I'm trying to put together a query that will fetch the date, purchase amount, and number of transactions of the last time each user made a purchase. I am pulling from a user day table that contains a row for each time a user does anything in the app, purchase or not. Basically all I am trying to get is the most recent date in which the number of transactions field was greater than zero. The below query returns all days of purchase made by a particular user when all I'm looking for is the last purchase so just the 1st row shown in the attached screenshot is what I am trying to get.
screen shot of query and result set
select tuid, max(event_day),
purchases_day_rev as last_dop_rev,
purchases_day_num as last_dop_quantity,
purchases_day_rev/nullif(purchases_day_num,0) as last_dop_spend_pp
from
(select tuid, event_day,purchases_day_rev,purchases_day_num
from
app.user_day
where purchases_day_num > 0
and tuid='122d665e-1d71-4319-bb0d-05c7f37a28b0'
group by 1,2,3,4) a
group by 1,3,4,5
I'm not going to comment on the logic of your query... if all you want is the first row of your result set, you can try:
<your query here> ORDER BY 2 DESC LIMIT 1 ;
Where ORDER BY 2 DESC orders the result set on max(event_day) and LIMIT 1 extracts only the first row.
I don't know all of the ins and outs of your data, but I don't understand why you are grouping within the subquery without any aggregate function (sum, average, min, max, etc). With that said, I would try something like this:
select tuid
,event_day
,purchases_day_rev as last_dop_rev
,purchases_day_num as last_dop_quantity
,purchases_day_rev/nullif(purchases_day_num,0) as last_day_spend_pp
from app.user_day a
inner join
(
select tuid
,max(event_day) as MAX_DAY
from app.user_day
where purchases_day_num > 0
and tuid='122d665e-1d71-4319-bb0d-05c7f37a28b0'
group by 1
) b
on a.tuid = b.tuid
and a.event_day = b.max_day;
Related
I have a table with user, date and a col each for messages sent and messages received:
I want to get the max of messages_sent/messages_recieved by date and user for that ratio. So this is the output I expect:
Andrew Lean 10/2/2020 10
Andrew Harp 10/1/2020 6
This is my query:
SELECT
ds.date, ds.user_name, max(ds.ratio) from
(select a.user_name, a.date, a.message_sent/ a.message_received as ratio
from messages a
group by a.user_name, a.date) ds
group by ds.date
But the output I get is:
Andrew Lean 10/2/2020 10
Jalinn Kim 10/1/2020 6
In the above output 6 is the correct max ratio for the date grouped but the user is wrong. What am I doing wrong?
With a recent version of most databases, you could do something like this.
This assumes, as in your data, there's one row per user per day. If you have more rows per user per day, you'll need to provide a little more detail about how to combine them or ignore some rows. You could want to SUM them. It's tough to know.
WITH cte AS (
select a.user_name, a.date
, a.message_sent / a.message_received AS ratio
, ROW_NUMBER() OVER (PARTITION BY a.date ORDER BY a.message_sent / a.message_received DESC) as rn
from messages a
)
SELECT t.user_name, t.date, t.ratio
FROM cte AS t
WHERE t.rn = 1
;
Note: There's no attempt to handle ties, where more than one user has the same ratio. We could use RANK (or other methods) for that, if your database supports it.
Here, I am just calculating the ratio for each column in the first CTE.
In the second part, I am getting the maximum results of the ratio calculated in the first part on date level. This means I am assuming each user will have one row for each date.
The max() function on date level will ensure that we always get the highest ratio on date level.
There could be ties, between the ratios for that we can use ROW_NUMBER' OR RANK()` to set a rank for each row based on the criteria that we would like to pass in case of ties and then filter on the rank generated.
with data as (
select
date,
user_id,
messages_sent / messages_recieved as ratio
from [table name]
)
select
date,
max(ratio) as higest_ratio_per_date
from data
group by 1,2
I have been trying to write a query to perfect this instance but cant seem to do the trick because I am still receiving duplicated. Hoping I can get help how to fix this issue.
SELECT DISTINCT
1.Client
1.ID
1.Thing
1.Status
MIN(1.StatusDate) as 'statdate'
FROM
SAMPLE 1
WHERE
[]
GROUP BY
1.Client
1.ID
1.Thing
1.status
My output is as follows
Client Id Thing Status Statdate
CompanyA 123 Thing1 Approved 12/9/2019
CompanyA 123 Thing1 Denied 12/6/2019
So although the query is doing what I asked and showing the mininmum status date per status, I want only the first status date. I have about 30k rows to filter through so whatever does not run overload the query and have it not run. Any help would be appreciated
Use window functions:
SELECT s.*
FROM (SELECT s.*,
ROW_NUMBER() OVER (PARTITION BY id ORDER BY statdate) as seqnum
FROM SAMPLE s
WHERE []
) s
WHERE seqnum = 1;
This returns the first row for each id.
Use whichever of these you feel more comfortable with/understand:
SELECT
*
FROM
(
SELECT *, ROW_NUMBER() OVER (PARTITION BY id ORDER BY statusdate) as rn
FROM sample
WHERE ...
) x
WHERE rn = 1
The way that one works is to number all rows sequentially in order of StatusDate, restarting the numbering from 1 every time ID changes. If you thus collect all the number 1's togetyher you have your set of "first records"
Or can coordinate a MIN:
SELECT
*
FROM
sample s
INNER JOIN
(SELECT ID, MIN(statusDate) as minDate FROM sample WHERE ... GROUP BY ID) mins
ON s.ID = mins.ID and s.StatusDate = mins.MinDate
WHERE
...
