Tcl : Guaranteed evaluation sequence of a boolean expression? - conditional-statements

Let's say I have a conditional Tcl expression that is a boolean combination of steps.
Will the expression always be evaluated left to right (excluding parentheses)?
If the expression becomes true will the rest of the evaluation stop?
I have this piece of code that parses a file and conditionally replaces stuff in the lines.
set fp [ open "file" ]
set data [ read $fp ]
close $fp
foreach line [ split $data \n ] {
if { $enable_patch && [ regsub {<some_pattern>} $line {<some_other_pattern>} line ]} {
puts $outfp $line
<do_some_more_stuff>
}
}
So my issue here is that unless enable_patch is true, I don't want the line to be modified. Now my test shows that the code is deterministic in Tcl 8.5 on Linux. But I am wondering if this would break under other conditions/ versions/ OSes.

Yes, the || and && operators are "short-circuiting" operators in TCL. That means you can rely on them being evaluated left-to-right, and that evaluation will stop as soon as the value of the expression is known.

Related

How to use the eval statement in (g)awk?

Due to that awk does not seem to have callbacks, I was planning to use the eval statement for this. So I had a look at the GNU user guide,
https://www.gnu.org/software/gawk/manual/html_node/Viewing-And-Changing-Data.html
and then wrote this simple script.
BEGIN {
args[1]="\"a\""
args[2]="\"b\""
args[3]="\"c\""
args[4]="\"\""
run_callback("printargs",args)
print args[4]
}
function run_callback(callback,args)
{
nargs=length(args)
if (nargs>0)
{
argstring=args[1]
for (argn=2;argn<=nargs;argn++)
{
argstring=argstring","args[argn]
}
}
callbackstr = callback"("argstring")"
print callbackstr
eval callbackstr
}
function printargs(arg1,arg2,arg3,res)
{
res=arg1","arg2","arg3
print "res="res
}
However, the printout is not what I expected. I get this,
[~]-> gawk -f callback.awk
printargs(a,b,c,"")
""
And not the expected,
[~]-> gawk -f callback.awk
printargs(a,b,c,"")
res=a,b,c
"Not sure what is supposed to be here, but it is not relevant."
It feels as if nothing actually happens inside the eval statement. Anyone who knows what happens here?
gawk version is 4.1.3
BR
Patrik
That's in the documentation for the gawk debugger. It's not a normal gawk function.
However, gawk does support calling a function whose name is in a string with the #var(args,...) notation (More information in the documentation):
BEGIN {
args[1]="a"
args[2]="b"
args[3]="c"
args[4]="\"\""
run_callback("printargs",args[1],args[2],args[3],args[4])
print args[4]
}
function run_callback(callback,arg1,arg2,arg3,res)
{
#callback(arg1,arg2,arg3,res);
}
function printargs(arg1,arg2,arg3,res)
{
res=arg1","arg2","arg3
print "res="res
}
when run will print out
res=a,b,c
""
Note that args[4] isn't modified from this. From the documentation on function argument passing convention:
Instead, the passing convention is determined at runtime when the function is called, according to the following rule: if the argument is an array variable, then it is passed by reference. Otherwise, the argument is passed by value.
If you passed args directly and modified elements of it in the callback, you'd see the changes reflected.
awk doesn't have any eval keyword.
This can be check with gawk --dump-variables option
gawk --dump-variables -f callback.awk
It outputs the file awkvars.out and you'll find in it:
eval: uninitialized scalar

Is Perl 6's uncuddled else a special case for statement separation?

From the syntax doc:
A closing curly brace followed by a newline character implies a statement separator, which is why you don't need to write a semicolon after an if statement block.
if True {
say "Hello";
}
say "world";
That's fine and what was going on with Why is this Perl 6 feed operator a “bogus statement”?.
However, how does this rule work for an uncuddled else? Is this a special case?
if True {
say "Hello";
}
else {
say "Something else";
}
say "world";
Or, how about the with-orwith example:
my $s = "abc";
with $s.index("a") { say "Found a at $_" }
orwith $s.index("b") { say "Found b at $_" }
orwith $s.index("c") { say "Found c at $_" }
else { say "Didn't find a, b or c" }
The documentation you found was not completely correct. The documentation has been updated and is now correct. It now reads:
Complete statements ending in bare blocks can omit the trailing semicolon, if no additional statements on the same line follow the block's closing curly brace }.
...
For a series of blocks that are part of the same if/elsif/else (or similar) construct, the implied separator rule only applies at the end of the last block of that series.
Original answer:
Looking at the grammar for if in nqp and Rakudo, it seems that an if/elsif/else set of blocks gets parsed out together as one control statement.
Rule for if in nqp
rule statement_control:sym<if> {
<sym>\s
<xblock>
[ 'elsif'\s <xblock> ]*
[ 'else'\s <else=.pblock> ]?
}
(https://github.com/perl6/nqp/blob/master/src/NQP/Grammar.nqp#L243, as of August 5, 2017)
Rule for if in Rakudo
rule statement_control:sym<if> {
$<sym>=[if|with]<.kok> {}
<xblock(so ~$<sym>[0] ~~ /with/)>
[
[
| 'else'\h*'if' <.typed_panic: 'X::Syntax::Malformed::Elsif'>
| 'elif' { $/.typed_panic('X::Syntax::Malformed::Elsif', what => "elif") }
| $<sym>='elsif' <xblock>
| $<sym>='orwith' <xblock(1)>
]
]*
{}
[ 'else' <else=.pblock(so ~$<sym>[-1] ~~ /with/)> ]?
}
(https://github.com/rakudo/rakudo/blob/nom/src/Perl6/Grammar.nqp#L1450 as of August 5, 2017)

