Complex Case Statement Issue - Oracle SQL - sql

Wrote the query below, but am getting multiplied amounts because the aggregation needs to occur before the case statements. Would love some advice on the best way to structure this.
Select Store, CUSTID, CUST.ID_CUST,
Sum(
CASE
WHEN Cust_Gift.Code_Status = 'C' AND Gift_Item.FLAG_STORE_LOC = 'N'
THEN Cust_Gift.AMT_PAID ELSE 0
END) GiftAmt,
Sum(
CASE WHEN Cust_Gift.Code_Status = 'C' AND Gift_Item.FLAG_STORE_LOC = 'Y'
THEN Cust_Gift.AMT ELSE 0
END) CustGiftAmt,
Sum(
CASE WHEN Cust_Coupon.Code_Status = 'C'
THEN Cust_Coupon.AMT
ELSE 0
END) CouponAmt,
Sum(CASE WHEN Cust_Sports.Status = 'C'
THEN Cust_Sports.AMT
ELSE 0
END) SportsAmt
FROM CUST
LEFT OUTER JOIN CUST_GIFT
ON CUST.ID_CUST = CUST_GIFT.ID_CUST
LEFT OUTER JOIN CUST_COUPON
ON CUST.ID_CUST = CUST_COUPON.ID_CUST
LEFT OUTER JOIN CUST_SPORTS
ON CUST.ID_CUST = CUST_SPORTS.ID_CUST
INNER JOIN GIFT_ITEM
ON CUST_GIFT.ID_GIFT_ITEM = GIFT_ITEM.ID_GIFT_ITEM
WHERE (STORE = 'M669098' OR STORE = 'M66923434' )
Group by CustID, Store, CUST.ID_CUST

This is one way you could do it:
SELECT cust.store,
cust.custid,
cust.id_cust,
gift.giftamt,
gift.custgift,
cpn.couponamt,
sprt.sportsamt
FROM cust
LEFT OUTER JOIN (SELECT id_cust,
SUM(CASE WHEN cg.code_status = 'C' AND gi.flag_store_loc = 'N' THEN cg.amt_paid END) giftamt,
SUM(CASE WHEN cg.code_status = 'C' AND gi.flag_store_loc = 'Y' THEN cg.amt_paid END) custgiftamt
FROM cust_gift cg
INNER JOIN gift_item gi ON cg.id_gift_item = gi.id_gift_item) gift ON cust.id_cust = gift.id_cust
LEFT OUTER JOIN (SELECT id_cust,
SUM(CASE WHEN code_status = 'C' THEN amt END) couponamt
FROM cust_coupon) cpn ON cust.id_cust = cpn.id_cust
LEFT OUTER JOIN (SELECT id_cust,
SUM(CASE WHEN status = 'C' THEN amt END) sportsamt
FROM cust_sports) sprt ON cust.id_cust = sprt.id_cust
WHERE (STORE = 'M669098' OR STORE = 'M66923434');

