I have a tensor with probabilities. This is a dynamic tensor with shape (?, 30) and I am selecting index with the best probability of these 30 values as :
best_probability = tf.argmax(probability, axis = 1)
Now the dimensions of tensor best_probability is (?,). Now I want to select the values with these indices from another tensor called data with dimensions (?, 30, 1024, 3). Essentially from each of the 30 values select one with best probability using best_probability tensor.
The final output should have dimensions of (?, 1024, 3).
PS:- I tried gather_nd but it need indexing of best_probability tensor something like [[0, 9], [1, 10], [2, 15], [3, 25]]. To do so I wrote following snippet.
selected_data = tf.stack(tf.range(probability.shape[0]),
tf.argmax(probability, axis = 1))
This doesn't work as I am dealing with a dynamic tensor. Is there any alternative to solve this problem.
I was able to solve this issue using tf.batch_gather and tf.reshape
selected_data = tf.reshape(tf.batch_gather(data, best_probability),
(-1, data.shape[2],data.shape[3]))
Related
I have extracted the embeddings for a particular entity X from every sentence in my dataset. Where X is mentioned more than once within the same sentence, this yields an embedding for each mention: I'd like to put these through an average pooling layer to arrive at a single embedding for X in each sentence.
Simplified working example:
import tensorflow as tf
embeddings = tf.constant([[1, 1, 1],
[2, 2, 2],
[4, 4, 4],
[5, 5, 5]])
# Let's imagine rows [1, 1, 1] & [4, 4, 4]
# correspond to embeddings for X from the same sentence
# We can indicate sentence belonging through an sent_idxs variable:
sent_idxs = tf.constant([0, 1, 0, 2])
With the help of related stackoverflow questions (Torch - How to calculate average of tensors with the same indexes, Summing over specific indices PyTorch (similar to scatter_add)), I could average embeddings corresponding to the same sentence like this:
unique_idxs, _, counts = tf.unique_with_counts(sent_idxs) # counts = ([2, 1, 1])
result_holder = tf.zeros([unique_idxs.shape[0], embeddings.shape[1]], dtype= embeddings.dtype)
embeddings = tf.tensor_scatter_nd_add(result_holder, tf.expand_dims(sent_idxs, axis=1), embeddings)
embeddings /= counts[:, None]
However, I would prefer to re-shape my original embeddings to instead perform the averaging with AveragePooling2D or AveragePooling1D, and I'm really struggling with imagining the appropriate shape to enable this.
Summarize the problem
I am working with high dimensional tensors in pytorch and I need to index one tensor with the argmax values from another tensor. So I need to index tensor y of dim [3,4] with the results from the argmax of tensor xwith dim [3,4]. If tensors are:
import torch as T
# Tensor to get argmax from
# expected argmax: [2, 0, 1]
x = T.tensor([[1, 2, 8, 3],
[6, 3, 3, 5],
[2, 8, 1, 7]])
# Tensor to index with argmax from preivous
# expected tensor to retrieve [2, 4, 9]
y = T.tensor([[0, 1, 2, 3],
[4, 5, 6, 7],
[8, 9, 10, 11]])
# argmax
x_max, x_argmax = T.max(x, dim=1)
I would like an operation that given the argmax indexes of x, or x_argmax, retrieves the values in tensor y in the same indexes x_argmax indexes.
Describe what you’ve tried
This is what I have tried:
# What I have tried
print(y[x_argmax])
print(y[:, x_argmax])
print(y[..., x_argmax])
print(y[x_argmax.unsqueeze(1)])
I have been reading a lot about numpy indexing, basic indexing, advanced indexing and combined indexing. I have been trying to use combined indexing (since I want a slice in first dimension of the tensor and the indexes values on the second one). But I have not been able to come up with a solution for this use case.
