COUNT from DISTINCT values in multiple columns - sql

Question

If this has been asked before, I apologize, I wasn't able to find a question/solution like it before breaking down and posting. I have the below query (using Oracle SQL) that works fine in a sense, but not fully what I'm looking for.
SELECT
order_date,
p_category,
CASE
WHEN ( issue_grp = 1 ) THEN '1'
ELSE '2/3 '
END AS issue_group,
srt AS srt_level,
COUNT(*) AS total_orders
FROM
database.t_con
WHERE
order_date IN (
'&Enter_Date_YYYYMM'
)
GROUP BY
p_category,
CASE
WHEN ( issue_grp = 1 ) THEN '1'
ELSE '2/3 '
END,
srt,
order_date
ORDER BY
p_category,
issue_group,
srt_level,
order_date
Current Return (12 rows):
Needed Return (8 rows without the tan rows being shown):
Here is the logic of total_order column that I'm expecting:
count of order_date where (srt_level = 80 + 100 + Late) ... 'Late' counts needed to be added to the total, just not be displayed
I'm eventually adding a filled_orders column that will go before the total_orders column, but I'm just not there yet.
Sorry I wasn't as descriptive earlier. Thanks again!

Answer 1

You don't appear to need a subquery; if you want the count for each combination of values then group by those, and aggregate at that level; something like:
SELECT
t1.order_date,
t1.p_category,
CASE
WHEN ( t1.issue_grp = 1 ) THEN '1'
ELSE '2/3 '
END AS issue_group,
t1.srt AS srt_level,
COUNT(*) AS total_orders
FROM
database.t_con t1
WHERE
t1.order_date = TO_DATE ( '&Enter_Date_YYYYMM', 'YYYYMM' )
GROUP BY
t1.p_category,
CASE
WHEN ( t1.issue_grp = 1 ) THEN '1'
ELSE '2/3 '
END,
t1.srt,
t1.order_date
ORDER BY
p_category,
issue_group,
srt_level,
order_date;
You shouldn't be relying on implicit conversion and NLS settings for your date argument (assuming order_date is actually a date column, not a string), so I've used an explicit TO_DATE() call, using the format suggested by your substitution variable name and prompt.
However, that will give you the first day of the supplied month, since a day number isn't being supplied. It's more likely that you either want to prompt for a full date, or (possibly) just the year/month but want to include all days in that month - which IN() will not do, if that was your intention. It also implies that stored dates all have their time portions set to midnight, as that is all it will match on. If those values have non-midnight times then you need a range to pick those up too.

Answer 2

I got it working to the extent of what my question was. Just needed to nest each column where counts/calculations were happening.
SELECT
order_date,
p_category,
issue_group,
srt_level,
order_count,
SUM(order_count) OVER(
PARTITION BY order_date, issue_group, p_category
) AS total_orders
FROM
(
SELECT
order_date,
p_category,
CASE
WHEN ( issue_grp = 1 ) THEN '1'
ELSE '2/3 '
END AS issue_group,
srt AS srt_level,
COUNT(*) AS order_count
FROM
database.t_con
WHERE
order_date IN (
'&Enter_Date_YYYYMM'
)
GROUP BY
p_category,
CASE
WHEN ( issue_grp = 1 ) THEN '1'
ELSE '2/3 '
END,
srt,
order_date
)
ORDER BY
order_date,
p_category,
issue_group