Related

Sum without couting duplicate values SQL

I have a table suivis containing columns id_action AND id_individu, that table can contain multiple duplicate value (not the entire row, only the column).
example :
I have also a table individus containing a column statut_collaborateur, that table can have two values : 'no' and 'granted'.
i need help to count the number of id_individu having statut_collaborateur = no and statut_collaborateur = granted but only once.
For now, i managed to do this :
SELECT j.date_debut, j.date_fin, j.titre, so.id_identite, so.nom_societe,
SUM(CASE WHEN (i.statut_collaborateur = 'granted') THEN 1 ELSE 0 END) AS interne,
SUM(CASE WHEN (i.statut_collaborateur = 'no') THEN 1 ELSE 0 END) AS externe,
r.nom_responsable
FROM individus AS i
LEFT JOIN suivis AS s ON s.id_individu = i.id_individu
LEFT JOIN jurys AS j ON j.id_jury = s.id_jury
LEFT JOIN societes AS so ON so.id_societe = j.id_societe
LEFT JOIN responsables AS r ON r.id_responsable = j.id_responsable
WHERE s.id_action = 22
AND j.statut IN (1,3)
AND j.date_debut BETWEEN '2018-01-01 00:00:00' AND '2018-10-23 23:59:59'
GROUP BY s.id_jury`
The major problem is that i have to do it in the sum, i tried count also but same result, my count is 5, it should be 3 ( 3 distinct individu).
Number of column in selection should need to include on group by
SELECT j.date_debut, j.date_fin, j.titre, so.id_identite, so.nom_societe,
SUM(CASE WHEN (i.statut_collaborateur = 'granted') THEN 1 ELSE 0 END) AS interne,
SUM(CASE WHEN (i.statut_collaborateur = 'no') THEN 1 ELSE 0 END) AS externe,
r.nom_responsable
FROM individus AS i
LEFT JOIN suivis AS s ON s.id_individu = i.id_individu
LEFT JOIN jurys AS j ON j.id_jury = s.id_jury
LEFT JOIN societes AS so ON so.id_societe = j.id_societe
LEFT JOIN responsables AS r ON r.id_responsable = j.id_responsable
WHERE s.id_action = 22
AND j.statut IN (1,3)
AND j.date_debut BETWEEN '2018-01-01 00:00:00' AND '2018-10-23 23:59:59'
GROUP BY j.date_debut, j.date_fin, j.titre, so.id_identite, so.nom_societe,r.nom_responsable
Join only the desired columns with a distinct statement for the table individus
SELECT j.date_debut, j.date_fin, j.titre, so.id_identite, so.nom_societe,
SUM(CASE WHEN (i.statut_collaborateur = 'granted') THEN 1 ELSE 0 END) AS interne,
SUM(CASE WHEN (i.statut_collaborateur = 'no') THEN 1 ELSE 0 END) AS externe,
r.nom_responsable
FROM (SELECT DISTINCT i.id_individu ,i.statut_collaborateur from individus )AS i
LEFT JOIN suivis AS s ON s.id_individu = i.id_individu
LEFT JOIN jurys AS j ON j.id_jury = s.id_jury
LEFT JOIN societes AS so ON so.id_societe = j.id_societe
LEFT JOIN responsables AS r ON r.id_responsable = j.id_responsable
WHERE s.id_action = 22
AND j.statut IN (1,3)
AND j.date_debut BETWEEN '2018-01-01 00:00:00' AND '2018-10-23 23:59:59'
GROUP BY j.date_debut, j.date_fin, j.titre, so.id_identite, so.nom_societe,r.nom_responsable