You are looking for torch.gather:
idx = torch.argmax(x, dim=1, keepdim=true) # get argmax directly, w/o max
out = torch.gather(y, 1, idx)
Resulting with
tensor([[2],
[4],
[9]])
How about y[T.arange(3), x_argmax]?
That does the job for me...
Explanation: You take dimensional information away when you invoke T.max(x, dim=1), so this information needs to be restored explicitly.
I am finding it impossible to get the max tensor in an n-dimensional array, even by summing the tensors and using gather or gather_nd.
By max tensor I mean the set of weights with the highest sum.
I have a tensor of shape (-1, 4, 30, 256) where 256 is the weights.
I need to get the maximum set of weights for each (-1, 0, 30), (-1, 1, 30), (-1, 2, 30) and (-1, 3, 30), so under each tensor in the 2nd dimension.
This would ideally result in a (-1, 4, 256) tensor.
reduce_max and any other max function will only return the maximum element values within the last dimension, not the maximum tensor (which is the set of weights with the highest sum) in the dimension itself. I have tried:
p1 = tf.reduce_sum(tensor, axis=3) # (-1, 4, 30)
p2 = tf.argmax(p1, 2) # (-1, 4)
Which gives the appropriate index values for the 3rd dimension:
[[0, 2, 2, 0],
[0, 1, 3, 0],
...
But running tf.gather or tf.gather_nd on the above does not work, even when splitting my data beforehand and using different axes.
Further, I can get the appropriated indexes if I use gather_nd by hand, eg:
tf.gather_nd(out5, [[0,0,0], [0,1,2], [0,2,2], [0,3,0], [1,0,0], [1,1,2], [1,2,2], [1,3,1]])
But as we are using a tensorflow variable of an unknown first dimension, I cannot build these indexes.
I have searched through related workarounds and found nothing applicable.
Can anyone tell me how to accomplish this? Thanks!
edit for clarification:
The maximum tensor of weights would be the set of weights with the highest sum:
[[ 1, 2, 3], [0, 0, 2], [1, 0, 2]] would be [1, 2, 3]
I figured it out using map_fn:
I reshaped my tensor to (-1, 120, 256)
tfr = tf.reshape(sometensor, ((-1, 120, 256)))
def func(slice):
f1 = tf.reduce_sum(slice, axis=1)
f2 = tf.argmax(f1)
return(slice[f2])
bla = tf.map_fn(func, tfr)
Which returns (-1,256) with the greatested summed vector (highest set of weights).
Basically, map_fn will iterate along the 2nd to last axis, so it slices a chunk of (120,256) to func repeatedly (how ever many entries are on the first axis). It then returns the appropriate (1,256) chunk by chunk which, voila, gives the answer.
I have two following tensors (note that they are both Tensorflow tensors which means they are still virtually symbolic at the time I construct the following slicing op before I launch a tf.Session()):
params: has shape (64,784, 256)
indices: has shape (64, 784)
and I want to construct an op that returns the following tensor:
output: has shape (64,784) where
output[i,j] = params_tensor[i,j, indices[i,j] ]
What is the most efficient way in Tensorflow to do so?
ps: I tried with tf.gather but couldn't make use of it to perform the operation I described above.
Many thanks.
-Bests
You can get exactly what you want using tf.gather_nd. The final expression is:
tf.gather_nd(params, tf.stack([tf.tile(tf.expand_dims(tf.range(tf.shape(indices)[0]), 1), [1, tf.shape(indices)[1]]), tf.transpose(tf.tile(tf.expand_dims(tf.range(tf.shape(indices)[1]), 1), [1, tf.shape(indices)[0]])), indices], 2))
This expression has the following explanation:
tf.gather_nd does what you expected and uses the indices to gather the output from the params
tf.stack combines three separate tensors, the last of which is the indices. The first two tensors specify the ordering of the first two dimensions (axis 0 and axis 1 of params/indices)
For the example provided, this ordering is simply 0, 1, 2, ..., 63 for axis 0, and 0, 1, 2, ... 783 for axis 1. These sequences are obtained with tf.range(tf.shape(indices)[0]) and tf.range(tf.shape(indices)[1]), respectively.