How to change Boolean variable based on expression?

I'm trying to change the value of a Boolean variable using expression in bash script (Debian Jessie) but it's not working as intended!
Here is my code
vld=true
while ! [ $vld ]
do
echo "Enter a number: [1-30]:"
read myinput
$vld=[ $myinput -ge 1 ] && [ $myinput -le 30 ]
done
echo "Your number is $myinput
When I this script it says:
8: ./test.sh true=[: not found
Then it keeps on the loop as the variable is not receiving the result of the expression but is used itself!

Break down JSON string in simple perl or simple unix?

ok so i have have this
{"status":0,"id":"7aceb216d02ecdca7ceffadcadea8950-1","hypotheses":[{"utterance":"hello how are you","confidence":0.96311796}]}
and at the moment i'm using this shell command to decode it to get the string i need,
echo $x | grep -Po '"utterance":.*?[^\\]"' | sed -e s/://g -e s/utterance//g -e 's/"//g'
but this only works when you have a grep compiled with perl and plus the script i use to get that JSON string is written in perl, so is there any way i can do this same decoding in a simple perl script or a simpler unix command, or better yet, c or objective-c?
the script i'm using to get the json is here, http://pastebin.com/jBGzJbMk and if you want a file to use then download http://trevorrudolph.com/a.flac
How about:
perl -MJSON -nE 'say decode_json($_)->{hypotheses}[0]{utterance}'
in script form:
use JSON;
while (<>) {
print decode_json($_)->{hypotheses}[0]{utterance}, "\n"
}
Well, I'm not sure if I can deduce what you are after correctly, but this is a way to decode that JSON string in perl.
Of course, you'll need to know the data structure in order to get the data you need. The line that prints the "utterance" string is commented out in the code below.
use strict;
use warnings;
use Data::Dumper;
use JSON;
my $json = decode_json
q#{"status":0,"id":"7aceb216d02ecdca7ceffadcadea8950-1","hypotheses":[{"utterance":"hello how are you","confidence":0.96311796}]}#;
#print $json->{'hypotheses'}[0]{'utterance'};
print Dumper $json;
Output:
$VAR1 = {
'status' => 0,
'hypotheses' => [
{
'utterance' => 'hello how are you',
'confidence' => '0.96311796'
}
],
'id' => '7aceb216d02ecdca7ceffadcadea8950-1'
};
Quick hack:
while (<>) {
say for /"utterance":"?(.*?)(?<!\\)"/;
}
Or as a one-liner:
perl -lnwe 'print for /"utterance":"(.+?)(?<!\\)"/g' inputfile.txt
The one-liner is troublesome if you happen to be using Windows, since " is interpreted by the shell.
Quick hack#2:
This will hopefully go through any hash structure and find keys.
my $json = decode_json $str;
say find_key($json, 'utterance');
sub find_key {
my ($ref, $find) = #_;
if (ref $ref) {
if (ref $ref eq 'HASH' and defined $ref->{$find}) {
return $ref->{$find};
} else {
for (values $ref) {
my $found = find_key($_, $find);
if (defined $found) {
return $found;
}
}
}
}
return;
}
Based on the naming, it's possible to have multiple hypotheses. The prints the utterance of each hypothesis:
echo '{"status":0,"id":"7aceb216d02ecdca7ceffadcadea8950-1","hypotheses":[{"utterance":"hello how are you","confidence":0.96311796}]}' | \
perl -MJSON::XS -n000E'
say $_->{utterance}
for #{ JSON::XS->new->decode($_)->{hypotheses} }'
Or as a script:
use feature qw( say );
use JSON::XS;
my $json = '{"status":0,"id":"7aceb216d02ecdca7ceffadcadea8950-1","hypotheses":[{"utterance":"hello how are you","confidence":0.96311796}]}';
say $_->{utterance}
for #{ JSON::XS->new->decode($json)->{hypotheses} };
If you don't want to use any modules from CPAN and try a regex instead there are multiple variants you can try:
# JSON is on a single line:
$json = '{"other":"stuff","hypo":[{"utterance":"hi, this is \"bob\"","moo":0}]}';
# RegEx with negative look behind:
# Match everything up to a double quote without a Backslash in front of it
print "$1\n" if ($json =~ m/"utterance":"(.*?)(?<!\\)"/)
This regex works if there is only one utterance. It doesn't matter what else is in the string around it, since it only searches for the double quoted string following the utterance key.
For a more robust version you could add whitespace where necessary/possible and make the . in the RegEx match newlines: m/"utterance"\s*:\s*"(.*?)(?<!\\)"/s
If you have multiple entries for the utterance confidence hash/object, changing case and weird formatting of the JSON string try this:
# weird JSON:
$json = <<'EOJSON';
{
"status":0,
"id":"an ID",
"hypotheses":[
{
"UtTeraNcE":"hello my name is \"Bob\".",
"confidence":0.0
},
{
'utterance' : 'how are you?',
"confidence":0.1
},
{
"utterance"
: "
thought
so!
",
"confidence" : 0.9
}
]
}
EOJSON
# RegEx with alternatives:
print "$1\n" while ( $json =~ m/["']utterance["']\s*:\s*["'](([^\\"']|\\.)*)["']/gis);
The main part of this RegEx is "(([^\\"]|\\.)*)". Description in detail as extended regex:
/
["'] # opening quotes
( # start capturing parentheses for $1
( # start of grouping alternatives
[^\\"'] # anything that's not a backslash or a quote
| # or
\\. # a backslash followed by anything
) # end of grouping
* # in any quantity
) # end capturing parentheses
["'] # closing quotes
/xgs
If you have many data sets and speed is a concern you can add the o modifier to the regex and use character classes instead of the i modifier. You can suppress the capturing of the alternatives to $2 with clustering parenthesis (?:pattern). Then you get this final result:
m/["'][uU][tT][tT][eE][rR][aA][nN][cC][eE]["']\s*:\s*["']((?:[^\\"']|\\.)*)["']/gos
Yes, sometimes perl looks like a big explosion in a bracket factory ;-)
Just stubmled upon another nice method of doing this, i finaly found how to acsess the Mac OS X JavaScript engine form commandline, heres the script,
alias jsc='/System/Library/Frameworks/JavaScriptCore.framework/Versions/A/Resources/jsc'
x='{"status":0,"id":"7aceb216d02ecdca7ceffadcadea8950-1","hypotheses":[{"utterance":"hello how are you","confidence":0.96311796}]}'
jsc -e "print(${x}['hypotheses'][0]['utterance'])"
Ugh, yes i came up with another answer, im strudying python and it reads arrays in both its python format and the same format as a json so, i jsut made this one liner when your variable is x
python -c "print ${x}['hypotheses'][0]['utterance']"
figured it out for unix but would love to see your perl and c, objective-c answers...
echo $X | sed -e 's/.*utterance//' -e 's/confidence.*//' -e s/://g -e 's/"//g' -e 's/,//g'
:D
shorter copy of the same sed:
echo $X | sed -e 's/.*utterance//;s/confidence.*//;s/://g;s/"//g;s/,//g'

