I am trying to use sparql to find all French labels of words that are related to a given English word.
The query I made is something like the following:
SELECT ?extword ?word ?label where {
?word rdfs:label "shark"#eng.
{?extword rdf:type ?word}
UNION
{?word rdf:type ?extword}.
?extword rdfs:label ?label filter(lang(?label)="fra")
}
While it does give me the French labels of the extword as desired, it does not give the French labels of word itself.
What I need is to insert a clause to express the relation that extword is exactly word, like this:
SELECT ?extword ?word ?label where {
?word rdfs:label "shark"#eng.
{?extword = ?word}
UNION
{?extword rdf:type ?word}
UNION
{?word rdf:type ?extword}.
?extword rdfs:label ?label filter(lang(?label)="fra")
}
It turns out to be syntax error. Is it possible to also include the French labels of word itself, without doing another query?
To be clearer, the result I expect is the result from my first query combined with result from the following query:
SELECT ?word ?label where {
?word rdfs:label "shark"#eng.
?word rdfs:label ?label filter(lang(?label)="fra")
}
Related
Can some one help me how to use group_concat in sparql query. When i am using in the database it is pulling out iri from the data. How to pull the the labels for the objects present in the database using group_concat.
You will usually have IRIs with a label. Now, to return labels only, a query like this will work:
SELECT ?item ?label
WHERE {
?item rdfs:label ?label
}
Note that rdfs:label is conventionally used for labels, but any name can be used - it depends on the data that you have.
Now, imagine we want to find a GROUP_CONCAT of children's names, grouped by mother.
First, the query for the children and labels looks like this:
SELECT ?mother ?child ?label
WHERE {
?mother :hasChild ?child .
?child rdfs:label ?label .
}
Notice that ?mother and ?child will be bound to IRIs here, and ?label to a string.
Now for the GROUP_CONCAT, you will just need a query like:
SELECT ?mother (GROUP_CONCAT(?label; SEPARATOR=", ") AS ?concat)
WHERE {
?mother :hasChild ?child .
?child rdfs:label ?label .
}
GROUP BY ?mother
I need to find the names of similar types from DBpedia so I'm trying to figure out a query which can return me the names of entities which have same subject type in its dct:subject (example I want to find similar types of white house so i want to write a query for same . I'm considering the dct:subject to find them ). If there is any other approach please mention it
Previously I tried it for rdf:type but the result are not so good and some time it shows time out
I have done my problem by the query mentioned below and now i want to consider dct:subject instead of rdf:type
select distinct ?label ?resource count(distinct ?type) as ?score where {
values ?type { dbo:Thing dbo:Organization yago:WikicatIslam-relatedControversies yago:WikicatIslamistGroups yago:WikicatRussianFederalSecurityServiceDesignatedTerroristOrganizations yago:Abstraction100002137 yago:Act100030358 yago:Cabal108241798 yago:Group100031264 yago:Movement108464601 yago:PoliticalMovement108472335
}
?resource rdfs:label ?label ;
foaf:name ?name ;
a ?type .
FILTER (lang(?label) = 'en').
}
ORDER BY DESC(?score)
I am using the following query
PREFIX dct: <http://purl.org/dc/terms/>
SELECT ?subject WHERE {
?concept rdfs:label 'Exoskeleton'#en ;
^dct:subject ?subject .
}
ORDER BY ?subject
This doesn't give me any results. However, the rdfs:label exists. (See http://dbpedia.org/page/Exoskeleton.)
On querying with a different label, it works :
PREFIX dct: <http://purl.org/dc/terms/>
SELECT ?subject WHERE {
?concept rdfs:label 'Machine learning'#en ;
^dct:subject ?subject .
}
ORDER BY ?subject
The above query works and gives me the results. (See http://dbpedia.org/page/Machine_learning.)
What do I change, such that the first query works too?
The dct:subject predicate is used between a page and a category it belongs to. So, your second query is giving you results that are in Category:Machine learning. But since there is no Category:Exoskeleton, your first query gives you no results. This also means the two pages you liked to are irrelevant to your queries.