For the example provided, indices has shape (64, 784). The other two tensors from the last point above need to have this same shape in order to be combined with tf.stack
First, an additional dimension/axis is added to each of the two sequences using tf.expand_dims.
The use of tf.tile and tf.transpose can be shown by example: Assume the first two axes of params and index have shape (5,3). We want the first tensor to be:
[[0, 0, 0], [1, 1, 1], [2, 2, 2], [3, 3, 3], [4, 4, 4]]
We want the second tensor to be:
[[0, 1, 2], [0, 1, 2], [0, 1, 2], [0, 1, 2], [0, 1, 2]]
These two tensors almost function like specifying the coordinates in a grid for the associated indices.
The final part of tf.stack combines the three tensors on a new third axis, so that the result has the same 3 axes as params.
Keep in mind if you have more or less axes than in the question, you need to modify the number of coordinate-specifying tensors in tf.stack accordingly.
What you want is like a custom reduction function. If you are keeping something like index of maximum value at indices then I would suggest using tf.reduce_max:
max_params = tf.reduce_max(params_tensor, reduction_indices=[2])
Otherwise, here is one way to get what you want (Tensor objects are not assignable so we create a 2d list of tensors and pack it using tf.pack):
import tensorflow as tf
import numpy as np
with tf.Graph().as_default():
params_tensor = tf.pack(np.random.randint(1,256, [5,5,10]).astype(np.int32))
indices = tf.pack(np.random.randint(1,10,[5,5]).astype(np.int32))
output = [ [None for j in range(params_tensor.get_shape()[1])] for i in range(params_tensor.get_shape()[0])]
for i in range(params_tensor.get_shape()[0]):
for j in range(params_tensor.get_shape()[1]):
output[i][j] = params_tensor[i,j,indices[i,j]]
output = tf.pack(output)
with tf.Session() as sess:
params_tensor,indices,output = sess.run([params_tensor,indices,output])
print params_tensor
print indices
print output
I know I'm late, but I recently had to do something similar, and was able to to do it using Ragged Tensors:
output = tf.gather(params, tf.RaggedTensor.from_tensor(indices), batch_dims=-1, axis=-1)
Hope it helps
I have a tensor of shape (30, 116, 10), and I want to swap the first two dimensions, so that I have a tensor of shape (116, 30, 10)
I saw that numpy as such a function implemented (np.swapaxes) and I searched for something similar in tensorflow but I found nothing.
Do you have any idea?
tf.transpose provides the same functionality as np.swapaxes, although in a more generalized form. In your case, you can do tf.transpose(orig_tensor, [1, 0, 2]) which would be equivalent to np.swapaxes(orig_np_array, 0, 1).
It is possible to use tf.einsum to swap axes if the number of input dimensions is unknown. For example:
tf.einsum("ij...->ji...", input) will swap the first two dimensions of input;
tf.einsum("...ij->...ji", input) will swap the last two dimensions;
tf.einsum("aij...->aji...", input) will swap the second and the third
dimension;
tf.einsum("ijk...->kij...", input) will permute the first three dimensions;
and so on.
You can transpose just the last two axes with tf.linalg.matrix_transpose, or more generally, you can swap any number of trailing axes by working out what the leading indices are dynamically, and using relative indices for the axes you want to transpose
x = tf.ones([5, 3, 7, 11])
trailing_axes = [-1, -2]
leading = tf.range(tf.rank(x) - len(trailing_axes)) # [0, 1]
trailing = trailing_axes + tf.rank(x) # [3, 2]
new_order = tf.concat([leading, trailing], axis=0) # [0, 1, 3, 2]
res = tf.transpose(x, new_order)
res.shape # [5, 3, 11, 7]