I have the following string in sql server where the length is variable
Declare #string Varchar(max) = 'abjrc_chdc_hyku_abv_ytr_DCD_HTR_TBF'
How could I select the characters after the 4th '_' in this string? (expected result: ytr_DCD_HTR_TBF)
Also how to select only the 4th part of the string (result: abv)
Any Ideas?
Thanks
If you know exactly how many characters are in the string at any time, then you can use SUBSTRING, so you can call the first string like this
Declare #string Varchar(max) = 'abjrc_chdc_hyku_abv_ytr_DCD_HTR_TBF';
Declare #last4 Varchar(max) = SELECT SUBSTRING(#string, 21, 35);
Declare #before4 Varchar(max) = SELECT SUBSTRING(#string, 17, 19);
If y ou really need to split the string for each '_' then you can use this as well
hope i helped.
If you will do it for multiple line creating function would be better. I have prepared sample for your two question :
Declare #string Varchar(max) = 'abjrc_chdc_hyku_abv_ytr_DCD_HTR_TBF'
Declare #NewString Varchar(max) = #string
Declare #Find4thPart Varchar(max) =''
DECLARE #Sep VARCHAR(10)='_'
DECLARE #Pos INT=4
WHILE #Pos>0
BEGIN
SET #NewString = SUBSTRING(#NewString, CHARINDEX(#Sep,#NewString)+1,100)
IF #Pos=2
SET #Find4thPart = SUBSTRING(#NewString,1, CHARINDEX(#Sep,#NewString)-1)
SET #Pos=#Pos-1
--SELECT #NewString
END
seLECT #NewString ,#Find4thPart
Related
I want to remove particular value from my string. My string can be of any length. E.g.
string 1:
{"ABC":1,"ABC_DT":-1,"ABC_DBQty":0,"ABC_DSQty":0,"ABC_LMT":1,"ABC_DT":-1,"CTSD":"TEST","SD":1,"TE":23}
string 2:
{"ABC":1,"ABC_DT":-1,"ABC_DBQty":0,"ABC_DSQty":0,"ABC_LMT":1,"ABC_DT":-1,"CTSD":"TEST","TE":23}
I want this 23 as a result. How can I get this in SQL Server 2014?
DECLARE #string VARCHAR(500) = '{"ABC":1,"ABC_DT":-1,"ABC_DBQty":0,"ABC_DSQty":0,"ABC_LMT":1,"ABC_DT":-1,"CTSD":"TEST","TE":23}'
SET #string = REVERSE(#string)
SELECT REVERSE(
SUBSTRING(#string,2,CHARINDEX(':',#string)-1-1)
) --return: 23
SOLUTION:
DECLARE #str VARCHAR(MAX) = '{"ABC":1,"ABC_DT":-1,"ABC_DBQty":0,"ABC_DSQty":0,"ABC_LMT":1,"ABC_DT":-1,"CTSD":"TEST","TE":23}'
,#posA INT = 0
,#posB INT = 0
,#res VARCHAR(MAX) = ''
SET #posA = PATINDEX('%"TE":%}', #str) +5;
SET #posB = CHARINDEX('}', #str, #posA+1);
SET #res = SUBSTRING (#str ,#posA, #posB-#posA )
SELECT #res AS 'STR_res', CAST(#res AS INT) AS 'INT_res'
use the JSON_VALUE function:
https://learn.microsoft.com/en-us/sql/t-sql/functions/json-value-transact-sql?view=sql-server-2017&viewFallbackFrom=sql-server-2014
(unfortunately available since 2016)
I am struggling to substring and get the values in SQL.
I am having a JSON String like the following:
DECLARE #string varchar(max)= '[{"CustomFieldId":18,"FieldName":"ABCD","FieldType":"freeText","FieldValue":null,"Details":null,"Value":null,"RelationTable":null,"Isisible":true,"IsAdmin":false,"CreatedDate":null,"ModifiedDate":null,"LoggedInUser":"TESTUSER"},{"CustomFieldId":19,"FieldName":"Workdomain","FieldType":"freeText","FieldValue":null,"Details":null,"Value":null,"RelationTable":null,"IsVisible":true,"IsAdmin":false,"CreatedDate":null,"ModifiedDate":null,"LoggedInUser":"149645"},{"CustomFieldId":20,"FieldName":"TEST1234","FieldType":"freeText","FieldValue":"Sometest","Details":null,"Value":null,"RelationTable":null,"IsVisible":false,"IsAdmin":false,"CreatedDate":null,"ModifiedDate":null,"_listlovFields":[],"org4Values":[],"LoggedInUser":"TESTUSER"}]'
or it can also be like this:
DECLARE #string varchar(max) = '[{"CustomFieldId":20,"FieldName":"TEST1234","FieldType":"freeText","FieldValue":"Sometest","Details":null,"Value":null,"RelationTable":null,"IsVisible":false,"IsAdmin":false,"CreatedDate":null,"ModifiedDate":null,"LoggedInUser":"TESTUSER"}]'
Now from any one of them I need to get the 'FieldValue' of a particular 'CustomFieldId' with a particular 'FieldName' and where the FieldValue starts with a particular string.
