I currently am working with two conditions that I would like to combine into one, but ran into some trouble. I have a dataset that includes quantity and date. I have created a date flag in the form of a case statement that flags whether it is the last day of the week, and gives it a "Y" or "N". The end result that I need is what that last DATE of the week.
My end result/goal is Column D
Here is my current source code:
select
pos.quantity_on_hand,
d.cal_date,
case
when date_key in( Select max(date_key) from edw.D_dates group by fiscal_year_nbr, fiscal_week_nbr)
then 'Y'
else 'N'
end Week_end_flag
from
edw.f_pos_daily pos,
edw.d_dates d,
where
pos.pos_date_key = d.date_key
I then create another custom column in PowerBI Desktop that looks like this:
This is what I used for my column calculation:
Last Inventory Date = RETURN(CALCULATE(MAXX(Inventory, Inventory[Cal_date]), filter ('D_Dates', 'D_Dates'[Week_end_flag]="Y")).
I tried to combine them into one, with something like this, but have failed:
case
when date_key in( Select max(date_key) from edw.D_dates group by fiscal_year_nbr, fiscal_week_nbr)
then MAX (cal_date) from edw.D_Dates where cal_date< current_date AS 'yyyy-mm-dd'
else 'N'
end Week_End_flag
Use the select command inside the then clause
change this line:
then MAX (cal_date) from edw.D_Dates where cal_date< current_date AS 'yyyy-mm-dd'
to:
then (SELECT MAX (cal_date) from edw.D_Dates where cal_date< current_date AS 'yyyy-mm-dd')
complete code:
select
pos.quantity_on_hand,
d.cal_date,
case
when date_key in( Select max(date_key) from edw.D_dates group by fiscal_year_nbr, fiscal_week_nbr)
then (SELECT MAX (cal_date) from edw.D_Dates where cal_date< current_date AS 'yyyy-mm-dd')
else 'N'
end Week_end_flag
from
edw.f_pos_daily pos,
edw.d_dates d,
where
pos.pos_date_key = d.date_key
Related
Question
The following is a snippet of my data:
Create Table Emps(person VARCHAR(50), started DATE, stopped DATE);
Insert Into Emps Values
('p1','2015-10-10','2016-10-10'),
('p1','2016-10-11','2017-10-11'),
('p1','2017-10-12','2018-10-13'),
('p2','2019-11-13','2019-11-13'),
('p2','2019-11-14','2020-10-14'),
('p3','2020-07-15','2021-08-15'),
('p3','2021-08-16','2022-08-16');
db<>fiddle.
I want to use T-SQL to get a count of how many persons fulfil the following criteria at least once - multiples should also count as one:
For a person:
One of the dates in 'started' (say s1) is larger than at least one of the dates in 'ended' (say e1)
s1 and e1 are in the same year, to be set manually - e.g. '2021-01-01' until '2022-01-01'
Example expected response
If I put the date range '2016-01-01' until '2017-01-01' somewhere in a WHERE / HAVING clause, the output should be 1 as only p1 has both a start date and an end date that fall in 2016 where the start date is larger than the end date:
s1 = '2016-10-11', and e1 = '2016-10-10'.
Why can't I do this myself
The reason I'm stuck is that I don't know how to do this rowwise comparison between groups. The question requires comparing values across columns (start with end) across rows, within a person ID.
Use conditional aggregation to get the maximum start date and the minimum stop date in the given range.
select person
from emps
group by person
having max(case when started >= '2016-01-01' and started < '2017-01-01'
then started end) >
min(case when stopped >= '2016-01-01' and stopped < '2017-01-01'
then stopped end);
Demo: https://dbfiddle.uk/?rdbms=sqlserver_2019&fiddle=45adb153fcac9ce72708f1283cac7833
I would choose to use a self-outer-join with an exists correlation, it should be pretty much the most performant, all things being equal.
select Count(*)
from emps e
where exists (
select * from emps e2
where e2.person = e.person
and e2.stopped > e.started
and e.started between '20160101' and '20170101'
and e2.started between '20160101' and '20170101'
);
You said you plan to set the dates manually, so this works where we set the start date in one CTE, and the end date in another CTE. Then we calculate the min/max for each, and use that criteria in the query where statement.
