I am trying to print all columns "*" and at the end it should display COUNT as DISTINCT and GROUP BY SalesPersonID
I have done many tests with sub queries and main query but it doesnt work
SELECT S.SalesPersonID, COUNT(*)
FROM [AdventureWorks2014].[Sales].Store AS S
GROUP BY S.SalesPersonID
This query gives me accurate counts but I intend to print more columns and as soon as I enter another column the query wont work which I believe it is a GROUP BY SELECT Statment.
How would you do this please.
MySQL 8.0/SQL Server support windowed COUNT(*)
SELECT *,COUNT(*) OVER(PARTITION BY S.SalesPersonID) AS cnt
FROM AdventureWorks2014.Sales.Store AS S
Related
I need to sum the result of count of a column in one query.
Is it possible to have like this query?
SELECT sum(count(pro_id)) from jalasat group by pro_id
You have not mentioned which SQL database you are using so you may modify this slightly to fit it to what you are using:
SELECT SUM(cnt) FROM (SELECT COUNT(pro_id) as cnt
FROM jalasat
GROUP BY continent) as t1
I'm trying to select the 5 rows with the highest count value
This is my query:
string sql = "SELECT top 5 count FROM Likes ORDER BY COUNT(*) DESC";
It's just throwing an error code that
Column 'Likes.count' is invalid in the select list because it is not
contained in either an aggregate function or the GROUP BY clause.
It's for a project I've got to present tomorrow...
On SQL Server, simply do this:
SELECT TOP 5 * FROM Likes ORDER BY [Count] DESC
This assumes that your Likes-table already contains a column named [Count] meaning that you don't need to count the records yourself (which is what COUNT(*) does).
You should not use COUNT(*) here for order by.
SELECT top 5 [count] FROM Likes ORDER BY [Count] DESC
count is a reserved word which is why you should stay clear of using them for column names. If you don't want to rename the column you can escape it, different dbms may effect who you do this. In ssms you would use square brackets.
string sql = "SELECT top 5 [count] FROM Likes ORDER BY COUNT(*) DESC";
I am using SQL 2012 and trying to identify rows where the SourceDataID column has two unique entries in the PartyCode column, and I'm having difficulties.
SELECT PartyCode, SourceDataID, count (*) as CNT
FROM CustomerOrderLocation (nolock)
GROUP BY PartyCode, SourceDataID
HAVING (Count(PartyCode)>1)
ORDER BY PartyCode
Results are returning as such:
W3333 948_O 31
(party code/sourcedataid/CNT)
This is showing me the total entries where the Partycode and the SourceDataID are listed together in the table. However, I need it to show a count of any instances where W333 lists 948_O as the SourceDataID more than once.
I'm not having luck structuring the query to pull the results I am looking to get. How can I do this?
A CTE coupled with the PARTITION BY function is helpful in finding duplicates of this manner. Code below:
WITH CTE AS(
SELECT PartyCode, SourceDataID,
ROW_NUMBER()OVER(PARTITION BY SourceDataID ORDER BY SourceDataID) RN
FROM CustomerOrderLocation (NOLOCK))
SELECT * FROM CTE WHERE RN > 1
This should return every duplicate PartyCode attached to a SourceDataID.
If you want to see the entire result, change the last SELECT statement to:
SELECT * FROM CTE ORDER BY PartyCode, RN
Thanks for the help everyone. I did not do the best job of describing the issue but this is the query I ended up creating to get my result set.
;with cte1 (sourcedataid, partycode) as (select sourcedataid, partycode from customerorderparty (nolock) group by PartyCode, SourceDataID)
select count(sourcedataid), sourcedataid from cte1 group by sourcedataid having count(sourcedataid) >1
I'm looking get two things from a query, given a set of contraints:
The first match
The total number of matches
I can get the first match by:
SELECT TOP 1
ID,
ReportYear,
Name,
SignDate,
...
FROM Table
WHERE
...
ORDER BY ... //I can put in here which one I want to take
And then I can get the match count if I use
SELECT
MIN(ID),
MIN(ReportYear),
MIN(Name),
MIN(SignDate),
... ,
COUNT(*) as MatchCount
FROM Table
WHERE
...
GROUP BY
??? // I don't really want any grouping
I really want to avoid both grouping and using an aggregate function on all my results. This question SQL Server Select COUNT without using aggregate function or group by suggests the answer would be
SELECT TOP 1
ID,
ReportYear,
Name,
SignDate,
... ,
##ROWCOUNT as MatchCount
FROM Table
This works without the TOP 1, but when it's in there, ##ROWCOUNT = number of rows returned, which is 1. How can I get essentially the output of COUNT(*) (whatever's left after the where clause) without any grouping or need to aggregate all the columns?
What I don't want to do is repeat each of these twice, once for the first row and then again for the ##ROWCOUNT. I'm not finding a way I can properly use GROUP BY, because I strictly want the number of items that match my criteria, and I want columns that if I GROUPed them would throw this number off - unless I'm misunderstanding GROUP BY.
Assuming you are using a newish version of SQL Server (2008+ from memory) then you can use analytic functions.
Simplifying things somewhat, they are a way of way of doing an aggregate over a set of data instead of a group - an extension on basic aggregates.
Instead of this:
SELECT
... ,
COUNT(*) as MatchCount
FROM Table
WHERE
...
You do this:
SELECT
... ,
COUNT(*) as MatchCount OVER (PARTITION BY <group fields> ORDER BY <order fields> )
FROM Table
WHERE
...
GROUP BY
Without actually running some code, I can't recall exactly which aggregates that you can't use in this fashion. Count is fine though.
Well, you can use OVER clause, which is an window function.
SELECT TOP (1)
OrderID, CustID, EmpID,
COUNT(*) OVER() AS MatchCount
FROM Sales.Orders
WHERE OrderID % 2 = 1
ORDER BY OrderID DESC
Try next query:
select top 1
*, count(*) over () rowsCount
from
(
select
*, dense_rank() over (order by ValueForOrder) n
from
myTable
) t
where
n = 1
If i perform a standard query in SQLite:
SELECT * FROM my_table
I get all records in my table as expected. If i perform following query:
SELECT *, 1 FROM my_table
I get all records as expected with rightmost column holding '1' in all records. But if i perform the query:
SELECT *, COUNT(*) FROM my_table
I get only ONE row (with rightmost column is a correct count).
Why is such results? I'm not very good in SQL, maybe such behavior is expected? It seems very strange and unlogical to me :(.
SELECT *, COUNT(*) FROM my_table is not what you want, and it's not really valid SQL, you have to group by all the columns that's not an aggregate.
You'd want something like
SELECT somecolumn,someothercolumn, COUNT(*)
FROM my_table
GROUP BY somecolumn,someothercolumn
If you want to count the number of records in your table, simply run:
SELECT COUNT(*) FROM your_table;
count(*) is an aggregate function. Aggregate functions need to be grouped for a meaningful results. You can read: count columns group by
If what you want is the total number of records in the table appended to each row you can do something like
SELECT *
FROM my_table
CROSS JOIN (SELECT COUNT(*) AS COUNT_OF_RECS_IN_MY_TABLE
FROM MY_TABLE)