Like, I am going to get these:
declare #propName varchar(max) = 'Test1234',
#customFieldId varchar(max) = 20,
#value varchar(max) = 'Some'
So, in this particular case, I need to get the FieldValue of customfield with CustomFieldId:"20", FieldName":"TEST1234" and where FieldValue starts with 'Some'.
The output simply needs be the string 'Sometest' as this is the FieldValue of CustomFieldId:"20"
Any help in this would be highly appreciated.
this is quite easy to solve when you install regex functions on your sql server. I've included the link where you can find them.
https://www.simple-talk.com/sql/t-sql-programming/clr-assembly-regex-functions-for-sql-server-by-example/
declare #CustomFieldId nvarchar(50)= '20'
declare #FieldName nvarchar(50) = 'TEST1234'
declare #FieldValueStartsWith nvarchar(50) = 'Some'
declare #input nvarchar(500)
select #input = '[{"CustomFieldId":20,"FieldName":"TEST1234","FieldType":"freeText","FieldValue":"Sometest","Details":null,"Value":null,"RelationTable":null,"IsVisible":false,"IsAdmin":false,"CreatedDate":null,"ModifiedDate":null,"LoggedInUser":"TESTUSER"}]'
declare #result nvarchar(500)
declare #expression nvarchar(200) = '.*"CustomFieldId":' + #CustomFieldId + ',"FieldName":"' + #FieldName + '".*"FieldValue":("' + #FieldValueStartsWith + '\w+").*'
select #result = dbo.RegExReplaceX(#expression,#input,'$1',dbo.RegExOptionEnumeration(0,0,0,0,1,0,0,0,0)) -- OPTION = FOR CASE SENSITIVE
if #result = #input SELECT NULL ELSE SELECT #RESULT
I am using SQL Server 2012.I have been assigned a task where one of my column (JsonText) of table Sample contains json data. I want to pass parse that data and insert into columns of another table (Test). I searched on net 'openjson' is supported in SQL Server 2016. How to do in SQL Server 2012?
Table1 : Sample
Id JsonText Active
JsonText
webaddress?{'data':'{"PId": "XXXX","Status": "YES","Name":"XXX","Address":"XXXX","MobileNumber":"xxx"}'}
I am intrested only 'PID,Address,MobileNumber' columns not all.
Table Test structure like this
Id, PID, Address, MobileNumber
Isaac your code is not working with not quoted values e.g. {"isAuthorized":"false","customerID":null}. I fixed this and your function should look like this.
ALTER FUNCTION [dbo].[JSON_VALUE]
(
#JSON NVARCHAR(3000),
#column NVARCHAR(3000)
)
RETURNS NVARCHAR(3000)
AS
BEGIN
DECLARE #value NVARCHAR(3000);
DECLARE #trimmedJSON NVARCHAR(3000);
DECLARE #start INT;
DECLARE #end INT;
set #start = PATINDEX('%' + #column + '":%',#JSON) + LEN(#column) + 2;
SET #trimmedJSON = SUBSTRING(#JSON, #start, LEN(#JSON));
Set #end = CHARINDEX(',',#trimmedJSON);
SET #value = REPLACE(SUBSTRING(#trimmedJSON, 0, #end),'"','');
RETURN #value
END
I created a function compatible with SQL 2012 to take care of this
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
-- =============================================
-- Author: Isaac Adams
-- Create date: 7/12/2018
-- Description: Give the JSON string and the name of the column from which you want the value
-- =============================================
CREATE FUNCTION JSON_VALUE
(
#JSON NVARCHAR(3000),
#column NVARCHAR(3000)
)
RETURNS NVARCHAR(3000)
AS
BEGIN
DECLARE #value NVARCHAR(3000);
DECLARE #trimmedJSON NVARCHAR(3000);
DECLARE #start INT;
DECLARE #length INT;
SET #start = PATINDEX('%' + #column + '":"%',#JSON) + LEN(#column) + 3;
SET #trimmedJSON = SUBSTRING(#JSON, #start, LEN(#JSON));
SET #length = PATINDEX('%", "%', #trimmedJSON);
SET #value = SUBSTRING(#trimmedJSON, 0, #length);
RETURN #value
END
GO
>>> at JSON_VALUE function, at PATINDEX('%", "%', #trimmedJSON);
remove space from '%", "%'
if your JSON value is like
'{"street":"street1","street2":"street232423"}'
You can use JSON_VALUE(ColumnName,'$.Path') for pairs Json in TSQL, for example:
select JSON_VALUE(webaddress,'$.data.PID') as 'PID',
JSON_VALUE(webaddress,'$.data.Status') as 'Status',
JSON_VALUE(webaddress,'$.data.Name') as 'Name'
from test
I have contact_firstname column which has some special characters like (#,&,-,_, etc) in the data stored in that column. I want to first find all those special characters in each record and replace those characters with a space. I found a query on this website which helps identify the special characters but I am not sure how to find charindex of each special character in the below string and replace it with a space.