with min_max_start as (
select person,
min(started) as min_start, --obsolete
max(started) as max_start
from emps
where started >= '2016-01-01'
group by person
),
min_max_end as (
select person,
min(stopped) as min_stop,
max(stopped) as max_stop --obsolete
from emps
where stopped < '2017-01-01'
group by person
)
select count(distinct e.person)
from emps e
join min_max_start mms
on e.person = mms.person
join min_max_end mme
on e.person = mme.person
where mms.max_start> mme.min_stop
Output: 1
Try the following:
With CTE as
(
Select D.person, D.started, T.stopped,
case
when Year(D.started) = Year(T.stopped) and D.started > T.stopped
then 1
else 0
end as chk
From
(Select person, started From Emps Where started >= '2016-01-01') D
Join
(Select person, stopped From Emps Where stopped <= '2017-01-01') T
On D.person = T.person
)
Select Count(Distinct person) as CNT
From CTE
Where chk = 1;
To get the employee list who met the criteria use the following on the CTE instead of the above Select Count... query:
Select person, started, stopped
From CTE
Where chk = 1;
See a demo from db<>fiddle.
I have 2 SQL statements to look up successful transactions and failed transactions.
SELECT COUNT (code_reseller) as trx_success, kode_reseller
FROM transaksi
where status = '20' AND CAST (date_entri AS DATE) = CAST (GETDATE() AS DATE)
group by code_reseller
ORDER BY trx_success DESC
AND
SELECT COUNT (code_reseller) as trx_fail, kode_reseller
FROM transaksi
where status > '20' AND CAST (date_entri AS DATE) = CAST (GETDATE() AS DATE)
group by code_reseller
ORDER BY trx_fail DESC
How to combine into one table with 3 columns result with code_reseller, trx_success and trx_fail?
Use conditional aggregation and combine the queries:
SELECT
kode_reseller,
COUNT(CASE WHEN status = '20' THEN 1 END) AS trx_success,
COUNT(CASE WHEN status > '20' THEN 1 END) AS trx_fail
FROM transaksi
WHERE
CAST(date_entri AS DATE) = CAST(GETDATE() AS DATE)
GROUP BY
kode_reseller;
The strategy here is to move the filtering on the status column which previously appeared in the two WHERE clauses into the conditional counts in the SELECT clause. The restriction on date_entri can stay there, since both queries have it.
As suggested by #Dale k, you can do it like this.
You cannot add order by inside, so create an alias table and give order by condition.
SELECT *
FROM
(
SELECT COUNT (code_reseller) as trx_success, kode_reseller
FROM transaksi
WHERE status = '20' AND CAST (date_entri AS DATE) = CAST (GETDATE() AS DATE)
GROUP BY code_reseller
UNION ALL
SELECT COUNT (code_reseller) as trx_fail, kode_reseller
FROM transaksi
WHERE status > '20' AND CAST (date_entri AS DATE) = CAST (GETDATE() AS DATE)
GROUP BY code_reseller
) a
ORDER BY a.trx_success DESC --here we get first select query table' column name and datatype and no of column will be same required in union/union all
I'm trying to use a nested aggregate function. I know that SQL does not support it, but I really need to do something like the below query. Basically, I want to count the number of users for each day. But I want to only count the users that haven't completed an order within a 15 days window (relative to a specific day) and that have completed any order within a 30 days window (relative to a specific day). I already know that it is not possible to solve this problem using a regular subquery (it does not allow to change subquery values for each date). The "id" and the "state" attributes are related to the orders. Also, I'm using Fivetran with Snowflake.
SELECT
db.created_at::date as Date,
count(case when
(count(case when (db.state = 'finished')
and (db.created_at::date between dateadd(day,-15,Date) and dateadd(day,-1,Date)) then db.id end)
= 0) and
(count(case when (db.state = 'finished')
and (db.created_at::date between dateadd(day,-30,Date) and dateadd(day,-16,Date)) then db.id end)
> 0) then db.user end)
FROM
data_base as db
WHERE
db.created_at::date between '2020-01-01' and dateadd(day,-1,current_date)
GROUP BY Date
In other words, I want to transform the below query in a way that the "current_date" changes for each date.