How to join two sub queries and find the difference of attribute values in SQL

From the below query, I want to know how to combine these two sub-queries and also find the difference of values of the attributes specified for two different years.
I had tried joining them using joins, but I do not have a common attribute on which I can combine them as they are for two different years. I need to find the difference in order to compute the change as seen in the attached picture. Can anyone help?
(select (CONVERT(INT,SUBSTRING(ACADEMIC_PERIOD,1,4)))-1 as 'Year1',
SUM(CASE WHEN dh.HOME = 'f' THEN 1 else 0 END) as 'foriegn1',
SUM(CASE WHEN dh.HOME = 'o' THEN 1 else 0 END) AS 'outofstate1',
SUM(CASE WHEN dh.HOME = 'i' THEN 1 else 0 END) AS 'texas1',
SUM(CASE WHEN dh.HOME = 'u' THEN 1 else 0 END) AS 'Unknown1',
COUNT(*) as Totalenrollment
FROM dw_enrollment_F d
inner join dim_Time t
on d.TIME_KEY = t.TIME_KEY
inner join dim_Home dh
on d.HOME_KEY = dh.HOME_KEY
inner join dim_Student_Level sl
on d.STUDENT_LEVEL_KEY = sl.STUDENT_LEVEL_KEY
where t.ACADEMIC_PERIOD_all =20162
and t.ACADEMIC_PERIOD_ALL not in('20157','20165','20168','20169','20167')
GROUP BY (CONVERT(INT,SUBSTRING(ACADEMIC_PERIOD,1,4)) ) -1)
(select (CONVERT(INT,SUBSTRING(ACADEMIC_PERIOD,1,4)))-1 as 'Year2',
SUM(CASE WHEN dh.HOME = 'f' THEN 1 else 0 END) as 'foriegn2',
SUM(CASE WHEN dh.HOME = 'o' THEN 1 else 0 END) AS 'outofstate2',
SUM(CASE WHEN dh.HOME = 'i' THEN 1 else 0 END) AS 'texas2',
SUM(CASE WHEN dh.HOME = 'u' THEN 1 else 0 END) AS 'Unknown2',
COUNT(*) as Totalenrollment2
FROM dw_enrollment_F d
inner join dim_Time t
on d.TIME_KEY = t.TIME_KEY
inner join dim_Home dh
on d.HOME_KEY = dh.HOME_KEY
inner join dim_Student_Level sl
on d.STUDENT_LEVEL_KEY = sl.STUDENT_LEVEL_KEY
where t.ACADEMIC_PERIOD_all = 20172
and t.ACADEMIC_PERIOD_ALL not in('20157','20165','20168','20169','20167')
GROUP BY (CONVERT(INT,SUBSTRING(ACADEMIC_PERIOD,1,4)) ) -1)

