As simple sorting by two values in Kotlin can be like this:
.sortedWith(compareBy({ it.lastName }, { it.firstName }))
How to sort by those 2 field and adding case insensitive order?
I know that this can be only applied to sorting by one field:
.sortedWith(compareBy(String.CASE_INSENSITIVE_ORDER, { it.lastName })
How to do this for both fields?
Not like this?
.sortedWith(compareBy({ it.lastName.toLowerCase() }, { it.firstName.toLowerCase() }))
Related
I have a record of First_Name and Second_Name stored in MySql DB. Currently I am displaying it in 2 different columns of Ag-Grid. I need those data to be combined together as Name and to be displayed in Ag-Grid's single column. Please help!
I am using Vue.Js
You should use a valueGetter in your columnDef like this -
{
headerName: 'Name',
colId: 'name',
valueGetter: function(params) {
return params.data.First_Name + " " + params.data.Second_Name;
},
},
Example from docs here
The ans stated by Pratik is right. Maybe you can use arrow functions for valueGetter so that the code looks more concise and simplify function scoping.
{
headerName: 'Name',
valueGetter: params => {
return ${params.data.First_Name} ${params.data.Second_Name};
},
},
I'm having trouble getting the correct query with sequelize.
I have an array representing ids of entries lets say its like this -
userVacationsIds = [1,2,3]
i made the first query like this
Vacation.findAll({
where: {
id: {
[Op.or]: userVacationsIds
}
}
})
.then(vacationSpec => {
Vacation.findAll({
where:{
//Here i need to get all entries that DONT have the ids from the array
}
}
})
I can't get the correct query as specified in my code "comment"
I've tried referring to sequelize documentation but i can't understand how to chain these queries specifically
Also tried an online converter but that failed too.
Specified the code i have above
So i just need some help getting this query correct please.
I eventually expect to get 2 arrays - one containing all entries with the ids from the array, the other containing everything else (as in id is NOT in the array)
I figured it out.
I feel silly.
This is the query that worked
Vacation.findAll({
where: {
id: {
[Op.or]: userVacationsIds
}
}
}).then(vacationSpec => {
Vacation.findAll({
where: {
id: {
[Op.notIn]: userVacationsIds
}
}
})
Let's say I have a list of Strings in Kotlin: stringList: MutableList<String>
Then it is is easy to sort such list in case insensitive order by doing this:
stringList.sortWith(String.CASE_INSENSITIVE_ORDER)
But how would I sort a list of objects in case insensitive order? For example: places: MutableList<Place>
Where Place is a simple class with 2 fields - name: String and id: Int, and I would like to sort these Places by the name field.
I tried to do something like this: places.sortedWith(compareBy { it.name }) but this solution doesn't take letter case into account.
It looks like compareBy might be able to take a Comparator as an argument, see the documentation here: https://kotlinlang.org/api/latest/jvm/stdlib/kotlin.comparisons/compare-by.html
Try:
places.sortWith(compareBy(String.CASE_INSENSITIVE_ORDER, { it.name }))
to sort the array in place, or you can assign it to a new variable using
val newArray = places.sortedWith(compareBy(String.CASE_INSENSITIVE_ORDER, { it.name }))
Sort Ascending - case insensitive:
myList.sortedBy { it.name?.toLowerCase() }
Sort Descending - case insensitive:
myList.sortedByDescending { it.name?.toLowerCase() }
With SQL we can do the following :
select * from x where concat(x.y ," ",x.z) like "%find m%"
when x.y = "find" and x.z = "me".
How do I do the same thing with MongoDB, When I use a JSON structure similar to this:
{
data:
[
{
id:1,
value : "find"
},
{
id:2,
value : "me"
}
]
}
The comparison to SQL here is not valid since no relational database has the same concept of embedded arrays that MongoDB has, and is provided in your example. You can only "concat" between "fields in a row" of a table. Basically not the same thing.
You can do this with the JavaScript evaluation of $where, which is not optimal, but it's a start. And you can add some extra "smarts" to the match as well with caution:
db.collection.find({
"$or": [
{ "data.value": /^f/ },
{ "data.value": /^m/ }
],
"$where": function() {
var items = [];
this.data.forEach(function(item) {
items.push(item.value);
});
var myString = items.join(" ");
if ( myString.match(/find m/) != null )
return 1;
}
})
So there you go. We optimized this a bit by taking the first characters from your "test string" in each word and compared the tokens to each element of the array in the document.
The next part "concatenates" the array elements into a string and then does a "regex" comparison ( same as "like" ) on the concatenated result to see if it matches. Where it does then the document is considered a match and returned.
Not optimal, but these are the options available to MongoDB on a structure like this. Perhaps the structure should be different. But you don't specify why you want this so we can't advise a better solution to what you want to achieve.
I am working with a dgrid where I want to find a search term in my grid on two columns.
For instance, I want to see if the scientific name and commonName columns contain the string "Aca" (I want my search to be case insensitive)
My Grid definition:
var CustomGrid = declare([Grid, Pagination ]);
var gridStore = new Memory({ idProperty: 'tsn', data: null });
gridStore.queryEngine = rql.query;
grid = new CustomGrid({
store: gridStore,
columns:
[
{ field: "tsn", label: "TSN #"},
{ field: "scientificName", label: "Scientific Name"},
{ field: "commonName", label: "Common Name",},
],
autoHeight: 'true',
firstLastArrows: 'true',
pageSizeOptions: [50, 100],
}, id);
With the built in query language (I think simple query language), I was able to find the term in one column or the other, but I couldn't do a complex search that would return results for both columns.
grid.set("query", { scientificName : new RegExp(speciesKeyword, "i") });
grid.refresh()
I started reading and I think RQL can solve this problem, however, I am struggling with the syntax.
I have been looking at these pages:
http://rql-engine.eu01.aws.af.cm/
https://github.com/kriszyp/rql
And I am able to understand basic queries, however the "contains" syntax eludes me.
For instance if I had this simple data set and wanted to find the entries with scientific and common names that contain the string "Aca" I would think my contains query would look like this:
contains(scientificName,string:aca)
However, this results in no matches.
[
{
"tsn": 1,
"scientificName": "Acalypha ostryifolia",
"commonName": "Rough-pod Copperleaf",
},
{
"tsn": 2,
"scientificName": "Aegalius acadicus",
"commonName": "Northern Saw-whet Owl",
},
{
"tsn": 3,
"scientificName": "Portulaca pilosa",
"commonName": "2012-02-01",
},
{
"tsn": 4,
"scientificName": "Accipiter striatus",
"commonName": "Kiss-me-quick",
},
{
"tsn": 5,
"scientificName": "Acorus americanus",
"commonName": "American Sweetflag",
}
]
Can someone guide me in how to formulate the correct syntax? Thank you.
From what I'm briefly reading, it appears that:
contains was replaced by any and all
these are meant for array comparisons, not string comparisons
I'm not sure offhand whether RegExps can just be handed to other operations e.g. eq.
With dojo/store/Memory, you can also pass a query function which will allow you to do whatever you want, so if you wanted to compare for a match in one field or the other you could do something like this:
grid.set('query', function (item) {
var scientificRx = new RegExp(speciesKeyword, 'i');
var commonRx = new RegExp(...);
return scientificRx.test(item.scientificName) || commonRx.test(item.commonName);
});
Of course, if you want to filter only items that match both, you can do that with simple object syntax:
grid.set('query', {
scientificName: scientificRx,
commonName: commonRx
});