WITH completed_15_days_before AS (
select
db.user as User,
count(case when db.state = 'finished' then db.id end) as Completed
from
data_base as db
where
db.created_at::date between dateadd(day,-15,current_date) and dateadd(day,-1,current_date)
group by User
),
completed_16_days_before AS (
select
db.user as User,
count(case when db.state = 'finished' then db.id end) as Completed
from
data_base as db
where
db.created_at::date between dateadd(day,-30,current_date) and dateadd(day,-16,current_date)
group by User
)
SELECT
date(db.created_at) as Date,
count(distinct case when comp_15.completadas = 0 and comp_16.completadas > 0 then comp_15.user end) as "Total Users Churn",
count(distinct case when comp_15.completadas > 0 then comp_15.user end) as "Total Users Active",
week(Date) as Week
FROM
data_base as db
left join completadas_15_days_before as comp_15 on comp_15.user = db.user
left join completadas_16_days_before as comp_16 on comp_16.user = db.user
WHERE
db.created_at::date between '2020-01-01' and dateadd(day,-1,current_date)
GROUP BY Date
Does anyone have a clue on how to solve this puzzle? Thank you very much!
The following should give you roughly what you want - difficult to test without sample data but should be a good enough starting point for you to then amend it to give you exactly what you want.
I've commented to the code to hopefully explain what each section is doing.
-- set parameter for the first date you want to generate the resultset for
set start_date = TO_DATE('2020-01-01','YYYY-MM-DD');
-- calculate the number of days between the start_date and the current date
set num_days = (Select datediff(day, $start_date , current_date()+1));
--generate a list of all the dates from the start date to the current date
-- i.e. every date that needs to appear in the resultset
WITH date_list as (
select
dateadd(
day,
'-' || row_number() over (order by null),
dateadd(day, '+1', current_date())
) as date_item
from table (generator(rowcount => ($num_days)))
)
--Create a list of all the orders that are in scope
-- i.e. 30 days before the start_date up to the current date
-- amend WHERE clause to in/exclude records as appropriate
,order_list as (
SELECT created_at, rt_id
from data_base
where created_at between dateadd(day,-30,$start_date) and current_date()
and state = 'finished'
)
SELECT dl.date_item
,COUNT (DISTINCT ol30.RT_ID) AS USER_COUNT
,COUNT (ol30.RT_ID) as ORDER_COUNT
FROM date_list dl
-- get all orders between -30 and -16 days of each date in date_list
left outer join order_list ol30 on ol30.created_at between dateadd(day,-30,dl.date_item) and dateadd(day,-16,dl.date_item)
-- exclude records that have the same RT_ID as in the ol30 dataset but have a date between 0 amd -15 of the date in date_list
WHERE NOT EXISTS (SELECT ol15.RT_ID
FROM order_list ol15
WHERE ol30.RT_ID = ol15.RT_ID
AND ol15.created_at between dateadd(day,-15,dl.date_item) and dl.date_item)
GROUP BY dl.date_item
ORDER BY dl.date_item;
If this has been asked before, I apologize, I wasn't able to find a question/solution like it before breaking down and posting. I have the below query (using Oracle SQL) that works fine in a sense, but not fully what I'm looking for.
SELECT
order_date,
p_category,
CASE
WHEN ( issue_grp = 1 ) THEN '1'
ELSE '2/3 '
END AS issue_group,
srt AS srt_level,
COUNT(*) AS total_orders
FROM
database.t_con
WHERE
order_date IN (
'&Enter_Date_YYYYMM'
)
GROUP BY
p_category,
CASE
WHEN ( issue_grp = 1 ) THEN '1'
ELSE '2/3 '
END,
srt,
order_date
ORDER BY
p_category,
issue_group,
srt_level,
order_date
Current Return (12 rows):
Needed Return (8 rows without the tan rows being shown):
Here is the logic of total_order column that I'm expecting:
count of order_date where (srt_level = 80 + 100 + Late) ... 'Late' counts needed to be added to the total, just not be displayed
I'm eventually adding a filled_orders column that will go before the total_orders column, but I'm just not there yet.