DECLARE #MyString VARCHAR(100)
SET #MyString = '!Char$Fox#'
IF (#MyString LIKE '%[^a-zA-Z0-9]%')
BEGIN
PRINT 'Contains "special" characters'
END
I think you have to loop, as Tab Alleman mentioned:
declare #MyString varchar(100) = '!Char$Fox#'
declare #i int = 0
declare #char varchar(1)
declare #len int = LEN(#MyString)
declare #result varchar(100) = ''
while #i < #len
begin
set #char = SUBSTRING(#MyString, #i, 1)
if #char like '%[^a-zA-Z0-9]%'
begin
set #char = ' '
end
set #result = #result + #char
set #i = #i + 1
end
select #result
You can also do this:
DECLARE #InvalidChars VARCHAR(100)
DECLARE #MyString VARCHAR(100)
SET #InvalidChars = '!$#'
SET #MyString = '!Char$Fox#'
;WITH CTE AS
(
SELECT SUBSTRING(#InvalidChars, 1, 1) AS [String], 1 AS [Start], 1 AS [Counter]
UNION ALL
SELECT SUBSTRING(#InvalidChars, [Start] + 1, 1) AS [String], [Start] + 1, [Counter] + 1
FROM CTE
WHERE [Counter] < LEN(#InvalidChars)
)
SELECT #MyString = REPLACE(#MyString, CTE.[String], ' ') FROM CTE
SELECT #MyString
Result:
Char Fox
This is a combination of solutions found here:
How to Replace Multiple Characters in SQL?
T-SQL: Opposite to string concatenation - how to split string into multiple records [duplicate]
I am trying to select a part of a url which is after a wildcard expression and before another expression using SQL Server 2008 R2.
I have a url like:
https%www.msn.com%2ftokenauth%mapserver%ftoken%aogvgkooo%json
or:
https%www.msn.com%2ftokenauth%mapserver%token=aogvgkooo%json.
How do I write a sql query to only show aogvgkooo? The url is stored in column called url.
Here is my select statement:
select REPLACE(REPLACE(url, 'token=', ''),'%json', '')
have you looked at SUBSTRING, CHARINDEX or PATINDEX functions? this site gives a good explanation of them:
http://social.technet.microsoft.com/wiki/contents/articles/17948.t-sql-right-left-substring-and-charindex-functions.aspx
and this one gives an example as well
http://sqlzoo.net/howto/source/u.cgi/tip238311/sqlserver
DECLARE #url varchar(100)
SET #url ='https%www.msn.com%2ftokenauth%mapserver%token=aogvgkooo%json'
SELECT Replace(Replace(Replace(#url,substring(#url,1,Patindex('%token=%',#url)-1),''),'token=',''),'%json','')
sql fiddler
A user-defined function might be a good choice.
create function findToken (
#url nvarchar(max),
#tag nvarchar(100),
#after nvarchar(100)
) returns nvarchar(max) as begin
declare #token nvarchar(max);
declare #start int = charindex(#tag,#url) + len(#tag);
declare #justPast int = charindex(#after,#url,#start);
if #start = len(#tag) or #justPast = 0
return NULL;
return substring(#url,#start,#justPast-#start)
end;
go
declare #url varchar(100);
set #url ='https%www.msn.com%2ftokenauth%mapserver%token=aogvgkooo%json';
select
dbo.findToken(#url,'token=','%json');
DECLARE #url nvarchar(255),
#startPos nvarchar(100),
#endPos nvarchar(100)
SET #url ='https%www.msn.com%2ftokenauth%mapserver%token=aogvgkooo%json'
SET #startPos = 'token%'
SET #endPos = '%json'
SELECT SUBSTRING(#url,CHARINDEX(#startPos,REPLACE (#url,'=','%'),0)+ LEN(#startPos) ,CHARINDEX(#endPos,REPLACE (#url,'=','%'),0)-(CHARINDEX(#startPos,REPLACE (#url,'=','%'),0)+ LEN(#startPos)))
More general approach:
DECLARE #s VARCHAR(100) = 'https%www.msn.com%2ftokenauth%mapserver%ftoken%aogvgkooo%json'
SELECT REVERSE(SUBSTRING(
REVERSE(#s),
CHARINDEX('%', REVERSE(#s)) + 1,
CHARINDEX('%', REVERSE(#s), CHARINDEX('%', REVERSE(#s)) + 1) -
CHARINDEX('%', REVERSE(#s)) - 1))
Reversing string, then take substring from first occurence of % till second occurence, then reversing again.