Is it possible to override rebol path operator?

It is possible to overide rebol system words like print, make etc., so is it possible to do the same with the path operator ? Then what's the syntax ?
Another possible approach is to use REBOL meta-programming capabilities and preprocess your own code to catch path accesses and add your handler code. Here's an example :
apply-my-rule: func [spec [block!] /local value][
print [
"-- path access --" newline
"object:" mold spec/1 newline
"member:" mold spec/2 newline
"value:" mold set/any 'value get in get spec/1 spec/2 newline
"--"
]
:value
]
my-do: func [code [block!] /local rule pos][
parse code rule: [
any [
pos: path! (
pos: either object? get pos/1/1 [
change/part pos reduce ['apply-my-rule to-block pos/1] 1
][
next pos
]
) :pos
| into rule ;-- dive into nested blocks
| skip ;-- skip every other values
]
]
do code
]
;-- example usage --
obj: make object! [
a: 5
]
my-do [
print mold obj/a
]
This will give you :
-- path access --
object: obj
member: a
value: 5
--
5
Another (slower but more flexible) approach could also be to pass your code in string mode to the preprocessor allowing freeing yourself from any REBOL specific syntax rule like in :
my-alternative-do {
print mold obj..a
}
The preprocessor code would then spot all .. places and change the code to properly insert calls to 'apply-my-rule, and would in the end, run the code with :
do load code
There's no real limits on how far you can process and change your whole code at runtime (the so-called "block mode" of the first example being the most efficient way).
You mean replace (say)....
print mold system/options
with (say)....
print mold system..options
....where I've replaced REBOL's forward slash with dot dot syntax?
Short answer: no. Some things are hardwired into the parser.