I don't know how to change the first query so that it works, because I don't understand what would "working" entail.
Devil is in the details:
PREFIX dct: <http://purl.org/dc/terms/>
SELECT ?concept WHERE {
?concept rdfs:label 'Machine learning'#en.
}
ORDER BY ?concept
Returns two results:
http://dbpedia.org/resource/Category:Machine_learning
http://dbpedia.org/resource/Machine_learning
While Exoskeleton has no corresponding concept:
http://dbpedia.org/resource/Exoskeleton
Thus your inverse property path finds resources under a http://dbpedia.org/resource/Category:Machine_learning concept but not under a http://dbpedia.org/resource/Machine_learning or http://dbpedia.org/resource/Exoskeleton pages.
If you drop the inverse modifier,
PREFIX dct: <http://purl.org/dc/terms/>
SELECT ?subject WHERE {
?concept rdfs:label 'Exoskeleton'#en ;
dct:subject ?subject .
}
ORDER BY ?subject
Will return the categories (subject) for the concepts under a given label.
I am trying to get abstract using Sqarql with dbpedia datasets.
When I am running the following query on Virtuoso,
PREFIX dbpedia-owl: <http://dbpedia.org/ontology/>
SELECT DISTINCT ?abstract WHERE {
[ rdfs:label ?name
; dbpedia-owl:abstract ?abstract
] .
FILTER langMatches(lang(?abstract),"en")
VALUES ?name { "London"#en }
}
LIMIT 10
I am getting the result, however if I modify the name to say 'Gokarna' which is a south indian tourist spot, I am not getting any data. However I do see the resource page online on dbpedia for Gokarna(http://dbpedia.org/page/Gokarna,_India). What am I doing wrong? I need to get similar data for close to 800 indian places.
When you use values, you'd get only those that exactly match your string. For Gokarna, that would work for #de, #it, #fr, but not for #en, as there the label is different, as you can see also from the previous answer.
I would suggest to use contains, instead of values:
PREFIX dbpedia-owl: <http://dbpedia.org/ontology/>
SELECT DISTINCT ?abstract WHERE {
[ rdfs:label ?name
; dbpedia-owl:abstract ?abstract
] .
FILTER langMatches(lang(?abstract),"en")
FILTER langMatches(lang(?name),"en")
FILTER CONTAINS (?name, "Gokarna" )
}
LIMIT 10
I am not that experience with Sqarql but as much i can see in your code and checked with dbpedia library...
it is not just Gokarna. it is "Gokarna,_India".
This should work..
PREFIX dbpedia-owl: <http://dbpedia.org/ontology/>
SELECT DISTINCT ?abstract WHERE {
[ rdfs:label ?name
; dbpedia-owl:abstract ?abstract
] .
FILTER langMatches(lang(?abstract),"en")
VALUES ?name { "Gokarna,_India"#en }
}
LIMIT 10
If you look through the DBpedia page for Gokarna, India that you linked to, you'll notice that its rdfs:label is "Gokarna, India". But its foaf:name is just "Gokarna". This would mean you should modify your query to:
PREFIX dbpedia-owl: <http://dbpedia.org/ontology/>
SELECT DISTINCT ?abstract WHERE {
[ foaf:name ?name
; dbpedia-owl:abstract ?abstract
] .
FILTER langMatches(lang(?abstract),"en")
VALUES ?name { "Gokarna"#en }
}
LIMIT 10
Though this will return other Gokarnas too: Gokarna, Nepal, Gokarna, Bangladesh and Gokarna (film). If you want to remove these, you will have to figure out another filter (possibly dbo:country dbr:India).
I need to extract the URIs of a specific resource from DBpedia.
Example, my specific resource is "France", I extracted its label but I don't know how to get its URI.
Here is my query so far :
SELECT ?label
WHERE{
res:France rdfs:label ?label .
FILTER (lang(?label) = 'fr') .}
Thanks for your help !
You need to filter your resource to be able to extract the URI. Try this:
SELECT distinct *
WHERE{
?uri rdfs:label ?label
filter (?uri=res:France && lang(?label) = 'fr')
}