This one prepares a list of all the ID and the min date, then joins it back to the main table. You thus get all the data back that was lost during the grouping operation; you cannot simultaneously "keep data" and "throw away data" during a group; if you group by more than just ID, you get more groups (as you have found). If you only group by ID you lose the other columns. There isn't any way to say "GROUP BY id, AND take the MIN date, AND also take all the other data from the same row as the min date" without doing a "group by id, take min date, then join this data set back to the main dataset to get the other data for that min date". If you try and do it all in a single grouping you'll fail because you either have to group by more columns, or use aggregating functions for the other data in the SELECT, which mixes your data up; when groups are done, the concept of "other data from the same row" is gone
Be aware that this can return duplicate rows if two records have identical min dates. The ROW_NUMBER form doesn't return duplicated records but if two records have the same minimum StatusDate then which one you'll get is random. To force a specific one, ORDER BY more stuff so you can be sure which will end up with 1
I have two tables. One is NAV where product daily new price is updated. Second is TDK table where item wise stock is available.
Now I want to get a summery report as per buyer name where all product wise total will come and from table one latest price will come.
I have tried below query...
SELECT dbo.TDK.buyer, dbo.NAV.Product_Name, sum(dbo.TDK.TD_UNITS) as Units, sum(dbo.TDK.TD_AMT) as 'Amount',dbo.NAV.NAValue
FROM dbo.TDK INNER JOIN
dbo.NAV
ON dbo.TDK.Products = dbo.NAV.Product_Name
group by dbo.TDK.buyer, dbo.NAV.Product_Name, dbo.NAV.NAValue
Imnportant: Common columns in both tables...
Table one NAV has column as Products
Table two TDK has column as Product_Name
If I have NAValue 4 records for one product then this query shows 4 lines with same total.
What I need??
I want this query to show only one line with latest NAValue price.
I want display one more line with Units*NAValue (latest) as "Latest Market Value".
Please guide.
What field contains the quote date? I am assuming you have a DATIME field, quoteDate, in dbo.NAV table and my other assumption is that you only store the Date part (i.e. mid-night, time = 00:00:00).
SELECT
t.buyer,
n.Product_Name,
sum(t.TD_UNITS) as Units,
sum(t.TD_AMT) as 'Amount',
n.NAValue
FROM dbo.TDK t
INNER JOIN dbo.NAV n
ON t.Products = n.Product_Name
AND n.quoteDate > getdate()-2
group by t.buyer, n.Product_Name, n.NAValue, n.QuoteDate
GetDate() will give you the current date and time. Subtracting 2 would get it before yesterday but after the day before yesterday.
Also, add n.quoteDate in your select and group by. Even though you don't need it, in case that one day you have a day of bad data with double record in NAV table, one with midnight time and another with 6 PM time.
Your code looks like SQL Server. I think you just want APPLY:
SELECT t.buyer, n.Product_Name, t.TD_UNITS as Units, t.TD_AMT as Amount, n.NAValue
FROM dbo.TDK t CROSS APPLY
(SELECT TOP (1) n.*
FROM dbo.NAV n
WHERE t.Products = n.Product_Name
ORDER BY ?? DESC -- however you define "latest"
) n;
I want to write a query that will have the average(that wont be hard) but when I get that average I want to save it somewhere. Let's I have a average save from last month table_a.last_month_average. And now I run the query again and this would be the current_month_average. I want to compare this two columns and see if the current_month_average increase from last_month_average.
After I compare I would like to output the biggest average number from those two. After I do this I would like to move the current_month_average to last_month_average so that one becomes the old average when next month the query runs.
Is this possible in sql? or maybe there is a better way to do this?any suggestions will help.
After I compare I would like to output the biggest average number from those two. After I do this I would like to move the current_month_average to last_month_average so that one becomes the old average when next month the query runs.
By my understanding, this operation is to select maximum month_average from all history records. So you don't need to keep a record of current_month_average and last_month_average. Instead, a table of all history month average is helpful. Assume there is table named monthaverage with columns (Id, Month, Average), you can query
SELECT TOP 1 T1.*
, CASE WHEN
T1.Average > (SELECT TOP 1 T2.Average
FROM monthaverage T2
WHERE T2.Month < T1.Month
ORDER BY Month DESC)
THEN 'Increased'
ELSE 'Not Increased'
END
FROM monthaverage T1
ORDER BY T1.Average DESC
If you have chance to run it from SQL SERVER 2012, you can leverage LAST_VALUE function. Query is like
SELECT TOP 1 *, CASE WHEN Average > LAST_VALUE(Average) OVER (ORDER BY Month) THEN 'Increased' ELSE 'Not Increased' END
FROM monthaverage
ORDER BY Average DESC
I have a table SIGNUPS, where I register all signups to a specific event. Now, I would like to get all people who signed up to an event, with an extra column STATUS telling if the user is actually accepted (STATUS = "OK") or if it is in a waiting list (STATUS="WL"). I tried something like this
SELECT *, IDUSER IN (SELECT IDUSER FROM SIGNUPS ORDER BY DATE ASC LIMIT 10)
as STATUS from SIGNUPS WHERE IDEVENT = 1
This should return STATUS 1 for the first 10 users who signed up, and 0 for all other ones. Unluckily, I get a Mysql error telling me that LIMIT in subqueries is not yet supported.
Could you please suggest another way to get the same information?
Thanks
Something like the following will get what you need - although I haven't tested it against some sample tables. The subqueries find the date above which the last ten signups occur, which is then used to comapre to the date of the current row.
select
s.*,
s.DATE > d.min_date_10 AS STATUS
from SIGNUPS s
join (
select MIN(DATE) AS min_date_10 from (
select DATE from SIGNUPS order by DATE asc LIMIT 10
) a
) d
WHERE IDEVENT = 1