Summing two seperate queries into one value using UNION ALL clause

I have the following query (as part of a larger query). I am trying to get the sum results from 2 different data sets within a subquery but I am having trouble trying to encapsulate the two into 1 value. What I have is this:
(Select SUM('Invoiced MTD') from
((Select SUM(CASE WHEN SOH.LASDLVNUM_0 <> '' AND SOH.LASINVNUM_0 <> '' AND MONTH(SOH.SHIDAT_0) = MONTH(GETDATE()) THEN
(SOP.NETPRI_0 * SOQ.QTY_0 * SOH.CHGRAT_0) ELSE 0 END) as 'Invoiced MTD'
From x3v6.CICPROD.SORDER SOH
LEFT OUTER JOIN x3v6.CICPROD.BPCUSTOMER BPC on SOH.BPCORD_0 = BPC.BPCNUM_0
LEFT OUTER JOIN x3v6.CICPROD.SORDERQ SOQ on SOH.SOHNUM_0 = SOQ.SOHNUM_0
LEFT OUTER JOIN x3v6.CICPROD.SORDERP SOP on SOQ.SOHNUM_0 = SOP.SOHNUM_0 and SOQ.SOPLIN_0 = SOP.SOPLIN_0 and SOQ.SOQSEQ_0 = SOP.SOPSEQ_0
LEFT OUTER JOIN x3v6.CICPROD.ITMMASTER ITM on SOP.ITMREF_0 = ITM.ITMREF_0 ))
UNION ALL
((Select SUM(CASE WHEN SIH.INVTYP_0 = 2 and MONTH(SIH.ACCDAT_0) = MONTH(GETDATE()) THEN SID.AMTNOTLIN_0 * (-1) ELSE 0 END) as 'Invoiced MTD'
From x3v6.CICPROD.SINVOICE SIH
Left Outer Join x3v6.CICPROD.SINVOICED SID on SIH.NUM_0 = SID.NUM_0))
as 'T2',
But I am getting an error where the UNION ALL clauses is, and I can't figure it out. Basically I want to combine Sales credit memos with the sales order dollar totals from a seperate table.
Can anyone assist me with this?
What about this ?
Select SUM([Invoiced MTD]) from
(
Select SUM(CASE WHEN SOH.LASDLVNUM_0 <> '' AND SOH.LASINVNUM_0 <> '' AND MONTH(SOH.SHIDAT_0) = MONTH(GETDATE())
THEN (SOP.NETPRI_0 * SOQ.QTY_0 * SOH.CHGRAT_0) ELSE 0 END) as 'Invoiced MTD'
From x3v6.CICPROD.SORDER SOH
LEFT OUTER JOIN x3v6.CICPROD.BPCUSTOMER BPC on SOH.BPCORD_0 = BPC.BPCNUM_0
LEFT OUTER JOIN x3v6.CICPROD.SORDERQ SOQ on SOH.SOHNUM_0 = SOQ.SOHNUM_0
LEFT OUTER JOIN x3v6.CICPROD.SORDERP SOP on SOQ.SOHNUM_0 = SOP.SOHNUM_0 and SOQ.SOPLIN_0 = SOP.SOPLIN_0 and SOQ.SOQSEQ_0 = SOP.SOPSEQ_0
LEFT OUTER JOIN x3v6.CICPROD.ITMMASTER ITM on SOP.ITMREF_0 = ITM.ITMREF_0
UNION ALL
Select SUM(CASE WHEN SIH.INVTYP_0 = 2 and MONTH(SIH.ACCDAT_0) = MONTH(GETDATE())
THEN SID.AMTNOTLIN_0 * (-1) ELSE 0 END) as 'Invoiced MTD'
From x3v6.CICPROD.SINVOICE SIH
Left Outer Join x3v6.CICPROD.SINVOICED SID on SIH.NUM_0 = SID.NUM_0
)T
Does this work? I'm not sure exactly what is causing your issue, but you definitely don't need so many parenthesis. I would also recommend using something that formats/ beautifies your SQL. It's a great way to 1) keep your code looking consistent and 2) flesh out syntax errors.
SELECT SUM(x.invoiced_mtd)
FROM (SELECT SUM(CASE
WHEN soh.lasdlvnum_0 <> '' AND soh.lasinvnum_0 <> '' AND
MONTH(soh.shidat_0) = MONTH(getdate()) THEN
(sop.netpri_0 * soq.qty_0 * soh.chgrat_0)
ELSE
0
END) AS invoiced_mtd
FROM x3v6.cicprod.sorder soh
LEFT OUTER JOIN x3v6.cicprod.bpcustomer bpc
ON soh.bpcord_0 = bpc.bpcnum_0
LEFT OUTER JOIN x3v6.cicprod.sorderq soq
ON soh.sohnum_0 = soq.sohnum_0
LEFT OUTER JOIN x3v6.cicprod.sorderp sop
ON soq.sohnum_0 = sop.sohnum_0
AND soq.soplin_0 = sop.soplin_0
AND soq.soqseq_0 = sop.sopseq_0
LEFT OUTER JOIN x3v6.cicprod.itmmaster itm
ON sop.itmref_0 = itm.itmref_0
UNION ALL
SELECT SUM(CASE
WHEN sih.invtyp_0 = 2 AND
MONTH(sih.accdat_0) = MONTH(getdate()) THEN
sid.amtnotlin_0 * (-1)
ELSE
0
END)
FROM x3v6.cicprod.sinvoice sih
LEFT OUTER JOIN x3v6.cicprod.sinvoiced sid
ON sih.num_0 = sid.num_0) x;
Try using a CTE for the UNION query first. Here is a simplified example with the same structure as your query:
;with cteTest AS (
((select 2 as 'test'))
union all
((select 3 as 'test'))
)
select sum(test) from cteTest