Sorry I wasn't as descriptive earlier. Thanks again!
You don't appear to need a subquery; if you want the count for each combination of values then group by those, and aggregate at that level; something like:
SELECT
t1.order_date,
t1.p_category,
CASE
WHEN ( t1.issue_grp = 1 ) THEN '1'
ELSE '2/3 '
END AS issue_group,
t1.srt AS srt_level,
COUNT(*) AS total_orders
FROM
database.t_con t1
WHERE
t1.order_date = TO_DATE ( '&Enter_Date_YYYYMM', 'YYYYMM' )
GROUP BY
t1.p_category,
CASE
WHEN ( t1.issue_grp = 1 ) THEN '1'
ELSE '2/3 '
END,
t1.srt,
t1.order_date
ORDER BY
p_category,
issue_group,
srt_level,
order_date;
You shouldn't be relying on implicit conversion and NLS settings for your date argument (assuming order_date is actually a date column, not a string), so I've used an explicit TO_DATE() call, using the format suggested by your substitution variable name and prompt.
However, that will give you the first day of the supplied month, since a day number isn't being supplied. It's more likely that you either want to prompt for a full date, or (possibly) just the year/month but want to include all days in that month - which IN() will not do, if that was your intention. It also implies that stored dates all have their time portions set to midnight, as that is all it will match on. If those values have non-midnight times then you need a range to pick those up too.
I got it working to the extent of what my question was. Just needed to nest each column where counts/calculations were happening.
SELECT
order_date,
p_category,
issue_group,
srt_level,
order_count,
SUM(order_count) OVER(
PARTITION BY order_date, issue_group, p_category
) AS total_orders
FROM
(
SELECT
order_date,
p_category,
CASE
WHEN ( issue_grp = 1 ) THEN '1'
ELSE '2/3 '
END AS issue_group,
srt AS srt_level,
COUNT(*) AS order_count
FROM
database.t_con
WHERE
order_date IN (
'&Enter_Date_YYYYMM'
)
GROUP BY
p_category,
CASE
WHEN ( issue_grp = 1 ) THEN '1'
ELSE '2/3 '
END,
srt,
order_date
)
ORDER BY
order_date,
p_category,
issue_group
I have an order file, with order id and ship date. Orders can only be shipped monday - friday. This means there are no records selected for Saturday and Sunday.
I use the same order file to get all order dates, with date in the same format (yyyymmdd).
i want to select a count of all the records from the order file based on order date... and (i believe) full outer join (or maybe right join?) the date file... because i would like to see
20120330 293
20120331 0
20120401 0
20120402 920
20120403 430
20120404 827
etc...
however, my sql statement is still not returning a zero record for the 31st and 1st.
with DatesTable as (
select ohordt "Date" from kivalib.orhdrpf
where ohordt between 20120315 and 20120406
group by ohordt order by ohordt
)
SELECT ohscdt, count(OHTXN#) "Count"
FROM KIVALIB.ORHDRPF full outer join DatesTable dts on dts."Date" = ohordt
--/*order status = filled & order type = 1 & date between (some fill date range)*/
WHERE OHSTAT = 'F' AND OHTYP = 1 and ohscdt between 20120401 and 20120406
GROUP BY ohscdt ORDER BY ohscdt
any ideas what i'm doing wrong?
thanks!
It's because there is no data for those days, they do not show up as rows. You can use a recursive CTE to build a contiguous list of dates between two values that the query can join on:
It will look something like:
WITH dates (val) AS (
SELECT CAST('2012-04-01' AS DATE)
FROM SYSIBM.SYSDUMMY1
UNION ALL
SELECT Val + 1 DAYS
FROM dates
WHERE Val < CAST('2012-04-06' AS DATE)
)
SELECT d.val AS "Date", o.ohscdt, COALESCE(COUNT(o.ohtxn#), 0) AS "Count"
FROM dates AS d
LEFT JOIN KIVALIB.ORDHRPF AS o
ON o.ohordt = TO_CHAR(d.val, 'YYYYMMDD')
WHERE o.ohstat = 'F'
AND o.ohtyp = 1