Sum without couting duplicate values SQL - sql

Question

I have a table suivis containing columns id_action AND id_individu, that table can contain multiple duplicate value (not the entire row, only the column).
example :
I have also a table individus containing a column statut_collaborateur, that table can have two values : 'no' and 'granted'.
i need help to count the number of id_individu having statut_collaborateur = no and statut_collaborateur = granted but only once.
For now, i managed to do this :
SELECT j.date_debut, j.date_fin, j.titre, so.id_identite, so.nom_societe,
SUM(CASE WHEN (i.statut_collaborateur = 'granted') THEN 1 ELSE 0 END) AS interne,
SUM(CASE WHEN (i.statut_collaborateur = 'no') THEN 1 ELSE 0 END) AS externe,
r.nom_responsable
FROM individus AS i
LEFT JOIN suivis AS s ON s.id_individu = i.id_individu
LEFT JOIN jurys AS j ON j.id_jury = s.id_jury
LEFT JOIN societes AS so ON so.id_societe = j.id_societe
LEFT JOIN responsables AS r ON r.id_responsable = j.id_responsable
WHERE s.id_action = 22
AND j.statut IN (1,3)
AND j.date_debut BETWEEN '2018-01-01 00:00:00' AND '2018-10-23 23:59:59'
GROUP BY s.id_jury`
The major problem is that i have to do it in the sum, i tried count also but same result, my count is 5, it should be 3 ( 3 distinct individu).

Answer 1

Number of column in selection should need to include on group by
SELECT j.date_debut, j.date_fin, j.titre, so.id_identite, so.nom_societe,
SUM(CASE WHEN (i.statut_collaborateur = 'granted') THEN 1 ELSE 0 END) AS interne,
SUM(CASE WHEN (i.statut_collaborateur = 'no') THEN 1 ELSE 0 END) AS externe,
r.nom_responsable
FROM individus AS i
LEFT JOIN suivis AS s ON s.id_individu = i.id_individu
LEFT JOIN jurys AS j ON j.id_jury = s.id_jury
LEFT JOIN societes AS so ON so.id_societe = j.id_societe
LEFT JOIN responsables AS r ON r.id_responsable = j.id_responsable
WHERE s.id_action = 22
AND j.statut IN (1,3)
AND j.date_debut BETWEEN '2018-01-01 00:00:00' AND '2018-10-23 23:59:59'
GROUP BY j.date_debut, j.date_fin, j.titre, so.id_identite, so.nom_societe,r.nom_responsable

Answer 2

Join only the desired columns with a distinct statement for the table individus
SELECT j.date_debut, j.date_fin, j.titre, so.id_identite, so.nom_societe,
SUM(CASE WHEN (i.statut_collaborateur = 'granted') THEN 1 ELSE 0 END) AS interne,
SUM(CASE WHEN (i.statut_collaborateur = 'no') THEN 1 ELSE 0 END) AS externe,
r.nom_responsable
FROM (SELECT DISTINCT i.id_individu ,i.statut_collaborateur from individus )AS i
LEFT JOIN suivis AS s ON s.id_individu = i.id_individu
LEFT JOIN jurys AS j ON j.id_jury = s.id_jury
LEFT JOIN societes AS so ON so.id_societe = j.id_societe
LEFT JOIN responsables AS r ON r.id_responsable = j.id_responsable
WHERE s.id_action = 22
AND j.statut IN (1,3)
AND j.date_debut BETWEEN '2018-01-01 00:00:00' AND '2018-10-23 23:59:59'
GROUP BY j.date_debut, j.date_fin, j.titre, so.id_identite, so.nom_societe,r.nom_responsable