SQL Server Converting Rows to Columns

I am currently extracting data using 3 different tables, and below is the output.
Current Result:
Query Used:
SELECT
dbo.TableB.TrackingID, dbo.TableA.FinancialID,
dbo.TableA.ParcelCode, dbo.TableA.TotalAmount,
dbo.TableB.FinanceType, dbo.TableB.TransactionType,
dbo.TableC.CustID
FROM
dbo.TableA
INNER JOIN
dbo.TableB ON dbo.TableA.FinancialID = dbo.TableB.FinancialID
INNER JOIN
dbo.TableC ON dbo.TableB.TrackingID = dbo.TableC.TrackingID
WHERE
(dbo.TableB.TrackingID = '17006218AU')
I would like to have the following output:
Desired Output:
You can get the output you desire with grouping and some CASE statements inside SUM aggregate functions:
SELECT
dbo.TableB.TrackingID,
dbo.TableA.ParcelCode,
dbo.TableC.CustID,
SUM(CASE WHEN dbo.TableB.FinanceType = 'Invoice' THEN dbo.TableA.TotalAmount ELSE 0 END) AS TotalAmount,
SUM(CASE WHEN dbo.TableB.FinanceType = 'Invoice' AND TransType='Card' THEN dbo.TableA.TotalAmount ELSE 0 END) AS CardInvoice,
SUM(CASE WHEN dbo.TableB.FinanceType = 'Invoice' AND TransType='Cash' THEN dbo.TableA.TotalAmount ELSE 0 END) AS CashInvoice,
SUM(CASE WHEN dbo.TableB.FinanceType = 'PaymentRecepit' THEN dbo.TableA.TotalAmount ELSE 0 END) AS CardPaymentRecepit
FROM dbo.TableA
INNER JOIN dbo.TableB ON dbo.TableA.FinancialID = dbo.TableB.FinancialID
INNER JOIN dbo.TableC ON dbo.TableB.TrackingID = dbo.TableC.TrackingID
WHERE
dbo.TableB.TrackingID = '17006218AU'
GROUP BY
dbo.TableB.TrackingID,
dbo.TableA.ParcelCode,
dbo.TableC.CustID

SQL QUERY with subquery Optimization

how can i optimize these query
SELECT
mp.ProviderName
,(SELECT count(mc.ClaimSubmissionID) FROM dbo.MST_Claim mc WHERE mc.HeaderID=mpach.HeaderID AND mc.IsActive=1) AS total_claim
,(SELECT count(mc.ClaimSubmissionID) FROM dbo.MST_Claim mc WHERE mc.HeaderID=mpach.HeaderID AND mc.op=1) AS total_op
,(SELECT count(mc.ClaimSubmissionID) FROM dbo.MST_Claim mc WHERE mc.HeaderID=mpach.HeaderID AND mc.ip=1) AS total_ip
FROM dbo.MST_PriorAuthorization_Claim_Header mpach
INNER JOIN dbo.MS_Provider mp ON mp.Provider_ID = mpach.Provider_ID
Use Sum of CASE Statements to avoid all those subqueries.
SELECT
mp.ProviderName,
SUM(CASE WHEN mc.IsActive=1 THEN 1 ELSE 0 END ) AS total_claim,
SUM(CASE WHEN mc.op=1 THEN 1 ELSE 0 END ) AS total_op,
SUM(CASE WHEN mc.ip=1 THEN 1 ELSE 0 END ) AS total_ip
FROM dbo.MST_PriorAuthorization_Claim_Header mpach
INNER JOIN dbo.MS_Provider mp ON mp.Provider_ID = mpach.Provider_ID
INNER JOIN dbo.MST_Claim mc ON mc.HeaderID=mpach.HeaderID
You can modify your query using a CASE statement like below
SELECT
mp.ProviderName
,sum(case when mc.IsActive=1 then mc.ClaimSubmissionID else 0 end) AS total_claim,
sum(case when mc.op=1 then mc.ClaimSubmissionID else 0 end) AS total_op
sum(case when mc.ip=1 then mc.ClaimSubmissionID else 0 end) AS total_ip
FROM dbo.MST_PriorAuthorization_Claim_Header mpach
INNER JOIN dbo.MS_Provider mp ON mp.Provider_ID = mpach.Provider_ID
JOIN dbo.MST_Claim mc ON mc.HeaderID = mpach.HeaderID;