild.AddNew
rsChild.Fields("FileData").LoadFromFile (filePath)
rsChild.Update
rsParent.Update
rsParent.MoveNext
Loop
Next
End Function
Thanks!!
Remember that the attachment is really a file (whether its an OLE object or not). While it may be possible to perform a copy-paste of the object from Outlook into Access, my recommendation is to save the attachment as a file:
dim filepath as String
dim filename as String
filepath = "C:\appropriatefolder\"
filename = Attachment.FileName
Attachment.SaveAsFile filepath & filename
Now you're in a position to save the attachment in Access, but I seriously don't recommend using the Attachment field type. It can be rather tricky to use. So my solution to the same problem was to create a field of type Hyperlink. Then your statement in your macro will simply be:
rsAtt!ATTACHMENT_LINK = filename & "#" & filepath & filename
The hyperlink definition is important and uses the format:
displayString # fullPathToFile [ # optionalPositionInsideFile ]
EDIT: Using the Attachment Field Type in Access
The Attachment field type in an Access table can be understood if you consider it an embedded recordset within that single record. Therefore, every time you add a new record (or read an existing record), you have to handle the Attachment field a bit differently. In fact, the .Value of the Attachment field is the recordset itself.
Option Compare Database
Option Explicit
Sub test()
AddAttachment "C:\Temp\DepTree.txt"
End Sub
Sub AddAttachment(filename As String)
Dim tblAppointments As DAO.Recordset
Dim attachmentField As DAO.Recordset
Dim tblField As Field
Set tblAppointments = CurrentDb.OpenRecordset("TBL_APPT_ATTACHMENT", dbOpenDynaset)
tblAppointments.AddNew
tblAppointments![APPT_ITEM_ID] = "new item id"
tblAppointments![APPT_FIELD_ID] = "new field id"
tblAppointments![ATTACHMENT_TITLE] = "new attachment"
tblAppointments![ATTACHMENT_FILENAME] = filename
'--- the attachment field itself is a recordset, because you can add multiple
' attachments to this single record. so connect to the recordset using the
' .Value of the parent record field, then use it like a recordset
Set attachmentField = tblAppointments![ATTACHMENT_BLOB].Value
attachmentField.AddNew
attachmentField.Fields("FileData").LoadFromFile filename
attachmentField.Update
tblAppointments.Update
tblAppointments.Close
Set tblAppointments = Nothing
End Sub
Here is what I ended up doing.
Private Function createRecord(fItem As Outlook.AppointmentItem)
Set rsAtt = CurrentDb.OpenRecordset("TBL_APPT_ATTACHMENT")
rsAtt.OpenRecordset
For Each Attachment In fItem.Attachments
'Save file to harddrive.
filePath = "c:\temp\" + Attachment.FileName
Attachment.SaveAsFile (filePath)
rsAtt.AddNew
rsAtt!APPT_ITEM_ID = aID
rsAtt!APPT_FIELD_id = rsOl!ID
rsAtt!ATTACHMENT_TITLE = Attachment.DisplayName
rsAtt!ATTACHMENT_FILENAME = Attachment.FileName
Call FileToBlob(filePath, rsAtt!ATTACHMENT_BLOB)
rsAttID = rsAtt!ID
rsAtt.Update
Next
End Function
Public Function FileToBlob(strFile As String, ByRef Field As Object)
On Error GoTo FileToBlobError
If Len(Dir(strFile)) > 0 Then
Dim nFileNum As Integer
Dim byteData() As Byte
nFileNum = FreeFile()
Open strFile For Binary Access Read As nFileNum
If LOF(nFileNum) > 0 Then
ReDim byteData(1 To LOF(nFileNum))
Get #nFileNum, , byteData
Field = byteData
End If
Else
MsgBox "Error: File not found", vbCritical, _
"Error reading file in FileToBlob"
End If
FileToBlobExit:
If nFileNum > 0 Then Close nFileNum
Exit Function
FileToBlobError:
MsgBox "Error " & Err.Number & ": " & Err.Description, vbCritical, _
"Error reading file in FileToBlob"
Resume FileToBlobExit
End Function