How to group by name and get the average of Ganesh and Suresh marks
I have a PSQL table like below
Name Marks
Ganesh 80
Ganesh 90
Ganesh 70
Suresh 60
Suresh 70
Suresh 75
I am expecting output like below:
Name Marks
Ganesh 240
Suresh 205
I need an Postgresql query to get get the above output
Related
I have a large access table that I need to pull specific data from with a query.
I need to get a list of all the IDs that meet a specific criteria, i.e. 3 months in a row with a cage number less than 50.
The SQL code I'm currently working with is below, but it only gives me which months of the past 3 had a cage number below 50.
SELECT [AbBehWeeklyMonitor Database].AnimalID, [AbBehWeeklyMonitor Database].Date, [AbBehWeeklyMonitor Database].Cage
FROM [AbBehWeeklyMonitor Database]
WHERE ((([AbBehWeeklyMonitor Database].Date)>=DateAdd("m",-3,Date())) AND (([AbBehWeeklyMonitor Database].Cage)<50))
ORDER BY [AbBehWeeklyMonitor Database].AnimalID DESC;
I would need it to look at the past 3 months for each ID, and only output if all 3 met the specific criteria, but I'm not sure where to go from here.
Any help would be appreciated.
Data Sample:
Date
AnimalID
Cage
6/28/2022
12345
50
5/19/2021
12345
32
3/20/2008
12345
75
5/20/2022
23569
4
8/20/2022
23569
4
5/20/2022
44444
71
8/1/2012
44444
4
4/1/2022
78986
30
1/20/2022
78986
1
9/14/2022
65659
59
8/10/2022
65659
48
7/14/2022
65659
30
6/14/2022
95659
12
8/14/2022
91111
51
7/14/2022
91111
5
6/14/2022
91111
90
8/14/2022
88888
4
7/14/2022
88888
5
6/14/2022
88888
15
Consider:
Query1:
SELECT AnimalID, Count(*) AS Cnt
FROM Table1
WHERE (((Cage)<50) AND (([Date]) Between #6/1/2022# And #8/31/2022#))
GROUP BY AnimalID
HAVING (((Count(*))=3));
Query2
SELECT Table1.*
FROM Query1 INNER JOIN Table1 ON Query1.AnimalID = Table1.AnimalID
WHERE ((([Date]) Between #6/1/2022# And #8/31/2022#));
Output:
Date AnimalID Cage
6/14/2022 65659 12
7/14/2022 65659 30
8/10/2022 65659 48
6/14/2022 88888 15
7/14/2022 88888 5
8/14/2022 88888 4
Date is a reserved word and really should not use reserved words as names.
i have a table like this:
id
person
20
adams
20
george
40
jina
46
rico
80
naya
90
john
90
peter
90
richard
i want to find a way to select a new_id starting from 1 and increazing +1 every time id is different. for example i want a select with a result like this:
new_id
id
person
1
20
adams
1
20
george
2
40
jina
3
46
rico
4
80
naya
5
90
john
5
90
peter
5
90
richard
is there any function in postgres doing something like that?
use dense_rank()
select dense_rank()over(order by id) as newid,id,persion
from table_name
demo link
I would like to use microsoft access or query to change from table1
student name course_attended date quiz score
john course 1 3/1/2017 98
carl course 1 3/1/2017 90
george course 1 3/1/2017 77
john course 2 3/5/2017 99
carl course 2 3/5/2017 96
george course 2 3/5/2017 80
john course 3 4/4/2017 77
carl course 3 4/4/2017 80
george course 3 4/4/2017 85
to table2
student name course 1 course 2 course 3
john 3/1/2017 3/5/2017 4/4/2017
98 99 95
carl 3/1/2017 3/5/2017 4/4/2017
90 96 89
george 3/1/2017 3/5/2017 4/4/2017
77 80 85
Basically, with select distinct [student name] use transformation and pivot
to change from table1 to table2. Please help. I would be greatly appreciated it.
If you don't need to do any calcs on the output, try:
TRANSFORM First([attend_date] & Chr(13) & Chr(10) & [quiz_score]) AS Data
SELECT student_name
FROM Tablename
GROUP BY student_name
PIVOT course;
Date is a reserved word. Should not use reserved words as names. Also, avoid spaces and special characters/punctuation (underscore only exception) in names.
I tried this,
TRANSFORM First([date_a] & Chr(13) & Chr(10) & [quiz_score]) AS Data
SELECT student_name
FROM tbl_quiz
GROUP BY student_name
PIVOT course_attended;
and the query does not show the quiz_score. However, the form created from the query result shows it.
Thanks a lot.
The query I'm trying to answer is 'How many sales above or equal to 60 has each person made?'
My table (sales$):
SaleID name salevalue
1 Steve 100
2 John 50
3 Ellen 25
4 Steve 100
5 Mary 60
6 Mary 80
7 John 70
8 Mary 55
9 Steve 65
10 Ellen 120
11 Ellen 30
12 Ellen 40
13 John 40
14 Mary 60
15 Steve 50
My code is:
select name,
COUNT(*) as 'sales above 60'
from Sales$
group by salevalue, name
having salevalue >= 60;
Which gives:
Ellen 1
John 1
Mary 2
Mary 1
Steve 1
Steve 2
The information is correct in that Mary & Steve both have 3 sales, however I'm forced by the HAVING command to group them out.
Any ideas? I'm sure I've just taken a wrong turning.
You can use conditional aggregation for this:
select name,
COUNT(case when salevalue >= 60 then 1 end) as 'sales above 60'
from Sales$
group by name
This way COUNT will take into consideration only records having salevalue >= 60.
I've swapped the HAVING statement for a WHERE and achieved the desired result:
select name, count(*) 'sales above 50'
from sales$
where salevalue >=60
group by name
(Lightbulb moment after posting)
I have one file (name File1) who is like that:
AGE NAME (names are unique)
10 john
20 fred
10 james
15 jack
20 alfred
20 henry
and I would like to get the name of the olders with one query:
AGE NAME
20 fred
20 alfred
20 henry
Is it possible?
SQL:
SELECT AGE, NAME FROM File1 WHERE AGE = (SELECT MAX(AGE) FROM File1)